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Correct quoting in eval


Should variables be quoted when executed?In a Bash Script how does the continue command work with embedded loops?Why does sendmail work differently in different shells?How can I have more than one possibility in a script's shebang line?What is wrong with my init.d script [Segmentation fault]How do I check for the existence of a process without a failed exit code being returned?Preform operation in bash only if a variable is less than a second variableparallel processing reading from a file in a loopBash interactive - entire script writing to historyCron jobs monitoring using exit codeParallel ssh commands forking in background but keeping ssh open






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2















I have a script, that does nothing useful but execute the positional arguments. (I'm aware of the security risks, and the script does not make anything useful because it's a minimal working example.)



$ cat script
> #!/usr/bin/env bash
>
> eval "$*"


$ cat "docu ment"
> Lorem ipsum dolor sit amet


What I would like to do is call the script with ./script cat "docu ment", or ./script cat docu ment, but the quotes or the escape character vanishes and the script will try cat docu ment, which doesn't work. How would I fix the quoting in such a case?



EDIT: What I really want to do, is invoke a command as many times until it returns a successful exit code, or it tried n times. My script looks like this:



#!/usr/bin/env bash

# Try command several times, until it reports success (exit code 0)
# or I give up (tried n times)

tryMax=10
try=1

# Do until loop in bash
while
eval "$@"
exitcode="$?"
[[ "$exitcode" -ne 0 && "$try" -lt "$tryMax" ]]
do (( try++ ))
done

if [[ "$exitcode" -ne 0 ]]; then
echo -n "I tried hard, but did not manage to make this work. The exit code "
echo "of the last iteration of this command was: $exitcode."
exit "$exitcode"
fi









share|improve this question



















  • 1





    ./script cat ""docu ment"" will work in this case, but are you really sure that's what you want to do? It's really not viable to pass evaluable scripts in that way, by hand anyway. "$@" would do the same for your toy example - what is your real use case? What sort of commands do you expect to be provided?

    – Michael Homer
    May 5 at 8:29











  • Use @ instead of *. But better still, don't use eval. It's far more likely there's a safer way of doing whatever it is you're trying to do. Show us that, and you'll get a safe alternative.

    – roaima
    May 5 at 8:29











  • You are right. Maybe it's a XY problem. I edited the question, showing what I really want to do.

    – pfnuesel
    May 5 at 8:35











  • See also: unix.stackexchange.com/questions/251103/…

    – muru
    May 5 at 8:37











  • Unless your command has a shell construct, like pipes or variable assignments, you don't need eval

    – muru
    May 5 at 8:38

















2















I have a script, that does nothing useful but execute the positional arguments. (I'm aware of the security risks, and the script does not make anything useful because it's a minimal working example.)



$ cat script
> #!/usr/bin/env bash
>
> eval "$*"


$ cat "docu ment"
> Lorem ipsum dolor sit amet


What I would like to do is call the script with ./script cat "docu ment", or ./script cat docu ment, but the quotes or the escape character vanishes and the script will try cat docu ment, which doesn't work. How would I fix the quoting in such a case?



EDIT: What I really want to do, is invoke a command as many times until it returns a successful exit code, or it tried n times. My script looks like this:



#!/usr/bin/env bash

# Try command several times, until it reports success (exit code 0)
# or I give up (tried n times)

tryMax=10
try=1

# Do until loop in bash
while
eval "$@"
exitcode="$?"
[[ "$exitcode" -ne 0 && "$try" -lt "$tryMax" ]]
do (( try++ ))
done

if [[ "$exitcode" -ne 0 ]]; then
echo -n "I tried hard, but did not manage to make this work. The exit code "
echo "of the last iteration of this command was: $exitcode."
exit "$exitcode"
fi









share|improve this question



















  • 1





    ./script cat ""docu ment"" will work in this case, but are you really sure that's what you want to do? It's really not viable to pass evaluable scripts in that way, by hand anyway. "$@" would do the same for your toy example - what is your real use case? What sort of commands do you expect to be provided?

    – Michael Homer
    May 5 at 8:29











  • Use @ instead of *. But better still, don't use eval. It's far more likely there's a safer way of doing whatever it is you're trying to do. Show us that, and you'll get a safe alternative.

