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Asymptote: 3d graph over a disc
Squiggly line in AsymptoteDrawing a surface over a nonrectangular domain in asymptotetransparency groups in asymptoteCropping 3D Graphs in AsymptoteAsymptote: have stuff outside the box3D Vector Fields in AsymptoteExport asymptote 3D arrowsUnderbrace in asymptoteproblems with labelpath asymptoteTikZ Arrowheads for Asymptote
Is there a straightforward way to draw a 3D graph over a disc domain? Say
z=x^2-y^2 for x^2+y^2<1.
[I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]
graphs asymptote
asked yesterday
Anton PetruninAnton Petrunin
542313
add a comment |
Is there a straightforward way to draw a 3D graph over a disc domain? Say
z=x^2-y^2 for x^2+y^2<1.
[I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]
graphs asymptote
asked yesterday
Anton PetruninAnton Petrunin
542313
add a comment |
Is there a straightforward way to draw a 3D graph over a disc domain? Say
z=x^2-y^2 for x^2+y^2<1.
[I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]
graphs asymptote
asked yesterday
Anton PetruninAnton Petrunin
542313
Is there a straightforward way to draw a 3D graph over a disc domain? Say
z=x^2-y^2 for x^2+y^2<1.
[I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]
graphs asymptote
graphs asymptote
asked yesterday
Anton PetruninAnton Petrunin
542313
asked yesterday
Anton PetruninAnton Petrunin
542313
asked yesterday
Anton PetruninAnton Petrunin
542313
asked yesterday
Anton PetruninAnton Petrunin
542313
asked yesterday
Anton PetruninAnton Petrunin
542313
542313
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).
documentclass[variwidth,border=3.14mm]standalone
usepackageasypictureB
begindocument
beginasypicturename=discgraph
usepackage("mathrsfs");
import graph3;
import solids;
import interpolate;
settings.outformat="pdf";
size(500);
defaultpen(0.5mm);
pen darkgreen=rgb(0,138/255,122/255);
draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);
draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);
draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);
//function: call the radial coordinate r=t.x and the angle phi=t.y
triple f(pair t)
return ((t.x)*cos(t.y), (t.x)*sin(t.y),
((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);
surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,
usplinetype=new splinetype[] notaknot,notaknot,monotonic,
vsplinetype=Spline);
pen p=rgb(0,0,.7);
draw(s,lightolive+white);
endasypicture
enddocument
answered yesterday
marmotmarmot
114k5145276
Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?
– Anton Petrunin
yesterday
@marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?
– Marian G.
yesterday
2
A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...
– O.G.
yesterday
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).
documentclass[variwidth,border=3.14mm]standalone
usepackageasypictureB
begindocument
beginasypicturename=discgraph
usepackage("mathrsfs");
import graph3;
import solids;
import interpolate;
settings.outformat="pdf";
size(500);
defaultpen(0.5mm);
pen darkgreen=rgb(0,138/255,122/255);
draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);
draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);
draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);
//function: call the radial coordinate r=t.x and the angle phi=t.y
triple f(pair t)
return ((t.x)*cos(t.y), (t.x)*sin(t.y),
((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);
surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,
usplinetype=new splinetype[] notaknot,notaknot,monotonic,
vsplinetype=Spline);
pen p=rgb(0,0,.7);
draw(s,lightolive+white);
endasypicture
enddocument
answered yesterday
marmotmarmot
114k5145276
Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?
– Anton Petrunin
yesterday
@marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?
– Marian G.
yesterday
2
A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...
– O.G.
yesterday
add a comment |
One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).
documentclass[variwidth,border=3.14mm]standalone
usepackageasypictureB
begindocument
beginasypicturename=discgraph
usepackage("mathrsfs");
import graph3;
import solids;
import interpolate;
settings.outformat="pdf";
size(500);
defaultpen(0.5mm);
pen darkgreen=rgb(0,138/255,122/255);
draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);
draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);
draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);
//function: call the radial coordinate r=t.x and the angle phi=t.y
triple f(pair t)
return ((t.x)*cos(t.y), (t.x)*sin(t.y),
((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);
surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,
usplinetype=new splinetype[] notaknot,notaknot,monotonic,
vsplinetype=Spline);
pen p=rgb(0,0,.7);
draw(s,lightolive+white);
endasypicture
enddocument
answered yesterday
marmotmarmot
114k5145276
Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?
– Anton Petrunin
yesterday
@marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?
– Marian G.
yesterday
2
A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...
– O.G.
yesterday
add a comment |
One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).
documentclass[variwidth,border=3.14mm]standalone
usepackageasypictureB
begindocument
beginasypicturename=discgraph
usepackage("mathrsfs");
import graph3;
import solids;
import interpolate;
settings.outformat="pdf";
size(500);
defaultpen(0.5mm);
pen darkgreen=rgb(0,138/255,122/255);
draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);
draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);
draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);
//function: call the radial coordinate r=t.x and the angle phi=t.y
triple f(pair t)
return ((t.x)*cos(t.y), (t.x)*sin(t.y),
((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);
surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,
usplinetype=new splinetype[] notaknot,notaknot,monotonic,
vsplinetype=Spline);
pen p=rgb(0,0,.7);
draw(s,lightolive+white);
endasypicture
enddocument
answered yesterday
marmotmarmot
114k5145276
One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).
documentclass[variwidth,border=3.14mm]standalone
usepackageasypictureB
begindocument
beginasypicturename=discgraph
usepackage("mathrsfs");
import graph3;
import solids;
import interpolate;
settings.outformat="pdf";
size(500);
defaultpen(0.5mm);
pen darkgreen=rgb(0,138/255,122/255);
draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);
draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);
draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);
//function: call the radial coordinate r=t.x and the angle phi=t.y
triple f(pair t)
return ((t.x)*cos(t.y), (t.x)*sin(t.y),
((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);
surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,
usplinetype=new splinetype[] notaknot,notaknot,monotonic,
vsplinetype=Spline);
pen p=rgb(0,0,.7);
draw(s,lightolive+white);
endasypicture
enddocument
answered yesterday
marmotmarmot
114k5145276
answered yesterday
marmotmarmot
114k5145276
answered yesterday
marmotmarmot
114k5145276
answered yesterday
marmotmarmot
114k5145276
114k5145276
Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?
– Anton Petrunin
yesterday
@marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?
– Marian G.
yesterday
2
A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...
– O.G.
yesterday
add a comment |
Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?
– Anton Petrunin
yesterday
@marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?
– Marian G.
yesterday
2
A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...
– O.G.
yesterday
Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?
– Anton Petrunin
yesterday
Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?
– Anton Petrunin
yesterday
@marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?
– Marian G.
yesterday
@marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?
– Marian G.
yesterday
2
2
A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...
– O.G.
yesterday
A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...
– O.G.
yesterday
add a comment |
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