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How to convert this very simple .htaccess to Nginx?

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;

1

I'm using this .htaccess that pass everything after URL to $param, so
example.com/news/id goes to PHP as $_GET['param']='news/id'. But Nginx is always throwing me to 404 page.

My .htaccess:

RewriteEngine On
RewriteCond %SCRIPT_FILENAME !-f
RewriteCond %SCRIPT_FILENAME !-d
RewriteRule (.*) index.php?param=$1

What I tried in Nginx default.conf:

server 
 listen 80;
 listen [::]:80;
 server_name domain.com;
 root /var/www/html;

 location / 
 if (!-f $uri)
 set $rule_0 1$rule_0;
 
 if (!-d $uri)
 set $rule_0 2$rule_0;
 
 if ($rule_0 = "21")
 rewrite ^(.*) index.php?param=$1;
 
 

nginx web-server .htaccess ngx-http-rewrite-module

share|improve this question

edited May 20 at 10:24

MrWhite

6,51621426

asked May 20 at 1:56

Sandro BenevidesSandro Benevides

165

add a comment | 

1

I'm using this .htaccess that pass everything after URL to $param, so
example.com/news/id goes to PHP as $_GET['param']='news/id'. But Nginx is always throwing me to 404 page.

My .htaccess:

RewriteEngine On
RewriteCond %SCRIPT_FILENAME !-f
RewriteCond %SCRIPT_FILENAME !-d
RewriteRule (.*) index.php?param=$1

What I tried in Nginx default.conf:

server 
 listen 80;
 listen [::]:80;
 server_name domain.com;
 root /var/www/html;

 location / 
 if (!-f $uri)
 set $rule_0 1$rule_0;
 
 if (!-d $uri)
 set $rule_0 2$rule_0;
 
 if ($rule_0 = "21")
 rewrite ^(.*) index.php?param=$1;
 
 

nginx web-server .htaccess ngx-http-rewrite-module

share|improve this question

edited May 20 at 10:24

MrWhite

6,51621426

asked May 20 at 1:56

Sandro BenevidesSandro Benevides

165

add a comment | 

I'm using this .htaccess that pass everything after URL to $param, so
example.com/news/id goes to PHP as $_GET['param']='news/id'. But Nginx is always throwing me to 404 page.

My .htaccess:

RewriteEngine On
RewriteCond %SCRIPT_FILENAME !-f
RewriteCond %SCRIPT_FILENAME !-d
RewriteRule (.*) index.php?param=$1

What I tried in Nginx default.conf:

server 
 listen 80;
 listen [::]:80;
 server_name domain.com;
 root /var/www/html;

 location / 
 if (!-f $uri)
 set $rule_0 1$rule_0;
 
 if (!-d $uri)
 set $rule_0 2$rule_0;
 
 if ($rule_0 = "21")
 rewrite ^(.*) index.php?param=$1;
 
 

nginx web-server .htaccess ngx-http-rewrite-module

share|improve this question

edited May 20 at 10:24

MrWhite

6,51621426

asked May 20 at 1:56

Sandro BenevidesSandro Benevides

165

RewriteEngine On
RewriteCond %SCRIPT_FILENAME !-f
RewriteCond %SCRIPT_FILENAME !-d
RewriteRule (.*) index.php?param=$1

server 
 listen 80;
 listen [::]:80;
 server_name domain.com;
 root /var/www/html;

 location / 
 if (!-f $uri)
 set $rule_0 1$rule_0;
 
 if (!-d $uri)
 set $rule_0 2$rule_0;
 
 if ($rule_0 = "21")
 rewrite ^(.*) index.php?param=$1;
 
 

share|improve this question

edited May 20 at 10:24

MrWhite

6,51621426

asked May 20 at 1:56

Sandro BenevidesSandro Benevides

165

share|improve this question

edited May 20 at 10:24

MrWhite

6,51621426

asked May 20 at 1:56

Sandro BenevidesSandro Benevides

165

edited May 20 at 10:24

MrWhite

6,51621426

edited May 20 at 10:24

MrWhite

6,51621426

asked May 20 at 1:56

Sandro BenevidesSandro Benevides

165

asked May 20 at 1:56

Sandro BenevidesSandro Benevides

165

2 Answers
2

active

oldest

votes

1

You don't use if here at all, nor do you manually check for the existence of files. This common pattern is handled instead by try_files.

