How do I reduce spacing between 2 segments of a line in a multiple alignment environment?Multiple alignmentLeft aligning equations without align characterAlignment in an alignat environmentMultiple alignment in align environmentAlignment and line breaking in alignment environmentMultiple = alignmentAlignment within enumerate environment and mhchemHow to fix multiple alignmentCentering between alignment charactersUnsuitable multiple alignment
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How do I reduce spacing between 2 segments of a line in a multiple alignment environment?
Multiple alignmentLeft aligning equations without align characterAlignment in an alignat environmentMultiple alignment in align environmentAlignment and line breaking in alignment environmentMultiple = alignmentAlignment within enumerate environment and mhchemHow to fix multiple alignmentCentering between alignment charactersUnsuitable multiple alignment
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
Currently, there is a large gap between the 2 segments of a line, causing its index to be pushed to the following line. How can I prevent this?
documentclassarticle
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&therefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat2
enddocument
align indexing alignment mhchem alignat
add a comment |
Currently, there is a large gap between the 2 segments of a line, causing its index to be pushed to the following line. How can I prevent this?
documentclassarticle
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&therefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat2
enddocument
align indexing alignment mhchem alignat
you could just add in preamble usepackagefullpage
– KJO
Jun 10 at 1:52
1
Other typography issues: Write phyical units (kJ) upright and separated by a space.H_f(C_2H6)^0
is wrong on several levels: subscript f should be upright, subscript formula should be upright (usece
), superscript is not a 0, butcirc
. IUPAC recommendation (Green Book) is to writeDelta_mathrmfH^circ (ceC2H6)
. Lastly, are you sure about your calculation? Unit of standard enthalpy is not kJ.
– mhchem
Jun 10 at 5:48
add a comment |
Currently, there is a large gap between the 2 segments of a line, causing its index to be pushed to the following line. How can I prevent this?
documentclassarticle
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&therefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat2
enddocument
align indexing alignment mhchem alignat
Currently, there is a large gap between the 2 segments of a line, causing its index to be pushed to the following line. How can I prevent this?
documentclassarticle
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&therefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat2
enddocument
align indexing alignment mhchem alignat
align indexing alignment mhchem alignat
edited Jun 10 at 1:52
Steven B. Segletes
167k9 gold badges210 silver badges428 bronze badges
167k9 gold badges210 silver badges428 bronze badges
asked Jun 10 at 1:20
David LuDavid Lu
161 bronze badge
161 bronze badge
you could just add in preamble usepackagefullpage
– KJO
Jun 10 at 1:52
1
Other typography issues: Write phyical units (kJ) upright and separated by a space.H_f(C_2H6)^0
is wrong on several levels: subscript f should be upright, subscript formula should be upright (usece
), superscript is not a 0, butcirc
. IUPAC recommendation (Green Book) is to writeDelta_mathrmfH^circ (ceC2H6)
. Lastly, are you sure about your calculation? Unit of standard enthalpy is not kJ.
– mhchem
Jun 10 at 5:48
add a comment |
you could just add in preamble usepackagefullpage
– KJO
Jun 10 at 1:52
1
Other typography issues: Write phyical units (kJ) upright and separated by a space.H_f(C_2H6)^0
is wrong on several levels: subscript f should be upright, subscript formula should be upright (usece
), superscript is not a 0, butcirc
. IUPAC recommendation (Green Book) is to writeDelta_mathrmfH^circ (ceC2H6)
. Lastly, are you sure about your calculation? Unit of standard enthalpy is not kJ.
– mhchem
Jun 10 at 5:48
you could just add in preamble usepackagefullpage
– KJO
Jun 10 at 1:52
you could just add in preamble usepackagefullpage
– KJO
Jun 10 at 1:52
1
1
Other typography issues: Write phyical units (kJ) upright and separated by a space.
