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Bash - Execute two commands and get exit status 1 if first fails

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4

In the case below, the report command must always be executed but I need to get an exit status 1 if the test command fails:

test;report
echo $?
0

How can I do it in a single bash line without creating a shell script?

bash exit-status

share|improve this question

edited May 17 at 20:23

Jeff Schaller♦

46k1165150

asked May 17 at 19:54

EduardoEduardo

1242

add a comment | 

4

In the case below, the report command must always be executed but I need to get an exit status 1 if the test command fails:

test;report
echo $?
0

How can I do it in a single bash line without creating a shell script?

bash exit-status

share|improve this question

edited May 17 at 20:23

Jeff Schaller♦

46k1165150

asked May 17 at 19:54

EduardoEduardo

1242

add a comment | 

In the case below, the report command must always be executed but I need to get an exit status 1 if the test command fails:

test;report
echo $?
0

How can I do it in a single bash line without creating a shell script?

bash exit-status

share|improve this question

edited May 17 at 20:23

Jeff Schaller♦

46k1165150

asked May 17 at 19:54

EduardoEduardo

1242

test;report
echo $?
0

share|improve this question

edited May 17 at 20:23

Jeff Schaller♦

46k1165150

asked May 17 at 19:54

EduardoEduardo

1242

share|improve this question

edited May 17 at 20:23

Jeff Schaller♦

46k1165150

asked May 17 at 19:54

EduardoEduardo

1242

edited May 17 at 20:23

Jeff Schaller♦

46k1165150

edited May 17 at 20:23

Jeff Schaller♦

46k1165150

asked May 17 at 19:54

EduardoEduardo

1242

asked May 17 at 19:54

EduardoEduardo

1242

4 Answers
4

active

oldest

votes

14

Save and reuse $?.

test; ret=$?; report; exit $ret

If you have multiple test commands and you want to run them all, but keep track of whether one has failed, you can use bash's ERR trap.

failures=0
trap 'failures=$((failures+1))' ERR
test1
test2
if ((failures == 0)); then
 echo "Success"
else
 echo "$failures failures"
 exit 1
fi

share|improve this answer

answered May 17 at 20:17

GillesGilles

556k13411421651

add a comment | 

9

What is a shell script except a file containing shell commands? You could pretend it's not a shell script and put it on one line with something like:

(test; r=$?; report; [ "$r" -gt 0 ] && exit 1; exit 0)

This exits the subshell with a 1 if the first command returned anything other than 0; otherwise, it returns 0.

For examples -- I'm just echoing something in lieu of running a real program:

$ (false; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
report
$ echo $?
1
$ (true; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
report
$ echo $?
0
$ # example with an exit-status of 2:
$ (grep foo bar; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
grep: bar: No such file or directory
report
$ echo $?
1

If you regularly set the errexit shell option, you'd want to add in an override so that the subshell doesn't exit prematurely:

(set +o errexit; false; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)

share|improve this answer

answered May 17 at 20:16

Jeff Schaller♦Jeff Schaller

46k1165150

add a comment | 

4

You said "exit status 1 if the test command fails". Assuming you intended to make that distinction (i.e., you want the exit value to be 1 even if the test command exits with, say, 2, or 3, or whatever), then this is a decent solution:

test && report; true; || report; false; 

If you did not really mean "1", but whatever non-zero that test exited with would be OK as your overall exit code, then the current top answer (save and reuse $?) works fine.

share|improve this answer

answered May 18 at 5:55

sitaramsitaram

613

add a comment | 

0

A really bad idea, but this seems to work, for some inspiration:

(trap report exit; test)

share|improve this answer

answered May 18 at 17:30

user23013user23013

642414

add a comment | 

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14

Save and reuse $?.

test; ret=$?; report; exit $ret

If you have multiple test commands and you want to run them all, but keep track of whether one has failed, you can use bash's ERR trap.

failures=0
trap 'failures=$((failures+1))' ERR
test1
test2
if ((failures == 0)); then
 echo "Success"
else
 echo "$failures failures"
 exit 1
fi

share|improve this answer

answered May 17 at 20:17

GillesGilles

556k13411421651

add a comment | 

14

Save and reuse $?.

test; ret=$?; report; exit $ret

If you have multiple test commands and you want to run them all, but keep track of whether one has failed, you can use bash's ERR trap.

failures=0
trap 'failures=$((failures+1))' ERR
test1
test2
if ((failures == 0)); then
 echo "Success"
else
 echo "$failures failures"
 exit 1
fi

share|improve this answer

answered May 17 at 20:17

GillesGilles

556k13411421651

add a comment | 

Save and reuse $?.

test; ret=$?; report; exit $ret

If you have multiple test commands and you want to run them all, but keep track of whether one has failed, you can use bash's ERR trap.

failures=0
trap 'failures=$((failures+1))' ERR
test1
test2
if ((failures == 0)); then
 echo "Success"
else
 echo "$failures failures"
 exit 1
fi

share|improve this answer

answered May 17 at 20:17

GillesGilles

556k13411421651

test; ret=$?; report; exit $ret

failures=0
trap 'failures=$((failures+1))' ERR
test1
test2
if ((failures == 0)); then
 echo "Success"
else
 echo "$failures failures"
 exit 1
fi

share|improve this answer

answered May 17 at 20:17

GillesGilles

556k13411421651

answered May 17 at 20:17

GillesGilles

556k13411421651

answered May 17 at 20:17

GillesGilles

556k13411421651

9

What is a shell script except a file containing shell commands? You could pretend it's not a shell script and put it on one line with something like:

(test; r=$?; report; [ "$r" -gt 0 ] && exit 1; exit 0)

This exits the subshell with a 1 if the first command returned anything other than 0; otherwise, it returns 0.

