Cycle through MeshStyle directives in ListLinePlot
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Cycle through MeshStyle directives in ListLinePlot
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
I would like to specify my own mesh styles for successive data rows within a single ListLinePlot. The Wolfram reference for ListLinePlot lists PlotStyle and MeshStyle as options for ListLinePlot. Both options' refrence pages state that
successive directives gi should be used cyclically
This works fine for PlotStyle, but not for MeshStyle. The following was run on Mathematica 12.0.0.0 on Linux:
ListLinePlot[
Table[1/n + RandomReal[-1, 1]/n, n, 1, 20],
Table[1/n, n, 1, 20]
,
Mesh -> All,
PlotStyle -> Red, Blue,
MeshStyle -> Yellow, Green
]
With this output:
Is this a bug or am I doing something wrong?
plotting
asked Jun 4 at 13:42
DLichtiDLichti
1536
$endgroup$
add a comment |
$begingroup$
I would like to specify my own mesh styles for successive data rows within a single ListLinePlot. The Wolfram reference for ListLinePlot lists PlotStyle and MeshStyle as options for ListLinePlot. Both options' refrence pages state that
successive directives gi should be used cyclically
This works fine for PlotStyle, but not for MeshStyle. The following was run on Mathematica 12.0.0.0 on Linux:
ListLinePlot[
Table[1/n + RandomReal[-1, 1]/n, n, 1, 20],
Table[1/n, n, 1, 20]
,
Mesh -> All,
PlotStyle -> Red, Blue,
MeshStyle -> Yellow, Green
]
With this output:
Is this a bug or am I doing something wrong?
plotting
asked Jun 4 at 13:42
DLichtiDLichti
1536
$endgroup$
add a comment |
$begingroup$
I would like to specify my own mesh styles for successive data rows within a single ListLinePlot. The Wolfram reference for ListLinePlot lists PlotStyle and MeshStyle as options for ListLinePlot. Both options' refrence pages state that
successive directives gi should be used cyclically
This works fine for PlotStyle, but not for MeshStyle. The following was run on Mathematica 12.0.0.0 on Linux:
ListLinePlot[
Table[1/n + RandomReal[-1, 1]/n, n, 1, 20],
Table[1/n, n, 1, 20]
,
Mesh -> All,
PlotStyle -> Red, Blue,
MeshStyle -> Yellow, Green
]
With this output:
Is this a bug or am I doing something wrong?
plotting
asked Jun 4 at 13:42
DLichtiDLichti
1536
$endgroup$
I would like to specify my own mesh styles for successive data rows within a single ListLinePlot. The Wolfram reference for ListLinePlot lists PlotStyle and MeshStyle as options for ListLinePlot. Both options' refrence pages state that
successive directives gi should be used cyclically
This works fine for PlotStyle, but not for MeshStyle. The following was run on Mathematica 12.0.0.0 on Linux:
ListLinePlot[
Table[1/n + RandomReal[-1, 1]/n, n, 1, 20],
Table[1/n, n, 1, 20]
,
Mesh -> All,
PlotStyle -> Red, Blue,
MeshStyle -> Yellow, Green
]
With this output:
Is this a bug or am I doing something wrong?
plotting
plotting
asked Jun 4 at 13:42
DLichtiDLichti
1536
asked Jun 4 at 13:42
DLichtiDLichti
1536
asked Jun 4 at 13:42
DLichtiDLichti
1536
asked Jun 4 at 13:42
DLichtiDLichti
1536
asked Jun 4 at 13:42
DLichtiDLichti
1536
1536
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
SeedRandom[123]
data = Table[1/n + RandomReal[-1, 1]/n, n, 1, 20], Table[1/n, n, 1, 20];
Assuming that you want different mesh styles for points on different lines (with default setting for the option MeshFunctions, that is, #&), you can
- Combine two separate plots using
Show:
Show[MapThread[ListLinePlot[#, Mesh -> All, PlotRange -> All,
PlotStyle -> #2, MeshStyle -> #3]&, data, Red, Blue, Yellow, Green],
PlotRange -> All]
- Post-process the output of a single
ListLinePlotto change the
colors of points:
llp = ListLinePlot[data, Mesh -> All,
PlotStyle -> Red, Blue, MeshStyle -> Yellow, Green, PlotRange -> All];
meshstyles = Reverse @ Yellow, Green;
llp /. p_Point :> First[meshstyles = RotateRight[meshstyles]], p
same picture
- Use a
Dynamicmesh style:
meshstyles = Reverse @ Yellow, Green;
ListLinePlot[data, Mesh -> All, PlotStyle -> Red, Blue, PlotRange -> All,
MeshStyle -> Dynamic[First[meshstyles = RotateRight[meshstyles]]]]
