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Issue with type force PATH search

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3

1

This is Bash. The behavior is similar in fish.

$ which python
/usr/bin/python
$ alias py=python
$ type py
py is aliased to `python'

​And then, running type -P py prints nothing, where as I expected to print /usr/bin/pyton in a similar fashion to what is seen below.​

$ type ls
ls is aliased to `ls --color=auto'
$ type -P ls
/bin/ls

The documentation for the -P option reads

 -P force a PATH search for each NAME, even if it is an alias,
 builtin, or function, and returns the name of the disk file
 that would be executed

I've confirmed that /usr/bin (the directory where python is located) is in PATH.

What is going on here?

bash fish shell-builtin

share|improve this question

edited Apr 4 at 9:08

Git Gud

asked Apr 4 at 8:50

Git GudGit Gud

1375

add a comment | 

3

1

This is Bash. The behavior is similar in fish.

$ which python
/usr/bin/python
$ alias py=python
$ type py
py is aliased to `python'

​And then, running type -P py prints nothing, where as I expected to print /usr/bin/pyton in a similar fashion to what is seen below.​

$ type ls
ls is aliased to `ls --color=auto'
$ type -P ls
/bin/ls

The documentation for the -P option reads

 -P force a PATH search for each NAME, even if it is an alias,
 builtin, or function, and returns the name of the disk file
 that would be executed

I've confirmed that /usr/bin (the directory where python is located) is in PATH.

What is going on here?

bash fish shell-builtin

share|improve this question

edited Apr 4 at 9:08

Git Gud

asked Apr 4 at 8:50

Git GudGit Gud

1375

add a comment | 

This is Bash. The behavior is similar in fish.

$ which python
/usr/bin/python
$ alias py=python
$ type py
py is aliased to `python'

​And then, running type -P py prints nothing, where as I expected to print /usr/bin/pyton in a similar fashion to what is seen below.​

$ type ls
ls is aliased to `ls --color=auto'
$ type -P ls
/bin/ls

The documentation for the -P option reads

 -P force a PATH search for each NAME, even if it is an alias,
 builtin, or function, and returns the name of the disk file
 that would be executed

I've confirmed that /usr/bin (the directory where python is located) is in PATH.

What is going on here?

bash fish shell-builtin

share|improve this question

edited Apr 4 at 9:08

Git Gud

asked Apr 4 at 8:50

Git GudGit Gud

1375

$ which python
/usr/bin/python
$ alias py=python
$ type py
py is aliased to `python'

$ type ls
ls is aliased to `ls --color=auto'
$ type -P ls
/bin/ls

 -P force a PATH search for each NAME, even if it is an alias,
 builtin, or function, and returns the name of the disk file
 that would be executed

share|improve this question

edited Apr 4 at 9:08

Git Gud

asked Apr 4 at 8:50

Git GudGit Gud

1375

share|improve this question

edited Apr 4 at 9:08

Git Gud

asked Apr 4 at 8:50

Git GudGit Gud

1375

asked Apr 4 at 8:50

Git GudGit Gud

1375

asked Apr 4 at 8:50

Git GudGit Gud

1375

2 Answers
2

active

oldest

votes

9

This:

force a PATH search for each NAME, even if it is an alias,

does not mean that bash will expand the alias and then search for the expanded command. It means that, if there were a command foo, and also an alias foo, the type -P foo will still look for the command named foo, even though there's an alias masking it. So bash isn't expanding py in type -P py to be python, and it won't show /usr/bin/python.

share|improve this answer

answered Apr 4 at 8:55

murumuru

37.2k589164

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Well, this could be clearer. Thanks.
  
  – Git Gud
  Apr 4 at 8:56
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Seems clear enough. NAME is the argument to type, not an alias expansion of the argument.
  
  – chepner
  Apr 4 at 18:42
  
  

  
  
  
  

add a comment | 

4

What’s going on is that your shell is looking for a binary named py in each directory on your PATH, and not finding any.

type -P doesn’t interpret aliases or functions; it forces the given name to be searched on the path, ignoring any other available command not of type “file” with the same name.

