How to project 3d image in the planes xy, xz, yz?Sketch-type graphics with transparency and dashed hidden lines?2D projection of a 3D surfaceImage processing, maskingForce change in aspect ratio of Inset imageColor Transfer from colored image into grayscale imageHow can I transfer colors from first image into second image?Coloring image components according to their areaCircular crop: extract non rectangular parts of an imageHow to convert an uploaded image to a “dot-to-dot” puzzle?Estimate the “Blurry” distribution of an imageHow to extract a single image from the output of the DiscreteWaveletTransform[]?How can I crop a 3D object in the format .obj or .noff?
Subtract the Folded Matrix
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How to project 3d image in the planes xy, xz, yz?
Sketch-type graphics with transparency and dashed hidden lines?2D projection of a 3D surfaceImage processing, maskingForce change in aspect ratio of Inset imageColor Transfer from colored image into grayscale imageHow can I transfer colors from first image into second image?Coloring image components according to their areaCircular crop: extract non rectangular parts of an imageHow to convert an uploaded image to a “dot-to-dot” puzzle?Estimate the “Blurry” distribution of an imageHow to extract a single image from the output of the DiscreteWaveletTransform[]?How can I crop a 3D object in the format .obj or .noff?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
Some idea of how to do something similar to the image, but with any 3d object
graphics graphics3d image-processing image image3d
edited Jun 3 at 6:26
user64494
3,96821323
asked Jun 2 at 22:24
zeroszeros
7601613
$endgroup$
add a comment |
$begingroup$
Some idea of how to do something similar to the image, but with any 3d object
graphics graphics3d image-processing image image3d
edited Jun 3 at 6:26
user64494
3,96821323
asked Jun 2 at 22:24
zeroszeros
7601613
$endgroup$
$begingroup$
Possible duplicate: mathematica.stackexchange.com/questions/164663/…. This also seems relevant to the image above, depending on what the dashed lines represent: mathematica.stackexchange.com/questions/45410/…
$endgroup$
– Michael E2
Jun 4 at 0:37
add a comment |
$begingroup$
Some idea of how to do something similar to the image, but with any 3d object
graphics graphics3d image-processing image image3d
edited Jun 3 at 6:26
user64494
3,96821323
asked Jun 2 at 22:24
zeroszeros
7601613
$endgroup$
Some idea of how to do something similar to the image, but with any 3d object
graphics graphics3d image-processing image image3d
graphics graphics3d image-processing image image3d
edited Jun 3 at 6:26
user64494
3,96821323
asked Jun 2 at 22:24
zeroszeros
7601613
edited Jun 3 at 6:26
user64494
3,96821323
asked Jun 2 at 22:24
zeroszeros
7601613
edited Jun 3 at 6:26
user64494
3,96821323
edited Jun 3 at 6:26
user64494
3,96821323
edited Jun 3 at 6:26
user64494
3,96821323
3,96821323
asked Jun 2 at 22:24
zeroszeros
7601613
asked Jun 2 at 22:24
zeroszeros
7601613
asked Jun 2 at 22:24
zeroszeros
7601613
7601613
$begingroup$
