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Grandpa has another non math question
A simple association between letters and numbersNon-puzzling nephewsAnother Next Number QuestionGrandpa and numbers: Another Grandpa Mystery3 = 6 ? Another non math question. Another Grandpa Mystery$6$ is prime? Another Grandpa Mystery (not made by @DEEM, this time)Alphabets and Numbers? : Another Grandpa MysteryA silly silly questionAre these numbers unique?Can 4 = 6 and 10 = 1000? : Another Grandpa Question“Thinking of ” question for Comics readers
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
Grandpa says, " This is not algebra or may be it is!
IF
X = 2
R + C = 6
B + P = 5 or 6
Then
What is
I + T ?
There are, with my logic, three different answers!"
lateral-thinking
$endgroup$
|
show 1 more comment
$begingroup$
Grandpa says, " This is not algebra or may be it is!
IF
X = 2
R + C = 6
B + P = 5 or 6
Then
What is
I + T ?
There are, with my logic, three different answers!"
lateral-thinking
$endgroup$
$begingroup$
Yay! Another one of these! +1 and favorite.
$endgroup$
– Duck
Jun 9 at 20:23
2
$begingroup$
Grandpa seems like a troublemaker.
$endgroup$
– Rubio♦
Jun 9 at 20:24
2
$begingroup$
That he is @Rubio that he is. (Ask Grandma)
$endgroup$
– DEEM
Jun 9 at 20:25
$begingroup$
Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
$endgroup$
– Duck
Jun 9 at 20:26
$begingroup$
not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
$endgroup$
– DEEM
Jun 9 at 20:39
|
show 1 more comment
$begingroup$
Grandpa says, " This is not algebra or may be it is!
IF
X = 2
R + C = 6
B + P = 5 or 6
Then
What is
I + T ?
There are, with my logic, three different answers!"
lateral-thinking
$endgroup$
Grandpa says, " This is not algebra or may be it is!
IF
X = 2
R + C = 6
B + P = 5 or 6
Then
What is
I + T ?
There are, with my logic, three different answers!"
lateral-thinking
lateral-thinking
asked Jun 9 at 20:11
DEEMDEEM
6,9331 gold badge23 silver badges125 bronze badges
6,9331 gold badge23 silver badges125 bronze badges
$begingroup$
Yay! Another one of these! +1 and favorite.
$endgroup$
– Duck
Jun 9 at 20:23
2
$begingroup$
Grandpa seems like a troublemaker.
$endgroup$
– Rubio♦
Jun 9 at 20:24
2
$begingroup$
That he is @Rubio that he is. (Ask Grandma)
$endgroup$
– DEEM
Jun 9 at 20:25
$begingroup$
Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
$endgroup$
– Duck
Jun 9 at 20:26
$begingroup$
not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
$endgroup$
– DEEM
Jun 9 at 20:39
|
show 1 more comment
$begingroup$
Yay! Another one of these! +1 and favorite.
$endgroup$
– Duck
Jun 9 at 20:23
2
$begingroup$
Grandpa seems like a troublemaker.
$endgroup$
– Rubio♦
Jun 9 at 20:24
2
$begingroup$
That he is @Rubio that he is. (Ask Grandma)
$endgroup$
– DEEM
Jun 9 at 20:25
$begingroup$
Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
$endgroup$
– Duck
Jun 9 at 20:26
$begingroup$
not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
$endgroup$
– DEEM
Jun 9 at 20:39
$begingroup$
Yay! Another one of these! +1 and favorite.
$endgroup$
– Duck
Jun 9 at 20:23
$begingroup$
Yay! Another one of these! +1 and favorite.
$endgroup$
– Duck
Jun 9 at 20:23
2
2
$begingroup$
Grandpa seems like a troublemaker.
$endgroup$
– Rubio♦
Jun 9 at 20:24
$begingroup$
Grandpa seems like a troublemaker.