H_f(C_2H6)^0
is wrong on several levels: subscript f should be upright, subscript formula should be upright (use ce
), superscript is not a 0, but circ
. IUPAC recommendation (Green Book) is to write Delta_mathrmfH^circ (ceC2H6)
. Lastly, are you sure about your calculation? Unit of standard enthalpy is not kJ.– mhchem
Jun 10 at 5:48
Other typography issues: Write phyical units (kJ) upright and separated by a space.
H_f(C_2H6)^0
is wrong on several levels: subscript f should be upright, subscript formula should be upright (use ce
), superscript is not a 0, but circ
. IUPAC recommendation (Green Book) is to write Delta_mathrmfH^circ (ceC2H6)
. Lastly, are you sure about your calculation? Unit of standard enthalpy is not kJ.– mhchem
Jun 10 at 5:48
add a comment |
4 Answers
4
active
oldest
votes
Here, I use mathllap
on the last line. But as you can see, there is still one remaining margin issue that you need to consider.
Also, the endalignat
does not take an argument.
documentclassarticle
usepackage[pass,showframe]geometry
usepackagemathtools
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&mathllaptherefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat
enddocument
You could try to break up the remaining long line, but there may be other approaches, too...
I also made your kJ
units upright, though, as marmot points out, the siunitx
package is tailor made for applying units to quantities.
documentclassarticle
usepackage[pass,showframe]geometry
usepackagemathtools
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 mathrm,kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 mathrm,kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 mathrm,kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858\nonumber&&&phantom=+1560\
nonumber & &&= -84 mathrm,kJ \
nonumber &&mathllaptherefore Delta H_f(C_2H6)^0 &= -84mathrm,kJ
endalignat
enddocument
You need anothernonumber
in the second iteration; the last equation isn't numbered in the original.
– barbara beeton
Jun 10 at 2:25
2
Wouldn't that be a nice opportunity to advertizesiunitx
forkJ
?
– marmot
Jun 10 at 2:34
Thank you, @barbarabeeton
– Steven B. Segletes
Jun 10 at 3:19
2
RegardingH_f(C_2H6)^0
part: a. According to IUPAC, standard state should be denoted with either a superscript circle (^circ
) or a superscript Plimsoll symbol (^⦵
+ xelatex compiler), not a zero; b. subscriptf
("formation") should be upright, e.g.mathrmf
; c. It would be nice to fix typesetting for ethane (proper indices and upright font), e.g. withceC2H6
. I also agree with @marmot that usingsiunitx
would make the answer look more professional.
– andselisk
Jun 10 at 4:00
add a comment |
Use of fullpage style (must be the shortest CTAN manual that nobody reads :-)
you could just add in preamble
usepackagefullpage
documentclassarticle
usepackagefullpage
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&therefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat
enddocument
add a comment |
This does steal a bit of the left margin, if that is not acceptable I think you would need to wrap the final term over two lines.
documentclassarticle
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g)%Underfull hbox (badness 10000) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumberhspace*-250ptce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &therefore& Delta H_f(C_2H6)^0 &= -84kJ
endalignat2
enddocument
Note I moved the therefore
back a bit so it's not so cramped (and so the display is a bit narrower and requires less overhang). Also never use \
before a display.
Hi, can you elaborate a little bit on what you meant when you said "never use \ before a display"? Was there an extra \ in my document where there shouldn't have been one?
– David Lu
Jun 12 at 5:00
1
@DavidLu yes latex must have screamed badness 10000 at you:-) (that is it's maximum level in its assessment of the poor quality of the output), the\
beforebeginalignat
on the first line afterC2H6(g)}
is wrong.