Possible duplicate: mathematica.stackexchange.com/questions/164663/…. This also seems relevant to the image above, depending on what the dashed lines represent: mathematica.stackexchange.com/questions/45410/…
$endgroup$
– Michael E2
Jun 4 at 0:37
add a comment |
$begingroup$
Possible duplicate: mathematica.stackexchange.com/questions/164663/…. This also seems relevant to the image above, depending on what the dashed lines represent: mathematica.stackexchange.com/questions/45410/…
$endgroup$
– Michael E2
Jun 4 at 0:37
$begingroup$
Possible duplicate: mathematica.stackexchange.com/questions/164663/…. This also seems relevant to the image above, depending on what the dashed lines represent: mathematica.stackexchange.com/questions/45410/…
$endgroup$
– Michael E2
Jun 4 at 0:37
$begingroup$
Possible duplicate: mathematica.stackexchange.com/questions/164663/…. This also seems relevant to the image above, depending on what the dashed lines represent: mathematica.stackexchange.com/questions/45410/…
$endgroup$
– Michael E2
Jun 4 at 0:37
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
You can post-process a Graphics3D object to project the lines to the left, back and bottom planes using a function like:
ClearAll[projectToWalls]
projectToWalls = Module[pr = PlotRange[#],
Normal[#] /. Line[x_, ___] :>
Line[x], Line[x /. a_, b_, c_ :> pr[[1, 1]], b, c],
Line[x /. a_, b_, c_ :> a, pr[[2, 2]], c],
Line[x /. a_, b_, c_ :> a, b, pr[[3, 1]]]] &;
Examples:
pp1 = ParametricPlot3D[4 + (3 + Cos[v]) Sin[u],
4 + (3 + Cos[v]) Cos[u], 4 + Sin[v], 8 + (3 + Cos[v]) Cos[u],
3 + Sin[v], 4 + (3 + Cos[v]) Sin[u], u, 0, 2 Pi, v, 0, 2 Pi,
PlotStyle -> Red, Green];
projectToWalls @ pp1
projectToWalls @
Graphics3D[White, MeshPrimitives[Tetrahedron[], 1],
MeshPrimitives[Cuboid[0, 1/2, 0], 1],
PlotRange -> -1, 2, -1, 2, -1, 2, Background -> Black]
Update: Taking Roman's idea a step further using Textured polygons:
SeedRandom[1234];
P = Graphics3D[Hue@RandomReal[], # & /@ Cuboid @@@ RandomReal[0, 1, 10, 2, 3]];
pr = PlotRange[P];
rect = #, #2[[1]], #[[-1]], #2, #[[1]], #2[[-1]] & @@ Transpose[pr[[##]]] &;
texturedPoly = Texture[Rasterize[#, Background -> None]],
Polygon[#2, VertexTextureCoordinates -> 0, 0, 1, 0, 1, 1, 0, 1] &;
left, back, bottom = Show[P, ViewPoint -> #, Boxed -> False, Axes -> False,
Lighting -> "Neutral"] & /@ Right, Front, Top;
leftWall = Prepend[#, pr[[1, 1]] - 1] & /@ rect[2, 3];
backWall = Insert[#, pr[[2, 1]] + 2, 2] & /@ rect[1, 3];
bottomWall = Append[#, pr[[3, 1]] - 1] & /@ rect[1, 2];
Graphics3D[Opacity[.2], P[[1]], EdgeForm[None], Opacity[1],
MapThread[texturedPoly, left, back, bottom, leftWall, backWall, bottomWall],
BoxRatios -> 1, PlotRange -> -1, 1.5, -.5, 2.1, -1, 1.5]
answered Jun 2 at 23:50
kglrkglr
199k10226453
$endgroup$
add a comment |
$begingroup$
If you only need the 2D projection images, you can just project the 3D image from the six cardinal directions:
SeedRandom[1234];
P = Graphics3D[RandomColor[], # & /@ Cuboid @@@ RandomReal[0, 1, 10, 2, 3]]
Show[P, ViewPoint -> #] & /@ ∞,0,0, -∞,0,0, 0,∞,0, 0,-∞,0, 0,0,∞, 0,0,-∞
Working with the ViewVertical option might also help.
