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Question regarding MLE


Maximum Likelihood Estimation (MLE) in layman termsAsymptotically unbiased estimator using MLEMLE estimate of $beta/sigma$ - Linear regressionFind MLE on custom density functionHow can I prove the maximum likelihood estimate of $mu$ is actually a maximum likelihood estimate?Stuck on rejection region for Likelihood ratio testProving that MLE is max(x1,…,xn)Reasons for different parameters via MoM and MLEIs MLE intrinsically connected to logs?Sufficient Statistic and MLEMLE for Beta distribution, with $beta$ = 3






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2












$begingroup$


I have a question regarding maximum likelihood estimators/functions. I thought I understood the concept. But now i found an example of an Maximum likelihood function that i don’t get.



The question is to find the MLE for a hypergeometric distribution of M



I would have said that the Likelihood function is for $x_1,.....,x_k$



$$L(M)=prod_i=1^kfracbinomMx_ibinomN-Mn-x_ibinomNn$$



But now i found a solution just stating it to be



$$L(M)=fracbinomMxbinomN-Mn-xbinomNn$$



I don’t get why i can loose the Product sign...



Thanks for your help!










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    Maybe there is only one sample, i.e. $x_1=x$?
    $endgroup$
    – gunes
    Apr 23 at 7:55







  • 1




    $begingroup$
    Typically an exercise question would consider a single observation for MLE of hypergeometric distribution.
    $endgroup$
    – StubbornAtom
    Apr 23 at 8:02

















2












$begingroup$


I have a question regarding maximum likelihood estimators/functions. I thought I understood the concept. But now i found an example of an Maximum likelihood function that i don’t get.



The question is to find the MLE for a hypergeometric distribution of M



I would have said that the Likelihood function is for $x_1,.....,x_k$



$$L(M)=prod_i=1^kfracbinomMx_ibinomN-Mn-x_ibinomNn$$



But now i found a solution just stating it to be



$$L(M)=fracbinomMxbinomN-Mn-xbinomNn$$



I don’t get why i can loose the Product sign...



Thanks for your help!










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    Maybe there is only one sample, i.e. $x_1=x$?
    $endgroup$
    – gunes
    Apr 23 at 7:55







  • 1




    $begingroup$
    Typically an exercise question would consider a single observation for MLE of hypergeometric distribution.
    $endgroup$
    – StubbornAtom
    Apr 23 at 8:02













2












2








2





$begingroup$


I have a question regarding maximum likelihood estimators/functions. I thought I understood the concept. But now i found an example of an Maximum likelihood function that i don’t get.



The question is to find the MLE for a hypergeometric distribution of M



I would have said that the Likelihood function is for $x_1,.....,x_k$



$$L(M)=prod_i=1^kfracbinomMx_ibinomN-Mn-x_ibinomNn$$



But now i found a solution just stating it to be



$$L(M)=fracbinomMxbinomN-Mn-xbinomNn$$



I don’t get why i can loose the Product sign...



Thanks for your help!










share|cite|improve this question











$endgroup$




I have a question regarding maximum likelihood estimators/functions. I thought I understood the concept. But now i found an example of an Maximum likelihood function that i don’t get.



The question is to find the MLE for a hypergeometric distribution of M



I would have said that the Likelihood function is for $x_1,.....,x_k$



$$L(M)=prod_i=1^kfracbinomMx_ibinomN-Mn-x_ibinomNn$$



But now i found a solution just stating it to be



$$L(M)=fracbinomMxbinomN-Mn-xbinomNn$$



I don’t get why i can loose the Product sign...



Thanks for your help!







maximum-likelihood hypergeometric






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Apr 23 at 7:59









StubbornAtom

3,3611537




3,3611537










asked Apr 23 at 7:44









AngAng

917




917







  • 1




    $begingroup$
    Maybe there is only one sample, i.e. $x_1=x$?
    $endgroup$
    – gunes
    Apr 23 at 7:55







  • 1




    $begingroup$
    Typically an exercise question would consider a single observation for MLE of hypergeometric distribution.
    $endgroup$
    – StubbornAtom
    Apr 23 at 8:02












  • 1




    $begingroup$
    Maybe there is only one sample, i.e. $x_1=x$?
    $endgroup$
    – gunes
    Apr 23 at 7:55







  • 1




    $begingroup$
    Typically an exercise question would consider a single observation for MLE of hypergeometric distribution.
    $endgroup$
    – StubbornAtom
    Apr 23 at 8:02