same picture
- Use a function as the
MeshStylesetting:
meshstyles = Reverse @ Yellow, Green;
ListLinePlot[data, Mesh ->All, PlotStyle -> Red, Blue,PlotRange -> All,
MeshStyle -> (First[meshstyles = RotateRight[meshstyles]],
PointSize[Large], #&)]
same picture
All the methods above work with arbitrary number of data rows:
n = 10;
meshstyles = Reverse [ ColorData[70] /@ Range[n]];
plotstyles = ColorData[97] /@ Range[n];
SeedRandom[1]
data = MapThread[Plus, 5 + Range[n], (Accumulate /@ RandomReal[-1, 1, n, 15])];
ListLinePlot[data, Mesh -> All, ImageSize -> Large, PlotRange -> All,
PlotStyle -> plotstyles,
MeshStyle -> (First[meshstyles = RotateRight[meshstyles]], PointSize[Large], # &),
PlotLegends -> LineLegend[Automatic, Range[n], LegendMarkers ->
(Graphics[#, PointSize[Large], Point[0, 0]] & /@ Reverse[meshstyles])]]
answered Jun 4 at 13:57
kglrkglr
199k10228454
$endgroup$
$begingroup$
The styles rotation can be simplified by droppingReverse@...and usingLast[meshstyles = RotateLeft[meshstyles]], # &. Setting thePointSizeis not necessary.
$endgroup$
– DLichti
Jun 6 at 9:26
$begingroup$
@DLichti, thank you; great point. Will update with an edit.
$endgroup$
– kglr
Jun 6 at 9:32
add a comment |
$begingroup$
The problem is that in order for MeshStyle to cycle through the list, you have to have more than one mesh, and this is determined by the number of MeshFunctions you have. By default, this is set to
MeshFunctions -> #1&
for ListLinePlot. If you add
MeshFunctions -> #1 &, #2 &
to your plot, Yellow will be used for the horizontal mesh, and Green for the vertical mesh, e.g.
SeedRandom[15];
ListLinePlot[Table[1/n + RandomReal[-1, 1]/n, n, 1, 20],
Table[1/n, n, 1, 20], Mesh -> 5, 7,
MeshFunctions -> #1 &, #2 &, PlotStyle -> Red, Blue,
MeshStyle -> Yellow, Green]
answered Jun 4 at 13:56
rcollyerrcollyer
28.8k674167
$endgroup$
add a comment |
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2 Answers
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2 Answers
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$begingroup$
SeedRandom[123]
data = Table[1/n + RandomReal[-1, 1]/n, n, 1, 20], Table[1/n, n, 1, 20];
Assuming that you want different mesh styles for points on different lines (with default setting for the option MeshFunctions, that is, #&), you can
- Combine two separate plots using
Show:
Show[MapThread[ListLinePlot[#, Mesh -> All, PlotRange -> All,
PlotStyle -> #2, MeshStyle -> #3]&, data, Red, Blue, Yellow, Green],
PlotRange -> All]
- Post-process the output of a single
ListLinePlotto change the
colors of points:
llp = ListLinePlot[data, Mesh -> All,
PlotStyle -> Red, Blue, MeshStyle -> Yellow, Green, PlotRange -> All];
meshstyles = Reverse @ Yellow, Green;
llp /. p_Point :> First[meshstyles = RotateRight[meshstyles]], p
same picture
- Use a
Dynamicmesh style:
meshstyles = Reverse @ Yellow, Green;
ListLinePlot[data, Mesh -> All, PlotStyle -> Red, Blue, PlotRange -> All,
MeshStyle -> Dynamic[First[meshstyles = RotateRight[meshstyles]]]]
same picture
- Use a function as the
MeshStylesetting:
meshstyles = Reverse @ Yellow, Green;
ListLinePlot[data, Mesh ->All, PlotStyle -> Red, Blue,PlotRange -> All,
MeshStyle -> (First[meshstyles = RotateRight[meshstyles]],
PointSize[Large], #&)]
same picture
All the methods above work with arbitrary number of data rows:
n = 10;
meshstyles = Reverse [ ColorData[70] /@ Range[n]];
plotstyles = ColorData[97] /@ Range[n];
SeedRandom[1]
data = MapThread[Plus, 5 + Range[n], (Accumulate /@ RandomReal[-1, 1, n, 15])];
ListLinePlot[data, Mesh -> All, ImageSize -> Large, PlotRange -> All,
PlotStyle -> plotstyles,
MeshStyle -> (First[meshstyles = RotateRight[meshstyles]], PointSize[Large], # &),
PlotLegends -> LineLegend[Automatic, Range[n], LegendMarkers ->
(Graphics[#, PointSize[Large], Point[0, 0]] & /@ Reverse[meshstyles])]]
answered Jun 4 at 13:57
kglrkglr
199k10228454
$endgroup$
$begingroup$
The styles rotation can be simplified by droppingReverse@...and usingLast[meshstyles = RotateLeft[meshstyles]], # &. Setting thePointSizeis not necessary.