answered Jun 3 at 6:16
RomanRoman
11.4k11944
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can post-process a Graphics3D object to project the lines to the left, back and bottom planes using a function like:
ClearAll[projectToWalls]
projectToWalls = Module[pr = PlotRange[#],
Normal[#] /. Line[x_, ___] :>
Line[x], Line[x /. a_, b_, c_ :> pr[[1, 1]], b, c],
Line[x /. a_, b_, c_ :> a, pr[[2, 2]], c],
Line[x /. a_, b_, c_ :> a, b, pr[[3, 1]]]] &;
Examples:
pp1 = ParametricPlot3D[4 + (3 + Cos[v]) Sin[u],
4 + (3 + Cos[v]) Cos[u], 4 + Sin[v], 8 + (3 + Cos[v]) Cos[u],
3 + Sin[v], 4 + (3 + Cos[v]) Sin[u], u, 0, 2 Pi, v, 0, 2 Pi,
PlotStyle -> Red, Green];
projectToWalls @ pp1
projectToWalls @
Graphics3D[White, MeshPrimitives[Tetrahedron[], 1],
MeshPrimitives[Cuboid[0, 1/2, 0], 1],
PlotRange -> -1, 2, -1, 2, -1, 2, Background -> Black]
Update: Taking Roman's idea a step further using Textured polygons:
SeedRandom[1234];
P = Graphics3D[Hue@RandomReal[], # & /@ Cuboid @@@ RandomReal[0, 1, 10, 2, 3]];
pr = PlotRange[P];
rect = #, #2[[1]], #[[-1]], #2, #[[1]], #2[[-1]] & @@ Transpose[pr[[##]]] &;
texturedPoly = Texture[Rasterize[#, Background -> None]],
Polygon[#2, VertexTextureCoordinates -> 0, 0, 1, 0, 1, 1, 0, 1] &;
left, back, bottom = Show[P, ViewPoint -> #, Boxed -> False, Axes -> False,
Lighting -> "Neutral"] & /@ Right, Front, Top;
leftWall = Prepend[#, pr[[1, 1]] - 1] & /@ rect[2, 3];
backWall = Insert[#, pr[[2, 1]] + 2, 2] & /@ rect[1, 3];
bottomWall = Append[#, pr[[3, 1]] - 1] & /@ rect[1, 2];
Graphics3D[Opacity[.2], P[[1]], EdgeForm[None], Opacity[1],
MapThread[texturedPoly, left, back, bottom, leftWall, backWall, bottomWall],
BoxRatios -> 1, PlotRange -> -1, 1.5, -.5, 2.1, -1, 1.5]
answered Jun 2 at 23:50
kglrkglr
199k10226453
$endgroup$
add a comment |
$begingroup$
You can post-process a Graphics3D object to project the lines to the left, back and bottom planes using a function like:
ClearAll[projectToWalls]
projectToWalls = Module[pr = PlotRange[#],
Normal[#] /. Line[x_, ___] :>
Line[x], Line[x /. a_, b_, c_ :> pr[[1, 1]], b, c],
Line[x /. a_, b_, c_ :> a, pr[[2, 2]], c],
Line[x /. a_, b_, c_ :> a, b, pr[[3, 1]]]] &;
Examples:
pp1 = ParametricPlot3D[4 + (3 + Cos[v]) Sin[u],
4 + (3 + Cos[v]) Cos[u], 4 + Sin[v], 8 + (3 + Cos[v]) Cos[u],
3 + Sin[v], 4 + (3 + Cos[v]) Sin[u], u, 0, 2 Pi, v, 0, 2 Pi,
PlotStyle -> Red, Green];
projectToWalls @ pp1
projectToWalls @
Graphics3D[White, MeshPrimitives[Tetrahedron[], 1],
MeshPrimitives[Cuboid[0, 1/2, 0], 1],
PlotRange -> -1, 2, -1, 2, -1, 2, Background -> Black]
Update: Taking Roman's idea a step further using Textured polygons:
SeedRandom[1234];
P = Graphics3D[Hue@RandomReal[], # & /@ Cuboid @@@ RandomReal[0, 1, 10, 2, 3]];
pr = PlotRange[P];
rect = #, #2[[1]], #[[-1]], #2, #[[1]], #2[[-1]] & @@ Transpose[pr[[##]]] &;
texturedPoly = Texture[Rasterize[#, Background -> None]],
Polygon[#2, VertexTextureCoordinates -> 0, 0, 1, 0, 1, 1, 0, 1] &;
left, back, bottom = Show[P, ViewPoint -> #, Boxed -> False, Axes -> False,
Lighting -> "Neutral"] & /@ Right, Front, Top;
