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WAS IT A CAT I SAW? Do Some Detective Work & Catch The Imposters

What could have been the sentences I was thinking about?Can you work out the number which replaces the question mark?Can the Policeman catch the Thief?Can the policeman actually catch the thief, instead of shooting?Some day in the park with Fiqo

-1

$begingroup$

Carolina County Community Cat Conference is going on at a resort exclusively reserved for Prime Members.

Some look-alike impostors, aka cats, have sneaked in. They all wear fancy name tags that reveal their character.

Toss on a Sherlock Holmes hat and catch these cunning cats, that is the imposters, by examining their name tags closely. Initially assume all are Prime Members, unless you notice a specific character in the name tag that reveals that it they are not a Prime Member, and instead are actually a cat.

Only basic knowledge of primality test is needed to catch the culprit.

1) was it a rat I saw

2) Tacocat

3) Madam I m Adam

4) Malayalam

5) Dammit I m mad

6) Step on no Pets

7) Never odd or even

8) Do geese see god

9) Toppot

10) Redder

11) Race fast safe car

12) Madam in Eden I m Adam

mathematics

share|improve this question

edited May 22 at 19:19

Rewan Demontay

1,208121

asked May 22 at 14:15

UvcUvc

1,297119

$endgroup$

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  Is the mathematics tag meant to be there?
  $endgroup$
  – gabbo1092
  May 22 at 14:20
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yes..need to understand prime properties
  $endgroup$
  – Uvc
  May 22 at 14:21
  

  
  
  
  

add a comment | 

-1

$begingroup$

Carolina County Community Cat Conference is going on at a resort exclusively reserved for Prime Members.

Some look-alike impostors, aka cats, have sneaked in. They all wear fancy name tags that reveal their character.

Toss on a Sherlock Holmes hat and catch these cunning cats, that is the imposters, by examining their name tags closely. Initially assume all are Prime Members, unless you notice a specific character in the name tag that reveals that it they are not a Prime Member, and instead are actually a cat.

Only basic knowledge of primality test is needed to catch the culprit.

1) was it a rat I saw

2) Tacocat

3) Madam I m Adam

4) Malayalam

5) Dammit I m mad

6) Step on no Pets

7) Never odd or even

8) Do geese see god

9) Toppot

10) Redder

11) Race fast safe car

12) Madam in Eden I m Adam

mathematics

share|improve this question

edited May 22 at 19:19

Rewan Demontay

1,208121

asked May 22 at 14:15

UvcUvc

1,297119

$endgroup$

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  Is the mathematics tag meant to be there?
  $endgroup$
  – gabbo1092
  May 22 at 14:20
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yes..need to understand prime properties
  $endgroup$
  – Uvc
  May 22 at 14:21
  

  
  
  
  

add a comment | 

$begingroup$

Carolina County Community Cat Conference is going on at a resort exclusively reserved for Prime Members.

Some look-alike impostors, aka cats, have sneaked in. They all wear fancy name tags that reveal their character.

Toss on a Sherlock Holmes hat and catch these cunning cats, that is the imposters, by examining their name tags closely. Initially assume all are Prime Members, unless you notice a specific character in the name tag that reveals that it they are not a Prime Member, and instead are actually a cat.

Only basic knowledge of primality test is needed to catch the culprit.

1) was it a rat I saw

2) Tacocat

3) Madam I m Adam

4) Malayalam

5) Dammit I m mad

6) Step on no Pets

7) Never odd or even

8) Do geese see god

9) Toppot

10) Redder

11) Race fast safe car

12) Madam in Eden I m Adam

mathematics

share|improve this question

edited May 22 at 19:19

Rewan Demontay

1,208121

asked May 22 at 14:15

UvcUvc

1,297119

$endgroup$

share|improve this question

edited May 22 at 19:19

Rewan Demontay

1,208121

asked May 22 at 14:15

UvcUvc

1,297119

share|improve this question

edited May 22 at 19:19

Rewan Demontay

1,208121

asked May 22 at 14:15

UvcUvc

1,297119

edited May 22 at 19:19

Rewan Demontay

1,208121

edited May 22 at 19:19

Rewan Demontay

1,208121

asked May 22 at 14:15

UvcUvc

1,297119

asked May 22 at 14:15

UvcUvc

1,297119

3 Answers
3

active

oldest

votes

4

$begingroup$

Partial answer

(I don't intend to make this less partial because that feels like a computer-based slog.)

I assume the idea is that each of these represents a prime number whose digits form the palindromic pattern given by the letters. Well,

any with an even number of digits must be an impostor, because any palindrome with an even number of digits is a multiple of 11. That means 6,7,9,10 are impostors.

