How do I find out when a node was added to an availability group?Replicate a database to one secondary replica, but not the other secondary replica using Availability Groupadding node to existing availability groupOne Availability group, two primary nodesWindows patching on 3 node Always On Availability GroupIncreasing tempdb data files on 2 node Availability GroupSQL Server 2014: Graceful shutdown of an Availability Group nodeCan't resume synchronization after patch failed on secondary node of Availability GroupSQL Server 2016 Availability Group - 2 Nodes as Primary & Readable Secondary, 1 Node as DRAvailability Group cluster memory issue after network issues. How to dump HADR Log Block Msg Pool?Failure to create availability group
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How do I find out when a node was added to an availability group?
Replicate a database to one secondary replica, but not the other secondary replica using Availability Groupadding node to existing availability groupOne Availability group, two primary nodesWindows patching on 3 node Always On Availability GroupIncreasing tempdb data files on 2 node Availability GroupSQL Server 2014: Graceful shutdown of an Availability Group nodeCan't resume synchronization after patch failed on secondary node of Availability GroupSQL Server 2016 Availability Group - 2 Nodes as Primary & Readable Secondary, 1 Node as DRAvailability Group cluster memory issue after network issues. How to dump HADR Log Block Msg Pool?Failure to create availability group
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Ideally, I am looking for T-SQL that returns two columns: the node name, and the date/time that node was added to the availability group, for all nodes in a given availability group.
sql-server availability-groups
asked Apr 4 at 13:06
Mark RaymondMark Raymond
15614
add a comment |
Ideally, I am looking for T-SQL that returns two columns: the node name, and the date/time that node was added to the availability group, for all nodes in a given availability group.
sql-server availability-groups
asked Apr 4 at 13:06
Mark RaymondMark Raymond
15614
add a comment |
Ideally, I am looking for T-SQL that returns two columns: the node name, and the date/time that node was added to the availability group, for all nodes in a given availability group.
sql-server availability-groups
asked Apr 4 at 13:06
Mark RaymondMark Raymond
15614
Ideally, I am looking for T-SQL that returns two columns: the node name, and the date/time that node was added to the availability group, for all nodes in a given availability group.
sql-server availability-groups
sql-server availability-groups
asked Apr 4 at 13:06
Mark RaymondMark Raymond
15614
asked Apr 4 at 13:06
Mark RaymondMark Raymond
15614
asked Apr 4 at 13:06
Mark RaymondMark Raymond
15614
asked Apr 4 at 13:06
Mark RaymondMark Raymond
15614
asked Apr 4 at 13:06
Mark RaymondMark Raymond
15614
15614
add a comment |
add a comment |
1 Answer
1
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oldest
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This is as far as I can see not possible with a single T-SQL statement as individual nodes hold only their own create date.
The sys.availability_replicas page makes reference to a column create_date. This is the datetime value of when the node was added.
To find the create_date for each replica you would need to first connect that replica and query the table for that instance only as below.
SELECT [replica_server_name],
[create_date]
FROM [master].[sys].[availability_replicas]
WHERE replica_server_name = @@SERVERNAME
answered Apr 4 at 13:11
George.PalaciosGeorge.Palacios
2,537826
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
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active
oldest
votes
This is as far as I can see not possible with a single T-SQL statement as individual nodes hold only their own create date.
The sys.availability_replicas page makes reference to a column create_date. This is the datetime value of when the node was added.
To find the create_date for each replica you would need to first connect that replica and query the table for that instance only as below.
SELECT [replica_server_name],
[create_date]
FROM [master].[sys].[availability_replicas]
WHERE replica_server_name = @@SERVERNAME
answered Apr 4 at 13:11
George.PalaciosGeorge.Palacios
2,537826
add a comment |
This is as far as I can see not possible with a single T-SQL statement as individual nodes hold only their own create date.
The sys.availability_replicas page makes reference to a column create_date. This is the datetime value of when the node was added.
To find the create_date for each replica you would need to first connect that replica and query the table for that instance only as below.
SELECT [replica_server_name],
[create_date]
FROM [master].[sys].[availability_replicas]
WHERE replica_server_name = @@SERVERNAME
answered Apr 4 at 13:11
George.PalaciosGeorge.Palacios
2,537826
add a comment |
This is as far as I can see not possible with a single T-SQL statement as individual nodes hold only their own create date.
The sys.availability_replicas page makes reference to a column create_date. This is the datetime value of when the node was added.
To find the create_date for each replica you would need to first connect that replica and query the table for that instance only as below.
SELECT [replica_server_name],
[create_date]
FROM [master].[sys].[availability_replicas]
WHERE replica_server_name = @@SERVERNAME
answered Apr 4 at 13:11
George.PalaciosGeorge.Palacios
2,537826
This is as far as I can see not possible with a single T-SQL statement as individual nodes hold only their own create date.
The sys.availability_replicas page makes reference to a column create_date. This is the datetime value of when the node was added.
To find the create_date for each replica you would need to first connect that replica and query the table for that instance only as below.
SELECT [replica_server_name],
[create_date]
FROM [master].[sys].[availability_replicas]
WHERE replica_server_name = @@SERVERNAME
answered Apr 4 at 13:11
George.PalaciosGeorge.Palacios
2,537826
answered Apr 4 at 13:11
George.PalaciosGeorge.Palacios
2,537826
answered Apr 4 at 13:11
George.PalaciosGeorge.Palacios
2,537826
answered Apr 4 at 13:11
George.PalaciosGeorge.Palacios
2,537826
2,537826
add a comment |
add a comment |
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