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Asymptote: 3d graph over a disc


Squiggly line in AsymptoteDrawing a surface over a nonrectangular domain in asymptotetransparency groups in asymptoteCropping 3D Graphs in AsymptoteAsymptote: have stuff outside the box3D Vector Fields in AsymptoteExport asymptote 3D arrowsUnderbrace in asymptoteproblems with labelpath asymptoteTikZ Arrowheads for Asymptote













5















Is there a straightforward way to draw a 3D graph over a disc domain? Say
z=x^2-y^2 for x^2+y^2<1.



[I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]










share|improve this question


























    5















    Is there a straightforward way to draw a 3D graph over a disc domain? Say
    z=x^2-y^2 for x^2+y^2<1.



    [I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]










    share|improve this question
























      5












      5








      5








      Is there a straightforward way to draw a 3D graph over a disc domain? Say
      z=x^2-y^2 for x^2+y^2<1.



      [I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]










      share|improve this question














      Is there a straightforward way to draw a 3D graph over a disc domain? Say
      z=x^2-y^2 for x^2+y^2<1.



      [I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]







      graphs asymptote






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked yesterday









      Anton PetruninAnton Petrunin

      542313




      542313




















          1 Answer
          1






          active

          oldest

          votes


















          5














          One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).



          documentclass[variwidth,border=3.14mm]standalone
          usepackageasypictureB
          begindocument
          beginasypicturename=discgraph
          usepackage("mathrsfs");
          import graph3;
          import solids;
          import interpolate;

          settings.outformat="pdf";


          size(500);

          defaultpen(0.5mm);
          pen darkgreen=rgb(0,138/255,122/255);

          draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);
          draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);
          draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);



          //function: call the radial coordinate r=t.x and the angle phi=t.y
          triple f(pair t)
          return ((t.x)*cos(t.y), (t.x)*sin(t.y),
          ((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);


          surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,
          usplinetype=new splinetype[] notaknot,notaknot,monotonic,
          vsplinetype=Spline);
          pen p=rgb(0,0,.7);
          draw(s,lightolive+white);
          endasypicture
          enddocument


          enter image description here






          share|improve this answer























          • Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?

            – Anton Petrunin
            yesterday











          • @marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?

            – Marian G.
            yesterday






          • 2





            A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...

            – O.G.
            yesterday











          Your Answer








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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          5














          One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).



          documentclass[variwidth,border=3.14mm]standalone
          usepackageasypictureB
          begindocument
          beginasypicturename=discgraph
          usepackage("mathrsfs");
          import graph3;
          import solids;
          import interpolate;

          settings.outformat="pdf";


          size(500);

          defaultpen(0.5mm);
          pen darkgreen=rgb(0,138/255,122/255);

          draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);
          draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);
          draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);



          //function: call the radial coordinate r=t.x and the angle phi=t.y
          triple f(pair t)
          return ((t.x)*cos(t.y), (t.x)*sin(t.y),
          ((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);


          surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,
          usplinetype=new splinetype[] notaknot,notaknot,monotonic,
          vsplinetype=Spline);
          pen p=rgb(0,0,.7);
          draw(s,lightolive+white);
          endasypicture
          enddocument


          enter image description here






          share|improve this answer























          • Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?

            – Anton Petrunin
            yesterday











          • @marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?

            – Marian G.
            yesterday






          • 2





            A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...

            – O.G.
            yesterday















          5














          One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).



          documentclass[variwidth,border=3.14mm]standalone
          usepackageasypictureB
          begindocument
          beginasypicturename=discgraph
          usepackage("mathrsfs");
          import graph3;
          import solids;
          import interpolate;

          settings.outformat="pdf";


          size(500);

          defaultpen(0.5mm);
          pen darkgreen=rgb(0,138/255,122/255);

          draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);
          draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);
          draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);



          //function: call the radial coordinate r=t.x and the angle phi=t.y
          triple f(pair t)
          return ((t.x)*cos(t.y), (t.x)*sin(t.y),
          ((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);


          surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,
          usplinetype=new splinetype[] notaknot,notaknot,monotonic,
          vsplinetype=Spline);
          pen p=rgb(0,0,.7);
          draw(s,lightolive+white);
          endasypicture
          enddocument


          enter image description here






          share|improve this answer























          • Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?

            – Anton Petrunin
            yesterday











          • @marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?

            – Marian G.
            yesterday






          • 2





            A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...

            – O.G.
            yesterday













          5












          5








          5







          One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).



          documentclass[variwidth,border=3.14mm]standalone
          usepackageasypictureB
          begindocument
          beginasypicturename=discgraph
          usepackage("mathrsfs");
          import graph3;
          import solids;
          import interpolate;

          settings.outformat="pdf";


          size(500);

          defaultpen(0.5mm);
          pen darkgreen=rgb(0,138/255,122/255);

          draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);
          draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);
          draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);



          //function: call the radial coordinate r=t.x and the angle phi=t.y
          triple f(pair t)
          return ((t.x)*cos(t.y), (t.x)*sin(t.y),
          ((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);


          surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,
          usplinetype=new splinetype[] notaknot,notaknot,monotonic,
          vsplinetype=Spline);
          pen p=rgb(0,0,.7);
          draw(s,lightolive+white);
          endasypicture
          enddocument


          enter image description here






          share|improve this answer













          One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).



          documentclass[variwidth,border=3.14mm]standalone
          usepackageasypictureB
          begindocument
          beginasypicturename=discgraph
          usepackage("mathrsfs");
          import graph3;
          import solids;
          import interpolate;

          settings.outformat="pdf";


          size(500);

          defaultpen(0.5mm);
          pen darkgreen=rgb(0,138/255,122/255);

          draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);
          draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);
          draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);



          //function: call the radial coordinate r=t.x and the angle phi=t.y
          triple f(pair t)
          return ((t.x)*cos(t.y), (t.x)*sin(t.y),
          ((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);


          surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,
          usplinetype=new splinetype[] notaknot,notaknot,monotonic,
          vsplinetype=Spline);
          pen p=rgb(0,0,.7);
          draw(s,lightolive+white);
          endasypicture
          enddocument


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered yesterday









          marmotmarmot

          114k5145276




          114k5145276












          • Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?

            – Anton Petrunin
            yesterday











          • @marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?

            – Marian G.
            yesterday






          • 2





            A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...

            – O.G.
            yesterday

















          • Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?

            – Anton Petrunin
            yesterday











          • @marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?

            – Marian G.
            yesterday






          • 2





            A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...

            – O.G.
            yesterday
















          Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?

          – Anton Petrunin
          yesterday





          Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?

          – Anton Petrunin
          yesterday













          @marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?

          – Marian G.
          yesterday





          @marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?

          – Marian G.
          yesterday




          2




          2





          A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...

          – O.G.
          yesterday





          A line has a thickness, a surface not. It is why you see the x-axis near origin. You can observe the same behavior with a simple square surface and the x-axis. Perhaps it is possible to avoid its by creating two z translated surfaces, but you have to manage the boundary...

          – O.G.
          yesterday

















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