Otdfbt

Causes of bimodal distributions when bootstrapping a meta-analysis model

Is there an official reason for not adding a post-credits scene?

Emotional immaturity of comic-book version of superhero Shazam

Understanding trademark infringements in a world where many dictionary words are trademarks?

Upside-Down Pyramid Addition...REVERSED!

Why are prions in animal diets not destroyed by the digestive system?

Why aren't nationalizations in Russia described as socialist?

What does this wavy downward arrow preceding a piano chord mean?

How to write a 12-bar blues melody

Wrong answer from DSolve when solving a differential equation

Out of scope work duties and resignation

Gerrymandering Puzzle - Rig the Election

My advisor talks about me to his colleague

Should I mention being denied entry to UK due to a confusion in my Visa and Ticket bookings?

What to use instead of cling film to wrap pastry

Where is the documentation for this ex command?

Appropriate certificate to ask for a fibre installation (ANSI/TIA-568.3-D?)

Can there be a single technologically advanced nation, in a continent full of non-technologically advanced nations?

ZSPL language, anyone heard of it?

Are pressure-treated posts that have been submerged for a few days ruined?

How do LIGO and VIRGO know that a gravitational wave has its origin in a neutron star or a black hole?

29er Road Tire?

How can I support myself financially as a 17 year old with a loan?

What does "Managed by Windows" do in the Power options for network connection?

Flattening the sub-lists [closed]

Remove elements at certain positions from all sub-lists?How to group lists that own one common element?Searching linked lists that contain lists?Partition list into a given number of sub-listsHow to plot specific listsList of (sub-)lists - query sub-lists by names?How to efficiently Flatten nested lists while preserving select levels?Flattening large list of listsDeleting sub-list that contains duplicatesSpeed up Flatten[] of a large nested list

2

$begingroup$

Is there a way to flatten the sub-lists within a list?

Transform

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

Into

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

I know I can do

Flatten /@ 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

I am wondering whether there are some dedicated functions for such sub-list flattening?

list-manipulation

share|improve this question

edited Apr 25 at 0:54

m0nhawk

2,92711532

asked Apr 25 at 0:52

bakerbaker

463

$endgroup$

closed as off-topic by MarcoB, m_goldberg, Henrik Schumacher, happy fish, bbgodfrey Apr 26 at 20:14

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question arises due to a simple mistake such as a trivial syntax error, incorrect capitalization, spelling mistake, or other typographical error and is unlikely to help any future visitors, or else it is easily found in the documentation." – MarcoB, m_goldberg, Henrik Schumacher, happy fish, bbgodfrey

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  try Flatten[list,1]
  $endgroup$
  – J42161217
  Apr 25 at 0:55
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  One can also consider using Join @@ yourlist.
  $endgroup$
  – Αλέξανδρος Ζεγγ
  Apr 25 at 3:27
  

  
  
  
  

add a comment | 

2

$begingroup$

Is there a way to flatten the sub-lists within a list?

Transform

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

Into

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

I know I can do

Flatten /@ 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

I am wondering whether there are some dedicated functions for such sub-list flattening?

list-manipulation

share|improve this question

edited Apr 25 at 0:54

m0nhawk

2,92711532

asked Apr 25 at 0:52

bakerbaker

463

$endgroup$

closed as off-topic by MarcoB, m_goldberg, Henrik Schumacher, happy fish, bbgodfrey Apr 26 at 20:14

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question arises due to a simple mistake such as a trivial syntax error, incorrect capitalization, spelling mistake, or other typographical error and is unlikely to help any future visitors, or else it is easily found in the documentation." – MarcoB, m_goldberg, Henrik Schumacher, happy fish, bbgodfrey

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  try Flatten[list,1]
  $endgroup$
  – J42161217
  Apr 25 at 0:55
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  One can also consider using Join @@ yourlist.
  $endgroup$
  – Αλέξανδρος Ζεγγ
  Apr 25 at 3:27
  

  
  
  
  

add a comment | 

$begingroup$

Is there a way to flatten the sub-lists within a list?