– David Carlisle
Jun 12 at 13:05
add a comment |
If you have space constraints, you can use more lines:
documentclassarticle
usepackageamsmath
usepackageamssymb
usepackage[version=4]mhchem
usepackagesiunitx
newcommandmove[2]hspace#1makebox[0pt][r]$displaystyle#2$
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g), in units~sikilojoule
beginalign
ce2C(s) + 2O2(g) &-> 2CO2(g) \
nonumber &move6emDelta H = -786 \
ce3H2(g) + 3/2 O2(g) &-> H2O(l) \
nonumber & move6emDelta H = -858 \
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) \
nonumber & move6emDelta H = 1560 \
ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) \
nonumber & move6emDelta H = -786-858+1560\
nonumber & move6em = -84 \
nonumber & move6emtherefore Delta H_f(ceC_2H6)^0 = SI-84kilojoule
endalign
enddocument
add a comment |
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4 Answers
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active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here, I use mathllap
on the last line. But as you can see, there is still one remaining margin issue that you need to consider.
Also, the endalignat
does not take an argument.
documentclassarticle
usepackage[pass,showframe]geometry
usepackagemathtools
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&mathllaptherefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat
enddocument
You could try to break up the remaining long line, but there may be other approaches, too...
I also made your kJ
units upright, though, as marmot points out, the siunitx
package is tailor made for applying units to quantities.
documentclassarticle
usepackage[pass,showframe]geometry
usepackagemathtools
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 mathrm,kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 mathrm,kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 mathrm,kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858\nonumber&&&phantom=+1560\
nonumber & &&= -84 mathrm,kJ \
nonumber &&mathllaptherefore Delta H_f(C_2H6)^0 &= -84mathrm,kJ
endalignat
enddocument
You need anothernonumber
in the second iteration; the last equation isn't numbered in the original.
– barbara beeton
Jun 10 at 2:25
2
Wouldn't that be a nice opportunity to advertizesiunitx
forkJ
?
– marmot
Jun 10 at 2:34
Thank you, @barbarabeeton
– Steven B. Segletes
Jun 10 at 3:19
2
RegardingH_f(C_2H6)^0
part: a. According to IUPAC, standard state should be denoted with either a superscript circle (^circ
) or a superscript Plimsoll symbol (^⦵
+ xelatex compiler), not a zero; b. subscriptf
("formation") should be upright, e.g.mathrmf
; c. It would be nice to fix typesetting for ethane (proper indices and upright font), e.g. withceC2H6
. I also agree with @marmot that usingsiunitx
would make the answer look more professional.
– andselisk
Jun 10 at 4:00
add a comment |
Here, I use mathllap
on the last line. But as you can see, there is still one remaining margin issue that you need to consider.
Also, the endalignat
does not take an argument.
documentclassarticle
usepackage[pass,showframe]geometry
usepackagemathtools
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&mathllaptherefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat
enddocument
You could try to break up the remaining long line, but there may be other approaches, too...
I also made your kJ
units upright, though, as marmot points out, the siunitx
package is tailor made for applying units to quantities.
documentclassarticle
usepackage[pass,showframe]geometry
usepackagemathtools
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 mathrm,kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 mathrm,kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 mathrm,kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858\nonumber&&&phantom=+1560\
nonumber & &&= -84 mathrm,kJ \
nonumber &&mathllaptherefore Delta H_f(C_2H6)^0 &= -84mathrm,kJ
endalignat
enddocument
You need anothernonumber
in the second iteration; the last equation isn't numbered in the original.
– barbara beeton
Jun 10 at 2:25
2
Wouldn't that be a nice opportunity to advertizesiunitx
forkJ
?
– marmot
Jun 10 at 2:34
Thank you, @barbarabeeton
– Steven B. Segletes
Jun 10 at 3:19
2
RegardingH_f(C_2H6)^0
part: a. According to IUPAC, standard state should be denoted with either a superscript circle (^circ
) or a superscript Plimsoll symbol (^⦵
+ xelatex compiler), not a zero; b. subscriptf
("formation") should be upright, e.g.mathrmf
; c. It would be nice to fix typesetting for ethane (proper indices and upright font), e.g. withceC2H6
. I also agree with @marmot that usingsiunitx
would make the answer look more professional.
– andselisk
Jun 10 at 4:00
add a comment |
Here, I use mathllap
on the last line. But as you can see, there is still one remaining margin issue that you need to consider.