leftWall = Prepend[#, pr[[1, 1]] - 1] & /@ rect[2, 3];
backWall = Insert[#, pr[[2, 1]] + 2, 2] & /@ rect[1, 3];
bottomWall = Append[#, pr[[3, 1]] - 1] & /@ rect[1, 2];
Graphics3D[Opacity[.2], P[[1]], EdgeForm[None], Opacity[1],
MapThread[texturedPoly, left, back, bottom, leftWall, backWall, bottomWall],
BoxRatios -> 1, PlotRange -> -1, 1.5, -.5, 2.1, -1, 1.5]
answered Jun 2 at 23:50
kglrkglr
199k10226453
$endgroup$
add a comment |
$begingroup$
You can post-process a Graphics3D object to project the lines to the left, back and bottom planes using a function like:
ClearAll[projectToWalls]
projectToWalls = Module[pr = PlotRange[#],
Normal[#] /. Line[x_, ___] :>
Line[x], Line[x /. a_, b_, c_ :> pr[[1, 1]], b, c],
Line[x /. a_, b_, c_ :> a, pr[[2, 2]], c],
Line[x /. a_, b_, c_ :> a, b, pr[[3, 1]]]] &;
Examples:
pp1 = ParametricPlot3D[4 + (3 + Cos[v]) Sin[u],
4 + (3 + Cos[v]) Cos[u], 4 + Sin[v], 8 + (3 + Cos[v]) Cos[u],
3 + Sin[v], 4 + (3 + Cos[v]) Sin[u], u, 0, 2 Pi, v, 0, 2 Pi,
PlotStyle -> Red, Green];
projectToWalls @ pp1
projectToWalls @
Graphics3D[White, MeshPrimitives[Tetrahedron[], 1],
MeshPrimitives[Cuboid[0, 1/2, 0], 1],
PlotRange -> -1, 2, -1, 2, -1, 2, Background -> Black]
Update: Taking Roman's idea a step further using Textured polygons:
SeedRandom[1234];
P = Graphics3D[Hue@RandomReal[], # & /@ Cuboid @@@ RandomReal[0, 1, 10, 2, 3]];
pr = PlotRange[P];
rect = #, #2[[1]], #[[-1]], #2, #[[1]], #2[[-1]] & @@ Transpose[pr[[##]]] &;
texturedPoly = Texture[Rasterize[#, Background -> None]],
Polygon[#2, VertexTextureCoordinates -> 0, 0, 1, 0, 1, 1, 0, 1] &;
left, back, bottom = Show[P, ViewPoint -> #, Boxed -> False, Axes -> False,
Lighting -> "Neutral"] & /@ Right, Front, Top;
leftWall = Prepend[#, pr[[1, 1]] - 1] & /@ rect[2, 3];
backWall = Insert[#, pr[[2, 1]] + 2, 2] & /@ rect[1, 3];
bottomWall = Append[#, pr[[3, 1]] - 1] & /@ rect[1, 2];
Graphics3D[Opacity[.2], P[[1]], EdgeForm[None], Opacity[1],
MapThread[texturedPoly, left, back, bottom, leftWall, backWall, bottomWall],
BoxRatios -> 1, PlotRange -> -1, 1.5, -.5, 2.1, -1, 1.5]
answered Jun 2 at 23:50
kglrkglr
199k10226453
$endgroup$
You can post-process a Graphics3D object to project the lines to the left, back and bottom planes using a function like:
ClearAll[projectToWalls]
projectToWalls = Module[pr = PlotRange[#],
Normal[#] /. Line[x_, ___] :>
Line[x], Line[x /. a_, b_, c_ :> pr[[1, 1]], b, c],
Line[x /. a_, b_, c_ :> a, pr[[2, 2]], c],
Line[x /. a_, b_, c_ :> a, b, pr[[3, 1]]]] &;
Examples:
pp1 = ParametricPlot3D[4 + (3 + Cos[v]) Sin[u],
4 + (3 + Cos[v]) Cos[u], 4 + Sin[v], 8 + (3 + Cos[v]) Cos[u],
3 + Sin[v], 4 + (3 + Cos[v]) Sin[u], u, 0, 2 Pi, v, 0, 2 Pi,
PlotStyle -> Red, Green];
projectToWalls @ pp1
projectToWalls @
Graphics3D[White, MeshPrimitives[Tetrahedron[], 1],
MeshPrimitives[Cuboid[0, 1/2, 0], 1],
PlotRange -> -1, 2, -1, 2, -1, 2, Background -> Black]
Update: Taking Roman's idea a step further using Textured polygons:
SeedRandom[1234];
P = Graphics3D[Hue@RandomReal[], # & /@ Cuboid @@@ RandomReal[0, 1, 10, 2, 3]];
