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Bash Script - Get result of `(.*)` (dot star) in grep regex

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;

4

Let's say I have the following JSON string in a Bash script variable, DATA:

 "id": 10,
 "name": "Person 1",
 "note": "This is a test"

I need to get the value of the name field. I have used grep like this:

NAME=$(echo "$DATA" | grep -E ""name": "(.*)"")

However, this returns "name": "Person 1". I need Person 1. How can I get the result of just the (.*)?

shell-script grep regular-expression

share|improve this question

asked May 4 at 5:28

APixel VisualsAPixel Visuals

1414

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  A more general answer: If the data was line based (not json), then you would use sed.
  
  – ctrl-alt-delor
  May 4 at 8:50
  

  
  
  
  

add a comment | 

4

Let's say I have the following JSON string in a Bash script variable, DATA:

 "id": 10,
 "name": "Person 1",
 "note": "This is a test"

I need to get the value of the name field. I have used grep like this:

NAME=$(echo "$DATA" | grep -E ""name": "(.*)"")

However, this returns "name": "Person 1". I need Person 1. How can I get the result of just the (.*)?

shell-script grep regular-expression

share|improve this question

asked May 4 at 5:28

APixel VisualsAPixel Visuals

1414

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  A more general answer: If the data was line based (not json), then you would use sed.
  
  – ctrl-alt-delor
  May 4 at 8:50
  

  
  
  
  

add a comment | 

Let's say I have the following JSON string in a Bash script variable, DATA:

 "id": 10,
 "name": "Person 1",
 "note": "This is a test"

I need to get the value of the name field. I have used grep like this:

NAME=$(echo "$DATA" | grep -E ""name": "(.*)"")

However, this returns "name": "Person 1". I need Person 1. How can I get the result of just the (.*)?

shell-script grep regular-expression

share|improve this question

asked May 4 at 5:28

APixel VisualsAPixel Visuals

1414

 "id": 10,
 "name": "Person 1",
 "note": "This is a test"

NAME=$(echo "$DATA" | grep -E ""name": "(.*)"")

share|improve this question

asked May 4 at 5:28

APixel VisualsAPixel Visuals

1414

share|improve this question

asked May 4 at 5:28

APixel VisualsAPixel Visuals

1414

asked May 4 at 5:28

APixel VisualsAPixel Visuals

1414

asked May 4 at 5:28

APixel VisualsAPixel Visuals

1414

1 Answer
1

active

oldest

votes

7

You can do this easily with jq:

$ DATA='
 "id": 10,
 "name": "Person 1",
 "note": "This is a test"
'
$ jq -r '.name' <<<"$DATA"
Person 1

In general, it's best to avoid regex for parsing structured data such as html, json, and yaml.

To accomplish this with grep, you need to use PCRE to leverage look-aheads and look-behinds:

$ echo $DATA | grep -Po '(?<="name": ").*(?=")'
Person 1

share|improve this answer

answered May 4 at 5:32

jordanmjordanm

31.6k38998

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  jq makes things a lot easier. Thank you so much! I'll accept the answer after the 10 minute timer
  
  – APixel Visuals
  May 4 at 5:37
  

  
  
  
  

add a comment | 

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7

You can do this easily with jq:

$ DATA='
 "id": 10,
 "name": "Person 1",
 "note": "This is a test"
'
$ jq -r '.name' <<<"$DATA"
Person 1

In general, it's best to avoid regex for parsing structured data such as html, json, and yaml.

To accomplish this with grep, you need to use PCRE to leverage look-aheads and look-behinds:

$ echo $DATA | grep -Po '(?<="name": ").*(?=")'
Person 1

share|improve this answer

answered May 4 at 5:32

jordanmjordanm

31.6k38998

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  jq makes things a lot easier. Thank you so much! I'll accept the answer after the 10 minute timer
  
  – APixel Visuals
  May 4 at 5:37
  

  
  
  
  

add a comment | 

7

You can do this easily with jq:

$ DATA='
 "id": 10,
 "name": "Person 1",
 "note": "This is a test"
'
$ jq -r '.name' <<<"$DATA"
Person 1

In general, it's best to avoid regex for parsing structured data such as html, json, and yaml.

To accomplish this with grep, you need to use PCRE to leverage look-aheads and look-behinds:

$ echo $DATA | grep -Po '(?<="name": ").*(?=")'
Person 1

share|improve this answer

answered May 4 at 5:32

jordanmjordanm

31.6k38998

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  jq makes things a lot easier. Thank you so much! I'll accept the answer after the 10 minute timer
  
  – APixel Visuals
  May 4 at 5:37
  

  
  
  
  

add a comment | 

You can do this easily with jq:

$ DATA='
 "id": 10,
 "name": "Person 1",
 "note": "This is a test"
'
$ jq -r '.name' <<<"$DATA"
Person 1

In general, it's best to avoid regex for parsing structured data such as html, json, and yaml.

To accomplish this with grep, you need to use PCRE to leverage look-aheads and look-behinds:

$ echo $DATA | grep -Po '(?<="name": ").*(?=")'
Person 1

share|improve this answer

answered May 4 at 5:32

jordanmjordanm

31.6k38998

$ DATA='
 "id": 10,
 "name": "Person 1",
 "note": "This is a test"
'
$ jq -r '.name' <<<"$DATA"
Person 1

$ echo $DATA | grep -Po '(?<="name": ").*(?=")'
Person 1

share|improve this answer

answered May 4 at 5:32

jordanmjordanm

31.6k38998

answered May 4 at 5:32

jordanmjordanm

31.6k38998

answered May 4 at 5:32

jordanmjordanm

31.6k38998