Applying a function to a nested listNested List ProductExtract function argumentsCreating a simple function to compute the average of the difference between pairs of elements in an arraySorting non-numerical listsExtract part of list by reading it in a cyclic mannerApplying a function along the desired dimensions of a n-dimensional arrayManipulating Elements in a Triple-Nested ListApplying function to all elements of the list of listApplying a function to a list of symbolic ratiosApplying a function to a list (compounding)
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Applying a function to a nested list
Nested List ProductExtract function argumentsCreating a simple function to compute the average of the difference between pairs of elements in an arraySorting non-numerical listsExtract part of list by reading it in a cyclic mannerApplying a function along the desired dimensions of a n-dimensional arrayManipulating Elements in a Triple-Nested ListApplying function to all elements of the list of listApplying a function to a list of symbolic ratiosApplying a function to a list (compounding)
$begingroup$
Say I have a list:
l = a, b, c, d
I now want to apply a function, call it F to that list in a way that I go from the lowest to highest level, i.e.
F[F[F[a,b], c] , d]
Is there a function in Mathematica which does exactly that?
list-manipulation functions
asked Apr 29 at 21:53
amator2357amator2357
61610
$endgroup$
add a comment |
$begingroup$
Say I have a list:
l = a, b, c, d
I now want to apply a function, call it F to that list in a way that I go from the lowest to highest level, i.e.
F[F[F[a,b], c] , d]
Is there a function in Mathematica which does exactly that?
list-manipulation functions
asked Apr 29 at 21:53
amator2357amator2357
61610
$endgroup$
4
$begingroup$
Why does the order fordandcchange, and not foraandb?
$endgroup$
– Carl Woll
Apr 29 at 22:30
$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
Apr 29 at 22:54
$begingroup$
In your example it does not matter whetherFis applied from the lowest level up or reverse. It it matters it may affect applicable solutions.
$endgroup$
– Kuba♦
Apr 30 at 6:27
add a comment |
$begingroup$
Say I have a list:
l = a, b, c, d
I now want to apply a function, call it F to that list in a way that I go from the lowest to highest level, i.e.
F[F[F[a,b], c] , d]
Is there a function in Mathematica which does exactly that?
list-manipulation functions
asked Apr 29 at 21:53
amator2357amator2357
61610
$endgroup$
Say I have a list:
l = a, b, c, d
I now want to apply a function, call it F to that list in a way that I go from the lowest to highest level, i.e.
F[F[F[a,b], c] , d]
Is there a function in Mathematica which does exactly that?
list-manipulation functions
list-manipulation functions
asked Apr 29 at 21:53
amator2357amator2357
61610
asked Apr 29 at 21:53
amator2357amator2357
61610
edited Apr 29 at 22:53
amator2357
asked Apr 29 at 21:53
amator2357amator2357
61610
asked Apr 29 at 21:53
amator2357amator2357
61610
asked Apr 29 at 21:53
amator2357amator2357
61610
61610
4
$begingroup$
Why does the order fordandcchange, and not foraandb?
$endgroup$
– Carl Woll
Apr 29 at 22:30
$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
Apr 29 at 22:54
$begingroup$
In your example it does not matter whetherFis applied from the lowest level up or reverse. It it matters it may affect applicable solutions.
$endgroup$
– Kuba♦
Apr 30 at 6:27
add a comment |
4
$begingroup$
Why does the order fordandcchange, and not foraandb?
$endgroup$
– Carl Woll
Apr 29 at 22:30
$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
Apr 29 at 22:54
$begingroup$
In your example it does not matter whetherFis applied from the lowest level up or reverse. It it matters it may affect applicable solutions.