For example:

location / 
 try_files $uri $uri/ /index.php?param=$uri;

(If your web app is broken and can't handle the leading / in the URI, fix the web app if possible, or see this question if not.)

share|improve this answer

answered May 20 at 2:08

Michael Hampton♦Michael Hampton

179k27326659

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I tried this but no success. Even if I try to reach /index.php directly nginx shows a 404 page. And the webapp is handling this properly, stopping nginx and starting httpd it works.
  
  – Sandro Benevides
  May 20 at 2:19
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @SandroBenevides Then you have some other problem. Check your error log.
  
  – Michael Hampton♦
  May 20 at 2:21
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @SandroBenevides A possible difference here is that the Nginx $uri variable contains a slash prefix, whereas the Apache $1 backreference in the .htaccess directive does not. However, you should be able to see that by examining the value of the param URL parameter? Or are you saying your script is not being called at all?
  
  – MrWhite
  May 20 at 10:44
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MrWhite If I comment this rule in location / block and access domain.com it works, and the script is doing its job properly. If I access domain.com/index.php, it shows 404 error and also if I try domain.com/news/id I get 404. I also tested sending a php file with echo phpinfo() and named as index, when trying to reach the file index.php it shows 404 error, if accessing just the domain.com it works. Other files as images I can access normally.
  
  – Sandro Benevides
  May 20 at 14:06
  
  

  
  
  
  

add a comment | 

1

I could fix it using these rules:

server
try_files $uri $uri/ @rewrite;
 location @rewrite 
 rewrite ^/(.*)$ /index.php?_url=$1;
 

If you have location / without any instructions inside, remove it.

share|improve this answer

answered May 20 at 18:15

Sandro BenevidesSandro Benevides

165

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  See also stackoverflow.com/questions/41908851/…
  
  – MrWhite
  May 20 at 20:26
  

  
  
  
  

add a comment | 

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1

You don't use if here at all, nor do you manually check for the existence of files. This common pattern is handled instead by try_files.

For example:

location / 
 try_files $uri $uri/ /index.php?param=$uri;

(If your web app is broken and can't handle the leading / in the URI, fix the web app if possible, or see this question if not.)

share|improve this answer

answered May 20 at 2:08

Michael Hampton♦Michael Hampton

179k27326659

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I tried this but no success. Even if I try to reach /index.php directly nginx shows a 404 page. And the webapp is handling this properly, stopping nginx and starting httpd it works.
  
  – Sandro Benevides
  May 20 at 2:19
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @SandroBenevides Then you have some other problem. Check your error log.
  
  – Michael Hampton♦
  May 20 at 2:21
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @SandroBenevides A possible difference here is that the Nginx $uri variable contains a slash prefix, whereas the Apache $1 backreference in the .htaccess directive does not. However, you should be able to see that by examining the value of the param URL parameter? Or are you saying your script is not being called at all?
  
  – MrWhite
  May 20 at 10:44
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MrWhite If I comment this rule in location / block and access domain.com it works, and the script is doing its job properly. If I access domain.com/index.php, it shows 404 error and also if I try domain.com/news/id I get 404. I also tested sending a php file with echo phpinfo() and named as index, when trying to reach the file index.php it shows 404 error, if accessing just the domain.com it works. Other files as images I can access normally.
  
  – Sandro Benevides
  May 20 at 14:06
  
  

  
  
  
  

add a comment | 

1

You don't use if here at all, nor do you manually check for the existence of files. This common pattern is handled instead by try_files.