My guess is

that the odd-length ones (including the Dammit... one if "I am" becomes "I'm") all do have corresponding primes. But actually checking that seems really tiresome. Also, it's kinda ambiguous whether we're supposed to assume that different letters correspond to different digits.

share|improve this answer

answered May 22 at 14:24

Gareth McCaughan♦Gareth McCaughan

73.7k3183284

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Garetth...Great quick detective work
  $endgroup$
  – Uvc
  May 22 at 14:28
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Isn't this.. a bit far-fetched, given the current description? o.O
  $endgroup$
  – athin
  May 22 at 14:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  It is surprising how the puzzles are dissected..if all the information is given explicitly, then no fun..club is primarily for prime numbers..stated..as a detective you have to examine the character and identify the distinguishing features from the majority. You identify the suspects and you can state your assumptions in doing so.
  $endgroup$
  – Uvc
  May 22 at 14:38
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  $begingroup$
  No, what I mean is that given the statement of the problem, I'm kinda think it's (a bit) too board. No clue or statement to hint or give the impression that each character represent a number. The Prime Member is not enough. I also answer all composite numbers to be the impostors. I can also count the letters, or summing the A1Z26 and pick the non-prime one. My answer is also possible despite not taking the prime as a step. Additionally, as Gareth also stated, there are still many ambiguous steps like different letters should be different numbers so similar idea may lead to different answers.
  $endgroup$
  – athin
  May 22 at 15:35
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I originally toyed with that idea..then it will be too easy.. I will take suggestions and add edits to make it easy for future readers ..in real life, detectives life is not easy..
  $endgroup$
  – Uvc
  May 22 at 15:49
  

  
  
  
  

 | 
show 1 more comment

4

$begingroup$

It's

Number $5$ as it's the only one which is not palindrome.

share|improve this answer

answered May 22 at 14:17

athinathin

11k23894

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Ah, beat me to it!
  $endgroup$
  – PartyHatPanda
  May 22 at 14:19
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  I suspect #5 is meant to say "I'm" rather than "I am".
  $endgroup$
  – Gareth McCaughan♦
  May 22 at 14:21
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @athin..all palindromes need not be primes..see Garett’s explanation
  $endgroup$
  – Uvc
  May 22 at 14:41
  

  
  
  
  

add a comment | 

2

$begingroup$

The immediate one that stands out is

Number 5, as it isn't a palindrome

share|improve this answer

answered May 22 at 14:19

PartyHatPandaPartyHatPanda

1,522620

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Need to more detailed detective work
  $endgroup$
  – Uvc
  May 22 at 14:21
  

  
  
  
  

add a comment | 

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4

$begingroup$

Partial answer

(I don't intend to make this less partial because that feels like a computer-based slog.)

I assume the idea is that each of these represents a prime number whose digits form the palindromic pattern given by the letters. Well,

any with an even number of digits must be an impostor, because any palindrome with an even number of digits is a multiple of 11. That means 6,7,9,10 are impostors.

My guess is

that the odd-length ones (including the Dammit... one if "I am" becomes "I'm") all do have corresponding primes. But actually checking that seems really tiresome. Also, it's kinda ambiguous whether we're supposed to assume that different letters correspond to different digits.

share|improve this answer

answered May 22 at 14:24

Gareth McCaughan♦Gareth McCaughan

73.7k3183284

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Garetth...Great quick detective work
  $endgroup$
  – Uvc
  May 22 at 14:28
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Isn't this.. a bit far-fetched, given the current description? o.O
  $endgroup$
  – athin
  May 22 at 14:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  It is surprising how the puzzles are dissected..if all the information is given explicitly, then no fun..club is primarily for prime numbers..stated..as a detective you have to examine the character and identify the distinguishing features from the majority. You identify the suspects and you can state your assumptions in doing so.
  $endgroup$
  – Uvc
  May 22 at 14:38
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  $begingroup$
  No, what I mean is that given the statement of the problem, I'm kinda think it's (a bit) too board. No clue or statement to hint or give the impression that each character represent a number. The Prime Member is not enough. I also answer all composite numbers to be the impostors. I can also count the letters, or summing the A1Z26 and pick the non-prime one. My answer is also possible despite not taking the prime as a step. Additionally, as Gareth also stated, there are still many ambiguous steps like different letters should be different numbers so similar idea may lead to different answers.
  $endgroup$
  – athin
  May 22 at 15:35
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I originally toyed with that idea..then it will be too easy.. I will take suggestions and add edits to make it easy for future readers ..in real life, detectives life is not easy..
  $endgroup$
  – Uvc
  May 22 at 15:49
  

  
  
  
  

 | 
show 1 more comment

4

$begingroup$

Partial answer

(I don't intend to make this less partial because that feels like a computer-based slog.)

I assume the idea is that each of these represents a prime number whose digits form the palindromic pattern given by the letters. Well,

any with an even number of digits must be an impostor, because any palindrome with an even number of digits is a multiple of 11. That means 6,7,9,10 are impostors.

