Deleting files older than 30 days based on filename as dateRemove files older than 5 days in UNIX (date in file name, not timestamp)Deleting many files except one typeBatch rename image files by age plus add date and variable to filenamefind and delete files older than specific days and have specific string in filenamesCommand that deletes all old files, folders and sub-foldersDelete sub-directories with YYYYMMDD in name older than N dayssynchronise with remote machine via http, and delete older filesMove files that have the same case-insensitive filenameFind and delete folders within directory that are older than x daysCopy files according the filename containing a future date in a specific format

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Deleting files older than 30 days based on filename as date


Remove files older than 5 days in UNIX (date in file name, not timestamp)Deleting many files except one typeBatch rename image files by age plus add date and variable to filenamefind and delete files older than specific days and have specific string in filenamesCommand that deletes all old files, folders and sub-foldersDelete sub-directories with YYYYMMDD in name older than N dayssynchronise with remote machine via http, and delete older filesMove files that have the same case-insensitive filenameFind and delete folders within directory that are older than x daysCopy files according the filename containing a future date in a specific format






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3















If I have a folder of files with their filenames as the date they were created:



2019_04_30.txt
2019_04_15.txt
2019_04_10.txt
2019_02_20.txt
2019_01_05.txt


How would I compare the files names against todays current date



$ date "+%Y_%m_%d"
>>> 2019_04_30


If the file names date is greater than 30 days then delete it. I would expect to end up with



2019_04_30.txt
2019_04_15.txt
2019_04_10.txt


I don't have to follow this naming convention, I could use a more suitable date format.










share|improve this question
























  • You can use YYYY-MM-DD for your filenames, it would help when using "date" functions then

    – darxmurf
    Apr 30 at 11:09

















3















If I have a folder of files with their filenames as the date they were created:



2019_04_30.txt
2019_04_15.txt
2019_04_10.txt
2019_02_20.txt
2019_01_05.txt


How would I compare the files names against todays current date



$ date "+%Y_%m_%d"
>>> 2019_04_30


If the file names date is greater than 30 days then delete it. I would expect to end up with



2019_04_30.txt
2019_04_15.txt
2019_04_10.txt


I don't have to follow this naming convention, I could use a more suitable date format.










share|improve this question
























  • You can use YYYY-MM-DD for your filenames, it would help when using "date" functions then

    – darxmurf
    Apr 30 at 11:09













3












3








3


1






If I have a folder of files with their filenames as the date they were created:



2019_04_30.txt
2019_04_15.txt
2019_04_10.txt
2019_02_20.txt
2019_01_05.txt


How would I compare the files names against todays current date



$ date "+%Y_%m_%d"
>>> 2019_04_30


If the file names date is greater than 30 days then delete it. I would expect to end up with



2019_04_30.txt
2019_04_15.txt
2019_04_10.txt


I don't have to follow this naming convention, I could use a more suitable date format.










share|improve this question
















If I have a folder of files with their filenames as the date they were created:



2019_04_30.txt
2019_04_15.txt
2019_04_10.txt
2019_02_20.txt
2019_01_05.txt


How would I compare the files names against todays current date



$ date "+%Y_%m_%d"
>>> 2019_04_30


If the file names date is greater than 30 days then delete it. I would expect to end up with



2019_04_30.txt
2019_04_15.txt
2019_04_10.txt


I don't have to follow this naming convention, I could use a more suitable date format.







linux bash filenames date rm






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Apr 30 at 14:01









Rui F Ribeiro

42.7k1486146




42.7k1486146










asked Apr 30 at 10:50









Ari VictorAri Victor

1504




1504












  • You can use YYYY-MM-DD for your filenames, it would help when using "date" functions then

    – darxmurf
    Apr 30 at 11:09

















  • You can use YYYY-MM-DD for your filenames, it would help when using "date" functions then

    – darxmurf
    Apr 30 at 11:09
















You can use YYYY-MM-DD for your filenames, it would help when using "date" functions then

– darxmurf
Apr 30 at 11:09





You can use YYYY-MM-DD for your filenames, it would help when using "date" functions then

– darxmurf
Apr 30 at 11:09










2 Answers
2






active

oldest

votes


















4














Here is a bash solution.



f30days=$(date +%s --date="-30 days")
for file in 20*.txt; do
fdate=$(echo $file | tr _ -)
fsec=$(date +%s --date=$fdate/.txt/)
if [[ $fsec -lt $f30days ]]; then
echo "rm $file"
fi
done


I ended it with "echo rm $file" instead of really deleting your files, this will test the result before.






share|improve this answer
































    4














    With zsh:



    zmodload zsh/datetime
    strftime -s start '%Y_%m_%d.txt' $((EPOCHSECONDS - 30*86400))
    echo -E rm -i 2*.txt(e:'[[ $REPLY > $start ]]':)


    Remove the echo -E when happy.



