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“Riffle” two strings
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Convenient string manipulationHow to join two Style[]d stringsStyle markers in stringsCounting instances where the two identical characters are at the same positions in two stringsHighlighting or coloring certain words / substrings appearing in a larger stringReversibly abstracting a list of strings as a graph object where vertices represent strings and edge connect pairs of strings based on various testsModifying strings in a list efficientlyHow to extract all sub-strings of string with a specified start and end using StringCases?How to return a default value if no match is found in search of stringHow to count the number of characters seperated by a special character in a string?
$begingroup$
I have two strings, e.g., s1="A|P|Q|Z" and s2="r|ss|t|yy", where "|" is meant to be a separator. I would like to get the result as another string s=Ar|Pss|Qt|Zyy by joining the corresponding parts of the two strings s1 and s2 as indicated by the separators. What would be a simple way to do this?
string-manipulation
asked Apr 9 at 19:37
nanjunnanjun
44629
$endgroup$
add a comment |
$begingroup$
I have two strings, e.g., s1="A|P|Q|Z" and s2="r|ss|t|yy", where "|" is meant to be a separator. I would like to get the result as another string s=Ar|Pss|Qt|Zyy by joining the corresponding parts of the two strings s1 and s2 as indicated by the separators. What would be a simple way to do this?
string-manipulation
asked Apr 9 at 19:37
nanjunnanjun
44629
$endgroup$
add a comment |
$begingroup$
I have two strings, e.g., s1="A|P|Q|Z" and s2="r|ss|t|yy", where "|" is meant to be a separator. I would like to get the result as another string s=Ar|Pss|Qt|Zyy by joining the corresponding parts of the two strings s1 and s2 as indicated by the separators. What would be a simple way to do this?
string-manipulation
asked Apr 9 at 19:37
nanjunnanjun
44629
$endgroup$
I have two strings, e.g., s1="A|P|Q|Z" and s2="r|ss|t|yy", where "|" is meant to be a separator. I would like to get the result as another string s=Ar|Pss|Qt|Zyy by joining the corresponding parts of the two strings s1 and s2 as indicated by the separators. What would be a simple way to do this?
string-manipulation
string-manipulation
asked Apr 9 at 19:37
nanjunnanjun
44629
asked Apr 9 at 19:37
nanjunnanjun
44629
asked Apr 9 at 19:37
nanjunnanjun
44629
asked Apr 9 at 19:37
nanjunnanjun
44629
asked Apr 9 at 19:37
nanjunnanjun
44629
44629
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Try this:
StringSplit[s1, s2, "|"] // Transpose // StringRiffle[#, "|", ""] &
answered Apr 9 at 19:47
sakrasakra
2,8031429
$endgroup$
$begingroup$
Clean and elegant (+1).
$endgroup$
– David G. Stork
Apr 9 at 19:53
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Try this:
StringSplit[s1, s2, "|"] // Transpose // StringRiffle[#, "|", ""] &
answered Apr 9 at 19:47
sakrasakra
2,8031429
$endgroup$
$begingroup$
Clean and elegant (+1).
$endgroup$
– David G. Stork
Apr 9 at 19:53
add a comment |
$begingroup$
Try this:
StringSplit[s1, s2, "|"] // Transpose // StringRiffle[#, "|", ""] &
answered Apr 9 at 19:47
sakrasakra
2,8031429
$endgroup$
$begingroup$
Clean and elegant (+1).
$endgroup$
– David G. Stork
Apr 9 at 19:53
add a comment |
$begingroup$
Try this:
StringSplit[s1, s2, "|"] // Transpose // StringRiffle[#, "|", ""] &
answered Apr 9 at 19:47
sakrasakra
2,8031429
$endgroup$
Try this:
StringSplit[s1, s2, "|"] // Transpose // StringRiffle[#, "|", ""] &
answered Apr 9 at 19:47
sakrasakra
2,8031429
answered Apr 9 at 19:47
sakrasakra
2,8031429
answered Apr 9 at 19:47
sakrasakra
2,8031429
answered Apr 9 at 19:47
sakrasakra
2,8031429
2,8031429
$begingroup$
Clean and elegant (+1).
$endgroup$
– David G. Stork
Apr 9 at 19:53
add a comment |
$begingroup$
Clean and elegant (+1).
$endgroup$
– David G. Stork
Apr 9 at 19:53
$begingroup$
Clean and elegant (+1).
$endgroup$
– David G. Stork
Apr 9 at 19:53
$begingroup$
Clean and elegant (+1).
$endgroup$
– David G. Stork
Apr 9 at 19:53
add a comment |
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