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Finding the repeating unit of polymerisation given two constituent molecules
The 2019 Stack Overflow Developer Survey Results Are InNumber of hydrogen molecules necessary in acetonitrile/butanediamine polymerisationHow to identify the repeating unit in a polymer?Contact lenses come in two polymer classes, ionic or non-ionic. Whats the significance of having both?Why the backbone of polylactic acid's repeating unit contains only one oxygen?How does cross-linking between polymer chains increase the melting point of the polymer?Polymerisation of methyl methacrylate - can the C=O group get involved?Why must polymers have a repeating unit?Calculating the enthalpy of polymerisation of ethylene given the bond strengthsRepeating unit of poly lactic acid (PLA)Why does the degree of polymerisation remain the same throughout chain-growth polymerisation?
$begingroup$
The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?
A. $requireencloseceenclosehorizontalstrike(HNCH2CONHCH2CH2NHCOenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CONHCH2NHCOenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2NHenclosehorizontalstrike)$
I came across this question which requires me to find the structure of the repeating unit of the polymer made by the reaction of two different compounds. However, I am not sure as to which repeating unit would suffice for this particular polymer.
As far as I know, there should be double bonds present at the ends of the repeating unit, so that the pi bond can break and allow the formation of additional bonds, and hence, a chain of molecules. However, using that line of thought I cannot seem to figure out the answer to the question.
I just need a direction, a hint or a clue as to how I should approach problems like such.
polymers
edited Apr 6 at 14:11
Karsten Theis
4,186542
asked Apr 6 at 11:46
Selena CarlosSelena Carlos
787
$endgroup$
add a comment |
$begingroup$
The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?
A. $requireencloseceenclosehorizontalstrike(HNCH2CONHCH2CH2NHCOenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CONHCH2NHCOenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2NHenclosehorizontalstrike)$
I came across this question which requires me to find the structure of the repeating unit of the polymer made by the reaction of two different compounds. However, I am not sure as to which repeating unit would suffice for this particular polymer.
As far as I know, there should be double bonds present at the ends of the repeating unit, so that the pi bond can break and allow the formation of additional bonds, and hence, a chain of molecules. However, using that line of thought I cannot seem to figure out the answer to the question.
I just need a direction, a hint or a clue as to how I should approach problems like such.
polymers
edited Apr 6 at 14:11
Karsten Theis
4,186542
asked Apr 6 at 11:46
Selena CarlosSelena Carlos
787
$endgroup$
4
$begingroup$
What you are mentioning is addition polymerization which malonic acid and ethylenediamine wouldn't dream of doing. Condensation occurs, rather.
$endgroup$
– William R. Ebenezer
Apr 6 at 11:51
1
$begingroup$
Draw out the skeletal structures with different colors so you can see how the building blocks combine. If you have monomers A and B, and A can't link with A and B can't link with B, the only polymer you can get is A-B-A-B-A...
$endgroup$
– Karsten Theis
Apr 6 at 14:07
1
$begingroup$
"As far as I know, there should be double bonds present at the ends of the repeating unit"; This is not correct.
$endgroup$
– A.K.
Apr 6 at 18:42
add a comment |
$begingroup$
The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?
A. $requireencloseceenclosehorizontalstrike(HNCH2CONHCH2CH2NHCOenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CONHCH2NHCOenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2NHenclosehorizontalstrike)$
I came across this question which requires me to find the structure of the repeating unit of the polymer made by the reaction of two different compounds. However, I am not sure as to which repeating unit would suffice for this particular polymer.
As far as I know, there should be double bonds present at the ends of the repeating unit, so that the pi bond can break and allow the formation of additional bonds, and hence, a chain of molecules. However, using that line of thought I cannot seem to figure out the answer to the question.
I just need a direction, a hint or a clue as to how I should approach problems like such.
polymers
edited Apr 6 at 14:11
Karsten Theis
4,186542
asked Apr 6 at 11:46
Selena CarlosSelena Carlos
787
$endgroup$
The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?
A. $requireencloseceenclosehorizontalstrike(HNCH2CONHCH2CH2NHCOenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CONHCH2NHCOenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2NHenclosehorizontalstrike)$
I came across this question which requires me to find the structure of the repeating unit of the polymer made by the reaction of two different compounds. However, I am not sure as to which repeating unit would suffice for this particular polymer.