    – roaima
    May 5 at 8:29











  • You are right. Maybe it's a XY problem. I edited the question, showing what I really want to do.

    – pfnuesel
    May 5 at 8:35











  • See also: unix.stackexchange.com/questions/251103/…

    – muru
    May 5 at 8:37











  • Unless your command has a shell construct, like pipes or variable assignments, you don't need eval

    – muru
    May 5 at 8:38













2












2








2


1






I have a script, that does nothing useful but execute the positional arguments. (I'm aware of the security risks, and the script does not make anything useful because it's a minimal working example.)



$ cat script
> #!/usr/bin/env bash
>
> eval "$*"


$ cat "docu ment"
> Lorem ipsum dolor sit amet


What I would like to do is call the script with ./script cat "docu ment", or ./script cat docu ment, but the quotes or the escape character vanishes and the script will try cat docu ment, which doesn't work. How would I fix the quoting in such a case?



EDIT: What I really want to do, is invoke a command as many times until it returns a successful exit code, or it tried n times. My script looks like this:



#!/usr/bin/env bash

# Try command several times, until it reports success (exit code 0)
# or I give up (tried n times)

tryMax=10
try=1

# Do until loop in bash
while
eval "$@"
exitcode="$?"
[[ "$exitcode" -ne 0 && "$try" -lt "$tryMax" ]]
do (( try++ ))
done

if [[ "$exitcode" -ne 0 ]]; then
echo -n "I tried hard, but did not manage to make this work. The exit code "
echo "of the last iteration of this command was: $exitcode."
exit "$exitcode"
fi









share|improve this question
















I have a script, that does nothing useful but execute the positional arguments. (I'm aware of the security risks, and the script does not make anything useful because it's a minimal working example.)



$ cat script
> #!/usr/bin/env bash
>
> eval "$*"


$ cat "docu ment"
> Lorem ipsum dolor sit amet


What I would like to do is call the script with ./script cat "docu ment", or ./script cat docu ment, but the quotes or the escape character vanishes and the script will try cat docu ment, which doesn't work. How would I fix the quoting in such a case?



EDIT: What I really want to do, is invoke a command as many times until it returns a successful exit code, or it tried n times. My script looks like this:



#!/usr/bin/env bash

# Try command several times, until it reports success (exit code 0)
# or I give up (tried n times)

tryMax=10
try=1

# Do until loop in bash
while
eval "$@"
exitcode="$?"
[[ "$exitcode" -ne 0 && "$try" -lt "$tryMax" ]]
do (( try++ ))
done

if [[ "$exitcode" -ne 0 ]]; then
echo -n "I tried hard, but did not manage to make this work. The exit code "
echo "of the last iteration of this command was: $exitcode."
exit "$exitcode"
fi






bash shell-script






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited May 5 at 8:34







pfnuesel

















asked May 5 at 8:22









pfnueselpfnuesel

2,82642342




2,82642342







  • 1





    ./script cat ""docu ment"" will work in this case, but are you really sure that's what you want to do? It's really not viable to pass evaluable scripts in that way, by hand anyway. "$@" would do the same for your toy example - what is your real use case? What sort of commands do you expect to be provided?

    – Michael Homer
    May 5 at 8:29











  • Use @ instead of *. But better still, don't use eval. It's far more likely there's a safer way of doing whatever it is you're trying to do. Show us that, and you'll get a safe alternative.

    – roaima
    May 5 at 8:29











  • You are right. Maybe it's a XY problem. I edited the question, showing what I really want to do.

    – pfnuesel
    May 5 at 8:35











  • See also: unix.stackexchange.com/questions/251103/…

    – muru
    May 5 at 8:37











  • Unless your command has a shell construct, like pipes or variable assignments, you don't need eval

    – muru
    May 5 at 8:38












  • 1





    ./script cat ""docu ment"" will work in this case, but are you really sure that's what you want to do? It's really not viable to pass evaluable scripts in that way, by hand anyway. "$@" would do the same for your toy example - what is your real use case? What sort of commands do you expect to be provided?

    – Michael Homer
    May 5 at 8:29











  • Use @ instead of *. But better still, don't use eval. It's far more likely there's a safer way of doing whatever it is you're trying to do. Show us that, and you'll get a safe alternative.

