I'm thinking of a number Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?systematic number removalWhat is a Voluminous Number™?Ten-digit number that satisfy divisibilty rules for 2,3,4,5,6,7,8,9,10&11What mysterious whole number am I?
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I'm thinking of a number
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?systematic number removalWhat is a Voluminous Number™?Ten-digit number that satisfy divisibilty rules for 2,3,4,5,6,7,8,9,10&11What mysterious whole number am I?
$begingroup$
The unusual thing about this number is that the most common phrases that use it are wrong. That is, while someone may often say there are X As in a B, the actual number is not X.
What number am I thinking of?
Hint 1:
"There are X As in a B", but almost every B contains at least X + 2 As.
Hint 2:
"There are X Cs in a D" but a D always contains between X + 0.1 and X + 0.3 Cs
number-property
asked Apr 14 at 4:13
Rupert MorrishRupert Morrish
3,6851935
$endgroup$
add a comment |
$begingroup$
The unusual thing about this number is that the most common phrases that use it are wrong. That is, while someone may often say there are X As in a B, the actual number is not X.
What number am I thinking of?
Hint 1:
"There are X As in a B", but almost every B contains at least X + 2 As.
Hint 2:
"There are X Cs in a D" but a D always contains between X + 0.1 and X + 0.3 Cs
number-property
asked Apr 14 at 4:13
Rupert MorrishRupert Morrish
3,6851935
$endgroup$
$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
Apr 14 at 18:40
$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
Apr 14 at 20:09
add a comment |
$begingroup$
The unusual thing about this number is that the most common phrases that use it are wrong. That is, while someone may often say there are X As in a B, the actual number is not X.
What number am I thinking of?
Hint 1:
"There are X As in a B", but almost every B contains at least X + 2 As.
Hint 2:
"There are X Cs in a D" but a D always contains between X + 0.1 and X + 0.3 Cs
number-property
asked Apr 14 at 4:13
Rupert MorrishRupert Morrish
3,6851935
$endgroup$
The unusual thing about this number is that the most common phrases that use it are wrong. That is, while someone may often say there are X As in a B, the actual number is not X.
What number am I thinking of?
Hint 1:
"There are X As in a B", but almost every B contains at least X + 2 As.
Hint 2:
"There are X Cs in a D" but a D always contains between X + 0.1 and X + 0.3 Cs
number-property
number-property
asked Apr 14 at 4:13
Rupert MorrishRupert Morrish
3,6851935
asked Apr 14 at 4:13
Rupert MorrishRupert Morrish
3,6851935
asked Apr 14 at 4:13
Rupert MorrishRupert Morrish
3,6851935
asked Apr 14 at 4:13
Rupert MorrishRupert Morrish
3,6851935
asked Apr 14 at 4:13
Rupert MorrishRupert Morrish
3,6851935
3,6851935
$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
Apr 14 at 18:40
$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
Apr 14 at 20:09
add a comment |
$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
Apr 14 at 18:40
$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
Apr 14 at 20:09
$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
Apr 14 at 18:40
$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
Apr 14 at 18:40
$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
Apr 14 at 20:09
$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
Apr 14 at 20:09
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
A number which fits is
$52$
Hint 1:
There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.
Hint 2:
It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
$365/7 approx 52.14...$ and $366/7 approx 52.28...$
answered Apr 14 at 5:42
TomTom
36.5k3132209
$endgroup$
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
A number which fits is
$52$
Hint 1:
There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.
Hint 2:
It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
$365/7 approx 52.14...$ and $366/7 approx 52.28...$
answered Apr 14 at 5:42
TomTom
36.5k3132209
$endgroup$
add a comment |
$begingroup$
A number which fits is
$52$
Hint 1:
There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.
Hint 2:
It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
$365/7 approx 52.14...$ and $366/7 approx 52.28...$
answered Apr 14 at 5:42
TomTom
36.5k3132209
$endgroup$
add a comment |
$begingroup$
A number which fits is
$52$
Hint 1:
There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.
Hint 2:
It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
$365/7 approx 52.14...$ and $366/7 approx 52.28...$
answered Apr 14 at 5:42
TomTom
36.5k3132209
$endgroup$
A number which fits is
$52$
Hint 1:
There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.
Hint 2:
It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
$365/7 approx 52.14...$ and $366/7 approx 52.28...$
answered Apr 14 at 5:42
TomTom
36.5k3132209
answered Apr 14 at 5:42
TomTom
36.5k3132209
answered Apr 14 at 5:42
TomTom
36.5k3132209
answered Apr 14 at 5:42
TomTom
36.5k3132209
36.5k3132209
add a comment |
add a comment |
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9wDUyQpFqSQRU,fqx5CJmO0H38HgJn8 UeSJ,lv5GA,JD0l6POy,KaguIbdIk6PaVQ 3Uqr Lgu0Dnv O w,np,86YO,oyJtOarKTsi bg
$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
Apr 14 at 18:40
$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
Apr 14 at 20:09