Arithmetically random bitstreamsA set with lower density equal to $0$ and upper density different from $0$Invariant means on the integersDensity of set of unique sumsCoefficients of factors of $x^n-1inmathbbQ[x]$Density measure on $mathbbN^2$Existence of ε-optimal Borel measurable policies in stochastic controlMultiples in sets of positive upper densityPairwise disjoint subsets of $mathbbN$ with positive upper densityAchieving every possible ranking by rearranging weightsNeighboring number of a permutation

Arithmetically random bitstreams


A set with lower density equal to $0$ and upper density different from $0$Invariant means on the integersDensity of set of unique sumsCoefficients of factors of $x^n-1inmathbbQ[x]$Density measure on $mathbbN^2$Existence of ε-optimal Borel measurable policies in stochastic controlMultiples in sets of positive upper densityPairwise disjoint subsets of $mathbbN$ with positive upper densityAchieving every possible ranking by rearranging weightsNeighboring number of a permutation













4












$begingroup$


Motivation (informal). When trying to generate a random bit-stream, we expect that "half of the" bits are $0$, and the "other half" are $1$. So, how about $010101ldots$? Well, we would also expect that if we look at every second member of the sequence, then "half of" those bits are $0$ and the other half are $1$. So, let's make this precise.



Formal version. Let $mathbbN$ denote the set of non-negative integers. We can identify every bit-stream, that is function $f:mathbbNto 0,1$ with some $Aincal P(mathbbN)$ (take $A = f^-1(1)$).



Given any $Ssubseteq mathbbN$ we define maps $mu_S^+, mu_S^-:cal P(mathbbN)to[0,1]$ by $$mu^+_S(A)= lim sup_ntoinftyfrac1+, text and mu^-_S(A)= lim inf_ntoinftyfrac1+.$$



We say that $A$ is well-balanced with respect to $S$ if $mu^+_S(A) = mu^-_S(A) = 1/2$.



For $a,bin mathbbN$ with $a>0$ we set $S_a,b = an+b:ninmathbbN$ and we say that $Aincal P(mathbbN)$ is arithmetically random if $A$ is well-balanced with respect to $S_a,b$ for any $a,binmathbbN$ with $a>0$.



What is an example of an arithmetically random set $Aincal P(mathbb N)$?










share|cite|improve this question











$endgroup$







  • 4




    $begingroup$
    Going by this title and motivation, it's worth pointing out a generalization: algorithmic randomness. This is one test of randomness; we can formulate other tests, and even asks for sequences that pass all such tests. en.wikipedia.org/wiki/Algorithmically_random_sequence
    $endgroup$
    – usul
    Jun 7 at 15:13











  • $begingroup$
    Brilliant - thanks @usul!
    $endgroup$
    – Dominic van der Zypen
    Jun 7 at 16:48






  • 1




    $begingroup$
    You might also read Knuth's discussion of random sequences in Volume 2 of The Art Of Computer Programming, especially Chapter 3.5, What is a Random Sequence?
    $endgroup$
    – Gerry Myerson
    Jun 9 at 1:29






  • 1




    $begingroup$
    +1 for the neat question, though I'd suggest not seeing this notion of a sequence being well-balanced as relating to it being "truly random".
    $endgroup$
    – Nat
    Jun 10 at 22:27










  • $begingroup$
    Thanks @nat for your comment - I changed the title to "arithmetically random".
    $endgroup$
    – Dominic van der Zypen
    Jun 11 at 4:41
















4












$begingroup$


Motivation (informal). When trying to generate a random bit-stream, we expect that "half of the" bits are $0$, and the "other half" are $1$. So, how about $010101ldots$? Well, we would also expect that if we look at every second member of the sequence, then "half of" those bits are $0$ and the other half are $1$. So, let's make this precise.



Formal version. Let $mathbbN$ denote the set of non-negative integers. We can identify every bit-stream, that is function $f:mathbbNto 0,1$ with some $Aincal P(mathbbN)$ (take $A = f^-1(1)$).



Given any $Ssubseteq mathbbN$ we define maps $mu_S^+, mu_S^-:cal P(mathbbN)to[0,1]$ by $$mu^+_S(A)= lim sup_ntoinftyfrac1+, text and mu^-_S(A)= lim inf_ntoinftyfrac1+.$$



We say that $A$ is well-balanced with respect to $S$ if $mu^+_S(A) = mu^-_S(A) = 1/2$.



