How to denote matrix elements succinctly? [closed]Fortran kind of matrix creationMatrix multiplication that includes a tensorHow to normalize parts of matrix elements?Row-wise matrix multiplicationReplacing elements of a matrixFill a matrix with the elements of a listMatrix operations “Modulus->non-prime” problemHow to list the pairwise matrix products of two lists of matricesDot Product of Block MatricesDefine a Givens rotation (or Jacobi rotation) matrix of size M
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How to denote matrix elements succinctly? [closed]
Fortran kind of matrix creationMatrix multiplication that includes a tensorHow to normalize parts of matrix elements?Row-wise matrix multiplicationReplacing elements of a matrixFill a matrix with the elements of a listMatrix operations “Modulus->non-prime” problemHow to list the pairwise matrix products of two lists of matricesDot Product of Block MatricesDefine a Givens rotation (or Jacobi rotation) matrix of size M
$begingroup$
Is there a more elegant way of dealing with the following subscripting?
Do[threetest =
MatrixRank[threepoints[[i]][[2]][[1]] -
threepoints[[i]][[1]][[1]],
threepoints[[i]][[2]][[2]] - threepoints[[i]][[1]][[2]],
threepoints[[i]][[3]][[1]] - threepoints[[i]][[1]][[1]],
threepoints[[i]][[3]][[2]] - threepoints[[i]][[1]][[2]]];
If[threetest < 2, Break[], 1], i, Binomial[n, 3]]
matrix notation
edited Apr 26 at 17:48
user64494
3,65111222
asked Apr 26 at 15:29
user94858user94858
161
$endgroup$
closed as off-topic by Roman, Henrik Schumacher, m_goldberg, happy fish, Alex Trounev Apr 27 at 12:25
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question arises due to a simple mistake such as a trivial syntax error, incorrect capitalization, spelling mistake, or other typographical error and is unlikely to help any future visitors, or else it is easily found in the documentation." – Roman, Henrik Schumacher, m_goldberg, happy fish, Alex Trounev
add a comment |
$begingroup$
Is there a more elegant way of dealing with the following subscripting?
Do[threetest =
MatrixRank[threepoints[[i]][[2]][[1]] -
threepoints[[i]][[1]][[1]],
threepoints[[i]][[2]][[2]] - threepoints[[i]][[1]][[2]],
threepoints[[i]][[3]][[1]] - threepoints[[i]][[1]][[1]],
threepoints[[i]][[3]][[2]] - threepoints[[i]][[1]][[2]]];
If[threetest < 2, Break[], 1], i, Binomial[n, 3]]
matrix notation
edited Apr 26 at 17:48
user64494
3,65111222
asked Apr 26 at 15:29
user94858user94858
161
$endgroup$
closed as off-topic by Roman, Henrik Schumacher, m_goldberg, happy fish, Alex Trounev Apr 27 at 12:25
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question arises due to a simple mistake such as a trivial syntax error, incorrect capitalization, spelling mistake, or other typographical error and is unlikely to help any future visitors, or else it is easily found in the documentation." – Roman, Henrik Schumacher, m_goldberg, happy fish, Alex Trounev
$begingroup$
If the last dimension ofthreePointsis two, then you might try something likeMatrixRank[threepoints[[i, 2 ;; 3]] - threepoints[[i, 1]]].
$endgroup$
– WReach
Apr 26 at 18:29
add a comment |
$begingroup$
Is there a more elegant way of dealing with the following subscripting?
Do[threetest =
MatrixRank[threepoints[[i]][[2]][[1]] -
threepoints[[i]][[1]][[1]],
threepoints[[i]][[2]][[2]] - threepoints[[i]][[1]][[2]],
threepoints[[i]][[3]][[1]] - threepoints[[i]][[1]][[1]],
threepoints[[i]][[3]][[2]] - threepoints[[i]][[1]][[2]]];
If[threetest < 2, Break[], 1], i, Binomial[n, 3]]
matrix notation
edited Apr 26 at 17:48
user64494
3,65111222
asked Apr 26 at 15:29
user94858user94858
161
$endgroup$
Is there a more elegant way of dealing with the following subscripting?
