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Double line is displayed as a rectangle [duplicate]
Unwanted faint lines connecting dashed double lineTikZ: Intersection point with a double-line pathTwo problems with double lines in TikZRotate a node but not its content: the case of the ellipse decorationHow to define the default vertical distance between nodes?Numerical conditional within tikz keys?Tikzpicture: Line break in node label to rightWhy do I get an extra white page before my TikZ picture?TikZ: Drawing an arc from an intersection to an intersectionDrawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themHow to draw a square and its diagonals with arrows?beginfigure… endfigure is not working with tikz package
This question already has an answer here:
Unwanted faint lines connecting dashed double line
1 answer
MWE:
documentclassarticle
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node (x) X;
node[above right=1mm and 2mm of x] (y) Y;
draw[double,double distance=2mm] (x) -- (y);
endtikzpicture
enddocument
How to remove the thin lines?
tikz-pgf
asked May 13 at 14:33
bodqhrohrobodqhrohro
25516
marked as duplicate by The old JouleV, Stefan Pinnow, Phelype Oleinik, Raaja, siracusa May 13 at 18:15
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
Unwanted faint lines connecting dashed double line
1 answer
MWE:
documentclassarticle
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node (x) X;
node[above right=1mm and 2mm of x] (y) Y;
draw[double,double distance=2mm] (x) -- (y);
endtikzpicture
enddocument
How to remove the thin lines?
tikz-pgf
asked May 13 at 14:33
bodqhrohrobodqhrohro
25516
marked as duplicate by The old JouleV, Stefan Pinnow, Phelype Oleinik, Raaja, siracusa May 13 at 18:15
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
See the answer of this question for instance.
– marmot
May 13 at 14:38
Or this one may even be simpler.
– marmot
May 13 at 14:41
add a comment |
This question already has an answer here:
Unwanted faint lines connecting dashed double line
1 answer
MWE:
documentclassarticle
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node (x) X;
node[above right=1mm and 2mm of x] (y) Y;
draw[double,double distance=2mm] (x) -- (y);
endtikzpicture
enddocument
How to remove the thin lines?
tikz-pgf
asked May 13 at 14:33
bodqhrohrobodqhrohro
25516
This question already has an answer here:
Unwanted faint lines connecting dashed double line
1 answer
MWE:
documentclassarticle
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node (x) X;
node[above right=1mm and 2mm of x] (y) Y;
draw[double,double distance=2mm] (x) -- (y);
endtikzpicture
enddocument
How to remove the thin lines?
This question already has an answer here:
Unwanted faint lines connecting dashed double line
1 answer
tikz-pgf
tikz-pgf
asked May 13 at 14:33
bodqhrohrobodqhrohro
25516
asked May 13 at 14:33
bodqhrohrobodqhrohro
25516
asked May 13 at 14:33
bodqhrohrobodqhrohro
25516
asked May 13 at 14:33
bodqhrohrobodqhrohro
25516
asked May 13 at 14:33
bodqhrohrobodqhrohro
25516
25516
marked as duplicate by The old JouleV, Stefan Pinnow, Phelype Oleinik, Raaja, siracusa May 13 at 18:15
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by The old JouleV, Stefan Pinnow, Phelype Oleinik, Raaja, siracusa May 13 at 18:15
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
See the answer of this question for instance.
– marmot
May 13 at 14:38
Or this one may even be simpler.
– marmot
May 13 at 14:41
add a comment |
See the answer of this question for instance.
– marmot
May 13 at 14:38
Or this one may even be simpler.
– marmot
May 13 at 14:41
See the answer of this question for instance.
– marmot
May 13 at 14:38
See the answer of this question for instance.
– marmot
May 13 at 14:38
Or this one may even be simpler.
– marmot
May 13 at 14:41
Or this one may even be simpler.
– marmot
May 13 at 14:41
add a comment |
2 Answers
2
active
oldest
votes
Although I voted to close your question as duplicate (sorry), this is a different approach which give you a real, literal equal sign.
documentclassarticle
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node (x) $X$;
node[above right=1mm and 2mm of x] (y) $Y$;
path (x) -- (y) node[midway,sloped] $=$;
endtikzpicture
enddocument
answered May 13 at 14:45
The old JouleVThe old JouleV
19.5k33175
add a comment |
Since this is a repeating question, here is a decoration that draws the double as two paths rather than a thick line with a white line on top, which is why you get the thin lines on the ends (for certain viewers, I think). The syntax is as simple as
draw[alt double,alt double distance=2mm] (x) -- (y);
and also works for curved lines, see
draw[alt double,alt double distance=2mm] (y) to[out=90,in=180] (z);
Here is the code.