$endgroup$
– DLichti
Jun 6 at 9:26
$begingroup$
@DLichti, thank you; great point. Will update with an edit.
$endgroup$
– kglr
Jun 6 at 9:32
add a comment |
$begingroup$
SeedRandom[123]
data = Table[1/n + RandomReal[-1, 1]/n, n, 1, 20], Table[1/n, n, 1, 20];
Assuming that you want different mesh styles for points on different lines (with default setting for the option MeshFunctions, that is, #&), you can
- Combine two separate plots using
Show:
Show[MapThread[ListLinePlot[#, Mesh -> All, PlotRange -> All,
PlotStyle -> #2, MeshStyle -> #3]&, data, Red, Blue, Yellow, Green],
PlotRange -> All]
- Post-process the output of a single
ListLinePlotto change the
colors of points:
llp = ListLinePlot[data, Mesh -> All,
PlotStyle -> Red, Blue, MeshStyle -> Yellow, Green, PlotRange -> All];
meshstyles = Reverse @ Yellow, Green;
llp /. p_Point :> First[meshstyles = RotateRight[meshstyles]], p
same picture
- Use a
Dynamicmesh style:
meshstyles = Reverse @ Yellow, Green;
ListLinePlot[data, Mesh -> All, PlotStyle -> Red, Blue, PlotRange -> All,
MeshStyle -> Dynamic[First[meshstyles = RotateRight[meshstyles]]]]
same picture
- Use a function as the
MeshStylesetting:
meshstyles = Reverse @ Yellow, Green;
ListLinePlot[data, Mesh ->All, PlotStyle -> Red, Blue,PlotRange -> All,
MeshStyle -> (First[meshstyles = RotateRight[meshstyles]],
PointSize[Large], #&)]
same picture
All the methods above work with arbitrary number of data rows:
n = 10;
meshstyles = Reverse [ ColorData[70] /@ Range[n]];
plotstyles = ColorData[97] /@ Range[n];
SeedRandom[1]
data = MapThread[Plus, 5 + Range[n], (Accumulate /@ RandomReal[-1, 1, n, 15])];
ListLinePlot[data, Mesh -> All, ImageSize -> Large, PlotRange -> All,
PlotStyle -> plotstyles,
MeshStyle -> (First[meshstyles = RotateRight[meshstyles]], PointSize[Large], # &),
PlotLegends -> LineLegend[Automatic, Range[n], LegendMarkers ->
(Graphics[#, PointSize[Large], Point[0, 0]] & /@ Reverse[meshstyles])]]
answered Jun 4 at 13:57
kglrkglr
199k10228454
$endgroup$
$begingroup$
The styles rotation can be simplified by droppingReverse@...and usingLast[meshstyles = RotateLeft[meshstyles]], # &. Setting thePointSizeis not necessary.
$endgroup$
– DLichti
Jun 6 at 9:26
$begingroup$
@DLichti, thank you; great point. Will update with an edit.