As far as I know, there should be double bonds present at the ends of the repeating unit, so that the pi bond can break and allow the formation of additional bonds, and hence, a chain of molecules. However, using that line of thought I cannot seem to figure out the answer to the question.
I just need a direction, a hint or a clue as to how I should approach problems like such.
polymers
polymers
edited Apr 6 at 14:11
Karsten Theis
4,186542
asked Apr 6 at 11:46
Selena CarlosSelena Carlos
787
edited Apr 6 at 14:11
Karsten Theis
4,186542
asked Apr 6 at 11:46
Selena CarlosSelena Carlos
787
edited Apr 6 at 14:11
Karsten Theis
4,186542
edited Apr 6 at 14:11
Karsten Theis
4,186542
edited Apr 6 at 14:11
Karsten Theis
4,186542
4,186542
asked Apr 6 at 11:46
Selena CarlosSelena Carlos
787
asked Apr 6 at 11:46
Selena CarlosSelena Carlos
787
asked Apr 6 at 11:46
Selena CarlosSelena Carlos
787
787
4
$begingroup$
What you are mentioning is addition polymerization which malonic acid and ethylenediamine wouldn't dream of doing. Condensation occurs, rather.
$endgroup$
– William R. Ebenezer
Apr 6 at 11:51
1
$begingroup$
Draw out the skeletal structures with different colors so you can see how the building blocks combine. If you have monomers A and B, and A can't link with A and B can't link with B, the only polymer you can get is A-B-A-B-A...
$endgroup$
– Karsten Theis
Apr 6 at 14:07
1
$begingroup$
"As far as I know, there should be double bonds present at the ends of the repeating unit"; This is not correct.
$endgroup$
– A.K.
Apr 6 at 18:42
add a comment |
4
$begingroup$
What you are mentioning is addition polymerization which malonic acid and ethylenediamine wouldn't dream of doing. Condensation occurs, rather.
$endgroup$
– William R. Ebenezer
Apr 6 at 11:51
1
$begingroup$
Draw out the skeletal structures with different colors so you can see how the building blocks combine. If you have monomers A and B, and A can't link with A and B can't link with B, the only polymer you can get is A-B-A-B-A...
$endgroup$
– Karsten Theis
Apr 6 at 14:07
1
$begingroup$
"As far as I know, there should be double bonds present at the ends of the repeating unit"; This is not correct.
$endgroup$
– A.K.
Apr 6 at 18:42
4
4
$begingroup$
What you are mentioning is addition polymerization which malonic acid and ethylenediamine wouldn't dream of doing. Condensation occurs, rather.
$endgroup$
– William R. Ebenezer
Apr 6 at 11:51
$begingroup$
What you are mentioning is addition polymerization which malonic acid and ethylenediamine wouldn't dream of doing. Condensation occurs, rather.
$endgroup$
– William R. Ebenezer
Apr 6 at 11:51
1
1
$begingroup$
Draw out the skeletal structures with different colors so you can see how the building blocks combine. If you have monomers A and B, and A can't link with A and B can't link with B, the only polymer you can get is A-B-A-B-A...
$endgroup$
– Karsten Theis
Apr 6 at 14:07
$begingroup$
Draw out the skeletal structures with different colors so you can see how the building blocks combine. If you have monomers A and B, and A can't link with A and B can't link with B, the only polymer you can get is A-B-A-B-A...
$endgroup$
– Karsten Theis
Apr 6 at 14:07
1
1
$begingroup$
"As far as I know, there should be double bonds present at the ends of the repeating unit"; This is not correct.
$endgroup$
– A.K.
Apr 6 at 18:42
$begingroup$
"As far as I know, there should be double bonds present at the ends of the repeating unit"; This is not correct.
$endgroup$
– A.K.
Apr 6 at 18:42
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
You are starting out with amino groups on one monomer and carboxylate groups on the other monomer. As William R. Ebenezer states in the comment, these combine via condensation (to form an amide, which is written as -NHCO- or -CONH- in condensed formulas). 
The linkages in the answer choices between repeating units are not visible until you write another repeating unit next to the ones shown. A. and B. show amide linkages between repeating units, while C. and D. show something else.
Here is the exercise rewritten to emphasize the amide bonds in the repeating units:
The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?