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarydecorations,positioning
pgfkeys/tikz/.cd,
alt double distance/.initial=5pt,
alt double step/.initial=1pt,
pgfdeclaredecorationdouble decoinitial
% initial arrow butt
stateinitial[width=pgfkeysvalueof/tikz/alt double step,next state=cont]
pgfmovetopgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfpathlinetopgfpoint0.3pgflinewidthpgfkeysvalueof/tikz/alt double distance/2
pgfpathmovetopgfpoint0.3pgflinewidth-pgfkeysvalueof/tikz/alt double distance/2
pgfpathlinetopgfpoint1pt-pgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastuppgfpoint1ptpgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastdownpgfpoint1pt-pgfkeysvalueof/tikz/alt double distance/2
statecont[width=pgfkeysvalueof/tikz/alt double step]
pgfmovetopgfpointanchorlastupcenter
pgfpathlinetopgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastuppgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfmovetopgfpointanchorlastdowncenter
pgfpathlinetopgfpointpgfkeysvalueof/tikz/alt double step-pgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastdownpgfpointpgfkeysvalueof/tikz/alt double step-pgfkeysvalueof/tikz/alt double distance/2
statefinal[width=0pt]
% perhaps unnecessary but doesn't hurt either
pgfmovetopgfpointdecoratedpathlast
tikzsetalt double/.style=decorate,decoration=double deco
begindocument
begintikzpicture
node (x) X;
node[above right=1mm and 2mm of x] (y) Y;
draw[alt double,alt double distance=2mm] (x) -- (y);
node[above right=1cm and 2cm of y] (z) Z;
draw[alt double,alt double distance=2mm] (y) to[out=90,in=180] (z);
endtikzpicture
enddocument
Using this decoration should also allow one to compute intersections with the double line.
answered May 13 at 15:05
marmotmarmot
130k6164312
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Although I voted to close your question as duplicate (sorry), this is a different approach which give you a real, literal equal sign.
documentclassarticle
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node (x) $X$;
node[above right=1mm and 2mm of x] (y) $Y$;
path (x) -- (y) node[midway,sloped] $=$;
endtikzpicture
enddocument
answered May 13 at 14:45
The old JouleVThe old JouleV
19.5k33175
add a comment |
Although I voted to close your question as duplicate (sorry), this is a different approach which give you a real, literal equal sign.
documentclassarticle
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node (x) $X$;
node[above right=1mm and 2mm of x] (y) $Y$;
path (x) -- (y) node[midway,sloped] $=$;
endtikzpicture
enddocument
answered May 13 at 14:45
The old JouleVThe old JouleV
19.5k33175
add a comment |
Although I voted to close your question as duplicate (sorry), this is a different approach which give you a real, literal equal sign.
documentclassarticle
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node (x) $X$;
node[above right=1mm and 2mm of x] (y) $Y$;
path (x) -- (y) node[midway,sloped] $=$;
endtikzpicture
enddocument
answered May 13 at 14:45
The old JouleVThe old JouleV
19.5k33175
Although I voted to close your question as duplicate (sorry), this is a different approach which give you a real, literal equal sign.
documentclassarticle
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node (x) $X$;
node[above right=1mm and 2mm of x] (y) $Y$;
path (x) -- (y) node[midway,sloped] $=$;
endtikzpicture
enddocument
answered May 13 at 14:45
The old JouleVThe old JouleV
19.5k33175
answered May 13 at 14:45
The old JouleVThe old JouleV
19.5k33175
answered May 13 at 14:45
The old JouleVThe old JouleV
19.5k33175
answered May 13 at 14:45
The old JouleVThe old JouleV
19.5k33175
19.5k33175
add a comment |
add a comment |
Since this is a repeating question, here is a decoration that draws the double as two paths rather than a thick line with a white line on top, which is why you get the thin lines on the ends (for certain viewers, I think). The syntax is as simple as
draw[alt double,alt double distance=2mm] (x) -- (y);
and also works for curved lines, see
draw[alt double,alt double distance=2mm] (y) to[out=90,in=180] (z);
Here is the code.