For $a,bin mathbbN$ with $a>0$ we set $S_a,b = an+b:ninmathbbN$ and we say that $Aincal P(mathbbN)$ is arithmetically random if $A$ is well-balanced with respect to $S_a,b$ for any $a,binmathbbN$ with $a>0$.



What is an example of an arithmetically random set $Aincal P(mathbb N)$?










share|cite|improve this question











$endgroup$







  • 4




    $begingroup$
    Going by this title and motivation, it's worth pointing out a generalization: algorithmic randomness. This is one test of randomness; we can formulate other tests, and even asks for sequences that pass all such tests. en.wikipedia.org/wiki/Algorithmically_random_sequence
    $endgroup$
    – usul
    Jun 7 at 15:13











  • $begingroup$
    Brilliant - thanks @usul!
    $endgroup$
    – Dominic van der Zypen
    Jun 7 at 16:48






  • 1




    $begingroup$
    You might also read Knuth's discussion of random sequences in Volume 2 of The Art Of Computer Programming, especially Chapter 3.5, What is a Random Sequence?
    $endgroup$
    – Gerry Myerson
    Jun 9 at 1:29






  • 1




    $begingroup$
    +1 for the neat question, though I'd suggest not seeing this notion of a sequence being well-balanced as relating to it being "truly random".
    $endgroup$
    – Nat
    Jun 10 at 22:27










  • $begingroup$
    Thanks @nat for your comment - I changed the title to "arithmetically random".
    $endgroup$
    – Dominic van der Zypen
    Jun 11 at 4:41














4












4








4


2



$begingroup$


Motivation (informal). When trying to generate a random bit-stream, we expect that "half of the" bits are $0$, and the "other half" are $1$. So, how about $010101ldots$? Well, we would also expect that if we look at every second member of the sequence, then "half of" those bits are $0$ and the other half are $1$. So, let's make this precise.



Formal version. Let $mathbbN$ denote the set of non-negative integers. We can identify every bit-stream, that is function $f:mathbbNto 0,1$ with some $Aincal P(mathbbN)$ (take $A = f^-1(1)$).



Given any $Ssubseteq mathbbN$ we define maps $mu_S^+, mu_S^-:cal P(mathbbN)to[0,1]$ by $$mu^+_S(A)= lim sup_ntoinftyfrac1+, text and mu^-_S(A)= lim inf_ntoinftyfrac1+.$$



We say that $A$ is well-balanced with respect to $S$ if $mu^+_S(A) = mu^-_S(A) = 1/2$.



For $a,bin mathbbN$ with $a>0$ we set $S_a,b = an+b:ninmathbbN$ and we say that $Aincal P(mathbbN)$ is arithmetically random if $A$ is well-balanced with respect to $S_a,b$ for any $a,binmathbbN$ with $a>0$.



What is an example of an arithmetically random set $Aincal P(mathbb N)$?










share|cite|improve this question











$endgroup$




Motivation (informal). When trying to generate a random bit-stream, we expect that "half of the" bits are $0$, and the "other half" are $1$. So, how about $010101ldots$? Well, we would also expect that if we look at every second member of the sequence, then "half of" those bits are $0$ and the other half are $1$. So, let's make this precise.



Formal version. Let $mathbbN$ denote the set of non-negative integers. We can identify every bit-stream, that is function $f:mathbbNto 0,1$ with some $Aincal P(mathbbN)$ (take $A = f^-1(1)$).



Given any $Ssubseteq mathbbN$ we define maps $mu_S^+, mu_S^-:cal P(mathbbN)to[0,1]$ by $$mu^+_S(A)= lim sup_ntoinftyfrac1+, text and mu^-_S(A)= lim inf_ntoinftyfrac1+.$$



We say that $A$ is well-balanced with respect to $S$ if $mu^+_S(A) = mu^-_S(A) = 1/2$.



For $a,bin mathbbN$ with $a>0$ we set $S_a,b = an+b:ninmathbbN$ and we say that $Aincal P(mathbbN)$ is arithmetically random if $A$ is well-balanced with respect to $S_a,b$ for any $a,binmathbbN$ with $a>0$.