    – roaima
    May 5 at 8:29











  • You are right. Maybe it's a XY problem. I edited the question, showing what I really want to do.

    – pfnuesel
    May 5 at 8:35











  • See also: unix.stackexchange.com/questions/251103/…

    – muru
    May 5 at 8:37











  • Unless your command has a shell construct, like pipes or variable assignments, you don't need eval

    – muru
    May 5 at 8:38







1




1





./script cat ""docu ment"" will work in this case, but are you really sure that's what you want to do? It's really not viable to pass evaluable scripts in that way, by hand anyway. "$@" would do the same for your toy example - what is your real use case? What sort of commands do you expect to be provided?

– Michael Homer
May 5 at 8:29





./script cat ""docu ment"" will work in this case, but are you really sure that's what you want to do? It's really not viable to pass evaluable scripts in that way, by hand anyway. "$@" would do the same for your toy example - what is your real use case? What sort of commands do you expect to be provided?

– Michael Homer
May 5 at 8:29













Use @ instead of *. But better still, don't use eval. It's far more likely there's a safer way of doing whatever it is you're trying to do. Show us that, and you'll get a safe alternative.

– roaima
May 5 at 8:29





Use @ instead of *. But better still, don't use eval. It's far more likely there's a safer way of doing whatever it is you're trying to do. Show us that, and you'll get a safe alternative.

– roaima
May 5 at 8:29













You are right. Maybe it's a XY problem. I edited the question, showing what I really want to do.

– pfnuesel
May 5 at 8:35





You are right. Maybe it's a XY problem. I edited the question, showing what I really want to do.

– pfnuesel
May 5 at 8:35













See also: unix.stackexchange.com/questions/251103/…

– muru
May 5 at 8:37





See also: unix.stackexchange.com/questions/251103/…

– muru
May 5 at 8:37













Unless your command has a shell construct, like pipes or variable assignments, you don't need eval

– muru
May 5 at 8:38





Unless your command has a shell construct, like pipes or variable assignments, you don't need eval

– muru
May 5 at 8:38










1 Answer
1






active

oldest

votes


















4














You don't need eval here. You can just use "$@":



while
"$@"
exitcode="$?"
[[ "$exitcode" -ne 0 && "$try" -lt "$tryMax" ]]
do ...


"$@" will expand to all the arguments to the script as separate "words" - respecting the original quoting that prevented word splitting - and then leave you with the first argument as the command waiting to run (cat), and the remaining arguments as arguments to cat (docu ment).



Where this won't work:



  • If you want the command passed in to use other higher-level shell constructs, like pipes, function definitions, loops, etc. These are all processed before parameter expansion, and won't be attempted again after "$@" is expanded.

  • If the command has its return code negated ! cmd. ! is also processed at the start of handling a command, before parameter expansion.

  • If the command is multiple commands x ; y or $'xny' or x $'n' y, or the same with && or ||. All those are just regular arguments.

  • If your command has variable assignments preceding it like LD_LIBRARY_PATH=/x foo. You can put them before the script name, but not the argument command.

  • If the command has redirections >foo, 3<bar in it. These may or may not be able to be affixed to the script, since the script has its own logging output.

  • If the command has here-documents or here-strings. These will only be readable one time if affixed to the script itself, so depending on exactly when the command fails you might or might not be all right. These would be very difficult to pass in suitably for eval anyway.

  • If the command is a subshell ( ... ) or command group ... ; . These will be treated as commands called ( and {, not as syntactic constructs.

  • If the command contains command substitution $(...) that needs to be run repeatedly. You can use that (or any other shell construct) to generate the original arguments, but they will all be fixed strings once the script starts running.

  • If the command has any other element that should be evaluated repeatedly, like $RANDOM or an arithmetic expansion $((i++)).

  • If the command is time. This is a shell reserved word, and not a built-in command, so it is also processed before parameter expansion.

Otherwise, however, you can successfully avoid eval entirely, and should probably do so. It's very fragile to construct correctly even ignoring any possible security issues.






share|improve this answer

























  • An excellent answer! Thank you very much for taking the time to answer so comprehensively.

    – pfnuesel
    May 5 at 9:14











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4














You don't need eval here. You can just use "$@":



while
"$@"
exitcode="$?"
[[ "$exitcode" -ne 0 && "$try" -lt "$tryMax" ]]
do ...