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarydecorations,positioning
pgfkeys/tikz/.cd,
alt double distance/.initial=5pt,
alt double step/.initial=1pt,
pgfdeclaredecorationdouble decoinitial
% initial arrow butt
stateinitial[width=pgfkeysvalueof/tikz/alt double step,next state=cont]
pgfmovetopgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfpathlinetopgfpoint0.3pgflinewidthpgfkeysvalueof/tikz/alt double distance/2
pgfpathmovetopgfpoint0.3pgflinewidth-pgfkeysvalueof/tikz/alt double distance/2
pgfpathlinetopgfpoint1pt-pgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastuppgfpoint1ptpgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastdownpgfpoint1pt-pgfkeysvalueof/tikz/alt double distance/2
statecont[width=pgfkeysvalueof/tikz/alt double step]
pgfmovetopgfpointanchorlastupcenter
pgfpathlinetopgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastuppgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfmovetopgfpointanchorlastdowncenter
pgfpathlinetopgfpointpgfkeysvalueof/tikz/alt double step-pgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastdownpgfpointpgfkeysvalueof/tikz/alt double step-pgfkeysvalueof/tikz/alt double distance/2
statefinal[width=0pt]
% perhaps unnecessary but doesn't hurt either
pgfmovetopgfpointdecoratedpathlast
tikzsetalt double/.style=decorate,decoration=double deco
begindocument
begintikzpicture
node (x) X;
node[above right=1mm and 2mm of x] (y) Y;
draw[alt double,alt double distance=2mm] (x) -- (y);
node[above right=1cm and 2cm of y] (z) Z;
draw[alt double,alt double distance=2mm] (y) to[out=90,in=180] (z);
endtikzpicture
enddocument
Using this decoration should also allow one to compute intersections with the double line.
answered May 13 at 15:05
marmotmarmot
130k6164312
add a comment |
Since this is a repeating question, here is a decoration that draws the double as two paths rather than a thick line with a white line on top, which is why you get the thin lines on the ends (for certain viewers, I think). The syntax is as simple as
draw[alt double,alt double distance=2mm] (x) -- (y);
and also works for curved lines, see
draw[alt double,alt double distance=2mm] (y) to[out=90,in=180] (z);
Here is the code.
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarydecorations,positioning
pgfkeys/tikz/.cd,
alt double distance/.initial=5pt,
alt double step/.initial=1pt,
pgfdeclaredecorationdouble decoinitial
% initial arrow butt
stateinitial[width=pgfkeysvalueof/tikz/alt double step,next state=cont]
pgfmovetopgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfpathlinetopgfpoint0.3pgflinewidthpgfkeysvalueof/tikz/alt double distance/2
pgfpathmovetopgfpoint0.3pgflinewidth-pgfkeysvalueof/tikz/alt double distance/2
pgfpathlinetopgfpoint1pt-pgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastuppgfpoint1ptpgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastdownpgfpoint1pt-pgfkeysvalueof/tikz/alt double distance/2
statecont[width=pgfkeysvalueof/tikz/alt double step]
pgfmovetopgfpointanchorlastupcenter
pgfpathlinetopgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastuppgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfmovetopgfpointanchorlastdowncenter
pgfpathlinetopgfpointpgfkeysvalueof/tikz/alt double step-pgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastdownpgfpointpgfkeysvalueof/tikz/alt double step-pgfkeysvalueof/tikz/alt double distance/2
statefinal[width=0pt]
% perhaps unnecessary but doesn't hurt either
pgfmovetopgfpointdecoratedpathlast
tikzsetalt double/.style=decorate,decoration=double deco
begindocument
begintikzpicture
node (x) X;
node[above right=1mm and 2mm of x] (y) Y;
draw[alt double,alt double distance=2mm] (x) -- (y);
node[above right=1cm and 2cm of y] (z) Z;
draw[alt double,alt double distance=2mm] (y) to[out=90,in=180] (z);
endtikzpicture
enddocument
Using this decoration should also allow one to compute intersections with the double line.
answered May 13 at 15:05
marmotmarmot
130k6164312
add a comment |
Since this is a repeating question, here is a decoration that draws the double as two paths rather than a thick line with a white line on top, which is why you get the thin lines on the ends (for certain viewers, I think). The syntax is as simple as
draw[alt double,alt double distance=2mm] (x) -- (y);
and also works for curved lines, see
draw[alt double,alt double distance=2mm] (y) to[out=90,in=180] (z);
Here is the code.