Also, the endalignat
does not take an argument.
documentclassarticle
usepackage[pass,showframe]geometry
usepackagemathtools
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&mathllaptherefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat
enddocument
You could try to break up the remaining long line, but there may be other approaches, too...
I also made your kJ
units upright, though, as marmot points out, the siunitx
package is tailor made for applying units to quantities.
documentclassarticle
usepackage[pass,showframe]geometry
usepackagemathtools
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 mathrm,kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 mathrm,kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 mathrm,kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858\nonumber&&&phantom=+1560\
nonumber & &&= -84 mathrm,kJ \
nonumber &&mathllaptherefore Delta H_f(C_2H6)^0 &= -84mathrm,kJ
endalignat
enddocument
Here, I use mathllap
on the last line. But as you can see, there is still one remaining margin issue that you need to consider.
Also, the endalignat
does not take an argument.
documentclassarticle
usepackage[pass,showframe]geometry
usepackagemathtools
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&mathllaptherefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat
enddocument
You could try to break up the remaining long line, but there may be other approaches, too...
I also made your kJ
units upright, though, as marmot points out, the siunitx
package is tailor made for applying units to quantities.
documentclassarticle
usepackage[pass,showframe]geometry
usepackagemathtools
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 mathrm,kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 mathrm,kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 mathrm,kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858\nonumber&&&phantom=+1560\
nonumber & &&= -84 mathrm,kJ \
nonumber &&mathllaptherefore Delta H_f(C_2H6)^0 &= -84mathrm,kJ
endalignat
enddocument
edited Jun 10 at 3:19
answered Jun 10 at 1:50
Steven B. SegletesSteven B. Segletes
167k9 gold badges210 silver badges428 bronze badges
167k9 gold badges210 silver badges428 bronze badges
You need anothernonumber
in the second iteration; the last equation isn't numbered in the original.
– barbara beeton
Jun 10 at 2:25
2
Wouldn't that be a nice opportunity to advertizesiunitx
forkJ
?
– marmot
Jun 10 at 2:34
Thank you, @barbarabeeton
– Steven B. Segletes
Jun 10 at 3:19
2
RegardingH_f(C_2H6)^0
part: a. According to IUPAC, standard state should be denoted with either a superscript circle (^circ
) or a superscript Plimsoll symbol (^⦵
+ xelatex compiler), not a zero; b. subscriptf
("formation") should be upright, e.g.mathrmf
; c. It would be nice to fix typesetting for ethane (proper indices and upright font), e.g. withceC2H6
. I also agree with @marmot that usingsiunitx
would make the answer look more professional.
– andselisk
Jun 10 at 4:00
add a comment |
You need anothernonumber
in the second iteration; the last equation isn't numbered in the original.
– barbara beeton
Jun 10 at 2:25
2
Wouldn't that be a nice opportunity to advertizesiunitx
forkJ
?
– marmot
Jun 10 at 2:34
Thank you, @barbarabeeton
– Steven B. Segletes
Jun 10 at 3:19
2
RegardingH_f(C_2H6)^0
part: a. According to IUPAC, standard state should be denoted with either a superscript circle (^circ
) or a superscript Plimsoll symbol (^⦵
+ xelatex compiler), not a zero; b. subscriptf
("formation") should be upright, e.g.mathrmf
; c. It would be nice to fix typesetting for ethane (proper indices and upright font), e.g. withceC2H6
. I also agree with @marmot that usingsiunitx
would make the answer look more professional.
