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When knowledge of one event tells us nothing about another
Has anyone solved PTLOS exercise 4.1?Log-linear analysis vs Breslow-day testHow to test for Pearson correlation when one variable is arbitratily fixed for number of cases?Probability of a deleterious mutation, given an observed distribution of mutationsAlternative to ANOVA when observations are derived from one anotherHow to quantify if one animal is following another“Counts” in contingency tables: Trying to understand misunderstandings with chi squared testsProbability of “manmade global warming is a problem with solutions that are cost-effective”Odds Ratio and gene mutations associationHow do we call when one model is trained by another?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
I have an example;
Say I have two genes on two different locations on two different chromosomes.
P(A) = gene is from location 1
P(B) = gene is from location 2
Geneticists believe that knowledge of the gene at one location tells us nothing about the gene at another location.
So are events A and B independent or mutually exclusive?
Mutually exclusive events cannot occur at once but both genes can exist on two different chromosomes at the same time, so shouldn't A and B be independent of each other?
I guess I am answering my own question then.
terminology independence biostatistics
edited May 5 at 5:54
Stephan Kolassa
50.6k8103189
asked May 5 at 4:53
saintacaciasaintacacia
275
$endgroup$
add a comment |
$begingroup$
I have an example;
Say I have two genes on two different locations on two different chromosomes.
P(A) = gene is from location 1
P(B) = gene is from location 2
Geneticists believe that knowledge of the gene at one location tells us nothing about the gene at another location.
So are events A and B independent or mutually exclusive?
Mutually exclusive events cannot occur at once but both genes can exist on two different chromosomes at the same time, so shouldn't A and B be independent of each other?
I guess I am answering my own question then.
terminology independence biostatistics
edited May 5 at 5:54
Stephan Kolassa
50.6k8103189
asked May 5 at 4:53
saintacaciasaintacacia
275
$endgroup$
add a comment |
$begingroup$
I have an example;
Say I have two genes on two different locations on two different chromosomes.
P(A) = gene is from location 1
P(B) = gene is from location 2
Geneticists believe that knowledge of the gene at one location tells us nothing about the gene at another location.
So are events A and B independent or mutually exclusive?
Mutually exclusive events cannot occur at once but both genes can exist on two different chromosomes at the same time, so shouldn't A and B be independent of each other?
I guess I am answering my own question then.
terminology independence biostatistics
edited May 5 at 5:54
Stephan Kolassa
50.6k8103189
asked May 5 at 4:53
saintacaciasaintacacia
275
$endgroup$
I have an example;
Say I have two genes on two different locations on two different chromosomes.
P(A) = gene is from location 1
P(B) = gene is from location 2
Geneticists believe that knowledge of the gene at one location tells us nothing about the gene at another location.
So are events A and B independent or mutually exclusive?
Mutually exclusive events cannot occur at once but both genes can exist on two different chromosomes at the same time, so shouldn't A and B be independent of each other?
I guess I am answering my own question then.
terminology independence biostatistics
terminology independence biostatistics
edited May 5 at 5:54
Stephan Kolassa
50.6k8103189
asked May 5 at 4:53
saintacaciasaintacacia
275
edited May 5 at 5:54
Stephan Kolassa
50.6k8103189
asked May 5 at 4:53
saintacaciasaintacacia
275
edited May 5 at 5:54
Stephan Kolassa
50.6k8103189
edited May 5 at 5:54
Stephan Kolassa
50.6k8103189
edited May 5 at 5:54
Stephan Kolassa
50.6k8103189
50.6k8103189
asked May 5 at 4:53
saintacaciasaintacacia
275
asked May 5 at 4:53
saintacaciasaintacacia
275
asked May 5 at 4:53
saintacaciasaintacacia
275
275
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Yes, you are answering your own question.
Wikipedia:
Two events are independent, statistically independent, or stochastically independent if the occurrence of one does not affect the probability of occurrence of the other.
If two events are mutually exclusive, then the presence of one event tells you that the other cannot occur, i.e., the presence of A implies that the probability for B is zero. This is certainly not independence. In your application, the correct term is "independent".