$endgroup$
– Kuba♦
Apr 30 at 6:27
4
4
$begingroup$
Why does the order for
d and c change, and not for a and b?$endgroup$
– Carl Woll
Apr 29 at 22:30
$begingroup$
Why does the order for
d and c change, and not for a and b?$endgroup$
– Carl Woll
Apr 29 at 22:30
$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
Apr 29 at 22:54
$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
Apr 29 at 22:54
$begingroup$
In your example it does not matter whether
F is applied from the lowest level up or reverse. It it matters it may affect applicable solutions.$endgroup$
– Kuba♦
Apr 30 at 6:27
$begingroup$
In your example it does not matter whether
F is applied from the lowest level up or reverse. It it matters it may affect applicable solutions.$endgroup$
– Kuba♦
Apr 30 at 6:27
add a comment |
4 Answers
4
active
oldest
votes
$begingroup$
Replace[l, x_List :> F[x], All]
F[F[F[a, b], c], d]
Also
ClearAll[f]
f[Except[_List, x_]] := x;
MapAll[f, l]
f[f[f[a, b], c], d]
answered Apr 29 at 23:34
kglrkglr
191k10212431
$endgroup$
add a comment |
$begingroup$
Another possibility, if you want just lists to acquire the F wrapper:
l /. List -> F@*List
F[F[F[a, b], c], d]
answered Apr 30 at 0:10
Carl WollCarl Woll
77.7k3102204
$endgroup$
add a comment |
$begingroup$
F@*Reverse@Map[F@*Reverse, l, -2]
F[d, F[c, F[b, a]]]
Fold[F[#2, #1] &, Flatten[l]]
F[d, F[c, F[b, a]]]
answered Apr 29 at 22:30
Henrik SchumacherHenrik Schumacher
61.8k585172
$endgroup$
$begingroup$
I think thatFlattenworks in this trivial case but it will not "find" the levels in a more complex situation
$endgroup$
– J42161217
Apr 29 at 22:41
add a comment |
$begingroup$
This works:
a, b, c, d //. s_?ListQ, t_?(Not@*ListQ) :> f[s], t // f
It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.
answered Apr 29 at 23:03
ShredderroyShredderroy
1,6201117
$endgroup$
add a comment |
Your Answer
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Replace[l, x_List :> F[x], All]
F[F[F[a, b], c], d]
Also
ClearAll[f]
f[Except[_List, x_]] := x;
MapAll[f, l]
f[f[f[a, b], c], d]
answered Apr 29 at 23:34
kglrkglr
191k10212431
$endgroup$
add a comment |
$begingroup$
Replace[l, x_List :> F[x], All]
F[F[F[a, b], c], d]
Also
ClearAll[f]
f[Except[_List, x_]] := x;
MapAll[f, l]
f[f[f[a, b], c], d]
answered Apr 29 at 23:34
kglrkglr
191k10212431
$endgroup$
add a comment |
$begingroup$
Replace[l, x_List :> F[x], All]
F[F[F[a, b], c], d]
Also
ClearAll[f]
f[Except[_List, x_]] := x;
MapAll[f, l]
f[f[f[a, b], c], d]
answered Apr 29 at 23:34
kglrkglr
191k10212431
$endgroup$
Replace[l, x_List :> F[x], All]
F[F[F[a, b], c], d]
Also
ClearAll[f]
f[Except[_List, x_]] := x;
MapAll[f, l]
f[f[f[a, b], c], d]
answered Apr 29 at 23:34
kglrkglr
191k10212431
answered Apr 29 at 23:34
kglrkglr
191k10212431
answered Apr 29 at 23:34
kglrkglr
191k10212431
answered Apr 29 at 23:34
kglrkglr
191k10212431
191k10212431
add a comment |
add a comment |
$begingroup$
Another possibility, if you want just lists to acquire the F wrapper:
l /. List -> F@*List
F[F[F[a, b], c], d]
answered Apr 30 at 0:10
Carl WollCarl Woll
77.7k3102204
$endgroup$
add a comment |
$begingroup$
Another possibility, if you want just lists to acquire the F wrapper:
l /. List -> F@*List
F[F[F[a, b], c], d]
answered Apr 30 at 0:10
Carl WollCarl Woll
77.7k3102204
$endgroup$
add a comment |
$begingroup$
Another possibility, if you want just lists to acquire the F wrapper:
l /. List -> F@*List
F[F[F[a, b], c], d]
answered Apr 30 at 0:10
Carl WollCarl Woll
77.7k3102204
$endgroup$
Another possibility, if you want just lists to acquire the F wrapper:
l /. List -> F@*List
F[F[F[a, b], c], d]
answered Apr 30 at 0:10
Carl WollCarl Woll
77.7k3102204
answered Apr 30 at 0:10
Carl WollCarl Woll
77.7k3102204