What is an example of an arithmetically random set $Aincal P(mathbb N)$?







nt.number-theory co.combinatorics measure-theory






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jun 11 at 4:42







Dominic van der Zypen

















asked Jun 7 at 7:47









Dominic van der ZypenDominic van der Zypen

15.7k5 gold badges32 silver badges81 bronze badges




15.7k5 gold badges32 silver badges81 bronze badges







  • 4




    $begingroup$
    Going by this title and motivation, it's worth pointing out a generalization: algorithmic randomness. This is one test of randomness; we can formulate other tests, and even asks for sequences that pass all such tests. en.wikipedia.org/wiki/Algorithmically_random_sequence
    $endgroup$
    – usul
    Jun 7 at 15:13











  • $begingroup$
    Brilliant - thanks @usul!
    $endgroup$
    – Dominic van der Zypen
    Jun 7 at 16:48






  • 1




    $begingroup$
    You might also read Knuth's discussion of random sequences in Volume 2 of The Art Of Computer Programming, especially Chapter 3.5, What is a Random Sequence?
    $endgroup$
    – Gerry Myerson
    Jun 9 at 1:29






  • 1




    $begingroup$
    +1 for the neat question, though I'd suggest not seeing this notion of a sequence being well-balanced as relating to it being "truly random".
    $endgroup$
    – Nat
    Jun 10 at 22:27










  • $begingroup$
    Thanks @nat for your comment - I changed the title to "arithmetically random".
    $endgroup$
    – Dominic van der Zypen
    Jun 11 at 4:41













  • 4




    $begingroup$
    Going by this title and motivation, it's worth pointing out a generalization: algorithmic randomness. This is one test of randomness; we can formulate other tests, and even asks for sequences that pass all such tests. en.wikipedia.org/wiki/Algorithmically_random_sequence
    $endgroup$
    – usul
    Jun 7 at 15:13











  • $begingroup$
    Brilliant - thanks @usul!
    $endgroup$
    – Dominic van der Zypen
    Jun 7 at 16:48






  • 1




    $begingroup$
    You might also read Knuth's discussion of random sequences in Volume 2 of The Art Of Computer Programming, especially Chapter 3.5, What is a Random Sequence?
    $endgroup$
    – Gerry Myerson
    Jun 9 at 1:29






  • 1




    $begingroup$
    +1 for the neat question, though I'd suggest not seeing this notion of a sequence being well-balanced as relating to it being "truly random".
    $endgroup$
    – Nat
    Jun 10 at 22:27










  • $begingroup$
    Thanks @nat for your comment - I changed the title to "arithmetically random".
    $endgroup$
    – Dominic van der Zypen
    Jun 11 at 4:41








4




4




$begingroup$
Going by this title and motivation, it's worth pointing out a generalization: algorithmic randomness. This is one test of randomness; we can formulate other tests, and even asks for sequences that pass all such tests. en.wikipedia.org/wiki/Algorithmically_random_sequence
$endgroup$
– usul
Jun 7 at 15:13





$begingroup$
Going by this title and motivation, it's worth pointing out a generalization: algorithmic randomness. This is one test of randomness; we can formulate other tests, and even asks for sequences that pass all such tests. en.wikipedia.org/wiki/Algorithmically_random_sequence
$endgroup$
– usul
Jun 7 at 15:13













$begingroup$
Brilliant - thanks @usul!
$endgroup$
– Dominic van der Zypen
Jun 7 at 16:48




$begingroup$
Brilliant - thanks @usul!
$endgroup$
– Dominic van der Zypen
Jun 7 at 16:48




1




1




$begingroup$
You might also read Knuth's discussion of random sequences in Volume 2 of The Art Of Computer Programming, especially Chapter 3.5, What is a Random Sequence?
$endgroup$
– Gerry Myerson
Jun 9 at 1:29




$begingroup$
You might also read Knuth's discussion of random sequences in Volume 2 of The Art Of Computer Programming, especially Chapter 3.5, What is a Random Sequence?
$endgroup$
– Gerry Myerson
Jun 9 at 1:29




1




1




$begingroup$
+1 for the neat question, though I'd suggest not seeing this notion of a sequence being well-balanced as relating to it being "truly random".
$endgroup$
– Nat
Jun 10 at 22:27




$begingroup$
+1 for the neat question, though I'd suggest not seeing this notion of a sequence being well-balanced as relating to it being "truly random".
$endgroup$
– Nat
Jun 10 at 22:27












$begingroup$
Thanks @nat for your comment - I changed the title to "arithmetically random".
$endgroup$
– Dominic van der Zypen
Jun 11 at 4:41





$begingroup$
Thanks @nat for your comment - I changed the title to "arithmetically random".
$endgroup$
– Dominic van der Zypen
Jun 11 at 4:41











3 Answers
3






active

oldest

votes


















7












$begingroup$

The Thue–Morse sequence is such an example, as was (first, I believe) proved by Dumont.