1




1




$begingroup$
Maybe there is only one sample, i.e. $x_1=x$?
$endgroup$
– gunes
Apr 23 at 7:55





$begingroup$
Maybe there is only one sample, i.e. $x_1=x$?
$endgroup$
– gunes
Apr 23 at 7:55





1




1




$begingroup$
Typically an exercise question would consider a single observation for MLE of hypergeometric distribution.
$endgroup$
– StubbornAtom
Apr 23 at 8:02




$begingroup$
Typically an exercise question would consider a single observation for MLE of hypergeometric distribution.
$endgroup$
– StubbornAtom
Apr 23 at 8:02










1 Answer
1






active

oldest

votes


















2












$begingroup$

Your second formula is the probability mass function of hypergeometric distribution. Likelihood function $mathcalL$ is defined as probability mass (or density) function $f$ evaluated on some point $x$ that is maximized in terms of parameter $theta$



$$
mathcalL(theta|X) = f(X, theta)
$$



if you have more then one such point, you usually assume that they are independent and identically distributed (all come from the same distribution), what leads to likelihood defined in terms of all your data



$$
mathcalL(theta|X_1,X_2,dots,X_n) = prod_i=1^n f(X_i, theta)
$$



This is what the first formula is.






share|cite|improve this answer









$endgroup$












  • $begingroup$
    The problem question, does state neither. that is why i would try to solve for any k. (X1....Xk)... my problem is that i have no idea how to solve it with the product sign.... i know i have to look at L(M)/L(M+1) and i can do that for the second formula without a problem. But i cant seem to get anywhere with the general form. (My math knowledge is not that great though....)
    $endgroup$
    – Ang
    Apr 23 at 8:47






  • 1




    $begingroup$
    @Ang sorry but I don't understand your comment. What exactly is the problem? Your question was asking about meaning of the $prod$ symbol, so I explained it.
    $endgroup$
    – Tim
    Apr 23 at 8:50










  • $begingroup$
    many thanks for that. i am sorry if i sounded rude, this was not my intent. how would one solve for the estimator with the product sign? i am getting nowhere when trying to solve....
    $endgroup$
    – Ang
    Apr 23 at 8:56










  • $begingroup$
    @Ang this seems to be separate question. Maybe post it as a separate question, with describing in greater detail how did you try solving it and where are you stuck.
    $endgroup$
    – Tim
    Apr 23 at 9:01










  • $begingroup$
    thanks! i will attempt a few more times and then post :) maybe i get lucky!
    $endgroup$
    – Ang
    Apr 23 at 9:02











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

Your second formula is the probability mass function of hypergeometric distribution. Likelihood function $mathcalL$ is defined as probability mass (or density) function $f$ evaluated on some point $x$ that is maximized in terms of parameter $theta$



$$
mathcalL(theta|X) = f(X, theta)
$$



if you have more then one such point, you usually assume that they are independent and identically distributed (all come from the same distribution), what leads to likelihood defined in terms of all your data



$$
mathcalL(theta|X_1,X_2,dots,X_n) = prod_i=1^n f(X_i, theta)
$$



This is what the first formula is.






share|cite|improve this answer









$endgroup$












  • $begingroup$
    The problem question, does state neither. that is why i would try to solve for any k. (X1....Xk)... my problem is that i have no idea how to solve it with the product sign.... i know i have to look at L(M)/L(M+1) and i can do that for the second formula without a problem. But i cant seem to get anywhere with the general form. (My math knowledge is not that great though....)
    $endgroup$
    – Ang
    Apr 23 at 8:47






  • 1




    $begingroup$
    @Ang sorry but I don't understand your comment. What exactly is the problem? Your question was asking about meaning of the $prod$ symbol, so I explained it.
    $endgroup$
    – Tim
    Apr 23 at 8:50










  • $begingroup$
    many thanks for that. i am sorry if i sounded rude, this was not my intent. how would one solve for the estimator with the product sign? i am getting nowhere when trying to solve....
    $endgroup$
    – Ang
    Apr 23 at 8:56










  • $begingroup$
    @Ang this seems to be separate question. Maybe post it as a separate question, with describing in greater detail how did you try solving it and where are you stuck.
    $endgroup$
    – Tim
    Apr 23 at 9:01