– andselisk
Jun 10 at 4:00
You need another
nonumber
in the second iteration; the last equation isn't numbered in the original.– barbara beeton
Jun 10 at 2:25
You need another
nonumber
in the second iteration; the last equation isn't numbered in the original.– barbara beeton
Jun 10 at 2:25
2
2
Wouldn't that be a nice opportunity to advertize
siunitx
for kJ
?– marmot
Jun 10 at 2:34
Wouldn't that be a nice opportunity to advertize
siunitx
for kJ
?– marmot
Jun 10 at 2:34
Thank you, @barbarabeeton
– Steven B. Segletes
Jun 10 at 3:19
Thank you, @barbarabeeton
– Steven B. Segletes
Jun 10 at 3:19
2
2
Regarding
H_f(C_2H6)^0
part: a. According to IUPAC, standard state should be denoted with either a superscript circle (^circ
) or a superscript Plimsoll symbol (^⦵
+ xelatex compiler), not a zero; b. subscript f
("formation") should be upright, e.g. mathrmf
; c. It would be nice to fix typesetting for ethane (proper indices and upright font), e.g. with ceC2H6
. I also agree with @marmot that using siunitx
would make the answer look more professional.– andselisk
Jun 10 at 4:00
Regarding
H_f(C_2H6)^0
part: a. According to IUPAC, standard state should be denoted with either a superscript circle (^circ
) or a superscript Plimsoll symbol (^⦵
+ xelatex compiler), not a zero; b. subscript f
("formation") should be upright, e.g. mathrmf
; c. It would be nice to fix typesetting for ethane (proper indices and upright font), e.g. with ceC2H6
. I also agree with @marmot that using siunitx
would make the answer look more professional.– andselisk
Jun 10 at 4:00
add a comment |
Use of fullpage style (must be the shortest CTAN manual that nobody reads :-)
you could just add in preamble
usepackagefullpage
documentclassarticle
usepackagefullpage
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&therefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat
enddocument
add a comment |
Use of fullpage style (must be the shortest CTAN manual that nobody reads :-)
you could just add in preamble
usepackagefullpage
documentclassarticle
usepackagefullpage
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&therefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat
enddocument
add a comment |
Use of fullpage style (must be the shortest CTAN manual that nobody reads :-)
you could just add in preamble
usepackagefullpage
documentclassarticle
usepackagefullpage
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&therefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat
enddocument
Use of fullpage style (must be the shortest CTAN manual that nobody reads :-)
you could just add in preamble
usepackagefullpage
documentclassarticle
usepackagefullpage
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumber ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &indent Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &&therefore Delta H_f(C_2H6)^0 &= -84kJ
endalignat
enddocument
edited Jun 10 at 2:19
answered Jun 10 at 2:10
KJOKJO
5,9051 gold badge4 silver badges28 bronze badges
5,9051 gold badge4 silver badges28 bronze badges
add a comment |
add a comment |
This does steal a bit of the left margin, if that is not acceptable I think you would need to wrap the final term over two lines.
documentclassarticle
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g)%Underfull hbox (badness 10000) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumberhspace*-250ptce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &therefore& Delta H_f(C_2H6)^0 &= -84kJ
endalignat2
enddocument
Note I moved the therefore
back a bit so it's not so cramped (and so the display is a bit narrower and requires less overhang). Also never use \
before a display.
Hi, can you elaborate a little bit on what you meant when you said "never use \ before a display"? Was there an extra \ in my document where there shouldn't have been one?
– David Lu
Jun 12 at 5:00
1
@DavidLu yes latex must have screamed badness 10000 at you:-) (that is it's maximum level in its assessment of the poor quality of the output), the\
beforebeginalignat
on the first line afterC2H6(g)}
is wrong.
– David Carlisle
Jun 12 at 13:05
add a comment |
This does steal a bit of the left margin, if that is not acceptable I think you would need to wrap the final term over two lines.
documentclassarticle
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g)%Underfull hbox (badness 10000) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumberhspace*-250ptce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &therefore& Delta H_f(C_2H6)^0 &= -84kJ
endalignat2
enddocument
Note I moved the therefore
back a bit so it's not so cramped (and so the display is a bit narrower and requires less overhang). Also never use \
before a display.
Hi, can you elaborate a little bit on what you meant when you said "never use \ before a display"? Was there an extra \ in my document where there shouldn't have been one?