$endgroup$
– Rubio♦
Jun 9 at 20:24
2
2
$begingroup$
That he is @Rubio that he is. (Ask Grandma)
$endgroup$
– DEEM
Jun 9 at 20:25
$begingroup$
That he is @Rubio that he is. (Ask Grandma)
$endgroup$
– DEEM
Jun 9 at 20:25
$begingroup$
Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
$endgroup$
– Duck
Jun 9 at 20:26
$begingroup$
Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
$endgroup$
– Duck
Jun 9 at 20:26
$begingroup$
not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
$endgroup$
– DEEM
Jun 9 at 20:39
$begingroup$
not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
$endgroup$
– DEEM
Jun 9 at 20:39
|
show 1 more comment
2 Answers
2
active
oldest
votes
$begingroup$
Here’s a thought...
X = 2
X is said like the word “ex” = 2 letters
R + C = 6
“are” plus “cee” (or “see” or “sea”) = 6
B + P = 5 or 6
“be” or “bee” plus “pee” (or “pea”) = 5 or 6
Thus, I + T =
Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6
for three solutions using the same logic, as requested.
... and “ti” would actually allow four answers, 3 4 5 or 6 :)
$endgroup$
$begingroup$
heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
$endgroup$
– Jonathan Allan
Jun 10 at 12:17
1
$begingroup$
I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
$endgroup$
– Bizhan
Jun 10 at 15:34
1
$begingroup$
@Bizhan ay me, you might be right. Er, wait ...
$endgroup$
– Rubio♦
Jun 11 at 2:08
$begingroup$
Oh! ay me! haha!
$endgroup$
– Bizhan
Jun 11 at 7:27
add a comment |
$begingroup$
X = 2
X is written in two strokes
R + C = 6
R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6
B + P = 5 or 6
B is 2 strokes, + is 2, P is 2 which will result in 6?
I + T
I will be 1 stroke + is 2, T is also 2 which will make 5
$endgroup$
3
$begingroup$
How do you make B two? At least three, surely.
$endgroup$
– Rand al'Thor
Jun 10 at 9:04
$begingroup$
This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
$endgroup$
– Rubio♦
Jun 10 at 9:50
$begingroup$
@Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept isI
3
"
$endgroup$
– UKMonkey
Jun 10 at 10:19
$begingroup$
I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
$endgroup$
– Mario Garcia
Jun 10 at 11:26
$begingroup$
This also fails to have 3 possible answers. You can debate how many there are forB
orP
, butI + T
is pretty unambiguous by these rules.
$endgroup$
– Darrel Hoffman
Jun 10 at 12:47
|
show 4 more comments
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Here’s a thought...
X = 2
X is said like the word “ex” = 2 letters
R + C = 6
“are” plus “cee” (or “see” or “sea”) = 6
B + P = 5 or 6
“be” or “bee” plus “pee” (or “pea”) = 5 or 6
Thus, I + T =
Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6
for three solutions using the same logic, as requested.
... and “ti” would actually allow four answers, 3 4 5 or 6 :)
$endgroup$
$begingroup$
heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
$endgroup$
– Jonathan Allan
Jun 10 at 12:17
1
$begingroup$
I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
$endgroup$
– Bizhan
Jun 10 at 15:34
1
$begingroup$
@Bizhan ay me, you might be right. Er, wait ...
$endgroup$
– Rubio♦
Jun 11 at 2:08
$begingroup$
Oh! ay me! haha!
$endgroup$
– Bizhan
Jun 11 at 7:27
add a comment |
$begingroup$
Here’s a thought...
X = 2
X is said like the word “ex” = 2 letters
R + C = 6
“are” plus “cee” (or “see” or “sea”) = 6
B + P = 5 or 6
“be” or “bee” plus “pee” (or “pea”) = 5 or 6
Thus, I + T =
Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6
for three solutions using the same logic, as requested.
... and “ti” would actually allow four answers, 3 4 5 or 6 :)
$endgroup$
$begingroup$
heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
$endgroup$
– Jonathan Allan
Jun 10 at 12:17
1
$begingroup$
I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
$endgroup$
– Bizhan
Jun 10 at 15:34
1
$begingroup$
@Bizhan ay me, you might be right. Er, wait ...
$endgroup$
– Rubio♦
Jun 11 at 2:08
$begingroup$
Oh! ay me! haha!
$endgroup$
– Bizhan
Jun 11 at 7:27
add a comment |
$begingroup$
Here’s a thought...