  • $begingroup$
    thanks! i will attempt a few more times and then post :) maybe i get lucky!
    $endgroup$
    – Ang
    Apr 23 at 9:02















2












$begingroup$

Your second formula is the probability mass function of hypergeometric distribution. Likelihood function $mathcalL$ is defined as probability mass (or density) function $f$ evaluated on some point $x$ that is maximized in terms of parameter $theta$



$$
mathcalL(theta|X) = f(X, theta)
$$



if you have more then one such point, you usually assume that they are independent and identically distributed (all come from the same distribution), what leads to likelihood defined in terms of all your data



$$
mathcalL(theta|X_1,X_2,dots,X_n) = prod_i=1^n f(X_i, theta)
$$



This is what the first formula is.






share|cite|improve this answer









$endgroup$












  • $begingroup$
    The problem question, does state neither. that is why i would try to solve for any k. (X1....Xk)... my problem is that i have no idea how to solve it with the product sign.... i know i have to look at L(M)/L(M+1) and i can do that for the second formula without a problem. But i cant seem to get anywhere with the general form. (My math knowledge is not that great though....)
    $endgroup$
    – Ang
    Apr 23 at 8:47






  • 1




    $begingroup$
    @Ang sorry but I don't understand your comment. What exactly is the problem? Your question was asking about meaning of the $prod$ symbol, so I explained it.
    $endgroup$
    – Tim
    Apr 23 at 8:50










  • $begingroup$
    many thanks for that. i am sorry if i sounded rude, this was not my intent. how would one solve for the estimator with the product sign? i am getting nowhere when trying to solve....
    $endgroup$
    – Ang
    Apr 23 at 8:56










  • $begingroup$
    @Ang this seems to be separate question. Maybe post it as a separate question, with describing in greater detail how did you try solving it and where are you stuck.
    $endgroup$
    – Tim
    Apr 23 at 9:01










  • $begingroup$
    thanks! i will attempt a few more times and then post :) maybe i get lucky!
    $endgroup$
    – Ang
    Apr 23 at 9:02













2












2








2





$begingroup$

Your second formula is the probability mass function of hypergeometric distribution. Likelihood function $mathcalL$ is defined as probability mass (or density) function $f$ evaluated on some point $x$ that is maximized in terms of parameter $theta$



$$
mathcalL(theta|X) = f(X, theta)
$$



if you have more then one such point, you usually assume that they are independent and identically distributed (all come from the same distribution), what leads to likelihood defined in terms of all your data



$$
mathcalL(theta|X_1,X_2,dots,X_n) = prod_i=1^n f(X_i, theta)
$$



This is what the first formula is.






share|cite|improve this answer









$endgroup$



Your second formula is the probability mass function of hypergeometric distribution. Likelihood function $mathcalL$ is defined as probability mass (or density) function $f$ evaluated on some point $x$ that is maximized in terms of parameter $theta$



$$
mathcalL(theta|X) = f(X, theta)
$$



if you have more then one such point, you usually assume that they are independent and identically distributed (all come from the same distribution), what leads to likelihood defined in terms of all your data



$$
mathcalL(theta|X_1,X_2,dots,X_n) = prod_i=1^n f(X_i, theta)
$$



This is what the first formula is.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Apr 23 at 8:00









TimTim

61k9135230




61k9135230











  • $begingroup$
    The problem question, does state neither. that is why i would try to solve for any k. (X1....Xk)... my problem is that i have no idea how to solve it with the product sign.... i know i have to look at L(M)/L(M+1) and i can do that for the second formula without a problem. But i cant seem to get anywhere with the general form. (My math knowledge is not that great though....)
    $endgroup$
    – Ang
    Apr 23 at 8:47






  • 1




    $begingroup$
    @Ang sorry but I don't understand your comment. What exactly is the problem? Your question was asking about meaning of the $prod$ symbol, so I explained it.
    $endgroup$
    – Tim
    Apr 23 at 8:50










  • $begingroup$
    many thanks for that. i am sorry if i sounded rude, this was not my intent. how would one solve for the estimator with the product sign? i am getting nowhere when trying to solve....
    $endgroup$
    – Ang
    Apr 23 at 8:56










  • $begingroup$
    @Ang this seems to be separate question. Maybe post it as a separate question, with describing in greater detail how did you try solving it and where are you stuck.
    $endgroup$
    – Tim
    Apr 23 at 9:01