A. $requireencloseceenclosehorizontalstrike(HNCH2CO-NHCH2CH2NH-COenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CO-NHCH2NH-COenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2NHenclosehorizontalstrike)$
Now that we emphasized the amide linkages, you can see that the first monomer in A, the second monomer in C and the second monomer in D don't match your starting materials. We can also exclude C. and D. because repeating units are not linked via amides. The answer has to be B.
answered Apr 6 at 14:17
Karsten TheisKarsten Theis
4,186542
$endgroup$
add a comment |
$begingroup$
You got the answer you have looking for in Karsten Theis' answer. However, your statement of "as far as I know, there should be double bonds present at the ends of the repeating unit" is not entirely correct for all polymers in general (see A.K.'s comment). Yes, some have double bonds within the chain and at the end. But, most polymers forms without assistance from double bonds and, hence do not contain double bonds (unsaturations). Here is two best known polymers we used in our day to day life:
Both are fabrics and none has end unsaturation. The reaction shows you that none need unsaturation to condense.
answered Apr 7 at 2:29
Mathew MahindaratneMathew Mahindaratne
6,070725
$endgroup$
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You are starting out with amino groups on one monomer and carboxylate groups on the other monomer. As William R. Ebenezer states in the comment, these combine via condensation (to form an amide, which is written as -NHCO- or -CONH- in condensed formulas).
The linkages in the answer choices between repeating units are not visible until you write another repeating unit next to the ones shown. A. and B. show amide linkages between repeating units, while C. and D. show something else.
Here is the exercise rewritten to emphasize the amide bonds in the repeating units:
The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?
A. $requireencloseceenclosehorizontalstrike(HNCH2CO-NHCH2CH2NH-COenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CO-NHCH2NH-COenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2NHenclosehorizontalstrike)$
Now that we emphasized the amide linkages, you can see that the first monomer in A, the second monomer in C and the second monomer in D don't match your starting materials. We can also exclude C. and D. because repeating units are not linked via amides. The answer has to be B.
answered Apr 6 at 14:17
Karsten TheisKarsten Theis
4,186542
$endgroup$
add a comment |
$begingroup$
You are starting out with amino groups on one monomer and carboxylate groups on the other monomer. As William R. Ebenezer states in the comment, these combine via condensation (to form an amide, which is written as -NHCO- or -CONH- in condensed formulas).
The linkages in the answer choices between repeating units are not visible until you write another repeating unit next to the ones shown. A. and B. show amide linkages between repeating units, while C. and D. show something else.
Here is the exercise rewritten to emphasize the amide bonds in the repeating units:
The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?
A. $requireencloseceenclosehorizontalstrike(HNCH2CO-NHCH2CH2NH-COenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CO-NHCH2NH-COenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2NHenclosehorizontalstrike)$
Now that we emphasized the amide linkages, you can see that the first monomer in A, the second monomer in C and the second monomer in D don't match your starting materials. We can also exclude C. and D. because repeating units are not linked via amides. The answer has to be B.
answered Apr 6 at 14:17
Karsten TheisKarsten Theis
4,186542
$endgroup$
add a comment |
$begingroup$
You are starting out with amino groups on one monomer and carboxylate groups on the other monomer. As William R. Ebenezer states in the comment, these combine via condensation (to form an amide, which is written as -NHCO- or -CONH- in condensed formulas).
The linkages in the answer choices between repeating units are not visible until you write another repeating unit next to the ones shown. A. and B. show amide linkages between repeating units, while C. and D. show something else.
Here is the exercise rewritten to emphasize the amide bonds in the repeating units:
The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?
A. $requireencloseceenclosehorizontalstrike(HNCH2CO-NHCH2CH2NH-COenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CO-NHCH2NH-COenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2NHenclosehorizontalstrike)$
Now that we emphasized the amide linkages, you can see that the first monomer in A, the second monomer in C and the second monomer in D don't match your starting materials. We can also exclude C. and D. because repeating units are not linked via amides. The answer has to be B.
answered Apr 6 at 14:17
Karsten TheisKarsten Theis
4,186542
$endgroup$
You are starting out with amino groups on one monomer and carboxylate groups on the other monomer. As William R. Ebenezer states in the comment, these combine via condensation (to form an amide, which is written as -NHCO- or -CONH- in condensed formulas).
The linkages in the answer choices between repeating units are not visible until you write another repeating unit next to the ones shown. A. and B. show amide linkages between repeating units, while C. and D. show something else.
Here is the exercise rewritten to emphasize the amide bonds in the repeating units:
The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?
