Arithmetically random bitstreamsA set with lower density equal to $0$ and upper density different from $0$Invariant means on the integersDensity of set of unique sumsCoefficients of factors of $x^n-1inmathbbQ[x]$Density measure on $mathbbN^2$Existence of ε-optimal Borel measurable policies in stochastic controlMultiples in sets of positive upper densityPairwise disjoint subsets of $mathbbN$ with positive upper densityAchieving every possible ranking by rearranging weightsNeighboring number of a permutation
Arithmetically random bitstreams
A set with lower density equal to $0$ and upper density different from $0$Invariant means on the integersDensity of set of unique sumsCoefficients of factors of $x^n-1inmathbbQ[x]$Density measure on $mathbbN^2$Existence of ε-optimal Borel measurable policies in stochastic controlMultiples in sets of positive upper densityPairwise disjoint subsets of $mathbbN$ with positive upper densityAchieving every possible ranking by rearranging weightsNeighboring number of a permutation
$begingroup$
Motivation (informal). When trying to generate a random bit-stream, we expect that "half of the" bits are $0$, and the "other half" are $1$. So, how about $010101ldots$? Well, we would also expect that if we look at every second member of the sequence, then "half of" those bits are $0$ and the other half are $1$. So, let's make this precise.
Formal version. Let $mathbbN$ denote the set of non-negative integers. We can identify every bit-stream, that is function $f:mathbbNto 0,1$ with some $Aincal P(mathbbN)$ (take $A = f^-1(1)$).
Given any $Ssubseteq mathbbN$ we define maps $mu_S^+, mu_S^-:cal P(mathbbN)to[0,1]$ by $$mu^+_S(A)= lim sup_ntoinftyfrac1+, text and mu^-_S(A)= lim inf_ntoinftyfrac1+.$$
We say that $A$ is well-balanced with respect to $S$ if $mu^+_S(A) = mu^-_S(A) = 1/2$.
For $a,bin mathbbN$ with $a>0$ we set $S_a,b = an+b:ninmathbbN$ and we say that $Aincal P(mathbbN)$ is arithmetically random if $A$ is well-balanced with respect to $S_a,b$ for any $a,binmathbbN$ with $a>0$.
What is an example of an arithmetically random set $Aincal P(mathbb N)$?
nt.number-theory co.combinatorics measure-theory
$endgroup$
add a comment |
$begingroup$
Motivation (informal). When trying to generate a random bit-stream, we expect that "half of the" bits are $0$, and the "other half" are $1$. So, how about $010101ldots$? Well, we would also expect that if we look at every second member of the sequence, then "half of" those bits are $0$ and the other half are $1$. So, let's make this precise.
Formal version. Let $mathbbN$ denote the set of non-negative integers. We can identify every bit-stream, that is function $f:mathbbNto 0,1$ with some $Aincal P(mathbbN)$ (take $A = f^-1(1)$).
Given any $Ssubseteq mathbbN$ we define maps $mu_S^+, mu_S^-:cal P(mathbbN)to[0,1]$ by $$mu^+_S(A)= lim sup_ntoinftyfrac1+, text and mu^-_S(A)= lim inf_ntoinftyfrac1+.$$
We say that $A$ is well-balanced with respect to $S$ if $mu^+_S(A) = mu^-_S(A) = 1/2$.
For $a,bin mathbbN$ with $a>0$ we set $S_a,b = an+b:ninmathbbN$ and we say that $Aincal P(mathbbN)$ is arithmetically random if $A$ is well-balanced with respect to $S_a,b$ for any $a,binmathbbN$ with $a>0$.
What is an example of an arithmetically random set $Aincal P(mathbb N)$?
nt.number-theory co.combinatorics measure-theory
$endgroup$
4
$begingroup$
Going by this title and motivation, it's worth pointing out a generalization: algorithmic randomness. This is one test of randomness; we can formulate other tests, and even asks for sequences that pass all such tests. en.wikipedia.org/wiki/Algorithmically_random_sequence
$endgroup$
– usul
Jun 7 at 15:13
$begingroup$
Brilliant - thanks @usul!