    On a GNU system and with the GNU shell (bash), you could do something approaching with:



    start=$(date -d '30 days ago' +%Y_%m_%d.txt)
    list=()
    shopt -s nullglob
    for file in 2*.txt; do
    [[ $file > $start ]] && list+=("$file")
    done
    if (( $#list[@] > 0)); then
    echo -E rm -i "$list[@]"
    fi





    share|improve this answer

























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      4














      Here is a bash solution.



      f30days=$(date +%s --date="-30 days")
      for file in 20*.txt; do
      fdate=$(echo $file | tr _ -)
      fsec=$(date +%s --date=$fdate/.txt/)
      if [[ $fsec -lt $f30days ]]; then
      echo "rm $file"
      fi
      done


      I ended it with "echo rm $file" instead of really deleting your files, this will test the result before.






      share|improve this answer





























        4














        Here is a bash solution.



        f30days=$(date +%s --date="-30 days")
        for file in 20*.txt; do
        fdate=$(echo $file | tr _ -)
        fsec=$(date +%s --date=$fdate/.txt/)
        if [[ $fsec -lt $f30days ]]; then
        echo "rm $file"
        fi
        done


        I ended it with "echo rm $file" instead of really deleting your files, this will test the result before.






        share|improve this answer



























          4












          4








          4







          Here is a bash solution.



          f30days=$(date +%s --date="-30 days")
          for file in 20*.txt; do
          fdate=$(echo $file | tr _ -)
          fsec=$(date +%s --date=$fdate/.txt/)
          if [[ $fsec -lt $f30days ]]; then
          echo "rm $file"
          fi
          done


          I ended it with "echo rm $file" instead of really deleting your files, this will test the result before.






          share|improve this answer















          Here is a bash solution.



          f30days=$(date +%s --date="-30 days")
          for file in 20*.txt; do
          fdate=$(echo $file | tr _ -)
          fsec=$(date +%s --date=$fdate/.txt/)
          if [[ $fsec -lt $f30days ]]; then
          echo "rm $file"
          fi
          done


          I ended it with "echo rm $file" instead of really deleting your files, this will test the result before.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Apr 30 at 14:27









          αғsнιη

          18k103271




          18k103271










          answered Apr 30 at 11:07









          darxmurfdarxmurf

          42411




          42411























              4














              With zsh:



              zmodload zsh/datetime
              strftime -s start '%Y_%m_%d.txt' $((EPOCHSECONDS - 30*86400))
              echo -E rm -i 2*.txt(e:'[[ $REPLY > $start ]]':)


              Remove the echo -E when happy.



              On a GNU system and with the GNU shell (bash), you could do something approaching with:



              start=$(date -d '30 days ago' +%Y_%m_%d.txt)
              list=()
              shopt -s nullglob
              for file in 2*.txt; do
              [[ $file > $start ]] && list+=("$file")
              done
              if (( $#list[@] > 0)); then
              echo -E rm -i "$list[@]"
              fi





              share|improve this answer





























                4














                With zsh:



                zmodload zsh/datetime
                strftime -s start '%Y_%m_%d.txt' $((EPOCHSECONDS - 30*86400))
                echo -E rm -i 2*.txt(e:'[[ $REPLY > $start ]]':)


                Remove the echo -E when happy.



                On a GNU system and with the GNU shell (bash), you could do something approaching with:



                start=$(date -d '30 days ago' +%Y_%m_%d.txt)
                list=()
                shopt -s nullglob
                for file in 2*.txt; do
                [[ $file > $start ]] && list+=("$file")
                done
                if (( $#list[@] > 0)); then
                echo -E rm -i "$list[@]"
                fi





                share|improve this answer



























                  4












                  4








                  4







                  With zsh:



                  zmodload zsh/datetime
                  strftime -s start '%Y_%m_%d.txt' $((EPOCHSECONDS - 30*86400))
                  echo -E rm -i 2*.txt(e:'[[ $REPLY > $start ]]':)


                  Remove the echo -E when happy.



                  On a GNU system and with the GNU shell (bash), you could do something approaching with:



                  start=$(date -d '30 days ago' +%Y_%m_%d.txt)
                  list=()
                  shopt -s nullglob
                  for file in 2*.txt; do
                  [[ $file > $start ]] && list+=("$file")
                  done
                  if (( $#list[@] > 0)); then
                  echo -E rm -i "$list[@]"
                  fi





                  share|improve this answer















                  With zsh:



                  zmodload zsh/datetime
                  strftime -s start '%Y_%m_%d.txt' $((EPOCHSECONDS - 30*86400))
                  echo -E rm -i 2*.txt(e:'[[ $REPLY > $start ]]':)


                  Remove the echo -E when happy.



                  On a GNU system and with the GNU shell (bash), you could do something approaching with:



                  start=$(date -d '30 days ago' +%Y_%m_%d.txt)
                  list=()
                  shopt -s nullglob
                  for file in 2*.txt; do
                  [[ $file > $start ]] && list+=("$file")
                  done
                  if (( $#list[@] > 0)); then
                  echo -E rm -i "$list[@]"
                  fi






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Apr 30 at 20:17

























                  answered Apr 30 at 11:52









                  Stéphane ChazelasStéphane Chazelas

                  317k57602964




                  317k57602964



























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