Do[threetest =
MatrixRank[threepoints[[i]][[2]][[1]] -
threepoints[[i]][[1]][[1]],
threepoints[[i]][[2]][[2]] - threepoints[[i]][[1]][[2]],
threepoints[[i]][[3]][[1]] - threepoints[[i]][[1]][[1]],
threepoints[[i]][[3]][[2]] - threepoints[[i]][[1]][[2]]];
If[threetest < 2, Break[], 1], i, Binomial[n, 3]]
matrix notation
matrix notation
edited Apr 26 at 17:48
user64494
3,65111222
asked Apr 26 at 15:29
user94858user94858
161
edited Apr 26 at 17:48
user64494
3,65111222
asked Apr 26 at 15:29
user94858user94858
161
edited Apr 26 at 17:48
user64494
3,65111222
edited Apr 26 at 17:48
user64494
3,65111222
edited Apr 26 at 17:48
user64494
3,65111222
3,65111222
asked Apr 26 at 15:29
user94858user94858
161
asked Apr 26 at 15:29
user94858user94858
161
asked Apr 26 at 15:29
user94858user94858
161
161
closed as off-topic by Roman, Henrik Schumacher, m_goldberg, happy fish, Alex Trounev Apr 27 at 12:25
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question arises due to a simple mistake such as a trivial syntax error, incorrect capitalization, spelling mistake, or other typographical error and is unlikely to help any future visitors, or else it is easily found in the documentation." – Roman, Henrik Schumacher, m_goldberg, happy fish, Alex Trounev
closed as off-topic by Roman, Henrik Schumacher, m_goldberg, happy fish, Alex Trounev Apr 27 at 12:25
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question arises due to a simple mistake such as a trivial syntax error, incorrect capitalization, spelling mistake, or other typographical error and is unlikely to help any future visitors, or else it is easily found in the documentation." – Roman, Henrik Schumacher, m_goldberg, happy fish, Alex Trounev
$begingroup$
If the last dimension ofthreePointsis two, then you might try something likeMatrixRank[threepoints[[i, 2 ;; 3]] - threepoints[[i, 1]]].
$endgroup$
– WReach
Apr 26 at 18:29
add a comment |
$begingroup$
If the last dimension ofthreePointsis two, then you might try something likeMatrixRank[threepoints[[i, 2 ;; 3]] - threepoints[[i, 1]]].
$endgroup$
– WReach
Apr 26 at 18:29
$begingroup$
If the last dimension of
threePoints is two, then you might try something like MatrixRank[threepoints[[i, 2 ;; 3]] - threepoints[[i, 1]]].$endgroup$
– WReach
Apr 26 at 18:29
$begingroup$
If the last dimension of
threePoints is two, then you might try something like MatrixRank[threepoints[[i, 2 ;; 3]] - threepoints[[i, 1]]].$endgroup$
– WReach
Apr 26 at 18:29
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
If threepoints is defined with any kind of regularity, then threepoints[[i]][[2]][[1]] is the same as threepoints[[i,2,1]]. See the documentation of Part.
Further, you can do vector processing with ;;, along the lines of
Do[threetest =
MatrixRank[threepoints[[i, 2, 1 ;; 2]] - threepoints[[i, 1, 1 ;; 2]],
threepoints[[i, 3, 1 ;; 2]] - threepoints[[i, 1, 1 ;; 2]]];
If[threetest < 2, Break[], 1],
i, Binomial[n, 3]]
If the third coordinate of threetest has only two slots (that is, if Dimensions[threetest] returns something,something,2), then the above can also be written as
Do[threetest =
MatrixRank[threepoints[[i, 2]] - threepoints[[i, 1]],
threepoints[[i, 3]] - threepoints[[i, 1]]];
If[threetest < 2, Break[], 1],
i, Binomial[n, 3]]
answered Apr 26 at 15:33
RomanRoman
7,14511134
$endgroup$
add a comment |
$begingroup$
The other thing I do is to use the stylized brackets in all of my MMA code. Stackexchange mangles it, so have to use a picture to demonstrate:
Big difference in readability.
answered Apr 26 at 18:04
MikeYMikeY
3,903916
$endgroup$
$begingroup$
Also, you can put them in the subscript and they work equally. And if it's still not enough, you can use the invisible comma to separate indices. ;-)
$endgroup$
– Veky
Apr 27 at 3:53
$begingroup$
It’s probably worth adding how to enter these doubled brackets using the keyboard: Esc–[–[–Esc.