X = 2
X is said like the word “ex” = 2 letters
R + C = 6
“are” plus “cee” (or “see” or “sea”) = 6
B + P = 5 or 6
“be” or “bee” plus “pee” (or “pea”) = 5 or 6
Thus, I + T =
Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6
for three solutions using the same logic, as requested.
... and “ti” would actually allow four answers, 3 4 5 or 6 :)
$endgroup$
Here’s a thought...
X = 2
X is said like the word “ex” = 2 letters
R + C = 6
“are” plus “cee” (or “see” or “sea”) = 6
B + P = 5 or 6
“be” or “bee” plus “pee” (or “pea”) = 5 or 6
Thus, I + T =
Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6
for three solutions using the same logic, as requested.
... and “ti” would actually allow four answers, 3 4 5 or 6 :)
answered Jun 9 at 23:59
Rubio♦Rubio
32.2k6 gold badges72 silver badges198 bronze badges
32.2k6 gold badges72 silver badges198 bronze badges
$begingroup$
heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
$endgroup$
– Jonathan Allan
Jun 10 at 12:17
1
$begingroup$
I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
$endgroup$
– Bizhan
Jun 10 at 15:34
1
$begingroup$
@Bizhan ay me, you might be right. Er, wait ...
$endgroup$
– Rubio♦
Jun 11 at 2:08
$begingroup$
Oh! ay me! haha!
$endgroup$
– Bizhan
Jun 11 at 7:27
add a comment |
$begingroup$
heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
$endgroup$
– Jonathan Allan
Jun 10 at 12:17
1
$begingroup$
I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
$endgroup$
– Bizhan
Jun 10 at 15:34
1
$begingroup$
@Bizhan ay me, you might be right. Er, wait ...
$endgroup$
– Rubio♦
Jun 11 at 2:08
$begingroup$
Oh! ay me! haha!
$endgroup$
– Bizhan
Jun 11 at 7:27
$begingroup$
heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
$endgroup$
– Jonathan Allan
Jun 10 at 12:17
$begingroup$
heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
$endgroup$
– Jonathan Allan
Jun 10 at 12:17
1
1
$begingroup$
I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
$endgroup$
– Bizhan
Jun 10 at 15:34
$begingroup$
I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
$endgroup$
– Bizhan
Jun 10 at 15:34
1
1
$begingroup$
@Bizhan ay me, you might be right. Er, wait ...
$endgroup$
– Rubio♦
Jun 11 at 2:08
$begingroup$
@Bizhan ay me, you might be right. Er, wait ...
$endgroup$
– Rubio♦
Jun 11 at 2:08
$begingroup$
Oh! ay me! haha!
$endgroup$
– Bizhan
Jun 11 at 7:27
$begingroup$
Oh! ay me! haha!
$endgroup$
– Bizhan
Jun 11 at 7:27
add a comment |
$begingroup$
X = 2
X is written in two strokes
R + C = 6
R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6
B + P = 5 or 6
B is 2 strokes, + is 2, P is 2 which will result in 6?
I + T
I will be 1 stroke + is 2, T is also 2 which will make 5
$endgroup$
3
$begingroup$
How do you make B two? At least three, surely.
$endgroup$
– Rand al'Thor
Jun 10 at 9:04
$begingroup$
This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
$endgroup$
– Rubio♦
Jun 10 at 9:50
$begingroup$
@Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept isI
3
"
$endgroup$
– UKMonkey
Jun 10 at 10:19
$begingroup$
I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
$endgroup$
– Mario Garcia
Jun 10 at 11:26
$begingroup$
This also fails to have 3 possible answers. You can debate how many there are forB
orP
, butI + T
is pretty unambiguous by these rules.
$endgroup$
– Darrel Hoffman
Jun 10 at 12:47
|
show 4 more comments
$begingroup$
X = 2
X is written in two strokes
R + C = 6
R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6
B + P = 5 or 6
B is 2 strokes, + is 2, P is 2 which will result in 6?
I + T
I will be 1 stroke + is 2, T is also 2 which will make 5
$endgroup$
3
$begingroup$
How do you make B two? At least three, surely.