pr = PlotRange[P];
rect = #, #2[[1]], #[[-1]], #2, #[[1]], #2[[-1]] & @@ Transpose[pr[[##]]] &;
texturedPoly = Texture[Rasterize[#, Background -> None]],
Polygon[#2, VertexTextureCoordinates -> 0, 0, 1, 0, 1, 1, 0, 1] &;
left, back, bottom = Show[P, ViewPoint -> #, Boxed -> False, Axes -> False,
Lighting -> "Neutral"] & /@ Right, Front, Top;
leftWall = Prepend[#, pr[[1, 1]] - 1] & /@ rect[2, 3];
backWall = Insert[#, pr[[2, 1]] + 2, 2] & /@ rect[1, 3];
bottomWall = Append[#, pr[[3, 1]] - 1] & /@ rect[1, 2];
Graphics3D[Opacity[.2], P[[1]], EdgeForm[None], Opacity[1],
MapThread[texturedPoly, left, back, bottom, leftWall, backWall, bottomWall],
BoxRatios -> 1, PlotRange -> -1, 1.5, -.5, 2.1, -1, 1.5]
answered Jun 2 at 23:50
kglrkglr
199k10226453
edited Jun 3 at 8:31
answered Jun 2 at 23:50
kglrkglr
199k10226453
answered Jun 2 at 23:50
kglrkglr
199k10226453
answered Jun 2 at 23:50
kglrkglr
199k10226453
199k10226453
add a comment |
add a comment |
$begingroup$
If you only need the 2D projection images, you can just project the 3D image from the six cardinal directions:
SeedRandom[1234];
P = Graphics3D[RandomColor[], # & /@ Cuboid @@@ RandomReal[0, 1, 10, 2, 3]]
Show[P, ViewPoint -> #] & /@ ∞,0,0, -∞,0,0, 0,∞,0, 0,-∞,0, 0,0,∞, 0,0,-∞
Working with the ViewVertical option might also help.
answered Jun 3 at 6:16
RomanRoman
11.4k11944
$endgroup$
add a comment |
$begingroup$
If you only need the 2D projection images, you can just project the 3D image from the six cardinal directions:
SeedRandom[1234];
P = Graphics3D[RandomColor[], # & /@ Cuboid @@@ RandomReal[0, 1, 10, 2, 3]]
Show[P, ViewPoint -> #] & /@ ∞,0,0, -∞,0,0, 0,∞,0, 0,-∞,0, 0,0,∞, 0,0,-∞
Working with the ViewVertical option might also help.
answered Jun 3 at 6:16
RomanRoman
11.4k11944
$endgroup$
add a comment |
$begingroup$
If you only need the 2D projection images, you can just project the 3D image from the six cardinal directions:
SeedRandom[1234];
P = Graphics3D[RandomColor[], # & /@ Cuboid @@@ RandomReal[0, 1, 10, 2, 3]]
Show[P, ViewPoint -> #] & /@ ∞,0,0, -∞,0,0, 0,∞,0, 0,-∞,0, 0,0,∞, 0,0,-∞
Working with the ViewVertical option might also help.
answered Jun 3 at 6:16
RomanRoman
11.4k11944
$endgroup$
If you only need the 2D projection images, you can just project the 3D image from the six cardinal directions:
SeedRandom[1234];
P = Graphics3D[RandomColor[], # & /@ Cuboid @@@ RandomReal[0, 1, 10, 2, 3]]
Show[P, ViewPoint -> #] & /@ ∞,0,0, -∞,0,0, 0,∞,0, 0,-∞,0, 0,0,∞, 0,0,-∞
Working with the ViewVertical option might also help.
answered Jun 3 at 6:16
RomanRoman
11.4k11944
answered Jun 3 at 6:16
RomanRoman
11.4k11944
answered Jun 3 at 6:16
RomanRoman
11.4k11944
answered Jun 3 at 6:16
RomanRoman
11.4k11944
11.4k11944
add a comment |
add a comment |
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$begingroup$
Possible duplicate: mathematica.stackexchange.com/questions/164663/…. This also seems relevant to the image above, depending on what the dashed lines represent: mathematica.stackexchange.com/questions/45410/…
$endgroup$
– Michael E2
Jun 4 at 0:37