  • $begingroup$
    thanks! i will attempt a few more times and then post :) maybe i get lucky!
    $endgroup$
    – Ang
    Apr 23 at 9:02
















  • $begingroup$
    The problem question, does state neither. that is why i would try to solve for any k. (X1....Xk)... my problem is that i have no idea how to solve it with the product sign.... i know i have to look at L(M)/L(M+1) and i can do that for the second formula without a problem. But i cant seem to get anywhere with the general form. (My math knowledge is not that great though....)
    $endgroup$
    – Ang
    Apr 23 at 8:47






  • 1




    $begingroup$
    @Ang sorry but I don't understand your comment. What exactly is the problem? Your question was asking about meaning of the $prod$ symbol, so I explained it.
    $endgroup$
    – Tim
    Apr 23 at 8:50










  • $begingroup$
    many thanks for that. i am sorry if i sounded rude, this was not my intent. how would one solve for the estimator with the product sign? i am getting nowhere when trying to solve....
    $endgroup$
    – Ang
    Apr 23 at 8:56










  • $begingroup$
    @Ang this seems to be separate question. Maybe post it as a separate question, with describing in greater detail how did you try solving it and where are you stuck.
    $endgroup$
    – Tim
    Apr 23 at 9:01










  • $begingroup$
    thanks! i will attempt a few more times and then post :) maybe i get lucky!
    $endgroup$
    – Ang
    Apr 23 at 9:02















$begingroup$
The problem question, does state neither. that is why i would try to solve for any k. (X1....Xk)... my problem is that i have no idea how to solve it with the product sign.... i know i have to look at L(M)/L(M+1) and i can do that for the second formula without a problem. But i cant seem to get anywhere with the general form. (My math knowledge is not that great though....)
$endgroup$
– Ang
Apr 23 at 8:47




$begingroup$
The problem question, does state neither. that is why i would try to solve for any k. (X1....Xk)... my problem is that i have no idea how to solve it with the product sign.... i know i have to look at L(M)/L(M+1) and i can do that for the second formula without a problem. But i cant seem to get anywhere with the general form. (My math knowledge is not that great though....)
$endgroup$
– Ang
Apr 23 at 8:47




1




1




$begingroup$
@Ang sorry but I don't understand your comment. What exactly is the problem? Your question was asking about meaning of the $prod$ symbol, so I explained it.
$endgroup$
– Tim
Apr 23 at 8:50




$begingroup$
@Ang sorry but I don't understand your comment. What exactly is the problem? Your question was asking about meaning of the $prod$ symbol, so I explained it.
$endgroup$
– Tim
Apr 23 at 8:50












$begingroup$
many thanks for that. i am sorry if i sounded rude, this was not my intent. how would one solve for the estimator with the product sign? i am getting nowhere when trying to solve....
$endgroup$
– Ang
Apr 23 at 8:56




$begingroup$
many thanks for that. i am sorry if i sounded rude, this was not my intent. how would one solve for the estimator with the product sign? i am getting nowhere when trying to solve....
$endgroup$
– Ang
Apr 23 at 8:56












$begingroup$
@Ang this seems to be separate question. Maybe post it as a separate question, with describing in greater detail how did you try solving it and where are you stuck.
$endgroup$
– Tim
Apr 23 at 9:01




$begingroup$
@Ang this seems to be separate question. Maybe post it as a separate question, with describing in greater detail how did you try solving it and where are you stuck.
$endgroup$
– Tim
Apr 23 at 9:01












$begingroup$
thanks! i will attempt a few more times and then post :) maybe i get lucky!
$endgroup$
– Ang
Apr 23 at 9:02




$begingroup$
thanks! i will attempt a few more times and then post :) maybe i get lucky!
$endgroup$
– Ang
Apr 23 at 9:02

