– David Lu
Jun 12 at 5:00
1
@DavidLu yes latex must have screamed badness 10000 at you:-) (that is it's maximum level in its assessment of the poor quality of the output), the\
beforebeginalignat
on the first line afterC2H6(g)}
is wrong.
– David Carlisle
Jun 12 at 13:05
add a comment |
This does steal a bit of the left margin, if that is not acceptable I think you would need to wrap the final term over two lines.
documentclassarticle
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g)%Underfull hbox (badness 10000) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumberhspace*-250ptce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &therefore& Delta H_f(C_2H6)^0 &= -84kJ
endalignat2
enddocument
Note I moved the therefore
back a bit so it's not so cramped (and so the display is a bit narrower and requires less overhang). Also never use \
before a display.
This does steal a bit of the left margin, if that is not acceptable I think you would need to wrap the final term over two lines.
documentclassarticle
usepackageamsmath
usepackagemhchem
usepackageamssymb
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g)%Underfull hbox (badness 10000) \
beginalignat2
ce2C(s) + 2O2(g) &-> 2CO2(g) &Delta H &= -786 kJ\
ce3H2(g) + 3/2 O2(g) &-> H2O(l) &Delta H &= -858 kJ\
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) &Delta H &= 1560 kJ\
nonumberhspace*-250ptce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) &Delta H &= -786-858+1560\
nonumber & &&= -84 kJ \
nonumber &therefore& Delta H_f(C_2H6)^0 &= -84kJ
endalignat2
enddocument
Note I moved the therefore
back a bit so it's not so cramped (and so the display is a bit narrower and requires less overhang). Also never use \
before a display.
answered Jun 10 at 15:46
David CarlisleDavid Carlisle
512k43 gold badges1163 silver badges1925 bronze badges
512k43 gold badges1163 silver badges1925 bronze badges
Hi, can you elaborate a little bit on what you meant when you said "never use \ before a display"? Was there an extra \ in my document where there shouldn't have been one?
– David Lu
Jun 12 at 5:00
1
@DavidLu yes latex must have screamed badness 10000 at you:-) (that is it's maximum level in its assessment of the poor quality of the output), the\
beforebeginalignat
on the first line afterC2H6(g)}
is wrong.
– David Carlisle
Jun 12 at 13:05
add a comment |
Hi, can you elaborate a little bit on what you meant when you said "never use \ before a display"? Was there an extra \ in my document where there shouldn't have been one?
– David Lu
Jun 12 at 5:00
1
@DavidLu yes latex must have screamed badness 10000 at you:-) (that is it's maximum level in its assessment of the poor quality of the output), the\
beforebeginalignat
on the first line afterC2H6(g)}
is wrong.
– David Carlisle
Jun 12 at 13:05
Hi, can you elaborate a little bit on what you meant when you said "never use \ before a display"? Was there an extra \ in my document where there shouldn't have been one?
– David Lu
Jun 12 at 5:00
Hi, can you elaborate a little bit on what you meant when you said "never use \ before a display"? Was there an extra \ in my document where there shouldn't have been one?