$endgroup$
– Rand al'Thor
Jun 10 at 9:04
$begingroup$
This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
$endgroup$
– Rubio♦
Jun 10 at 9:50
$begingroup$
@Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept isI
3
"
$endgroup$
– UKMonkey
Jun 10 at 10:19
$begingroup$
I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
$endgroup$
– Mario Garcia
Jun 10 at 11:26
$begingroup$
This also fails to have 3 possible answers. You can debate how many there are forB
orP
, butI + T
is pretty unambiguous by these rules.
$endgroup$
– Darrel Hoffman
Jun 10 at 12:47
|
show 4 more comments
$begingroup$
X = 2
X is written in two strokes
R + C = 6
R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6
B + P = 5 or 6
B is 2 strokes, + is 2, P is 2 which will result in 6?
I + T
I will be 1 stroke + is 2, T is also 2 which will make 5
$endgroup$
X = 2
X is written in two strokes
R + C = 6
R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6
B + P = 5 or 6
B is 2 strokes, + is 2, P is 2 which will result in 6?
I + T
I will be 1 stroke + is 2, T is also 2 which will make 5
answered Jun 10 at 7:26
MichaelMichael
692 bronze badges
692 bronze badges
3
$begingroup$
How do you make B two? At least three, surely.
$endgroup$
– Rand al'Thor
Jun 10 at 9:04
$begingroup$
This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
$endgroup$
– Rubio♦
Jun 10 at 9:50
$begingroup$
@Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept isI
3
"
$endgroup$
– UKMonkey
Jun 10 at 10:19
$begingroup$
I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
$endgroup$
– Mario Garcia
Jun 10 at 11:26
$begingroup$
This also fails to have 3 possible answers. You can debate how many there are forB
orP
, butI + T
is pretty unambiguous by these rules.
$endgroup$
– Darrel Hoffman
Jun 10 at 12:47
|
show 4 more comments
3
$begingroup$
How do you make B two? At least three, surely.
$endgroup$
– Rand al'Thor
Jun 10 at 9:04
$begingroup$
This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
$endgroup$
– Rubio♦
Jun 10 at 9:50
$begingroup$
@Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept isI
3
"
$endgroup$
– UKMonkey
Jun 10 at 10:19
$begingroup$
I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
$endgroup$
– Mario Garcia
Jun 10 at 11:26
$begingroup$
This also fails to have 3 possible answers. You can debate how many there are forB
orP
, butI + T
is pretty unambiguous by these rules.
$endgroup$
– Darrel Hoffman
Jun 10 at 12:47
3
3
$begingroup$
How do you make B two? At least three, surely.
$endgroup$
– Rand al'Thor
Jun 10 at 9:04
$begingroup$
How do you make B two? At least three, surely.
$endgroup$
– Rand al'Thor
Jun 10 at 9:04
$begingroup$
This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
$endgroup$
– Rubio♦
Jun 10 at 9:50
$begingroup$
This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
$endgroup$
– Rubio♦
Jun 10 at 9:50
$begingroup$
@Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept is
I
3
"$endgroup$
– UKMonkey
Jun 10 at 10:19
$begingroup$
@Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept is
I
3
"$endgroup$
– UKMonkey
Jun 10 at 10:19
$begingroup$
I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
$endgroup$
– Mario Garcia
Jun 10 at 11:26
$begingroup$
I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
$endgroup$
– Mario Garcia
Jun 10 at 11:26
$begingroup$
This also fails to have 3 possible answers. You can debate how many there are for
B
or P
, but I + T
is pretty unambiguous by these rules.$endgroup$
– Darrel Hoffman
Jun 10 at 12:47
$begingroup$
This also fails to have 3 possible answers. You can debate how many there are for
B
or P
, but I + T
is pretty unambiguous by these rules.$endgroup$
– Darrel Hoffman
Jun 10 at 12:47
|
show 4 more comments
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$begingroup$
Yay! Another one of these! +1 and favorite.
$endgroup$
– Duck
Jun 9 at 20:23
2
$begingroup$
Grandpa seems like a troublemaker.
$endgroup$
– Rubio♦
Jun 9 at 20:24
2
$begingroup$
That he is @Rubio that he is. (Ask Grandma)
$endgroup$
– DEEM
Jun 9 at 20:25
$begingroup$
Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
$endgroup$
– Duck
Jun 9 at 20:26
$begingroup$
not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
$endgroup$
– DEEM
Jun 9 at 20:39