(There’s an added subtlety with type -p and type -P: they take hashes into account, so they will show a hashed value if one exists, without looking in the PATH. But that’s not involved here.)

share|improve this answer

answered Apr 4 at 8:54

Stephen KittStephen Kitt

180k25409488

add a comment | 

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9

This:

force a PATH search for each NAME, even if it is an alias,

does not mean that bash will expand the alias and then search for the expanded command. It means that, if there were a command foo, and also an alias foo, the type -P foo will still look for the command named foo, even though there's an alias masking it. So bash isn't expanding py in type -P py to be python, and it won't show /usr/bin/python.

share|improve this answer

answered Apr 4 at 8:55

murumuru

37.2k589164

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Well, this could be clearer. Thanks.
  
  – Git Gud
  Apr 4 at 8:56
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Seems clear enough. NAME is the argument to type, not an alias expansion of the argument.
  
  – chepner
  Apr 4 at 18:42
  
  

  
  
  
  

add a comment | 

9

This:

force a PATH search for each NAME, even if it is an alias,

does not mean that bash will expand the alias and then search for the expanded command. It means that, if there were a command foo, and also an alias foo, the type -P foo will still look for the command named foo, even though there's an alias masking it. So bash isn't expanding py in type -P py to be python, and it won't show /usr/bin/python.

share|improve this answer

answered Apr 4 at 8:55

murumuru

37.2k589164

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Well, this could be clearer. Thanks.
  
  – Git Gud
  Apr 4 at 8:56
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Seems clear enough. NAME is the argument to type, not an alias expansion of the argument.
  
  – chepner
  Apr 4 at 18:42
  
  

  
  
  
  

add a comment | 

This:

force a PATH search for each NAME, even if it is an alias,

does not mean that bash will expand the alias and then search for the expanded command. It means that, if there were a command foo, and also an alias foo, the type -P foo will still look for the command named foo, even though there's an alias masking it. So bash isn't expanding py in type -P py to be python, and it won't show /usr/bin/python.

share|improve this answer

answered Apr 4 at 8:55

murumuru

37.2k589164

share|improve this answer

answered Apr 4 at 8:55

murumuru

37.2k589164

answered Apr 4 at 8:55

murumuru

37.2k589164

answered Apr 4 at 8:55

murumuru

37.2k589164

4

What’s going on is that your shell is looking for a binary named py in each directory on your PATH, and not finding any.

type -P doesn’t interpret aliases or functions; it forces the given name to be searched on the path, ignoring any other available command not of type “file” with the same name.

(There’s an added subtlety with type -p and type -P: they take hashes into account, so they will show a hashed value if one exists, without looking in the PATH. But that’s not involved here.)

share|improve this answer

answered Apr 4 at 8:54

Stephen KittStephen Kitt

180k25409488

add a comment | 

4

What’s going on is that your shell is looking for a binary named py in each directory on your PATH, and not finding any.

type -P doesn’t interpret aliases or functions; it forces the given name to be searched on the path, ignoring any other available command not of type “file” with the same name.

(There’s an added subtlety with type -p and type -P: they take hashes into account, so they will show a hashed value if one exists, without looking in the PATH. But that’s not involved here.)

share|improve this answer

answered Apr 4 at 8:54

Stephen KittStephen Kitt

180k25409488

add a comment | 

What’s going on is that your shell is looking for a binary named py in each directory on your PATH, and not finding any.

type -P doesn’t interpret aliases or functions; it forces the given name to be searched on the path, ignoring any other available command not of type “file” with the same name.

(There’s an added subtlety with type -p and type -P: they take hashes into account, so they will show a hashed value if one exists, without looking in the PATH. But that’s not involved here.)

share|improve this answer

answered Apr 4 at 8:54

Stephen KittStephen Kitt

180k25409488

share|improve this answer

answered Apr 4 at 8:54

Stephen KittStephen Kitt

180k25409488

answered Apr 4 at 8:54

Stephen KittStephen Kitt

180k25409488

answered Apr 4 at 8:54

Stephen KittStephen Kitt

180k25409488