$endgroup$
– Dominic van der Zypen
Jun 7 at 16:48
1
$begingroup$
You might also read Knuth's discussion of random sequences in Volume 2 of The Art Of Computer Programming, especially Chapter 3.5, What is a Random Sequence?
$endgroup$
– Gerry Myerson
Jun 9 at 1:29
1
$begingroup$
+1 for the neat question, though I'd suggest not seeing this notion of a sequence being well-balanced as relating to it being "truly random".
$endgroup$
– Nat
Jun 10 at 22:27
$begingroup$
Thanks @nat for your comment - I changed the title to "arithmetically random".
$endgroup$
– Dominic van der Zypen
Jun 11 at 4:41
add a comment |
$begingroup$
Motivation (informal). When trying to generate a random bit-stream, we expect that "half of the" bits are $0$, and the "other half" are $1$. So, how about $010101ldots$? Well, we would also expect that if we look at every second member of the sequence, then "half of" those bits are $0$ and the other half are $1$. So, let's make this precise.
Formal version. Let $mathbbN$ denote the set of non-negative integers. We can identify every bit-stream, that is function $f:mathbbNto 0,1$ with some $Aincal P(mathbbN)$ (take $A = f^-1(1)$).
Given any $Ssubseteq mathbbN$ we define maps $mu_S^+, mu_S^-:cal P(mathbbN)to[0,1]$ by $$mu^+_S(A)= lim sup_ntoinftyfrac1+, text and mu^-_S(A)= lim inf_ntoinftyfrac1+.$$
We say that $A$ is well-balanced with respect to $S$ if $mu^+_S(A) = mu^-_S(A) = 1/2$.
For $a,bin mathbbN$ with $a>0$ we set $S_a,b = an+b:ninmathbbN$ and we say that $Aincal P(mathbbN)$ is arithmetically random if $A$ is well-balanced with respect to $S_a,b$ for any $a,binmathbbN$ with $a>0$.
What is an example of an arithmetically random set $Aincal P(mathbb N)$?
nt.number-theory co.combinatorics measure-theory
$endgroup$
Motivation (informal). When trying to generate a random bit-stream, we expect that "half of the" bits are $0$, and the "other half" are $1$. So, how about $010101ldots$? Well, we would also expect that if we look at every second member of the sequence, then "half of" those bits are $0$ and the other half are $1$. So, let's make this precise.
Formal version. Let $mathbbN$ denote the set of non-negative integers. We can identify every bit-stream, that is function $f:mathbbNto 0,1$ with some $Aincal P(mathbbN)$ (take $A = f^-1(1)$).
Given any $Ssubseteq mathbbN$ we define maps $mu_S^+, mu_S^-:cal P(mathbbN)to[0,1]$ by $$mu^+_S(A)= lim sup_ntoinftyfrac1+, text and mu^-_S(A)= lim inf_ntoinftyfrac1+.$$
We say that $A$ is well-balanced with respect to $S$ if $mu^+_S(A) = mu^-_S(A) = 1/2$.
For $a,bin mathbbN$ with $a>0$ we set $S_a,b = an+b:ninmathbbN$ and we say that $Aincal P(mathbbN)$ is arithmetically random if $A$ is well-balanced with respect to $S_a,b$ for any $a,binmathbbN$ with $a>0$.
What is an example of an arithmetically random set $Aincal P(mathbb N)$?
nt.number-theory co.combinatorics measure-theory
nt.number-theory co.combinatorics measure-theory
edited Jun 11 at 4:42
Dominic van der Zypen
asked Jun 7 at 7:47
Dominic van der ZypenDominic van der Zypen
15.7k5 gold badges32 silver badges81 bronze badges
15.7k5 gold badges32 silver badges81 bronze badges
4
$begingroup$
Going by this title and motivation, it's worth pointing out a generalization: algorithmic randomness. This is one test of randomness; we can formulate other tests, and even asks for sequences that pass all such tests. en.wikipedia.org/wiki/Algorithmically_random_sequence
$endgroup$
– usul
Jun 7 at 15:13
$begingroup$
Brilliant - thanks @usul!
$endgroup$
– Dominic van der Zypen
Jun 7 at 16:48
1
$begingroup$
You might also read Knuth's discussion of random sequences in Volume 2 of The Art Of Computer Programming, especially Chapter 3.5, What is a Random Sequence?