answered Apr 30 at 0:10
Carl WollCarl Woll
77.7k3102204
answered Apr 30 at 0:10
Carl WollCarl Woll
77.7k3102204
77.7k3102204
add a comment |
add a comment |
$begingroup$
F@*Reverse@Map[F@*Reverse, l, -2]
F[d, F[c, F[b, a]]]
Fold[F[#2, #1] &, Flatten[l]]
F[d, F[c, F[b, a]]]
answered Apr 29 at 22:30
Henrik SchumacherHenrik Schumacher
61.8k585172
$endgroup$
$begingroup$
I think thatFlattenworks in this trivial case but it will not "find" the levels in a more complex situation
$endgroup$
– J42161217
Apr 29 at 22:41
add a comment |
$begingroup$
F@*Reverse@Map[F@*Reverse, l, -2]
F[d, F[c, F[b, a]]]
Fold[F[#2, #1] &, Flatten[l]]
F[d, F[c, F[b, a]]]
answered Apr 29 at 22:30
Henrik SchumacherHenrik Schumacher
61.8k585172
$endgroup$
$begingroup$
I think thatFlattenworks in this trivial case but it will not "find" the levels in a more complex situation
$endgroup$
– J42161217
Apr 29 at 22:41
add a comment |
$begingroup$
F@*Reverse@Map[F@*Reverse, l, -2]
F[d, F[c, F[b, a]]]
Fold[F[#2, #1] &, Flatten[l]]
F[d, F[c, F[b, a]]]
answered Apr 29 at 22:30
Henrik SchumacherHenrik Schumacher
61.8k585172
$endgroup$
F@*Reverse@Map[F@*Reverse, l, -2]
F[d, F[c, F[b, a]]]
Fold[F[#2, #1] &, Flatten[l]]
F[d, F[c, F[b, a]]]
answered Apr 29 at 22:30
Henrik SchumacherHenrik Schumacher
61.8k585172
answered Apr 29 at 22:30
Henrik SchumacherHenrik Schumacher
61.8k585172
answered Apr 29 at 22:30
Henrik SchumacherHenrik Schumacher
61.8k585172
answered Apr 29 at 22:30
Henrik SchumacherHenrik Schumacher
61.8k585172
61.8k585172
$begingroup$
I think thatFlattenworks in this trivial case but it will not "find" the levels in a more complex situation
$endgroup$
– J42161217
Apr 29 at 22:41
add a comment |
$begingroup$
I think thatFlattenworks in this trivial case but it will not "find" the levels in a more complex situation
$endgroup$
– J42161217
Apr 29 at 22:41
$begingroup$
I think that
Flatten works in this trivial case but it will not "find" the levels in a more complex situation$endgroup$
– J42161217
Apr 29 at 22:41
$begingroup$
I think that
Flatten works in this trivial case but it will not "find" the levels in a more complex situation$endgroup$
– J42161217
Apr 29 at 22:41
add a comment |
$begingroup$
This works:
a, b, c, d //. s_?ListQ, t_?(Not@*ListQ) :> f[s], t // f
It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.
answered Apr 29 at 23:03
ShredderroyShredderroy
1,6201117
$endgroup$
add a comment |
$begingroup$
This works:
a, b, c, d //. s_?ListQ, t_?(Not@*ListQ) :> f[s], t // f
It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.
answered Apr 29 at 23:03
ShredderroyShredderroy
1,6201117
$endgroup$
add a comment |
$begingroup$
This works:
a, b, c, d //. s_?ListQ, t_?(Not@*ListQ) :> f[s], t // f
It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.
answered Apr 29 at 23:03
ShredderroyShredderroy
1,6201117
$endgroup$
This works:
a, b, c, d //. s_?ListQ, t_?(Not@*ListQ) :> f[s], t // f
It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.
answered Apr 29 at 23:03
ShredderroyShredderroy
1,6201117
answered Apr 29 at 23:03
ShredderroyShredderroy
1,6201117
answered Apr 29 at 23:03
ShredderroyShredderroy
1,6201117
answered Apr 29 at 23:03
ShredderroyShredderroy
1,6201117
1,6201117
add a comment |
add a comment |
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pcsK6,adu0Cgon7K3P EfU5I gI2KCvSAM33qG1D8wzcL2k0Q,ZbI
4
$begingroup$
Why does the order for
dandcchange, and not foraandb?$endgroup$
– Carl Woll
Apr 29 at 22:30
$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
Apr 29 at 22:54
$begingroup$
In your example it does not matter whether
Fis applied from the lowest level up or reverse. It it matters it may affect applicable solutions.$endgroup$
– Kuba♦
Apr 30 at 6:27