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Club Baloncesto Breogán Índice Historia | Pavillón | Nome | O Breogán na cultura popular | Xogadores | Adestradores | Presidentes | Palmarés | Historial | Líderes | Notas | Véxase tamén | Menú de navegacióncbbreogan.galCadroGuía oficial da ACB 2009-10, páxina 201Guía oficial ACB 1992, páxina 183. Editorial DB.É de 6.500 espectadores sentados axeitándose á última normativa"Estudiantes Junior, entre as mellores canteiras"o orixinalHemeroteca El Mundo Deportivo, 16 setembro de 1970, páxina 12Historia do BreogánAlfredo Pérez, o último canoneiroHistoria C.B. BreogánHemeroteca de El Mundo DeportivoJimmy Wright, norteamericano do Breogán deixará Lugo por ameazas de morteResultados de Breogán en 1986-87Resultados de Breogán en 1990-91Ficha de Velimir Perasović en acb.comResultados de Breogán en 1994-95Breogán arrasa al Barça. "El Mundo Deportivo", 27 de setembro de 1999, páxina 58CB Breogán - FC BarcelonaA FEB invita a participar nunha nova Liga EuropeaCharlie Bell na prensa estatalMáximos anotadores 2005Tempada 2005-06 : Tódolos Xogadores da Xornada""Non quero pensar nunha man negra, mais pregúntome que está a pasar""o orixinalRaúl López, orgulloso dos xogadores, presume da boa saúde económica do BreogánJulio González confirma que cesa como presidente del BreogánHomenaxe a Lisardo GómezA tempada do rexurdimento celesteEntrevista a Lisardo GómezEl COB dinamita el Pazo para forzar el quinto (69-73)Cafés Candelas, patrocinador del CB Breogán"Suso Lázare, novo presidente do Breogán"o orixinalCafés Candelas Breogán firma el mayor triunfo de la historiaEl Breogán realizará 17 homenajes por su cincuenta aniversario"O Breogán honra ao seu fundador e primeiro presidente"o orixinalMiguel Giao recibiu a homenaxe do PazoHomenaxe aos primeiros gladiadores celestesO home que nos amosa como ver o Breo co corazónTita Franco será homenaxeada polos #50anosdeBreoJulio Vila recibirá unha homenaxe in memoriam polos #50anosdeBreo"O Breogán homenaxeará aos seus aboados máis veteráns"Pechada ovación a «Capi» Sanmartín e Ricardo «Corazón de González»Homenaxe por décadas de informaciónPaco García volve ao Pazo con motivo do 50 aniversario"Resultados y clasificaciones""O Cafés Candelas Breogán, campión da Copa Princesa""O Cafés Candelas Breogán, equipo ACB"C.B. Breogán"Proxecto social"o orixinal"Centros asociados"o orixinalFicha en imdb.comMario Camus trata la recuperación del amor en 'La vieja música', su última película"Páxina web oficial""Club Baloncesto Breogán""C. B. Breogán S.A.D."eehttp://www.fegaba.com

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Cegueira Índice Epidemioloxía | Deficiencia visual | Tipos de cegueira | Principais causas de cegueira | Tratamento | Técnicas de adaptación e axudas | Vida dos cegos | Primeiros auxilios | Crenzas respecto das persoas cegas | Crenzas das persoas cegas | O neno deficiente visual | Aspectos psicolóxicos da cegueira | Notas | Véxase tamén | Menú de navegación54.054.154.436928256blindnessDicionario da Real Academia GalegaPortal das Palabras"International Standards: Visual Standards — Aspects and Ranges of Vision Loss with Emphasis on Population Surveys.""Visual impairment and blindness""Presentan un plan para previr a cegueira"o orixinalACCDV Associació Catalana de Cecs i Disminuïts Visuals - PMFTrachoma"Effect of gene therapy on visual function in Leber's congenital amaurosis"1844137110.1056/NEJMoa0802268Cans guía - os mellores amigos dos cegosArquivadoEscola de cans guía para cegos en Mortágua, PortugalArquivado"Tecnología para ciegos y deficientes visuales. Recopilación de recursos gratuitos en la Red""Colorino""‘COL.diesis’, escuchar los sonidos del color""COL.diesis: Transforming Colour into Melody and Implementing the Result in a Colour Sensor Device"o orixinal"Sistema de desarrollo de sinestesia color-sonido para invidentes utilizando un protocolo de audio""Enseñanza táctil - geometría y color. Juegos didácticos para niños ciegos y videntes""Sistema Constanz"L'ocupació laboral dels cecs a l'Estat espanyol està pràcticament equiparada a la de les persones amb visió, entrevista amb Pedro ZuritaONCE (Organización Nacional de Cegos de España)Prevención da cegueiraDescrición de deficiencias visuais (Disc@pnet)Braillín, un boneco atractivo para calquera neno, con ou sen discapacidade, que permite familiarizarse co sistema de escritura e lectura brailleAxudas Técnicas36838ID00897494007150-90057129528256DOID:1432HP:0000618D001766C10.597.751.941.162C97109C0155020