$endgroup$
– Gerry Myerson
Jun 9 at 1:29
1
$begingroup$
+1 for the neat question, though I'd suggest not seeing this notion of a sequence being well-balanced as relating to it being "truly random".
$endgroup$
– Nat
Jun 10 at 22:27
$begingroup$
Thanks @nat for your comment - I changed the title to "arithmetically random".
$endgroup$
– Dominic van der Zypen
Jun 11 at 4:41
add a comment |
4
$begingroup$
Going by this title and motivation, it's worth pointing out a generalization: algorithmic randomness. This is one test of randomness; we can formulate other tests, and even asks for sequences that pass all such tests. en.wikipedia.org/wiki/Algorithmically_random_sequence
$endgroup$
– usul
Jun 7 at 15:13
$begingroup$
Brilliant - thanks @usul!
$endgroup$
– Dominic van der Zypen
Jun 7 at 16:48
1
$begingroup$
You might also read Knuth's discussion of random sequences in Volume 2 of The Art Of Computer Programming, especially Chapter 3.5, What is a Random Sequence?
$endgroup$
– Gerry Myerson
Jun 9 at 1:29
1
$begingroup$
+1 for the neat question, though I'd suggest not seeing this notion of a sequence being well-balanced as relating to it being "truly random".
$endgroup$
– Nat
Jun 10 at 22:27
$begingroup$
Thanks @nat for your comment - I changed the title to "arithmetically random".
$endgroup$
– Dominic van der Zypen
Jun 11 at 4:41
4
4
$begingroup$
Going by this title and motivation, it's worth pointing out a generalization: algorithmic randomness. This is one test of randomness; we can formulate other tests, and even asks for sequences that pass all such tests. en.wikipedia.org/wiki/Algorithmically_random_sequence
$endgroup$
– usul
Jun 7 at 15:13
$begingroup$
Going by this title and motivation, it's worth pointing out a generalization: algorithmic randomness. This is one test of randomness; we can formulate other tests, and even asks for sequences that pass all such tests. en.wikipedia.org/wiki/Algorithmically_random_sequence
$endgroup$
– usul
Jun 7 at 15:13
$begingroup$
Brilliant - thanks @usul!
$endgroup$
– Dominic van der Zypen
Jun 7 at 16:48
$begingroup$
Brilliant - thanks @usul!
$endgroup$
– Dominic van der Zypen
Jun 7 at 16:48
1
1
$begingroup$
You might also read Knuth's discussion of random sequences in Volume 2 of The Art Of Computer Programming, especially Chapter 3.5, What is a Random Sequence?
$endgroup$
– Gerry Myerson
Jun 9 at 1:29
$begingroup$
You might also read Knuth's discussion of random sequences in Volume 2 of The Art Of Computer Programming, especially Chapter 3.5, What is a Random Sequence?
$endgroup$
– Gerry Myerson
Jun 9 at 1:29
1
1
$begingroup$
+1 for the neat question, though I'd suggest not seeing this notion of a sequence being well-balanced as relating to it being "truly random".
$endgroup$
– Nat
Jun 10 at 22:27
$begingroup$
+1 for the neat question, though I'd suggest not seeing this notion of a sequence being well-balanced as relating to it being "truly random".
$endgroup$
– Nat
Jun 10 at 22:27
$begingroup$
Thanks @nat for your comment - I changed the title to "arithmetically random".
$endgroup$
– Dominic van der Zypen
Jun 11 at 4:41
$begingroup$
Thanks @nat for your comment - I changed the title to "arithmetically random".
$endgroup$
– Dominic van der Zypen
Jun 11 at 4:41
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
The Thue–Morse sequence is such an example, as was (first, I believe) proved by Dumont.
If you take a uniformly random real number in $[0,1]$, its binary expansion will have this property with probability $1$; I imagine it is conjectured that the binary expansion of every algebraic irrational number has this property.
You might also be interested in the related Erdös discrepancy problem.