A. $requireencloseceenclosehorizontalstrike(HNCH2CO-NHCH2CH2NH-COenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CO-NHCH2NH-COenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2NHenclosehorizontalstrike)$
Now that we emphasized the amide linkages, you can see that the first monomer in A, the second monomer in C and the second monomer in D don't match your starting materials. We can also exclude C. and D. because repeating units are not linked via amides. The answer has to be B.
answered Apr 6 at 14:17
Karsten TheisKarsten Theis
4,186542
edited Apr 6 at 15:29
answered Apr 6 at 14:17
Karsten TheisKarsten Theis
4,186542
answered Apr 6 at 14:17
Karsten TheisKarsten Theis
4,186542
answered Apr 6 at 14:17
Karsten TheisKarsten Theis
4,186542
4,186542
add a comment |
add a comment |
$begingroup$
You got the answer you have looking for in Karsten Theis' answer. However, your statement of "as far as I know, there should be double bonds present at the ends of the repeating unit" is not entirely correct for all polymers in general (see A.K.'s comment). Yes, some have double bonds within the chain and at the end. But, most polymers forms without assistance from double bonds and, hence do not contain double bonds (unsaturations). Here is two best known polymers we used in our day to day life:
Both are fabrics and none has end unsaturation. The reaction shows you that none need unsaturation to condense.
answered Apr 7 at 2:29
Mathew MahindaratneMathew Mahindaratne
6,070725
$endgroup$
add a comment |
$begingroup$
You got the answer you have looking for in Karsten Theis' answer. However, your statement of "as far as I know, there should be double bonds present at the ends of the repeating unit" is not entirely correct for all polymers in general (see A.K.'s comment). Yes, some have double bonds within the chain and at the end. But, most polymers forms without assistance from double bonds and, hence do not contain double bonds (unsaturations). Here is two best known polymers we used in our day to day life:
Both are fabrics and none has end unsaturation. The reaction shows you that none need unsaturation to condense.
answered Apr 7 at 2:29
Mathew MahindaratneMathew Mahindaratne
6,070725
$endgroup$
add a comment |
$begingroup$
You got the answer you have looking for in Karsten Theis' answer. However, your statement of "as far as I know, there should be double bonds present at the ends of the repeating unit" is not entirely correct for all polymers in general (see A.K.'s comment). Yes, some have double bonds within the chain and at the end. But, most polymers forms without assistance from double bonds and, hence do not contain double bonds (unsaturations). Here is two best known polymers we used in our day to day life:
Both are fabrics and none has end unsaturation. The reaction shows you that none need unsaturation to condense.
answered Apr 7 at 2:29
Mathew MahindaratneMathew Mahindaratne
6,070725
$endgroup$
You got the answer you have looking for in Karsten Theis' answer. However, your statement of "as far as I know, there should be double bonds present at the ends of the repeating unit" is not entirely correct for all polymers in general (see A.K.'s comment). Yes, some have double bonds within the chain and at the end. But, most polymers forms without assistance from double bonds and, hence do not contain double bonds (unsaturations). Here is two best known polymers we used in our day to day life:
Both are fabrics and none has end unsaturation. The reaction shows you that none need unsaturation to condense.
answered Apr 7 at 2:29
Mathew MahindaratneMathew Mahindaratne
6,070725
edited Apr 7 at 17:18
answered Apr 7 at 2:29
Mathew MahindaratneMathew Mahindaratne
6,070725
answered Apr 7 at 2:29
Mathew MahindaratneMathew Mahindaratne
6,070725
answered Apr 7 at 2:29
Mathew MahindaratneMathew Mahindaratne
6,070725
6,070725
add a comment |
add a comment |
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4
$begingroup$
What you are mentioning is addition polymerization which malonic acid and ethylenediamine wouldn't dream of doing. Condensation occurs, rather.
$endgroup$
– William R. Ebenezer
Apr 6 at 11:51
1
$begingroup$
Draw out the skeletal structures with different colors so you can see how the building blocks combine. If you have monomers A and B, and A can't link with A and B can't link with B, the only polymer you can get is A-B-A-B-A...
$endgroup$
– Karsten Theis
Apr 6 at 14:07
1
$begingroup$
"As far as I know, there should be double bonds present at the ends of the repeating unit"; This is not correct.
$endgroup$
– A.K.
Apr 6 at 18:42