Indexes with the same object_id but different namesWill a clustered index improve performance of updates performed sequentially on that clustered index?Does the number of indexes effect the modification of table?index doesn't work properlyWhy does selecting top 1 from composite index DESC also used to partition by month not select the top value?Creating an index on table A but with reference to table BWhat is the difference in performance between a two single-field indexes and one compound index?Copy a row from a table to another with the same columns but different order in a triggerFind tables with multiple indexes on same columnMS SQL Server differentiate system and user defined indexes using sys.indexes tableQuery to retrieve aggregated data using variables
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Indexes with the same object_id but different names
Will a clustered index improve performance of updates performed sequentially on that clustered index?Does the number of indexes effect the modification of table?index doesn't work properlyWhy does selecting top 1 from composite index DESC also used to partition by month not select the top value?Creating an index on table A but with reference to table BWhat is the difference in performance between a two single-field indexes and one compound index?Copy a row from a table to another with the same columns but different order in a triggerFind tables with multiple indexes on same columnMS SQL Server differentiate system and user defined indexes using sys.indexes tableQuery to retrieve aggregated data using variables
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
When I run
SELECT
count(object_id) AS count,
object_id,
min(name) as name1,
max(name) AS name2
FROM
sys.indexes
GROUP BY object_id HAVING COUNT(*) > 1 ORDER BY count
I will get a list of indexes having the same object_id, but not necessarily with the same name.
Should not all indexes with the same object_id have the same name?
t-sql index
add a comment |
When I run
SELECT
count(object_id) AS count,
object_id,
min(name) as name1,
max(name) AS name2
FROM
sys.indexes
GROUP BY object_id HAVING COUNT(*) > 1 ORDER BY count
I will get a list of indexes having the same object_id, but not necessarily with the same name.
Should not all indexes with the same object_id have the same name?
t-sql index
add a comment |
When I run
SELECT
count(object_id) AS count,
object_id,
min(name) as name1,
max(name) AS name2
FROM
sys.indexes
GROUP BY object_id HAVING COUNT(*) > 1 ORDER BY count
I will get a list of indexes having the same object_id, but not necessarily with the same name.
Should not all indexes with the same object_id have the same name?
t-sql index
When I run
SELECT
count(object_id) AS count,
object_id,
min(name) as name1,
max(name) AS name2
FROM
sys.indexes
GROUP BY object_id HAVING COUNT(*) > 1 ORDER BY count
I will get a list of indexes having the same object_id, but not necessarily with the same name.
Should not all indexes with the same object_id have the same name?
t-sql index
t-sql index
asked Apr 23 at 9:42
Anders LindénAnders Lindén
2671314
2671314
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The Object_ID
belongs to the object the index belongs to, such as an indexed view or a table.
When you look at the object_id
in the sys.indexes
documentation
object_id - ID of the object to which this index belongs.
If you want to uniquely identify the index you need the Object_ID
+ index_id
columns or the index_id
for a specific object_id
.
To verify this, you can add the OBJECT_NAME()
function to your query
SELECT
count(object_id) AS count,
object_id,
OBJECT_NAME(object_id),
min(name) as name1,
max(name) AS name2
FROM
sys.indexes
GROUP BY object_id HAVING COUNT(*) > 1 ORDER BY count;
add a comment |
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The Object_ID
belongs to the object the index belongs to, such as an indexed view or a table.
When you look at the object_id
in the sys.indexes
documentation
object_id - ID of the object to which this index belongs.
If you want to uniquely identify the index you need the Object_ID
+ index_id
columns or the index_id
for a specific object_id
.
To verify this, you can add the OBJECT_NAME()
function to your query
SELECT
count(object_id) AS count,
object_id,
OBJECT_NAME(object_id),
min(name) as name1,
max(name) AS name2
FROM
sys.indexes
GROUP BY object_id HAVING COUNT(*) > 1 ORDER BY count;
add a comment |
The Object_ID
belongs to the object the index belongs to, such as an indexed view or a table.
When you look at the object_id
in the sys.indexes
documentation
object_id - ID of the object to which this index belongs.
If you want to uniquely identify the index you need the Object_ID
+ index_id
columns or the index_id
for a specific object_id
.
To verify this, you can add the OBJECT_NAME()
function to your query
SELECT
count(object_id) AS count,
object_id,
OBJECT_NAME(object_id),
min(name) as name1,
max(name) AS name2
FROM
sys.indexes
GROUP BY object_id HAVING COUNT(*) > 1 ORDER BY count;
add a comment |
The Object_ID
belongs to the object the index belongs to, such as an indexed view or a table.
When you look at the object_id
in the sys.indexes
documentation
object_id - ID of the object to which this index belongs.
If you want to uniquely identify the index you need the Object_ID
+ index_id
columns or the index_id
for a specific object_id
.
To verify this, you can add the OBJECT_NAME()
function to your query
SELECT
count(object_id) AS count,
object_id,
OBJECT_NAME(object_id),
min(name) as name1,
max(name) AS name2
FROM
sys.indexes
GROUP BY object_id HAVING COUNT(*) > 1 ORDER BY count;
The Object_ID
belongs to the object the index belongs to, such as an indexed view or a table.
When you look at the object_id
in the sys.indexes
documentation
object_id - ID of the object to which this index belongs.
If you want to uniquely identify the index you need the Object_ID
+ index_id
columns or the index_id
for a specific object_id
.
To verify this, you can add the OBJECT_NAME()
function to your query
SELECT
count(object_id) AS count,
object_id,
OBJECT_NAME(object_id),
min(name) as name1,
max(name) AS name2
FROM
sys.indexes
GROUP BY object_id HAVING COUNT(*) > 1 ORDER BY count;
answered Apr 23 at 9:46
Randi VertongenRandi Vertongen
5,3611926
5,3611926
add a comment |
add a comment |
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