If you take a uniformly random real number in $[0,1]$, its binary expansion will have this property with probability $1$; I imagine it is conjectured that the binary expansion of every algebraic irrational number has this property.



You might also be interested in the related Erdös discrepancy problem.






share|cite|improve this answer









$endgroup$




















    3












    $begingroup$

    The Champernowne constant $C_2$ ( see https://en.wikipedia.org/wiki/Champernowne_constant )
    has the stronger property of normality (see https://en.wikipedia.org/wiki/Normal_number#Properties) for properties of normal numbers. If you examine a normal number along an infinite arithmetic progression and extract the resulting digits, this is also a normal number






    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
      $endgroup$
      – Greg Martin
      Jun 11 at 16:51


















    2












    $begingroup$

    Mauduit and Sarkozy have studied essentially this and other related pseudorandomness measures for finite as well as infinite $pm 1-$valued sequences, see here (not paywalled)and the references therein.



    Briefly, for a finite sequence $(e_1,ldots, e_N)in pm 1^N$ of length $N,$ they define the well-distribution measure of the sequence by
    $$
    W(e_1,ldots,e_N)=max_a,b,t in mathbbN left| sum_j=0^t-1 e_a+jb right|
    $$

    where the maximum is taken over all AP's within
    $1,2,ldots,N$.



    Another measure they define is the correlation measure of order $k$



    $$
    C_k(e_1,ldots,e_N)=max_M,0leq d_1<d_2<ldots<d_k left|
    sum_n=1^M e_n+d_1 e_n+d_2 cdots e_n+d_k
    right|
    $$

    with $M+d_kleq N.$ They prove that for any sequence,



    $$
    W(e_1,ldots,e_N) leq sqrt3 N C_2(e_1,ldots,e_N)
    $$

    while for almost all sequences in $pm 1^N$ one has
    $$
    sqrtN ll C_2(e_1,ldots,e_N) ll sqrtNlog N
    $$



    They also consider Champerpowne, Thue-Morse, and other sequences, with respect to these measures.






    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      That's beautiful, thanks @kodlu for this wonderful answer!
      $endgroup$
      – Dominic van der Zypen
      Jun 11 at 16:05













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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7












    $begingroup$

    The Thue–Morse sequence is such an example, as was (first, I believe) proved by Dumont.



    If you take a uniformly random real number in $[0,1]$, its binary expansion will have this property with probability $1$; I imagine it is conjectured that the binary expansion of every algebraic irrational number has this property.



    You might also be interested in the related Erdös discrepancy problem.






    share|cite|improve this answer









    $endgroup$

















      7












      $begingroup$

      The Thue–Morse sequence is such an example, as was (first, I believe) proved by Dumont.



      If you take a uniformly random real number in $[0,1]$, its binary expansion will have this property with probability $1$; I imagine it is conjectured that the binary expansion of every algebraic irrational number has this property.



      You might also be interested in the related Erdös discrepancy problem.






      share|cite|improve this answer









      $endgroup$















        7












        7








        7





        $begingroup$

        The Thue–Morse sequence is such an example, as was (first, I believe) proved by Dumont.



        If you take a uniformly random real number in $[0,1]$, its binary expansion will have this property with probability $1$; I imagine it is conjectured that the binary expansion of every algebraic irrational number has this property.



        You might also be interested in the related Erdös discrepancy problem.






        share|cite|improve this answer









        $endgroup$



        The Thue–Morse sequence is such an example, as was (first, I believe) proved by Dumont.



        If you take a uniformly random real number in $[0,1]$, its binary expansion will have this property with probability $1$; I imagine it is conjectured that the binary expansion of every algebraic irrational number has this property.