Transform

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

Into

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

I know I can do

Flatten /@ 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

I am wondering whether there are some dedicated functions for such sub-list flattening?

list-manipulation

share|improve this question

edited Apr 25 at 0:54

m0nhawk

2,92711532

asked Apr 25 at 0:52

bakerbaker

463

$endgroup$

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

Flatten /@ 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

share|improve this question

edited Apr 25 at 0:54

m0nhawk

2,92711532

asked Apr 25 at 0:52

bakerbaker

463

share|improve this question

edited Apr 25 at 0:54

m0nhawk

2,92711532

asked Apr 25 at 0:52

bakerbaker

463

edited Apr 25 at 0:54

m0nhawk

2,92711532

edited Apr 25 at 0:54

m0nhawk

2,92711532

asked Apr 25 at 0:52

bakerbaker

463

asked Apr 25 at 0:52

bakerbaker

463

2 Answers
2

active

oldest

votes

7

$begingroup$

You are doing redundant step with /@, Flatten can make this directly:

Flatten[1, x, 2, x, 3, x, 4, x, 5, 
 x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
(* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, 
 x, 9, x, 10, x *)

share|improve this answer

answered Apr 25 at 0:55

m0nhawkm0nhawk

2,92711532

$endgroup$

add a comment | 

1

$begingroup$

Yes, there is a built-in function for what you want to do.

data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
Catenate @ data

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

share|improve this answer

answered Apr 25 at 6:48

m_goldbergm_goldberg

89.4k873202

$endgroup$

add a comment | 

7

$begingroup$

You are doing redundant step with /@, Flatten can make this directly:

Flatten[1, x, 2, x, 3, x, 4, x, 5, 
 x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
(* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, 
 x, 9, x, 10, x *)

share|improve this answer

answered Apr 25 at 0:55

m0nhawkm0nhawk

2,92711532

$endgroup$

add a comment | 

7

$begingroup$

You are doing redundant step with /@, Flatten can make this directly:

Flatten[1, x, 2, x, 3, x, 4, x, 5, 
 x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
(* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, 
 x, 9, x, 10, x *)

share|improve this answer

answered Apr 25 at 0:55

m0nhawkm0nhawk

2,92711532

$endgroup$

add a comment | 

$begingroup$

You are doing redundant step with /@, Flatten can make this directly:

Flatten[1, x, 2, x, 3, x, 4, x, 5, 
 x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
(* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, 
 x, 9, x, 10, x *)

share|improve this answer

answered Apr 25 at 0:55

m0nhawkm0nhawk

2,92711532

$endgroup$

Flatten[1, x, 2, x, 3, x, 4, x, 5, 
 x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
(* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, 
 x, 9, x, 10, x *)

share|improve this answer

answered Apr 25 at 0:55

m0nhawkm0nhawk

2,92711532

answered Apr 25 at 0:55

m0nhawkm0nhawk

2,92711532

answered Apr 25 at 0:55

m0nhawkm0nhawk

2,92711532

1

$begingroup$

Yes, there is a built-in function for what you want to do.

data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
Catenate @ data

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

share|improve this answer

answered Apr 25 at 6:48

m_goldbergm_goldberg

89.4k873202

$endgroup$

add a comment | 

1

$begingroup$

Yes, there is a built-in function for what you want to do.

data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
Catenate @ data

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

share|improve this answer

answered Apr 25 at 6:48

m_goldbergm_goldberg

89.4k873202

$endgroup$

add a comment | 

$begingroup$

Yes, there is a built-in function for what you want to do.

data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
Catenate @ data

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

share|improve this answer

answered Apr 25 at 6:48

m_goldbergm_goldberg

89.4k873202

$endgroup$

data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
Catenate @ data

share|improve this answer

answered Apr 25 at 6:48

m_goldbergm_goldberg

89.4k873202

answered Apr 25 at 6:48

m_goldbergm_goldberg

89.4k873202

answered Apr 25 at 6:48

m_goldbergm_goldberg

89.4k873202