$endgroup$
add a comment |
$begingroup$
The Champernowne constant $C_2$ ( see https://en.wikipedia.org/wiki/Champernowne_constant )
has the stronger property of normality (see https://en.wikipedia.org/wiki/Normal_number#Properties) for properties of normal numbers. If you examine a normal number along an infinite arithmetic progression and extract the resulting digits, this is also a normal number
$endgroup$
$begingroup$
True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
$endgroup$
– Greg Martin
Jun 11 at 16:51
add a comment |
$begingroup$
Mauduit and Sarkozy have studied essentially this and other related pseudorandomness measures for finite as well as infinite $pm 1-$valued sequences, see here (not paywalled)and the references therein.
Briefly, for a finite sequence $(e_1,ldots, e_N)in pm 1^N$ of length $N,$ they define the well-distribution measure of the sequence by
$$
W(e_1,ldots,e_N)=max_a,b,t in mathbbN left| sum_j=0^t-1 e_a+jb right|
$$
where the maximum is taken over all AP's within
$1,2,ldots,N$.
Another measure they define is the correlation measure of order $k$
$$
C_k(e_1,ldots,e_N)=max_M,0leq d_1<d_2<ldots<d_k left|
sum_n=1^M e_n+d_1 e_n+d_2 cdots e_n+d_k
right|
$$
with $M+d_kleq N.$ They prove that for any sequence,
$$
W(e_1,ldots,e_N) leq sqrt3 N C_2(e_1,ldots,e_N)
$$
while for almost all sequences in $pm 1^N$ one has
$$
sqrtN ll C_2(e_1,ldots,e_N) ll sqrtNlog N
$$
They also consider Champerpowne, Thue-Morse, and other sequences, with respect to these measures.
$endgroup$
$begingroup$
That's beautiful, thanks @kodlu for this wonderful answer!
$endgroup$
– Dominic van der Zypen
Jun 11 at 16:05
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The Thue–Morse sequence is such an example, as was (first, I believe) proved by Dumont.
If you take a uniformly random real number in $[0,1]$, its binary expansion will have this property with probability $1$; I imagine it is conjectured that the binary expansion of every algebraic irrational number has this property.
You might also be interested in the related Erdös discrepancy problem.
$endgroup$
add a comment |
$begingroup$
The Thue–Morse sequence is such an example, as was (first, I believe) proved by Dumont.
If you take a uniformly random real number in $[0,1]$, its binary expansion will have this property with probability $1$; I imagine it is conjectured that the binary expansion of every algebraic irrational number has this property.
You might also be interested in the related Erdös discrepancy problem.
$endgroup$
add a comment |
$begingroup$
The Thue–Morse sequence is such an example, as was (first, I believe) proved by Dumont.
If you take a uniformly random real number in $[0,1]$, its binary expansion will have this property with probability $1$; I imagine it is conjectured that the binary expansion of every algebraic irrational number has this property.
You might also be interested in the related Erdös discrepancy problem.
$endgroup$
The Thue–Morse sequence is such an example, as was (first, I believe) proved by Dumont.
If you take a uniformly random real number in $[0,1]$, its binary expansion will have this property with probability $1$; I imagine it is conjectured that the binary expansion of every algebraic irrational number has this property.
You might also be interested in the related Erdös discrepancy problem.