My guess is

that the odd-length ones (including the Dammit... one if "I am" becomes "I'm") all do have corresponding primes. But actually checking that seems really tiresome. Also, it's kinda ambiguous whether we're supposed to assume that different letters correspond to different digits.

share|improve this answer

answered May 22 at 14:24

Gareth McCaughan♦Gareth McCaughan

73.7k3183284

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Garetth...Great quick detective work
  $endgroup$
  – Uvc
  May 22 at 14:28
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Isn't this.. a bit far-fetched, given the current description? o.O
  $endgroup$
  – athin
  May 22 at 14:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  It is surprising how the puzzles are dissected..if all the information is given explicitly, then no fun..club is primarily for prime numbers..stated..as a detective you have to examine the character and identify the distinguishing features from the majority. You identify the suspects and you can state your assumptions in doing so.
  $endgroup$
  – Uvc
  May 22 at 14:38
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  $begingroup$
  No, what I mean is that given the statement of the problem, I'm kinda think it's (a bit) too board. No clue or statement to hint or give the impression that each character represent a number. The Prime Member is not enough. I also answer all composite numbers to be the impostors. I can also count the letters, or summing the A1Z26 and pick the non-prime one. My answer is also possible despite not taking the prime as a step. Additionally, as Gareth also stated, there are still many ambiguous steps like different letters should be different numbers so similar idea may lead to different answers.
  $endgroup$
  – athin
  May 22 at 15:35
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I originally toyed with that idea..then it will be too easy.. I will take suggestions and add edits to make it easy for future readers ..in real life, detectives life is not easy..
  $endgroup$
  – Uvc
  May 22 at 15:49
  

  
  
  
  

 | 
show 1 more comment

$begingroup$

Partial answer

(I don't intend to make this less partial because that feels like a computer-based slog.)

I assume the idea is that each of these represents a prime number whose digits form the palindromic pattern given by the letters. Well,

any with an even number of digits must be an impostor, because any palindrome with an even number of digits is a multiple of 11. That means 6,7,9,10 are impostors.

My guess is

that the odd-length ones (including the Dammit... one if "I am" becomes "I'm") all do have corresponding primes. But actually checking that seems really tiresome. Also, it's kinda ambiguous whether we're supposed to assume that different letters correspond to different digits.

share|improve this answer

answered May 22 at 14:24

Gareth McCaughan♦Gareth McCaughan

73.7k3183284

$endgroup$

share|improve this answer

answered May 22 at 14:24

Gareth McCaughan♦Gareth McCaughan

73.7k3183284

answered May 22 at 14:24

Gareth McCaughan♦Gareth McCaughan

73.7k3183284

answered May 22 at 14:24

Gareth McCaughan♦Gareth McCaughan

73.7k3183284

4

$begingroup$

It's

Number $5$ as it's the only one which is not palindrome.

share|improve this answer

answered May 22 at 14:17

athinathin

11k23894

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Ah, beat me to it!
  $endgroup$
  – PartyHatPanda
  May 22 at 14:19
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  I suspect #5 is meant to say "I'm" rather than "I am".
  $endgroup$
  – Gareth McCaughan♦
  May 22 at 14:21
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @athin..all palindromes need not be primes..see Garett’s explanation
  $endgroup$
  – Uvc
  May 22 at 14:41
  

  
  
  
  

add a comment | 

4

$begingroup$

It's

Number $5$ as it's the only one which is not palindrome.

share|improve this answer

answered May 22 at 14:17

athinathin

11k23894

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Ah, beat me to it!
  $endgroup$
  – PartyHatPanda
  May 22 at 14:19
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  I suspect #5 is meant to say "I'm" rather than "I am".
  $endgroup$
  – Gareth McCaughan♦
  May 22 at 14:21
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @athin..all palindromes need not be primes..see Garett’s explanation
  $endgroup$
  – Uvc
  May 22 at 14:41
  

  
  
  
  

add a comment | 

$begingroup$

It's

Number $5$ as it's the only one which is not palindrome.

share|improve this answer

answered May 22 at 14:17

athinathin

11k23894

$endgroup$

share|improve this answer

answered May 22 at 14:17

athinathin

11k23894

answered May 22 at 14:17

athinathin

11k23894

answered May 22 at 14:17

athinathin

11k23894

2

$begingroup$

The immediate one that stands out is

Number 5, as it isn't a palindrome

share|improve this answer

answered May 22 at 14:19

PartyHatPandaPartyHatPanda

1,522620

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Need to more detailed detective work
  $endgroup$
  – Uvc
  May 22 at 14:21
  

  
  
  
  

add a comment | 

2

$begingroup$

The immediate one that stands out is

Number 5, as it isn't a palindrome

share|improve this answer

answered May 22 at 14:19

PartyHatPandaPartyHatPanda

1,522620

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Need to more detailed detective work
  $endgroup$
  – Uvc
  May 22 at 14:21
  

  
  
  
  

add a comment | 

$begingroup$

The immediate one that stands out is

Number 5, as it isn't a palindrome

share|improve this answer

answered May 22 at 14:19

PartyHatPandaPartyHatPanda

1,522620

$endgroup$

share|improve this answer

answered May 22 at 14:19

PartyHatPandaPartyHatPanda

1,522620

answered May 22 at 14:19

PartyHatPandaPartyHatPanda

1,522620

answered May 22 at 14:19

PartyHatPandaPartyHatPanda

1,522620