– David Lu
Jun 12 at 5:00
1
1
@DavidLu yes latex must have screamed badness 10000 at you:-) (that is it's maximum level in its assessment of the poor quality of the output), the
\
before beginalignat
on the first line after C2H6(g)}
is wrong.– David Carlisle
Jun 12 at 13:05
@DavidLu yes latex must have screamed badness 10000 at you:-) (that is it's maximum level in its assessment of the poor quality of the output), the
\
before beginalignat
on the first line after C2H6(g)}
is wrong.– David Carlisle
Jun 12 at 13:05
add a comment |
If you have space constraints, you can use more lines:
documentclassarticle
usepackageamsmath
usepackageamssymb
usepackage[version=4]mhchem
usepackagesiunitx
newcommandmove[2]hspace#1makebox[0pt][r]$displaystyle#2$
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g), in units~sikilojoule
beginalign
ce2C(s) + 2O2(g) &-> 2CO2(g) \
nonumber &move6emDelta H = -786 \
ce3H2(g) + 3/2 O2(g) &-> H2O(l) \
nonumber & move6emDelta H = -858 \
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) \
nonumber & move6emDelta H = 1560 \
ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) \
nonumber & move6emDelta H = -786-858+1560\
nonumber & move6em = -84 \
nonumber & move6emtherefore Delta H_f(ceC_2H6)^0 = SI-84kilojoule
endalign
enddocument
add a comment |
If you have space constraints, you can use more lines:
documentclassarticle
usepackageamsmath
usepackageamssymb
usepackage[version=4]mhchem
usepackagesiunitx
newcommandmove[2]hspace#1makebox[0pt][r]$displaystyle#2$
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g), in units~sikilojoule
beginalign
ce2C(s) + 2O2(g) &-> 2CO2(g) \
nonumber &move6emDelta H = -786 \
ce3H2(g) + 3/2 O2(g) &-> H2O(l) \
nonumber & move6emDelta H = -858 \
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) \
nonumber & move6emDelta H = 1560 \
ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) \
nonumber & move6emDelta H = -786-858+1560\
nonumber & move6em = -84 \
nonumber & move6emtherefore Delta H_f(ceC_2H6)^0 = SI-84kilojoule
endalign
enddocument
add a comment |
If you have space constraints, you can use more lines:
documentclassarticle
usepackageamsmath
usepackageamssymb
usepackage[version=4]mhchem
usepackagesiunitx
newcommandmove[2]hspace#1makebox[0pt][r]$displaystyle#2$
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g), in units~sikilojoule
beginalign
ce2C(s) + 2O2(g) &-> 2CO2(g) \
nonumber &move6emDelta H = -786 \
ce3H2(g) + 3/2 O2(g) &-> H2O(l) \
nonumber & move6emDelta H = -858 \
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) \
nonumber & move6emDelta H = 1560 \
ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) \
nonumber & move6emDelta H = -786-858+1560\
nonumber & move6em = -84 \
nonumber & move6emtherefore Delta H_f(ceC_2H6)^0 = SI-84kilojoule
endalign
enddocument
If you have space constraints, you can use more lines:
documentclassarticle
usepackageamsmath
usepackageamssymb
usepackage[version=4]mhchem
usepackagesiunitx
newcommandmove[2]hspace#1makebox[0pt][r]$displaystyle#2$
begindocument
Overall formation of ethane thingy: ce2 C(s) + 3 H2(g) -> C2H6(g), in units~sikilojoule
beginalign
ce2C(s) + 2O2(g) &-> 2CO2(g) \
nonumber &move6emDelta H = -786 \
ce3H2(g) + 3/2 O2(g) &-> H2O(l) \
nonumber & move6emDelta H = -858 \
ce2 CO2(g) + 3 H2O(l) &-> C2H6(g) + 7/2 O2 (g) \
nonumber & move6emDelta H = 1560 \
ce2 C(s) + 3 H2(g) + 7/2 O2(g) &-> C2H6(g) + 7/2 O2(g) \
nonumber & move6emDelta H = -786-858+1560\
nonumber & move6em = -84 \
nonumber & move6emtherefore Delta H_f(ceC_2H6)^0 = SI-84kilojoule
endalign
enddocument
answered Jun 10 at 16:29
egregegreg
750k89 gold badges1964 silver badges3306 bronze badges
750k89 gold badges1964 silver badges3306 bronze badges
add a comment |
add a comment |
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you could just add in preamble usepackagefullpage
– KJO
Jun 10 at 1:52
1
Other typography issues: Write phyical units (kJ) upright and separated by a space.
H_f(C_2H6)^0
is wrong on several levels: subscript f should be upright, subscript formula should be upright (usece
), superscript is not a 0, butcirc
. IUPAC recommendation (Green Book) is to writeDelta_mathrmfH^circ (ceC2H6)
. Lastly, are you sure about your calculation? Unit of standard enthalpy is not kJ.– mhchem
Jun 10 at 5:48