answered Jun 7 at 8:05
Greg MartinGreg Martin
9,3711 gold badge39 silver badges63 bronze badges
9,3711 gold badge39 silver badges63 bronze badges
add a comment |
add a comment |
$begingroup$
The Champernowne constant $C_2$ ( see https://en.wikipedia.org/wiki/Champernowne_constant )
has the stronger property of normality (see https://en.wikipedia.org/wiki/Normal_number#Properties) for properties of normal numbers. If you examine a normal number along an infinite arithmetic progression and extract the resulting digits, this is also a normal number
$endgroup$
$begingroup$
True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
$endgroup$
– Greg Martin
Jun 11 at 16:51
add a comment |
$begingroup$
The Champernowne constant $C_2$ ( see https://en.wikipedia.org/wiki/Champernowne_constant )
has the stronger property of normality (see https://en.wikipedia.org/wiki/Normal_number#Properties) for properties of normal numbers. If you examine a normal number along an infinite arithmetic progression and extract the resulting digits, this is also a normal number
$endgroup$
$begingroup$
True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
$endgroup$
– Greg Martin
Jun 11 at 16:51
add a comment |
$begingroup$
The Champernowne constant $C_2$ ( see https://en.wikipedia.org/wiki/Champernowne_constant )
has the stronger property of normality (see https://en.wikipedia.org/wiki/Normal_number#Properties) for properties of normal numbers. If you examine a normal number along an infinite arithmetic progression and extract the resulting digits, this is also a normal number
$endgroup$
The Champernowne constant $C_2$ ( see https://en.wikipedia.org/wiki/Champernowne_constant )
has the stronger property of normality (see https://en.wikipedia.org/wiki/Normal_number#Properties) for properties of normal numbers. If you examine a normal number along an infinite arithmetic progression and extract the resulting digits, this is also a normal number
answered Jun 9 at 0:57
Yuval PeresYuval Peres
1,6509 silver badges10 bronze badges
1,6509 silver badges10 bronze badges
$begingroup$
True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
$endgroup$
– Greg Martin
Jun 11 at 16:51
add a comment |
$begingroup$
True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
$endgroup$
– Greg Martin
Jun 11 at 16:51
$begingroup$
True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
$endgroup$
– Greg Martin
Jun 11 at 16:51
$begingroup$
True, although it's interesting to note that the convergence to normality (or to well-balanced as in the OP) is extremely slow.
$endgroup$
– Greg Martin
Jun 11 at 16:51
add a comment |
$begingroup$
Mauduit and Sarkozy have studied essentially this and other related pseudorandomness measures for finite as well as infinite $pm 1-$valued sequences, see here (not paywalled)and the references therein.
Briefly, for a finite sequence $(e_1,ldots, e_N)in pm 1^N$ of length $N,$ they define the well-distribution measure of the sequence by
$$
W(e_1,ldots,e_N)=max_a,b,t in mathbbN left| sum_j=0^t-1 e_a+jb right|
$$
where the maximum is taken over all AP's within
$1,2,ldots,N$.
Another measure they define is the correlation measure of order $k$
$$
C_k(e_1,ldots,e_N)=max_M,0leq d_1<d_2<ldots<d_k left|
sum_n=1^M e_n+d_1 e_n+d_2 cdots e_n+d_k
right|
$$
with $M+d_kleq N.$ They prove that for any sequence,
$$
W(e_1,ldots,e_N) leq sqrt3 N C_2(e_1,ldots,e_N)
$$
while for almost all sequences in $pm 1^N$ one has
$$
sqrtN ll C_2(e_1,ldots,e_N) ll sqrtNlog N
$$
They also consider Champerpowne, Thue-Morse, and other sequences, with respect to these measures.
$endgroup$
$begingroup$
That's beautiful, thanks @kodlu for this wonderful answer!
$endgroup$
– Dominic van der Zypen
Jun 11 at 16:05
add a comment |
$begingroup$
Mauduit and Sarkozy have studied essentially this and other related pseudorandomness measures for finite as well as infinite $pm 1-$valued sequences, see here (not paywalled)and the references therein.
Briefly, for a finite sequence $(e_1,ldots, e_N)in pm 1^N$ of length $N,$ they define the well-distribution measure of the sequence by
$$
W(e_1,ldots,e_N)=max_a,b,t in mathbbN left| sum_j=0^t-1 e_a+jb right|
$$
where the maximum is taken over all AP's within
$1,2,ldots,N$.
Another measure they define is the correlation measure of order $k$
$$
C_k(e_1,ldots,e_N)=max_M,0leq d_1<d_2<ldots<d_k left|
sum_n=1^M e_n+d_1 e_n+d_2 cdots e_n+d_k
right|
$$
with $M+d_kleq N.$ They prove that for any sequence,
$$
W(e_1,ldots,e_N) leq sqrt3 N C_2(e_1,ldots,e_N)
$$
while for almost all sequences in $pm 1^N$ one has
$$
sqrtN ll C_2(e_1,ldots,e_N) ll sqrtNlog N
$$
They also consider Champerpowne, Thue-Morse, and other sequences, with respect to these measures.
$endgroup$
$begingroup$
That's beautiful, thanks @kodlu for this wonderful answer!