For example:

location / 
 try_files $uri $uri/ /index.php?param=$uri;

(If your web app is broken and can't handle the leading / in the URI, fix the web app if possible, or see this question if not.)

share|improve this answer

answered May 20 at 2:08

Michael Hampton♦Michael Hampton

179k27326659

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I tried this but no success. Even if I try to reach /index.php directly nginx shows a 404 page. And the webapp is handling this properly, stopping nginx and starting httpd it works.
  
  – Sandro Benevides
  May 20 at 2:19
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @SandroBenevides Then you have some other problem. Check your error log.
  
  – Michael Hampton♦
  May 20 at 2:21
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @SandroBenevides A possible difference here is that the Nginx $uri variable contains a slash prefix, whereas the Apache $1 backreference in the .htaccess directive does not. However, you should be able to see that by examining the value of the param URL parameter? Or are you saying your script is not being called at all?
  
  – MrWhite
  May 20 at 10:44
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MrWhite If I comment this rule in location / block and access domain.com it works, and the script is doing its job properly. If I access domain.com/index.php, it shows 404 error and also if I try domain.com/news/id I get 404. I also tested sending a php file with echo phpinfo() and named as index, when trying to reach the file index.php it shows 404 error, if accessing just the domain.com it works. Other files as images I can access normally.
  
  – Sandro Benevides
  May 20 at 14:06
  
  

  
  
  
  

add a comment | 

You don't use if here at all, nor do you manually check for the existence of files. This common pattern is handled instead by try_files.

For example:

location / 
 try_files $uri $uri/ /index.php?param=$uri;

(If your web app is broken and can't handle the leading / in the URI, fix the web app if possible, or see this question if not.)

share|improve this answer

answered May 20 at 2:08

Michael Hampton♦Michael Hampton

179k27326659

location / 
 try_files $uri $uri/ /index.php?param=$uri;

share|improve this answer

answered May 20 at 2:08

Michael Hampton♦Michael Hampton

179k27326659

answered May 20 at 2:08

Michael Hampton♦Michael Hampton

179k27326659

answered May 20 at 2:08

Michael Hampton♦Michael Hampton

179k27326659

1

I could fix it using these rules:

server
try_files $uri $uri/ @rewrite;
 location @rewrite 
 rewrite ^/(.*)$ /index.php?_url=$1;
 

If you have location / without any instructions inside, remove it.

share|improve this answer

answered May 20 at 18:15

Sandro BenevidesSandro Benevides

165

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  See also stackoverflow.com/questions/41908851/…
  
  – MrWhite
  May 20 at 20:26
  

  
  
  
  

add a comment | 

1

I could fix it using these rules:

server
try_files $uri $uri/ @rewrite;
 location @rewrite 
 rewrite ^/(.*)$ /index.php?_url=$1;
 

If you have location / without any instructions inside, remove it.

share|improve this answer

answered May 20 at 18:15

Sandro BenevidesSandro Benevides

165

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  See also stackoverflow.com/questions/41908851/…
  
  – MrWhite
  May 20 at 20:26
  

  
  
  
  

add a comment | 

I could fix it using these rules:

server
try_files $uri $uri/ @rewrite;
 location @rewrite 
 rewrite ^/(.*)$ /index.php?_url=$1;
 

If you have location / without any instructions inside, remove it.

share|improve this answer

answered May 20 at 18:15

Sandro BenevidesSandro Benevides

165

server
try_files $uri $uri/ @rewrite;
 location @rewrite 
 rewrite ^/(.*)$ /index.php?_url=$1;
 

share|improve this answer

answered May 20 at 18:15

Sandro BenevidesSandro Benevides

165

answered May 20 at 18:15

Sandro BenevidesSandro Benevides

165

answered May 20 at 18:15

Sandro BenevidesSandro Benevides

165