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarydecorations,positioning
pgfkeys/tikz/.cd,
alt double distance/.initial=5pt,
alt double step/.initial=1pt,
pgfdeclaredecorationdouble decoinitial
% initial arrow butt
stateinitial[width=pgfkeysvalueof/tikz/alt double step,next state=cont]
pgfmovetopgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfpathlinetopgfpoint0.3pgflinewidthpgfkeysvalueof/tikz/alt double distance/2
pgfpathmovetopgfpoint0.3pgflinewidth-pgfkeysvalueof/tikz/alt double distance/2
pgfpathlinetopgfpoint1pt-pgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastuppgfpoint1ptpgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastdownpgfpoint1pt-pgfkeysvalueof/tikz/alt double distance/2
statecont[width=pgfkeysvalueof/tikz/alt double step]
pgfmovetopgfpointanchorlastupcenter
pgfpathlinetopgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastuppgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfmovetopgfpointanchorlastdowncenter
pgfpathlinetopgfpointpgfkeysvalueof/tikz/alt double step-pgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastdownpgfpointpgfkeysvalueof/tikz/alt double step-pgfkeysvalueof/tikz/alt double distance/2
statefinal[width=0pt]
% perhaps unnecessary but doesn't hurt either
pgfmovetopgfpointdecoratedpathlast
tikzsetalt double/.style=decorate,decoration=double deco
begindocument
begintikzpicture
node (x) X;
node[above right=1mm and 2mm of x] (y) Y;
draw[alt double,alt double distance=2mm] (x) -- (y);
node[above right=1cm and 2cm of y] (z) Z;
draw[alt double,alt double distance=2mm] (y) to[out=90,in=180] (z);
endtikzpicture
enddocument
Using this decoration should also allow one to compute intersections with the double line.
answered May 13 at 15:05
marmotmarmot
130k6164312
Since this is a repeating question, here is a decoration that draws the double as two paths rather than a thick line with a white line on top, which is why you get the thin lines on the ends (for certain viewers, I think). The syntax is as simple as
draw[alt double,alt double distance=2mm] (x) -- (y);
and also works for curved lines, see
draw[alt double,alt double distance=2mm] (y) to[out=90,in=180] (z);
Here is the code.
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarydecorations,positioning
pgfkeys/tikz/.cd,
alt double distance/.initial=5pt,
alt double step/.initial=1pt,
pgfdeclaredecorationdouble decoinitial
% initial arrow butt
stateinitial[width=pgfkeysvalueof/tikz/alt double step,next state=cont]
pgfmovetopgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfpathlinetopgfpoint0.3pgflinewidthpgfkeysvalueof/tikz/alt double distance/2
pgfpathmovetopgfpoint0.3pgflinewidth-pgfkeysvalueof/tikz/alt double distance/2
pgfpathlinetopgfpoint1pt-pgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastuppgfpoint1ptpgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastdownpgfpoint1pt-pgfkeysvalueof/tikz/alt double distance/2
statecont[width=pgfkeysvalueof/tikz/alt double step]
pgfmovetopgfpointanchorlastupcenter
pgfpathlinetopgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastuppgfpointpgfkeysvalueof/tikz/alt double steppgfkeysvalueof/tikz/alt double distance/2
pgfmovetopgfpointanchorlastdowncenter
pgfpathlinetopgfpointpgfkeysvalueof/tikz/alt double step-pgfkeysvalueof/tikz/alt double distance/2
pgfcoordinatelastdownpgfpointpgfkeysvalueof/tikz/alt double step-pgfkeysvalueof/tikz/alt double distance/2
statefinal[width=0pt]
% perhaps unnecessary but doesn't hurt either
pgfmovetopgfpointdecoratedpathlast
tikzsetalt double/.style=decorate,decoration=double deco
begindocument
begintikzpicture
node (x) X;
node[above right=1mm and 2mm of x] (y) Y;
draw[alt double,alt double distance=2mm] (x) -- (y);
node[above right=1cm and 2cm of y] (z) Z;
draw[alt double,alt double distance=2mm] (y) to[out=90,in=180] (z);
endtikzpicture
enddocument
Using this decoration should also allow one to compute intersections with the double line.
answered May 13 at 15:05
marmotmarmot
130k6164312
answered May 13 at 15:05
marmotmarmot
130k6164312
answered May 13 at 15:05
marmotmarmot
130k6164312
answered May 13 at 15:05
marmotmarmot
130k6164312
130k6164312
add a comment |
add a comment |
See the answer of this question for instance.
– marmot
May 13 at 14:38
Or this one may even be simpler.
– marmot
May 13 at 14:41