"$@" will expand to all the arguments to the script as separate "words" - respecting the original quoting that prevented word splitting - and then leave you with the first argument as the command waiting to run (cat), and the remaining arguments as arguments to cat (docu ment).



Where this won't work:



  • If you want the command passed in to use other higher-level shell constructs, like pipes, function definitions, loops, etc. These are all processed before parameter expansion, and won't be attempted again after "$@" is expanded.

  • If the command has its return code negated ! cmd. ! is also processed at the start of handling a command, before parameter expansion.

  • If the command is multiple commands x ; y or $'xny' or x $'n' y, or the same with && or ||. All those are just regular arguments.

  • If your command has variable assignments preceding it like LD_LIBRARY_PATH=/x foo. You can put them before the script name, but not the argument command.

  • If the command has redirections >foo, 3<bar in it. These may or may not be able to be affixed to the script, since the script has its own logging output.

  • If the command has here-documents or here-strings. These will only be readable one time if affixed to the script itself, so depending on exactly when the command fails you might or might not be all right. These would be very difficult to pass in suitably for eval anyway.

  • If the command is a subshell ( ... ) or command group ... ; . These will be treated as commands called ( and {, not as syntactic constructs.

  • If the command contains command substitution $(...) that needs to be run repeatedly. You can use that (or any other shell construct) to generate the original arguments, but they will all be fixed strings once the script starts running.

  • If the command has any other element that should be evaluated repeatedly, like $RANDOM or an arithmetic expansion $((i++)).

  • If the command is time. This is a shell reserved word, and not a built-in command, so it is also processed before parameter expansion.

Otherwise, however, you can successfully avoid eval entirely, and should probably do so. It's very fragile to construct correctly even ignoring any possible security issues.






share|improve this answer

























  • An excellent answer! Thank you very much for taking the time to answer so comprehensively.

    – pfnuesel
    May 5 at 9:14















4














You don't need eval here. You can just use "$@":



while
"$@"
exitcode="$?"
[[ "$exitcode" -ne 0 && "$try" -lt "$tryMax" ]]
do ...


"$@" will expand to all the arguments to the script as separate "words" - respecting the original quoting that prevented word splitting - and then leave you with the first argument as the command waiting to run (cat), and the remaining arguments as arguments to cat (docu ment).



Where this won't work:



  • If you want the command passed in to use other higher-level shell constructs, like pipes, function definitions, loops, etc. These are all processed before parameter expansion, and won't be attempted again after "$@" is expanded.

  • If the command has its return code negated ! cmd. ! is also processed at the start of handling a command, before parameter expansion.

  • If the command is multiple commands x ; y or $'xny' or x $'n' y, or the same with && or ||. All those are just regular arguments.

  • If your command has variable assignments preceding it like LD_LIBRARY_PATH=/x foo. You can put them before the script name, but not the argument command.

  • If the command has redirections >foo, 3<bar in it. These may or may not be able to be affixed to the script, since the script has its own logging output.

  • If the command has here-documents or here-strings. These will only be readable one time if affixed to the script itself, so depending on exactly when the command fails you might or might not be all right. These would be very difficult to pass in suitably for eval anyway.

  • If the command is a subshell ( ... ) or command group ... ; . These will be treated as commands called ( and {, not as syntactic constructs.

  • If the command contains command substitution $(...) that needs to be run repeatedly. You can use that (or any other shell construct) to generate the original arguments, but they will all be fixed strings once the script starts running.

  • If the command has any other element that should be evaluated repeatedly, like $RANDOM or an arithmetic expansion $((i++)).

  • If the command is time. This is a shell reserved word, and not a built-in command, so it is also processed before parameter expansion.

Otherwise, however, you can successfully avoid eval entirely, and should probably do so. It's very fragile to construct correctly even ignoring any possible security issues.






share|improve this answer

























  • An excellent answer! Thank you very much for taking the time to answer so comprehensively.

    – pfnuesel
    May 5 at 9:14













4












4








4







You don't need eval here. You can just use "$@":



while
"$@"
exitcode="$?"
[[ "$exitcode" -ne 0 && "$try" -lt "$tryMax" ]]
do ...