(Incidentally, genes are not necessarily independent, see linkage disequilibrium.)
answered May 5 at 5:53
Stephan KolassaStephan Kolassa
50.6k8103189
$endgroup$
$begingroup$
Hi Stephan, thanks for clarifying that and for the interesting article. I could not follow all the math but it was very interesting reading about linkage disequilibrium.
$endgroup$
– saintacacia
May 5 at 6:35
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
$begingroup$
Yes, you are answering your own question.
Wikipedia:
Two events are independent, statistically independent, or stochastically independent if the occurrence of one does not affect the probability of occurrence of the other.
If two events are mutually exclusive, then the presence of one event tells you that the other cannot occur, i.e., the presence of A implies that the probability for B is zero. This is certainly not independence. In your application, the correct term is "independent".
(Incidentally, genes are not necessarily independent, see linkage disequilibrium.)
answered May 5 at 5:53
Stephan KolassaStephan Kolassa
50.6k8103189
$endgroup$
$begingroup$
Hi Stephan, thanks for clarifying that and for the interesting article. I could not follow all the math but it was very interesting reading about linkage disequilibrium.
$endgroup$
– saintacacia
May 5 at 6:35
add a comment |
$begingroup$
Yes, you are answering your own question.
Wikipedia:
Two events are independent, statistically independent, or stochastically independent if the occurrence of one does not affect the probability of occurrence of the other.
If two events are mutually exclusive, then the presence of one event tells you that the other cannot occur, i.e., the presence of A implies that the probability for B is zero. This is certainly not independence. In your application, the correct term is "independent".
(Incidentally, genes are not necessarily independent, see linkage disequilibrium.)
answered May 5 at 5:53
Stephan KolassaStephan Kolassa
50.6k8103189
$endgroup$
$begingroup$
Hi Stephan, thanks for clarifying that and for the interesting article. I could not follow all the math but it was very interesting reading about linkage disequilibrium.
$endgroup$
– saintacacia
May 5 at 6:35
add a comment |
$begingroup$
Yes, you are answering your own question.
Wikipedia:
Two events are independent, statistically independent, or stochastically independent if the occurrence of one does not affect the probability of occurrence of the other.
If two events are mutually exclusive, then the presence of one event tells you that the other cannot occur, i.e., the presence of A implies that the probability for B is zero. This is certainly not independence. In your application, the correct term is "independent".
(Incidentally, genes are not necessarily independent, see linkage disequilibrium.)
answered May 5 at 5:53
Stephan KolassaStephan Kolassa
50.6k8103189
$endgroup$
Yes, you are answering your own question.
Wikipedia:
Two events are independent, statistically independent, or stochastically independent if the occurrence of one does not affect the probability of occurrence of the other.
If two events are mutually exclusive, then the presence of one event tells you that the other cannot occur, i.e., the presence of A implies that the probability for B is zero. This is certainly not independence. In your application, the correct term is "independent".
(Incidentally, genes are not necessarily independent, see linkage disequilibrium.)
answered May 5 at 5:53
Stephan KolassaStephan Kolassa
50.6k8103189
answered May 5 at 5:53
Stephan KolassaStephan Kolassa
50.6k8103189
answered May 5 at 5:53
Stephan KolassaStephan Kolassa
50.6k8103189
answered May 5 at 5:53
Stephan KolassaStephan Kolassa
50.6k8103189
50.6k8103189
$begingroup$
Hi Stephan, thanks for clarifying that and for the interesting article. I could not follow all the math but it was very interesting reading about linkage disequilibrium.
$endgroup$
– saintacacia
May 5 at 6:35
add a comment |
$begingroup$
Hi Stephan, thanks for clarifying that and for the interesting article. I could not follow all the math but it was very interesting reading about linkage disequilibrium.
$endgroup$
– saintacacia
May 5 at 6:35
$begingroup$
Hi Stephan, thanks for clarifying that and for the interesting article. I could not follow all the math but it was very interesting reading about linkage disequilibrium.
$endgroup$
– saintacacia
May 5 at 6:35
$begingroup$
Hi Stephan, thanks for clarifying that and for the interesting article. I could not follow all the math but it was very interesting reading about linkage disequilibrium.
$endgroup$
– saintacacia
May 5 at 6:35
add a comment |
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