$endgroup$
– Stephen Powell
Apr 27 at 9:17
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
If threepoints is defined with any kind of regularity, then threepoints[[i]][[2]][[1]] is the same as threepoints[[i,2,1]]. See the documentation of Part.
Further, you can do vector processing with ;;, along the lines of
Do[threetest =
MatrixRank[threepoints[[i, 2, 1 ;; 2]] - threepoints[[i, 1, 1 ;; 2]],
threepoints[[i, 3, 1 ;; 2]] - threepoints[[i, 1, 1 ;; 2]]];
If[threetest < 2, Break[], 1],
i, Binomial[n, 3]]
If the third coordinate of threetest has only two slots (that is, if Dimensions[threetest] returns something,something,2), then the above can also be written as
Do[threetest =
MatrixRank[threepoints[[i, 2]] - threepoints[[i, 1]],
threepoints[[i, 3]] - threepoints[[i, 1]]];
If[threetest < 2, Break[], 1],
i, Binomial[n, 3]]
answered Apr 26 at 15:33
RomanRoman
7,14511134
$endgroup$
add a comment |
$begingroup$
If threepoints is defined with any kind of regularity, then threepoints[[i]][[2]][[1]] is the same as threepoints[[i,2,1]]. See the documentation of Part.
Further, you can do vector processing with ;;, along the lines of
Do[threetest =
MatrixRank[threepoints[[i, 2, 1 ;; 2]] - threepoints[[i, 1, 1 ;; 2]],
threepoints[[i, 3, 1 ;; 2]] - threepoints[[i, 1, 1 ;; 2]]];
If[threetest < 2, Break[], 1],
i, Binomial[n, 3]]
If the third coordinate of threetest has only two slots (that is, if Dimensions[threetest] returns something,something,2), then the above can also be written as
Do[threetest =
MatrixRank[threepoints[[i, 2]] - threepoints[[i, 1]],
threepoints[[i, 3]] - threepoints[[i, 1]]];
If[threetest < 2, Break[], 1],
i, Binomial[n, 3]]
answered Apr 26 at 15:33
RomanRoman
7,14511134
$endgroup$
add a comment |
$begingroup$
If threepoints is defined with any kind of regularity, then threepoints[[i]][[2]][[1]] is the same as threepoints[[i,2,1]]. See the documentation of Part.
Further, you can do vector processing with ;;, along the lines of
Do[threetest =
MatrixRank[threepoints[[i, 2, 1 ;; 2]] - threepoints[[i, 1, 1 ;; 2]],
threepoints[[i, 3, 1 ;; 2]] - threepoints[[i, 1, 1 ;; 2]]];
If[threetest < 2, Break[], 1],
i, Binomial[n, 3]]
If the third coordinate of threetest has only two slots (that is, if Dimensions[threetest] returns something,something,2), then the above can also be written as
Do[threetest =
MatrixRank[threepoints[[i, 2]] - threepoints[[i, 1]],
threepoints[[i, 3]] - threepoints[[i, 1]]];
If[threetest < 2, Break[], 1],
i, Binomial[n, 3]]
answered Apr 26 at 15:33
RomanRoman
7,14511134
$endgroup$
If threepoints is defined with any kind of regularity, then threepoints[[i]][[2]][[1]] is the same as threepoints[[i,2,1]]. See the documentation of Part.
Further, you can do vector processing with ;;, along the lines of
Do[threetest =
MatrixRank[threepoints[[i, 2, 1 ;; 2]] - threepoints[[i, 1, 1 ;; 2]],
threepoints[[i, 3, 1 ;; 2]] - threepoints[[i, 1, 1 ;; 2]]];
If[threetest < 2, Break[], 1],
i, Binomial[n, 3]]
If the third coordinate of threetest has only two slots (that is, if Dimensions[threetest] returns something,something,2), then the above can also be written as
Do[threetest =
MatrixRank[threepoints[[i, 2]] - threepoints[[i, 1]],
threepoints[[i, 3]] - threepoints[[i, 1]]];
If[threetest < 2, Break[], 1],
i, Binomial[n, 3]]
answered Apr 26 at 15:33
RomanRoman
7,14511134
edited Apr 26 at 18:50
answered Apr 26 at 15:33
RomanRoman
7,14511134
answered Apr 26 at 15:33
RomanRoman
7,14511134
answered Apr 26 at 15:33
RomanRoman
7,14511134
7,14511134
add a comment |
add a comment |
$begingroup$
The other thing I do is to use the stylized brackets in all of my MMA code. Stackexchange mangles it, so have to use a picture to demonstrate:
Big difference in readability.