        You might also be interested in the related Erdös discrepancy problem.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jun 7 at 8:05









        Greg MartinGreg Martin

        9,3711 gold badge39 silver badges63 bronze badges




        9,3711 gold badge39 silver badges63 bronze badges





















            3












            $begingroup$

            The Champernowne constant $C_2$ ( see https://en.wikipedia.org/wiki/Champernowne_constant )
            has the stronger property of normality (see https://en.wikipedia.org/wiki/Normal_number#Properties) for properties of normal numbers. If you examine a normal number along an infinite arithmetic progression and extract the resulting digits, this is also a normal number






            share|cite|improve this answer









            $endgroup$












            • $begingroup$
              True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
              $endgroup$
              – Greg Martin
              Jun 11 at 16:51















            3












            $begingroup$

            The Champernowne constant $C_2$ ( see https://en.wikipedia.org/wiki/Champernowne_constant )
            has the stronger property of normality (see https://en.wikipedia.org/wiki/Normal_number#Properties) for properties of normal numbers. If you examine a normal number along an infinite arithmetic progression and extract the resulting digits, this is also a normal number






            share|cite|improve this answer









            $endgroup$












            • $begingroup$
              True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
              $endgroup$
              – Greg Martin
              Jun 11 at 16:51













            3












            3








            3





            $begingroup$

            The Champernowne constant $C_2$ ( see https://en.wikipedia.org/wiki/Champernowne_constant )
            has the stronger property of normality (see https://en.wikipedia.org/wiki/Normal_number#Properties) for properties of normal numbers. If you examine a normal number along an infinite arithmetic progression and extract the resulting digits, this is also a normal number






            share|cite|improve this answer









            $endgroup$



            The Champernowne constant $C_2$ ( see https://en.wikipedia.org/wiki/Champernowne_constant )
            has the stronger property of normality (see https://en.wikipedia.org/wiki/Normal_number#Properties) for properties of normal numbers. If you examine a normal number along an infinite arithmetic progression and extract the resulting digits, this is also a normal number







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered Jun 9 at 0:57









            Yuval PeresYuval Peres

            1,6509 silver badges10 bronze badges




            1,6509 silver badges10 bronze badges











            • $begingroup$
              True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
              $endgroup$
              – Greg Martin
              Jun 11 at 16:51
















            • $begingroup$
              True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
              $endgroup$
              – Greg Martin
              Jun 11 at 16:51















            $begingroup$
            True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
            $endgroup$
            – Greg Martin
            Jun 11 at 16:51




            $begingroup$
            True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
            $endgroup$
            – Greg Martin
            Jun 11 at 16:51











            2












            $begingroup$

            Mauduit and Sarkozy have studied essentially this and other related pseudorandomness measures for finite as well as infinite $pm 1-$valued sequences, see here (not paywalled)and the references therein.



            Briefly, for a finite sequence $(e_1,ldots, e_N)in pm 1^N$ of length $N,$ they define the well-distribution measure of the sequence by
            $$
            W(e_1,ldots,e_N)=max_a,b,t in mathbbN left| sum_j=0^t-1 e_a+jb right|
            $$

            where the maximum is taken over all AP's within
            $1,2,ldots,N$.



            Another measure they define is the correlation measure of order $k$



            $$
            C_k(e_1,ldots,e_N)=max_M,0leq d_1<d_2<ldots<d_k left|
            sum_n=1^M e_n+d_1 e_n+d_2 cdots e_n+d_k
            right|
            $$

            with $M+d_kleq N.$ They prove that for any sequence,



            $$
            W(e_1,ldots,e_N) leq sqrt3 N C_2(e_1,ldots,e_N)
            $$

            while for almost all sequences in $pm 1^N$ one has
            $$
            sqrtN ll C_2(e_1,ldots,e_N) ll sqrtNlog N
            $$



            They also consider Champerpowne, Thue-Morse, and other sequences, with respect to these measures.






            share|cite|improve this answer









            $endgroup$












            • $begingroup$
              That's beautiful, thanks @kodlu for this wonderful answer!
              $endgroup$
              – Dominic van der Zypen
              Jun 11 at 16:05















            2












            $begingroup$

            Mauduit and Sarkozy have studied essentially this and other related pseudorandomness measures for finite as well as infinite $pm 1-$valued sequences, see here (not paywalled)and the references therein.



            Briefly, for a finite sequence $(e_1,ldots, e_N)in pm 1^N$ of length $N,$ they define the well-distribution measure of the sequence by
            $$
            W(e_1,ldots,e_N)=max_a,b,t in mathbbN left| sum_j=0^t-1 e_a+jb right|
            $$

            where the maximum is taken over all AP's within
            $1,2,ldots,N$.