"$@" will expand to all the arguments to the script as separate "words" - respecting the original quoting that prevented word splitting - and then leave you with the first argument as the command waiting to run (cat), and the remaining arguments as arguments to cat (docu ment).



Where this won't work:



  • If you want the command passed in to use other higher-level shell constructs, like pipes, function definitions, loops, etc. These are all processed before parameter expansion, and won't be attempted again after "$@" is expanded.

  • If the command has its return code negated ! cmd. ! is also processed at the start of handling a command, before parameter expansion.

  • If the command is multiple commands x ; y or $'xny' or x $'n' y, or the same with && or ||. All those are just regular arguments.

  • If your command has variable assignments preceding it like LD_LIBRARY_PATH=/x foo. You can put them before the script name, but not the argument command.

  • If the command has redirections >foo, 3<bar in it. These may or may not be able to be affixed to the script, since the script has its own logging output.

  • If the command has here-documents or here-strings. These will only be readable one time if affixed to the script itself, so depending on exactly when the command fails you might or might not be all right. These would be very difficult to pass in suitably for eval anyway.

  • If the command is a subshell ( ... ) or command group ... ; . These will be treated as commands called ( and {, not as syntactic constructs.

  • If the command contains command substitution $(...) that needs to be run repeatedly. You can use that (or any other shell construct) to generate the original arguments, but they will all be fixed strings once the script starts running.

  • If the command has any other element that should be evaluated repeatedly, like $RANDOM or an arithmetic expansion $((i++)).

  • If the command is time. This is a shell reserved word, and not a built-in command, so it is also processed before parameter expansion.

Otherwise, however, you can successfully avoid eval entirely, and should probably do so. It's very fragile to construct correctly even ignoring any possible security issues.






share|improve this answer















You don't need eval here. You can just use "$@":



while
"$@"
exitcode="$?"
[[ "$exitcode" -ne 0 && "$try" -lt "$tryMax" ]]
do ...


"$@" will expand to all the arguments to the script as separate "words" - respecting the original quoting that prevented word splitting - and then leave you with the first argument as the command waiting to run (cat), and the remaining arguments as arguments to cat (docu ment).



Where this won't work:



  • If you want the command passed in to use other higher-level shell constructs, like pipes, function definitions, loops, etc. These are all processed before parameter expansion, and won't be attempted again after "$@" is expanded.

  • If the command has its return code negated ! cmd. ! is also processed at the start of handling a command, before parameter expansion.

  • If the command is multiple commands x ; y or $'xny' or x $'n' y, or the same with && or ||. All those are just regular arguments.

  • If your command has variable assignments preceding it like LD_LIBRARY_PATH=/x foo. You can put them before the script name, but not the argument command.

  • If the command has redirections >foo, 3<bar in it. These may or may not be able to be affixed to the script, since the script has its own logging output.

  • If the command has here-documents or here-strings. These will only be readable one time if affixed to the script itself, so depending on exactly when the command fails you might or might not be all right. These would be very difficult to pass in suitably for eval anyway.

  • If the command is a subshell ( ... ) or command group ... ; . These will be treated as commands called ( and {, not as syntactic constructs.

  • If the command contains command substitution $(...) that needs to be run repeatedly. You can use that (or any other shell construct) to generate the original arguments, but they will all be fixed strings once the script starts running.

  • If the command has any other element that should be evaluated repeatedly, like $RANDOM or an arithmetic expansion $((i++)).

  • If the command is time. This is a shell reserved word, and not a built-in command, so it is also processed before parameter expansion.

Otherwise, however, you can successfully avoid eval entirely, and should probably do so. It's very fragile to construct correctly even ignoring any possible security issues.







share|improve this answer














share|improve this answer



share|improve this answer








edited May 5 at 9:17

























answered May 5 at 8:43









Michael HomerMichael Homer

52.2k9144181




52.2k9144181












  • An excellent answer! Thank you very much for taking the time to answer so comprehensively.

    – pfnuesel
    May 5 at 9:14

















  • An excellent answer! Thank you very much for taking the time to answer so comprehensively.

    – pfnuesel
    May 5 at 9:14
















An excellent answer! Thank you very much for taking the time to answer so comprehensively.

– pfnuesel
May 5 at 9:14





An excellent answer! Thank you very much for taking the time to answer so comprehensively.

– pfnuesel
May 5 at 9:14

















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