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Can you express this orderly Palindromic Devil in strict ascending Pandigital form?

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3

0

$begingroup$

Given:

Devil as you know is $ 666 $

Using digits 1 to 9 in strict ascending order and only three mathematical signs ( +, -, /, x ... of these are allowed), write the Pandigital expression

$ 666 = $

mathematics calculation-puzzle no-computers

share|improve this question

edited May 18 at 19:41

Rubio♦

31.8k668194

asked May 17 at 16:21

UvcUvc

1,150119

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Parentheses or concatenation?
  $endgroup$
  – Jonathan Allan
  May 17 at 18:54
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Concatenated Numbers only..no other operators other than specified
  $endgroup$
  – Uvc
  May 17 at 18:57
  

  
  
  
  

add a comment | 

3

0

$begingroup$

Given:

Devil as you know is $ 666 $

Using digits 1 to 9 in strict ascending order and only three mathematical signs ( +, -, /, x ... of these are allowed), write the Pandigital expression

$ 666 = $

mathematics calculation-puzzle no-computers

share|improve this question

edited May 18 at 19:41

Rubio♦

31.8k668194

asked May 17 at 16:21

UvcUvc

1,150119

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Parentheses or concatenation?
  $endgroup$
  – Jonathan Allan
  May 17 at 18:54
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Concatenated Numbers only..no other operators other than specified
  $endgroup$
  – Uvc
  May 17 at 18:57
  

  
  
  
  

add a comment | 

$begingroup$

Given:

Devil as you know is $ 666 $

Using digits 1 to 9 in strict ascending order and only three mathematical signs ( +, -, /, x ... of these are allowed), write the Pandigital expression

$ 666 = $

mathematics calculation-puzzle no-computers

share|improve this question

edited May 18 at 19:41

Rubio♦

31.8k668194

asked May 17 at 16:21

UvcUvc

1,150119

$endgroup$

share|improve this question

edited May 18 at 19:41

Rubio♦

31.8k668194

asked May 17 at 16:21

UvcUvc

1,150119

share|improve this question

edited May 18 at 19:41

Rubio♦

31.8k668194

asked May 17 at 16:21

UvcUvc

1,150119

edited May 18 at 19:41

Rubio♦

31.8k668194

edited May 18 at 19:41

Rubio♦

31.8k668194

asked May 17 at 16:21

UvcUvc

1,150119

asked May 17 at 16:21

UvcUvc

1,150119

2 Answers
2

active

oldest

votes

6

$begingroup$

Assuming that concatenation is allowed

$1234 – 567 + 8 – 9 = 666$
(using three signs: -, + and -)

share|improve this answer

edited May 17 at 16:42

answered May 17 at 16:35

MichaelMaggsMichaelMaggs

827216

$endgroup$

add a comment | 

4

$begingroup$

Here's one:

$666=123+456+78+9$

---

(I initially thought this was one, but the restriction being made is to use three operation instances, rather than three of the set of allowed operations)

$666=123+45-6+7times 8times 9$

share|improve this answer

edited May 17 at 19:20

answered May 17 at 19:04

Jonathan AllanJonathan Allan

18.2k14698

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Only 3 mathematical signs permitted as per the puzzle
  $endgroup$
  – Uvc
  May 17 at 19:09
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  yeah plus, minus and multiply.
  $endgroup$
  – Jonathan Allan
  May 17 at 19:10
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Oh only three instances ?
  $endgroup$
  – Jonathan Allan
  May 17 at 19:11
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Found one using three instances and updated.
  $endgroup$
  – Jonathan Allan
  May 17 at 19:21
  

  
  
  
  

add a comment | 

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6

$begingroup$

Assuming that concatenation is allowed

$1234 – 567 + 8 – 9 = 666$
(using three signs: -, + and -)

share|improve this answer

edited May 17 at 16:42

answered May 17 at 16:35

MichaelMaggsMichaelMaggs

827216

$endgroup$

add a comment | 

6

$begingroup$

Assuming that concatenation is allowed

$1234 – 567 + 8 – 9 = 666$
(using three signs: -, + and -)

share|improve this answer

edited May 17 at 16:42

answered May 17 at 16:35

MichaelMaggsMichaelMaggs

827216

$endgroup$

add a comment | 

$begingroup$

Assuming that concatenation is allowed

$1234 – 567 + 8 – 9 = 666$
(using three signs: -, + and -)

share|improve this answer

edited May 17 at 16:42

answered May 17 at 16:35

MichaelMaggsMichaelMaggs

827216

$endgroup$

share|improve this answer

edited May 17 at 16:42

answered May 17 at 16:35

MichaelMaggsMichaelMaggs

827216

answered May 17 at 16:35

MichaelMaggsMichaelMaggs

827216

answered May 17 at 16:35

MichaelMaggsMichaelMaggs

827216

4

$begingroup$

Here's one:

$666=123+456+78+9$

---

(I initially thought this was one, but the restriction being made is to use three operation instances, rather than three of the set of allowed operations)

$666=123+45-6+7times 8times 9$

share|improve this answer

edited May 17 at 19:20

answered May 17 at 19:04

Jonathan AllanJonathan Allan

18.2k14698

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Only 3 mathematical signs permitted as per the puzzle
  $endgroup$
  – Uvc
  May 17 at 19:09
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  yeah plus, minus and multiply.
  $endgroup$
  – Jonathan Allan
  May 17 at 19:10
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Oh only three instances ?
  $endgroup$
  – Jonathan Allan
  May 17 at 19:11
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Found one using three instances and updated.
  $endgroup$
  – Jonathan Allan
  May 17 at 19:21
  

  
  
  
  

add a comment | 

4

$begingroup$

Here's one:

$666=123+456+78+9$

---

(I initially thought this was one, but the restriction being made is to use three operation instances, rather than three of the set of allowed operations)

$666=123+45-6+7times 8times 9$

share|improve this answer

edited May 17 at 19:20

answered May 17 at 19:04

Jonathan AllanJonathan Allan

18.2k14698

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Only 3 mathematical signs permitted as per the puzzle
  $endgroup$
  – Uvc
  May 17 at 19:09
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  yeah plus, minus and multiply.
  $endgroup$
  – Jonathan Allan
  May 17 at 19:10
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Oh only three instances ?
  $endgroup$
  – Jonathan Allan
  May 17 at 19:11
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Found one using three instances and updated.
  $endgroup$
  – Jonathan Allan
  May 17 at 19:21
  

  
  
  
  

add a comment | 

$begingroup$

Here's one:

$666=123+456+78+9$

---

(I initially thought this was one, but the restriction being made is to use three operation instances, rather than three of the set of allowed operations)

$666=123+45-6+7times 8times 9$

share|improve this answer

edited May 17 at 19:20

answered May 17 at 19:04

Jonathan AllanJonathan Allan

18.2k14698

$endgroup$

share|improve this answer

edited May 17 at 19:20

answered May 17 at 19:04

Jonathan AllanJonathan Allan

18.2k14698

answered May 17 at 19:04

Jonathan AllanJonathan Allan

18.2k14698

answered May 17 at 19:04

Jonathan AllanJonathan Allan

18.2k14698