answered Apr 26 at 18:04
MikeYMikeY
3,903916
$endgroup$
$begingroup$
Also, you can put them in the subscript and they work equally. And if it's still not enough, you can use the invisible comma to separate indices. ;-)
$endgroup$
– Veky
Apr 27 at 3:53
$begingroup$
It’s probably worth adding how to enter these doubled brackets using the keyboard: Esc–[–[–Esc.
$endgroup$
– Stephen Powell
Apr 27 at 9:17
add a comment |
$begingroup$
The other thing I do is to use the stylized brackets in all of my MMA code. Stackexchange mangles it, so have to use a picture to demonstrate:
Big difference in readability.
answered Apr 26 at 18:04
MikeYMikeY
3,903916
$endgroup$
$begingroup$
Also, you can put them in the subscript and they work equally. And if it's still not enough, you can use the invisible comma to separate indices. ;-)
$endgroup$
– Veky
Apr 27 at 3:53
$begingroup$
It’s probably worth adding how to enter these doubled brackets using the keyboard: Esc–[–[–Esc.
$endgroup$
– Stephen Powell
Apr 27 at 9:17
add a comment |
$begingroup$
The other thing I do is to use the stylized brackets in all of my MMA code. Stackexchange mangles it, so have to use a picture to demonstrate:
Big difference in readability.
answered Apr 26 at 18:04
MikeYMikeY
3,903916
$endgroup$
The other thing I do is to use the stylized brackets in all of my MMA code. Stackexchange mangles it, so have to use a picture to demonstrate:
Big difference in readability.
answered Apr 26 at 18:04
MikeYMikeY
3,903916
answered Apr 26 at 18:04
MikeYMikeY
3,903916
answered Apr 26 at 18:04
MikeYMikeY
3,903916
answered Apr 26 at 18:04
MikeYMikeY
3,903916
3,903916
$begingroup$
Also, you can put them in the subscript and they work equally. And if it's still not enough, you can use the invisible comma to separate indices. ;-)
$endgroup$
– Veky
Apr 27 at 3:53
$begingroup$
It’s probably worth adding how to enter these doubled brackets using the keyboard: Esc–[–[–Esc.
$endgroup$
– Stephen Powell
Apr 27 at 9:17
add a comment |
$begingroup$
Also, you can put them in the subscript and they work equally. And if it's still not enough, you can use the invisible comma to separate indices. ;-)
$endgroup$
– Veky
Apr 27 at 3:53
$begingroup$
It’s probably worth adding how to enter these doubled brackets using the keyboard: Esc–[–[–Esc.
$endgroup$
– Stephen Powell
Apr 27 at 9:17
$begingroup$
Also, you can put them in the subscript and they work equally. And if it's still not enough, you can use the invisible comma to separate indices. ;-)
$endgroup$
– Veky
Apr 27 at 3:53
$begingroup$
Also, you can put them in the subscript and they work equally. And if it's still not enough, you can use the invisible comma to separate indices. ;-)
$endgroup$
– Veky
Apr 27 at 3:53
$begingroup$
It’s probably worth adding how to enter these doubled brackets using the keyboard: Esc–[–[–Esc.
$endgroup$
– Stephen Powell
Apr 27 at 9:17
$begingroup$
It’s probably worth adding how to enter these doubled brackets using the keyboard: Esc–[–[–Esc.
$endgroup$
– Stephen Powell
Apr 27 at 9:17
add a comment |
$begingroup$
If the last dimension of
threePointsis two, then you might try something likeMatrixRank[threepoints[[i, 2 ;; 3]] - threepoints[[i, 1]]].$endgroup$
– WReach
Apr 26 at 18:29