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Command not found error throwed about function on shell script called with bash and curl after sudo su

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0

When doing:

#!/bin/bash
function01() 
 echo "Func01"

function02() 
 echo "Func02"

function03() 
 echo "Func03"

clear
function01
function02
#sudo su
function03

and calling as:

curl http://192.168.1.1:80/myScript.sh | sudo bash 

or

curl http://192.168.1.1:80/myScript.sh | bash 

It run ok but if uncommenting the line:

#sudo su

above then it throw the error:

bash: line 1: function03: command not found

linux bash shell-scripting

share|improve this question

asked May 20 at 19:13

MarkMark

115

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Erm, what are you even expecting sudo su to do in that context? BTW, you really should use sudo -i, not sudo su`.
  
  – Zoredache
  May 20 at 20:09
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Zoredache There is a block of code that doesnt run with just sudo context then doing sudo su to become root and execute the block, I dont know about sudo -i , i will try with it, thanks. By the way the code i wrote is really wrong ?
  
  – Mark
  May 20 at 20:21
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  If you are expecting sudo to be able to run that function, it isn't going to work. Those functions exist in the scope of the current shell running that script. If you use sudo that spawns a completely new shell. Your functions are not copied to the new shell.
  
  – Zoredache
  May 20 at 23:11
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Zoredache Im doing sudo echo 'something' > /etc/fstab and it dont work, need be with real root and I tried using sudo -i on the minimal example as you told on this body question but the error remains the same
  
  – Mark
  May 20 at 23:31
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Zoredache understood, then sudo su is creating another context, then i believe need call sudo -i before calling script with curl/bash and removing all sudo after it, thanks
  
  – Mark
  May 20 at 23:35
  

  
  
  
  

 | 
show 1 more comment

0

When doing:

#!/bin/bash
function01() 
 echo "Func01"

function02() 
 echo "Func02"

function03() 
 echo "Func03"

clear
function01
function02
#sudo su
function03

and calling as:

curl http://192.168.1.1:80/myScript.sh | sudo bash 

or

curl http://192.168.1.1:80/myScript.sh | bash 

It run ok but if uncommenting the line:

#sudo su

above then it throw the error:

bash: line 1: function03: command not found

linux bash shell-scripting

share|improve this question

asked May 20 at 19:13

MarkMark

115

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Erm, what are you even expecting sudo su to do in that context? BTW, you really should use sudo -i, not sudo su`.
  
  – Zoredache
  May 20 at 20:09
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Zoredache There is a block of code that doesnt run with just sudo context then doing sudo su to become root and execute the block, I dont know about sudo -i , i will try with it, thanks. By the way the code i wrote is really wrong ?
  
  – Mark
  May 20 at 20:21
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  If you are expecting sudo to be able to run that function, it isn't going to work. Those functions exist in the scope of the current shell running that script. If you use sudo that spawns a completely new shell. Your functions are not copied to the new shell.
  
  – Zoredache
  May 20 at 23:11
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Zoredache Im doing sudo echo 'something' > /etc/fstab and it dont work, need be with real root and I tried using sudo -i on the minimal example as you told on this body question but the error remains the same
  
  – Mark
  May 20 at 23:31
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Zoredache understood, then sudo su is creating another context, then i believe need call sudo -i before calling script with curl/bash and removing all sudo after it, thanks
  
  – Mark
  May 20 at 23:35
  

  
  
  
  

 | 
show 1 more comment

When doing:

#!/bin/bash
function01() 
 echo "Func01"

function02() 
 echo "Func02"

function03() 
 echo "Func03"

clear
function01
function02
#sudo su
function03

and calling as:

curl http://192.168.1.1:80/myScript.sh | sudo bash 

or

curl http://192.168.1.1:80/myScript.sh | bash 

It run ok but if uncommenting the line:

#sudo su

above then it throw the error:

bash: line 1: function03: command not found

linux bash shell-scripting

share|improve this question

asked May 20 at 19:13

MarkMark

115

#!/bin/bash
function01() 
 echo "Func01"

function02() 
 echo "Func02"

function03() 
 echo "Func03"

clear
function01
function02
#sudo su
function03

curl http://192.168.1.1:80/myScript.sh | sudo bash 

curl http://192.168.1.1:80/myScript.sh | bash 

#sudo su

bash: line 1: function03: command not found

share|improve this question

asked May 20 at 19:13

MarkMark

115

share|improve this question

asked May 20 at 19:13

MarkMark

115

asked May 20 at 19:13

MarkMark

115

asked May 20 at 19:13

MarkMark

115