            Another measure they define is the correlation measure of order $k$



            $$
            C_k(e_1,ldots,e_N)=max_M,0leq d_1<d_2<ldots<d_k left|
            sum_n=1^M e_n+d_1 e_n+d_2 cdots e_n+d_k
            right|
            $$

            with $M+d_kleq N.$ They prove that for any sequence,



            $$
            W(e_1,ldots,e_N) leq sqrt3 N C_2(e_1,ldots,e_N)
            $$

            while for almost all sequences in $pm 1^N$ one has
            $$
            sqrtN ll C_2(e_1,ldots,e_N) ll sqrtNlog N
            $$



            They also consider Champerpowne, Thue-Morse, and other sequences, with respect to these measures.






            share|cite|improve this answer









            $endgroup$












            • $begingroup$
              That's beautiful, thanks @kodlu for this wonderful answer!
              $endgroup$
              – Dominic van der Zypen
              Jun 11 at 16:05













            2












            2








            2





            $begingroup$

            Mauduit and Sarkozy have studied essentially this and other related pseudorandomness measures for finite as well as infinite $pm 1-$valued sequences, see here (not paywalled)and the references therein.



            Briefly, for a finite sequence $(e_1,ldots, e_N)in pm 1^N$ of length $N,$ they define the well-distribution measure of the sequence by
            $$
            W(e_1,ldots,e_N)=max_a,b,t in mathbbN left| sum_j=0^t-1 e_a+jb right|
            $$

            where the maximum is taken over all AP's within
            $1,2,ldots,N$.



            Another measure they define is the correlation measure of order $k$



            $$
            C_k(e_1,ldots,e_N)=max_M,0leq d_1<d_2<ldots<d_k left|
            sum_n=1^M e_n+d_1 e_n+d_2 cdots e_n+d_k
            right|
            $$

            with $M+d_kleq N.$ They prove that for any sequence,



            $$
            W(e_1,ldots,e_N) leq sqrt3 N C_2(e_1,ldots,e_N)
            $$

            while for almost all sequences in $pm 1^N$ one has
            $$
            sqrtN ll C_2(e_1,ldots,e_N) ll sqrtNlog N
            $$



            They also consider Champerpowne, Thue-Morse, and other sequences, with respect to these measures.






            share|cite|improve this answer









            $endgroup$



            Mauduit and Sarkozy have studied essentially this and other related pseudorandomness measures for finite as well as infinite $pm 1-$valued sequences, see here (not paywalled)and the references therein.



            Briefly, for a finite sequence $(e_1,ldots, e_N)in pm 1^N$ of length $N,$ they define the well-distribution measure of the sequence by
            $$
            W(e_1,ldots,e_N)=max_a,b,t in mathbbN left| sum_j=0^t-1 e_a+jb right|
            $$

            where the maximum is taken over all AP's within
            $1,2,ldots,N$.



            Another measure they define is the correlation measure of order $k$



            $$
            C_k(e_1,ldots,e_N)=max_M,0leq d_1<d_2<ldots<d_k left|
            sum_n=1^M e_n+d_1 e_n+d_2 cdots e_n+d_k
            right|
            $$

            with $M+d_kleq N.$ They prove that for any sequence,



            $$
            W(e_1,ldots,e_N) leq sqrt3 N C_2(e_1,ldots,e_N)
            $$

            while for almost all sequences in $pm 1^N$ one has
            $$
            sqrtN ll C_2(e_1,ldots,e_N) ll sqrtNlog N
            $$



            They also consider Champerpowne, Thue-Morse, and other sequences, with respect to these measures.







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered Jun 11 at 12:13









            kodlukodlu

            4,4272 gold badges21 silver badges32 bronze badges




            4,4272 gold badges21 silver badges32 bronze badges











            • $begingroup$
              That's beautiful, thanks @kodlu for this wonderful answer!
              $endgroup$
              – Dominic van der Zypen
              Jun 11 at 16:05
















            • $begingroup$
              That's beautiful, thanks @kodlu for this wonderful answer!
              $endgroup$
              – Dominic van der Zypen
              Jun 11 at 16:05















            $begingroup$
            That's beautiful, thanks @kodlu for this wonderful answer!
            $endgroup$
            – Dominic van der Zypen
            Jun 11 at 16:05




            $begingroup$
            That's beautiful, thanks @kodlu for this wonderful answer!
            $endgroup$
            – Dominic van der Zypen
            Jun 11 at 16:05

















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