$endgroup$
– Dominic van der Zypen
Jun 11 at 16:05
add a comment |
$begingroup$
Mauduit and Sarkozy have studied essentially this and other related pseudorandomness measures for finite as well as infinite $pm 1-$valued sequences, see here (not paywalled)and the references therein.
Briefly, for a finite sequence $(e_1,ldots, e_N)in pm 1^N$ of length $N,$ they define the well-distribution measure of the sequence by
$$
W(e_1,ldots,e_N)=max_a,b,t in mathbbN left| sum_j=0^t-1 e_a+jb right|
$$
where the maximum is taken over all AP's within
$1,2,ldots,N$.
Another measure they define is the correlation measure of order $k$
$$
C_k(e_1,ldots,e_N)=max_M,0leq d_1<d_2<ldots<d_k left|
sum_n=1^M e_n+d_1 e_n+d_2 cdots e_n+d_k
right|
$$
with $M+d_kleq N.$ They prove that for any sequence,
$$
W(e_1,ldots,e_N) leq sqrt3 N C_2(e_1,ldots,e_N)
$$
while for almost all sequences in $pm 1^N$ one has
$$
sqrtN ll C_2(e_1,ldots,e_N) ll sqrtNlog N
$$
They also consider Champerpowne, Thue-Morse, and other sequences, with respect to these measures.
$endgroup$
Mauduit and Sarkozy have studied essentially this and other related pseudorandomness measures for finite as well as infinite $pm 1-$valued sequences, see here (not paywalled)and the references therein.
Briefly, for a finite sequence $(e_1,ldots, e_N)in pm 1^N$ of length $N,$ they define the well-distribution measure of the sequence by
$$
W(e_1,ldots,e_N)=max_a,b,t in mathbbN left| sum_j=0^t-1 e_a+jb right|
$$
where the maximum is taken over all AP's within
$1,2,ldots,N$.
Another measure they define is the correlation measure of order $k$
$$
C_k(e_1,ldots,e_N)=max_M,0leq d_1<d_2<ldots<d_k left|
sum_n=1^M e_n+d_1 e_n+d_2 cdots e_n+d_k
right|
$$
with $M+d_kleq N.$ They prove that for any sequence,
$$
W(e_1,ldots,e_N) leq sqrt3 N C_2(e_1,ldots,e_N)
$$
while for almost all sequences in $pm 1^N$ one has
$$
sqrtN ll C_2(e_1,ldots,e_N) ll sqrtNlog N
$$
They also consider Champerpowne, Thue-Morse, and other sequences, with respect to these measures.
answered Jun 11 at 12:13
kodlukodlu
4,4272 gold badges21 silver badges32 bronze badges
4,4272 gold badges21 silver badges32 bronze badges
$begingroup$
That's beautiful, thanks @kodlu for this wonderful answer!
$endgroup$
– Dominic van der Zypen
Jun 11 at 16:05
add a comment |
$begingroup$
That's beautiful, thanks @kodlu for this wonderful answer!
$endgroup$
– Dominic van der Zypen
Jun 11 at 16:05
$begingroup$
That's beautiful, thanks @kodlu for this wonderful answer!
$endgroup$
– Dominic van der Zypen
Jun 11 at 16:05
$begingroup$
That's beautiful, thanks @kodlu for this wonderful answer!
$endgroup$
– Dominic van der Zypen
Jun 11 at 16:05
add a comment |
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4
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Going by this title and motivation, it's worth pointing out a generalization: algorithmic randomness. This is one test of randomness; we can formulate other tests, and even asks for sequences that pass all such tests. en.wikipedia.org/wiki/Algorithmically_random_sequence
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– usul
Jun 7 at 15:13
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Brilliant - thanks @usul!
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– Dominic van der Zypen
Jun 7 at 16:48
1
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You might also read Knuth's discussion of random sequences in Volume 2 of The Art Of Computer Programming, especially Chapter 3.5, What is a Random Sequence?
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– Gerry Myerson
Jun 9 at 1:29
1
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+1 for the neat question, though I'd suggest not seeing this notion of a sequence being well-balanced as relating to it being "truly random".
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– Nat
Jun 10 at 22:27
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Thanks @nat for your comment - I changed the title to "arithmetically random".
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– Dominic van der Zypen
Jun 11 at 4:41