For examples -- I'm just echoing something in lieu of running a real program:

$ (false; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
report
$ echo $?
1
$ (true; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
report
$ echo $?
0
$ # example with an exit-status of 2:
$ (grep foo bar; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
grep: bar: No such file or directory
report
$ echo $?
1

If you regularly set the errexit shell option, you'd want to add in an override so that the subshell doesn't exit prematurely:

(set +o errexit; false; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)

share|improve this answer

answered May 17 at 20:16

Jeff Schaller♦Jeff Schaller

46k1165150

add a comment | 

9

What is a shell script except a file containing shell commands? You could pretend it's not a shell script and put it on one line with something like:

(test; r=$?; report; [ "$r" -gt 0 ] && exit 1; exit 0)

This exits the subshell with a 1 if the first command returned anything other than 0; otherwise, it returns 0.

For examples -- I'm just echoing something in lieu of running a real program:

$ (false; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
report
$ echo $?
1
$ (true; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
report
$ echo $?
0
$ # example with an exit-status of 2:
$ (grep foo bar; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
grep: bar: No such file or directory
report
$ echo $?
1

If you regularly set the errexit shell option, you'd want to add in an override so that the subshell doesn't exit prematurely:

(set +o errexit; false; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)

share|improve this answer

answered May 17 at 20:16

Jeff Schaller♦Jeff Schaller

46k1165150

add a comment | 

What is a shell script except a file containing shell commands? You could pretend it's not a shell script and put it on one line with something like:

(test; r=$?; report; [ "$r" -gt 0 ] && exit 1; exit 0)

This exits the subshell with a 1 if the first command returned anything other than 0; otherwise, it returns 0.

For examples -- I'm just echoing something in lieu of running a real program:

$ (false; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
report
$ echo $?
1
$ (true; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
report
$ echo $?
0
$ # example with an exit-status of 2:
$ (grep foo bar; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
grep: bar: No such file or directory
report
$ echo $?
1

If you regularly set the errexit shell option, you'd want to add in an override so that the subshell doesn't exit prematurely:

(set +o errexit; false; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)

share|improve this answer

answered May 17 at 20:16

Jeff Schaller♦Jeff Schaller

46k1165150

(test; r=$?; report; [ "$r" -gt 0 ] && exit 1; exit 0)

$ (false; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
report
$ echo $?
1
$ (true; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
report
$ echo $?
0
$ # example with an exit-status of 2:
$ (grep foo bar; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)
grep: bar: No such file or directory
report
$ echo $?
1

(set +o errexit; false; r=$?; echo report; [ "$r" -gt 0 ] && exit 1; exit 0)

share|improve this answer

answered May 17 at 20:16

Jeff Schaller♦Jeff Schaller

46k1165150

answered May 17 at 20:16

Jeff Schaller♦Jeff Schaller

46k1165150

answered May 17 at 20:16

Jeff Schaller♦Jeff Schaller

46k1165150

4

You said "exit status 1 if the test command fails". Assuming you intended to make that distinction (i.e., you want the exit value to be 1 even if the test command exits with, say, 2, or 3, or whatever), then this is a decent solution:

test && report; true; || report; false; 

If you did not really mean "1", but whatever non-zero that test exited with would be OK as your overall exit code, then the current top answer (save and reuse $?) works fine.

share|improve this answer

answered May 18 at 5:55

sitaramsitaram

613

add a comment | 

4

You said "exit status 1 if the test command fails". Assuming you intended to make that distinction (i.e., you want the exit value to be 1 even if the test command exits with, say, 2, or 3, or whatever), then this is a decent solution:

test && report; true; || report; false; 

If you did not really mean "1", but whatever non-zero that test exited with would be OK as your overall exit code, then the current top answer (save and reuse $?) works fine.

share|improve this answer

answered May 18 at 5:55

sitaramsitaram

613

add a comment | 

You said "exit status 1 if the test command fails". Assuming you intended to make that distinction (i.e., you want the exit value to be 1 even if the test command exits with, say, 2, or 3, or whatever), then this is a decent solution:

test && report; true; || report; false; 

If you did not really mean "1", but whatever non-zero that test exited with would be OK as your overall exit code, then the current top answer (save and reuse $?) works fine.

share|improve this answer

answered May 18 at 5:55

sitaramsitaram

613

test && report; true; || report; false; 

share|improve this answer

answered May 18 at 5:55

sitaramsitaram

613

answered May 18 at 5:55

sitaramsitaram

613

answered May 18 at 5:55

sitaramsitaram

613

0

A really bad idea, but this seems to work, for some inspiration:

(trap report exit; test)

share|improve this answer

answered May 18 at 17:30

user23013user23013

642414

add a comment | 

0

A really bad idea, but this seems to work, for some inspiration:

(trap report exit; test)

share|improve this answer

answered May 18 at 17:30

user23013user23013

642414

add a comment | 

A really bad idea, but this seems to work, for some inspiration:

(trap report exit; test)

share|improve this answer

answered May 18 at 17:30

user23013user23013

642414

(trap report exit; test)

share|improve this answer

answered May 18 at 17:30

user23013user23013

642414

answered May 18 at 17:30

user23013user23013

642414

answered May 18 at 17:30

user23013user23013

642414