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monit reload - how to know when it is finished?
How to prevent monit daemon stopped?monit sumary not working when domain specified in use addressMonit restarting actionSuppress Monit message 'Monit instance changed' on stop/startMonit configuration reload - supposed to restart monitored services?How to get monit to only alert once when a check fails, not when it comes back successful?how do I set monit to non-daemon modeHow to configure monit, check process to start program when only filesystem is available?Syntax error: when using “check program” in monitMonit: How to exec when timeout/unmonitor?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I have this requirement to add services to monit dynamically. So what I am doing is copying the service monit file to /etc/monit.d/ (which is included in /etc/monitrc) and reloading monit.
cp <service-monit-file> /etc/monit.d/
monit reload
monit monitor <service-name>
Now monit commands run in background. So, monit monitor
command fails (service not found) as monit reload
did not finish immediately.
So what approach can be taken to ensure that monit monitor
is called only after monit reload
finishes. I have tried monit -I reload
, but the result is same.
Checking monit log with tail and breaking when "reloaded" string comes is also not possible as tail will output to stdout, which is not allowed.
monit daemon
add a comment |
I have this requirement to add services to monit dynamically. So what I am doing is copying the service monit file to /etc/monit.d/ (which is included in /etc/monitrc) and reloading monit.
cp <service-monit-file> /etc/monit.d/
monit reload
monit monitor <service-name>
Now monit commands run in background. So, monit monitor
command fails (service not found) as monit reload
did not finish immediately.
So what approach can be taken to ensure that monit monitor
is called only after monit reload
finishes. I have tried monit -I reload
, but the result is same.
Checking monit log with tail and breaking when "reloaded" string comes is also not possible as tail will output to stdout, which is not allowed.
monit daemon
add a comment |
I have this requirement to add services to monit dynamically. So what I am doing is copying the service monit file to /etc/monit.d/ (which is included in /etc/monitrc) and reloading monit.
cp <service-monit-file> /etc/monit.d/
monit reload
monit monitor <service-name>
Now monit commands run in background. So, monit monitor
command fails (service not found) as monit reload
did not finish immediately.
So what approach can be taken to ensure that monit monitor
is called only after monit reload
finishes. I have tried monit -I reload
, but the result is same.
Checking monit log with tail and breaking when "reloaded" string comes is also not possible as tail will output to stdout, which is not allowed.
monit daemon
I have this requirement to add services to monit dynamically. So what I am doing is copying the service monit file to /etc/monit.d/ (which is included in /etc/monitrc) and reloading monit.
cp <service-monit-file> /etc/monit.d/
monit reload
monit monitor <service-name>
Now monit commands run in background. So, monit monitor
command fails (service not found) as monit reload
did not finish immediately.
So what approach can be taken to ensure that monit monitor
is called only after monit reload
finishes. I have tried monit -I reload
, but the result is same.
Checking monit log with tail and breaking when "reloaded" string comes is also not possible as tail will output to stdout, which is not allowed.
monit daemon
monit daemon
asked May 2 at 9:11
SoumenSoumen
1135
1135
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I can't reproduce this issue (I get a different error) but I guess the monit monitor
command fails with a non-zero return value in your case. Then I would do:
while ! monit monitor <service-name> 2>/dev/null
do
sleep 1
done
Note: you may want to add a timeout mechanism to avoid an infinite while
loop.
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I can't reproduce this issue (I get a different error) but I guess the monit monitor
command fails with a non-zero return value in your case. Then I would do:
while ! monit monitor <service-name> 2>/dev/null
do
sleep 1
done
Note: you may want to add a timeout mechanism to avoid an infinite while
loop.
add a comment |
I can't reproduce this issue (I get a different error) but I guess the monit monitor
command fails with a non-zero return value in your case. Then I would do:
while ! monit monitor <service-name> 2>/dev/null
do
sleep 1
done
Note: you may want to add a timeout mechanism to avoid an infinite while
loop.
add a comment |
I can't reproduce this issue (I get a different error) but I guess the monit monitor
command fails with a non-zero return value in your case. Then I would do:
while ! monit monitor <service-name> 2>/dev/null
do
sleep 1
done
Note: you may want to add a timeout mechanism to avoid an infinite while
loop.
I can't reproduce this issue (I get a different error) but I guess the monit monitor
command fails with a non-zero return value in your case. Then I would do:
while ! monit monitor <service-name> 2>/dev/null
do
sleep 1
done
Note: you may want to add a timeout mechanism to avoid an infinite while
loop.
answered May 2 at 9:49
GohuGohu
123117
123117
add a comment |
add a comment |
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