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get a specific line from in linux using grep
The Next CEO of Stack OverflowGet results from grep in the order they appear?Grep a word from a filehow to grep out a particular line from a fileGetting the last match in a file using grepHow to define mail from and host settings in Websphere 6.1 for Java applicationGet some meaning from apache logs with awk and grepGrep regex Stdout to telnetPass parameter from Local to Sudo userGrep --only-match without new lineGrep last match from file
Hello I am new to linux and grep and awk commands.
I am trying to get the number value from this string variable and then store it in another variable.
var1="Version must be incremented on update. Current version is: 532"
var2=var1 | grep "?"
What should I do in order to only retrieve val 532 from the above string and store it in var2
unix shell shell-scripting grep awk
asked 18 hours ago
jamesorcjamesorc
182
add a comment |
Hello I am new to linux and grep and awk commands.
I am trying to get the number value from this string variable and then store it in another variable.
var1="Version must be incremented on update. Current version is: 532"
var2=var1 | grep "?"
What should I do in order to only retrieve val 532 from the above string and store it in var2
unix shell shell-scripting grep awk
asked 18 hours ago
jamesorcjamesorc
182
add a comment |
Hello I am new to linux and grep and awk commands.
I am trying to get the number value from this string variable and then store it in another variable.
var1="Version must be incremented on update. Current version is: 532"
var2=var1 | grep "?"
What should I do in order to only retrieve val 532 from the above string and store it in var2
unix shell shell-scripting grep awk
asked 18 hours ago
jamesorcjamesorc
182
Hello I am new to linux and grep and awk commands.
I am trying to get the number value from this string variable and then store it in another variable.
var1="Version must be incremented on update. Current version is: 532"
var2=var1 | grep "?"
What should I do in order to only retrieve val 532 from the above string and store it in var2
unix shell shell-scripting grep awk
unix shell shell-scripting grep awk
asked 18 hours ago
jamesorcjamesorc
182
asked 18 hours ago
jamesorcjamesorc
182
asked 18 hours ago
jamesorcjamesorc
182
asked 18 hours ago
jamesorcjamesorc
182
asked 18 hours ago
jamesorcjamesorc
182
182
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You need $var1 to reference it, rather than var1. You need to echo it so that Bash won't try to run it as a program. You should put double-quotes around it as well.
For grep, you need a regular expression to match the numbers, lots of patterns might work but I'm using "one or more digits, at the end of the string", and you need the grep option -o to print only the matching text, instead of the whole line.
Run this inside $() to stop the shell trying to run the result as a program, and your code looks like this:
var1="Version must be incremented on update. Current version is: 532"
var2=$(echo "$var1" | grep '[0-9]+$' -o)
echo "$var2"
# 532
answered 17 hours ago
TessellatingHecklerTessellatingHeckler
5,24432039
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You need $var1 to reference it, rather than var1. You need to echo it so that Bash won't try to run it as a program. You should put double-quotes around it as well.
For grep, you need a regular expression to match the numbers, lots of patterns might work but I'm using "one or more digits, at the end of the string", and you need the grep option -o to print only the matching text, instead of the whole line.
Run this inside $() to stop the shell trying to run the result as a program, and your code looks like this:
var1="Version must be incremented on update. Current version is: 532"
var2=$(echo "$var1" | grep '[0-9]+$' -o)
echo "$var2"
# 532
answered 17 hours ago
TessellatingHecklerTessellatingHeckler
5,24432039
add a comment |
You need $var1 to reference it, rather than var1. You need to echo it so that Bash won't try to run it as a program. You should put double-quotes around it as well.
For grep, you need a regular expression to match the numbers, lots of patterns might work but I'm using "one or more digits, at the end of the string", and you need the grep option -o to print only the matching text, instead of the whole line.
Run this inside $() to stop the shell trying to run the result as a program, and your code looks like this:
var1="Version must be incremented on update. Current version is: 532"
var2=$(echo "$var1" | grep '[0-9]+$' -o)
echo "$var2"
# 532
answered 17 hours ago
TessellatingHecklerTessellatingHeckler
5,24432039
add a comment |
You need $var1 to reference it, rather than var1. You need to echo it so that Bash won't try to run it as a program. You should put double-quotes around it as well.
For grep, you need a regular expression to match the numbers, lots of patterns might work but I'm using "one or more digits, at the end of the string", and you need the grep option -o to print only the matching text, instead of the whole line.
Run this inside $() to stop the shell trying to run the result as a program, and your code looks like this:
var1="Version must be incremented on update. Current version is: 532"
var2=$(echo "$var1" | grep '[0-9]+$' -o)
echo "$var2"
# 532
answered 17 hours ago
TessellatingHecklerTessellatingHeckler
5,24432039
You need $var1 to reference it, rather than var1. You need to echo it so that Bash won't try to run it as a program. You should put double-quotes around it as well.
For grep, you need a regular expression to match the numbers, lots of patterns might work but I'm using "one or more digits, at the end of the string", and you need the grep option -o to print only the matching text, instead of the whole line.
Run this inside $() to stop the shell trying to run the result as a program, and your code looks like this:
var1="Version must be incremented on update. Current version is: 532"
var2=$(echo "$var1" | grep '[0-9]+$' -o)
echo "$var2"
# 532
answered 17 hours ago
TessellatingHecklerTessellatingHeckler
5,24432039
answered 17 hours ago
TessellatingHecklerTessellatingHeckler
5,24432039
answered 17 hours ago
TessellatingHecklerTessellatingHeckler
5,24432039
answered 17 hours ago
TessellatingHecklerTessellatingHeckler
5,24432039
5,24432039
add a comment |
add a comment |
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