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How to update value in a file using sed linux
Atime value changing only once after file creationHow to put fixed-width, vertically-oriented key-value pairs in a CSV file?How to Prefix a column values with an apostrophe ( ' )?filesystem that works under qemu and I can mount on my hostHow to convert several tiff images into xyz coordinates in a single text file using the terminal?Compare and merge config file in CentOShard vs - in limits.confLinux server deny full accessHow does Linux resolve pathnames with the help of the dentry cache?extract field from file using sed or awk
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Need to change value corresponding to "root soft nproc" from 180000 to 40000. Sample file look like this:
Any easy way to do this in a single line?
map hard nofile 1000
root soft nofile 1000
root hard nofile 1010
map soft nproc 1200
map hard nproc 1200
root soft nproc 180000
root hard nproc 180000
linux
migrated from serverfault.com 2 days ago
This question came from our site for system and network administrators.
add a comment |
Need to change value corresponding to "root soft nproc" from 180000 to 40000. Sample file look like this:
Any easy way to do this in a single line?
map hard nofile 1000
root soft nofile 1000
root hard nofile 1010
map soft nproc 1200
map hard nproc 1200
root soft nproc 180000
root hard nproc 180000
linux
migrated from serverfault.com 2 days ago
This question came from our site for system and network administrators.
you are getting downvotes because it is OT for here. Ask on unix.stackexchange or superuser.com - and please format the code part properly...
– ivanivan
Apr 20 at 15:24
1
This has almost certainly been asked before
– Timothy Pulliam
Apr 21 at 1:18
add a comment |
Need to change value corresponding to "root soft nproc" from 180000 to 40000. Sample file look like this:
Any easy way to do this in a single line?
map hard nofile 1000
root soft nofile 1000
root hard nofile 1010
map soft nproc 1200
map hard nproc 1200
root soft nproc 180000
root hard nproc 180000
linux
Need to change value corresponding to "root soft nproc" from 180000 to 40000. Sample file look like this:
Any easy way to do this in a single line?
map hard nofile 1000
root soft nofile 1000
root hard nofile 1010
map soft nproc 1200
map hard nproc 1200
root soft nproc 180000
root hard nproc 180000
linux
linux
asked Apr 20 at 14:22
Arpit Garg
migrated from serverfault.com 2 days ago
This question came from our site for system and network administrators.
migrated from serverfault.com 2 days ago
This question came from our site for system and network administrators.
you are getting downvotes because it is OT for here. Ask on unix.stackexchange or superuser.com - and please format the code part properly...
– ivanivan
Apr 20 at 15:24
1
This has almost certainly been asked before
– Timothy Pulliam
Apr 21 at 1:18
add a comment |
you are getting downvotes because it is OT for here. Ask on unix.stackexchange or superuser.com - and please format the code part properly...
– ivanivan
Apr 20 at 15:24
1
This has almost certainly been asked before
– Timothy Pulliam
Apr 21 at 1:18
you are getting downvotes because it is OT for here. Ask on unix.stackexchange or superuser.com - and please format the code part properly...
– ivanivan
Apr 20 at 15:24
you are getting downvotes because it is OT for here. Ask on unix.stackexchange or superuser.com - and please format the code part properly...
– ivanivan
Apr 20 at 15:24
1
1
This has almost certainly been asked before
– Timothy Pulliam
Apr 21 at 1:18
This has almost certainly been asked before
– Timothy Pulliam
Apr 21 at 1:18
add a comment |
1 Answer
1
active
oldest
votes
You can use
sed 's/^(roots*softs*nprocs*)180000$/140000/' file > newfile
to replace the value in place use option -i
sed -i 's/^(roots*softs*nprocs*)180000/140000/' file
Syntax is: sed 's/replace_old/with_new/' file
^matches the beginning of the lines*matches any amount of whitespace characters (spaces and tabs)$matches the end of the line
The part inside (...) is captured in a group and replaced by the following part 140000 where 1 is a backreference to the captured group.
answered Apr 20 at 15:43
FreddyFreddy
2,241210
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use
sed 's/^(roots*softs*nprocs*)180000$/140000/' file > newfile
to replace the value in place use option -i
sed -i 's/^(roots*softs*nprocs*)180000/140000/' file
Syntax is: sed 's/replace_old/with_new/' file
^matches the beginning of the lines*matches any amount of whitespace characters (spaces and tabs)$matches the end of the line
The part inside (...) is captured in a group and replaced by the following part 140000 where 1 is a backreference to the captured group.
answered Apr 20 at 15:43
FreddyFreddy
2,241210
add a comment |
You can use
sed 's/^(roots*softs*nprocs*)180000$/140000/' file > newfile
to replace the value in place use option -i
sed -i 's/^(roots*softs*nprocs*)180000/140000/' file
Syntax is: sed 's/replace_old/with_new/' file
^matches the beginning of the lines*matches any amount of whitespace characters (spaces and tabs)$matches the end of the line
The part inside (...) is captured in a group and replaced by the following part 140000 where 1 is a backreference to the captured group.
answered Apr 20 at 15:43
FreddyFreddy
2,241210
add a comment |
You can use
sed 's/^(roots*softs*nprocs*)180000$/140000/' file > newfile
to replace the value in place use option -i
sed -i 's/^(roots*softs*nprocs*)180000/140000/' file
Syntax is: sed 's/replace_old/with_new/' file
^matches the beginning of the lines*matches any amount of whitespace characters (spaces and tabs)$matches the end of the line
The part inside (...) is captured in a group and replaced by the following part 140000 where 1 is a backreference to the captured group.
answered Apr 20 at 15:43
FreddyFreddy
2,241210
You can use
sed 's/^(roots*softs*nprocs*)180000$/140000/' file > newfile
to replace the value in place use option -i
sed -i 's/^(roots*softs*nprocs*)180000/140000/' file
Syntax is: sed 's/replace_old/with_new/' file
^matches the beginning of the lines*matches any amount of whitespace characters (spaces and tabs)$matches the end of the line
The part inside (...) is captured in a group and replaced by the following part 140000 where 1 is a backreference to the captured group.
answered Apr 20 at 15:43
FreddyFreddy
2,241210
answered Apr 20 at 15:43
FreddyFreddy
2,241210
answered Apr 20 at 15:43
FreddyFreddy
2,241210
answered Apr 20 at 15:43
FreddyFreddy
2,241210
2,241210
add a comment |
add a comment |
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you are getting downvotes because it is OT for here. Ask on unix.stackexchange or superuser.com - and please format the code part properly...
– ivanivan
Apr 20 at 15:24
1
This has almost certainly been asked before
– Timothy Pulliam
Apr 21 at 1:18