$endgroup$
– kglr
Jun 6 at 9:32
add a comment |
$begingroup$
SeedRandom[123]
data = Table[1/n + RandomReal[-1, 1]/n, n, 1, 20], Table[1/n, n, 1, 20];
Assuming that you want different mesh styles for points on different lines (with default setting for the option MeshFunctions, that is, #&), you can
- Combine two separate plots using
Show:
Show[MapThread[ListLinePlot[#, Mesh -> All, PlotRange -> All,
PlotStyle -> #2, MeshStyle -> #3]&, data, Red, Blue, Yellow, Green],
PlotRange -> All]
- Post-process the output of a single
ListLinePlotto change the
colors of points:
llp = ListLinePlot[data, Mesh -> All,
PlotStyle -> Red, Blue, MeshStyle -> Yellow, Green, PlotRange -> All];
meshstyles = Reverse @ Yellow, Green;
llp /. p_Point :> First[meshstyles = RotateRight[meshstyles]], p
same picture
- Use a
Dynamicmesh style:
meshstyles = Reverse @ Yellow, Green;
ListLinePlot[data, Mesh -> All, PlotStyle -> Red, Blue, PlotRange -> All,
MeshStyle -> Dynamic[First[meshstyles = RotateRight[meshstyles]]]]
same picture
- Use a function as the
MeshStylesetting:
meshstyles = Reverse @ Yellow, Green;
ListLinePlot[data, Mesh ->All, PlotStyle -> Red, Blue,PlotRange -> All,
MeshStyle -> (First[meshstyles = RotateRight[meshstyles]],
PointSize[Large], #&)]
same picture
All the methods above work with arbitrary number of data rows:
n = 10;
meshstyles = Reverse [ ColorData[70] /@ Range[n]];
plotstyles = ColorData[97] /@ Range[n];
SeedRandom[1]
data = MapThread[Plus, 5 + Range[n], (Accumulate /@ RandomReal[-1, 1, n, 15])];
ListLinePlot[data, Mesh -> All, ImageSize -> Large, PlotRange -> All,
PlotStyle -> plotstyles,
MeshStyle -> (First[meshstyles = RotateRight[meshstyles]], PointSize[Large], # &),
PlotLegends -> LineLegend[Automatic, Range[n], LegendMarkers ->
(Graphics[#, PointSize[Large], Point[0, 0]] & /@ Reverse[meshstyles])]]
answered Jun 4 at 13:57
kglrkglr
199k10228454
$endgroup$
SeedRandom[123]
data = Table[1/n + RandomReal[-1, 1]/n, n, 1, 20], Table[1/n, n, 1, 20];
Assuming that you want different mesh styles for points on different lines (with default setting for the option MeshFunctions, that is, #&), you can
- Combine two separate plots using
Show:
Show[MapThread[ListLinePlot[#, Mesh -> All, PlotRange -> All,
PlotStyle -> #2, MeshStyle -> #3]&, data, Red, Blue, Yellow, Green],
PlotRange -> All]
- Post-process the output of a single
ListLinePlotto change the
colors of points:
llp = ListLinePlot[data, Mesh -> All,
PlotStyle -> Red, Blue, MeshStyle -> Yellow, Green, PlotRange -> All];
meshstyles = Reverse @ Yellow, Green;
llp /. p_Point :> First[meshstyles = RotateRight[meshstyles]], p
same picture
- Use a
Dynamicmesh style:
meshstyles = Reverse @ Yellow, Green;
ListLinePlot[data, Mesh -> All, PlotStyle -> Red, Blue, PlotRange -> All,
MeshStyle -> Dynamic[First[meshstyles = RotateRight[meshstyles]]]]
same picture
- Use a function as the
MeshStylesetting:
meshstyles = Reverse @ Yellow, Green;
ListLinePlot[data, Mesh ->All, PlotStyle -> Red, Blue,PlotRange -> All,
MeshStyle -> (First[meshstyles = RotateRight[meshstyles]],
PointSize[Large], #&)]
same picture
All the methods above work with arbitrary number of data rows:
n = 10;
meshstyles = Reverse [ ColorData[70] /@ Range[n]];
plotstyles = ColorData[97] /@ Range[n];
SeedRandom[1]
data = MapThread[Plus, 5 + Range[n], (Accumulate /@ RandomReal[-1, 1, n, 15])];
ListLinePlot[data, Mesh -> All, ImageSize -> Large, PlotRange -> All,
PlotStyle -> plotstyles,
MeshStyle -> (First[meshstyles = RotateRight[meshstyles]], PointSize[Large], # &),
PlotLegends -> LineLegend[Automatic, Range[n], LegendMarkers ->
(Graphics[#, PointSize[Large], Point[0, 0]] & /@ Reverse[meshstyles])]]
answered Jun 4 at 13:57
kglrkglr
199k10228454
edited Jun 4 at 23:20
answered Jun 4 at 13:57
kglrkglr
199k10228454
answered Jun 4 at 13:57
kglrkglr
199k10228454
answered Jun 4 at 13:57
kglrkglr
199k10228454
199k10228454
$begingroup$
The styles rotation can be simplified by droppingReverse@...and usingLast[meshstyles = RotateLeft[meshstyles]], # &. Setting thePointSizeis not necessary.
$endgroup$
– DLichti
Jun 6 at 9:26
$begingroup$
@DLichti, thank you; great point. Will update with an edit.
$endgroup$
– kglr
Jun 6 at 9:32
add a comment |
$begingroup$
The styles rotation can be simplified by droppingReverse@...and usingLast[meshstyles = RotateLeft[meshstyles]], # &. Setting thePointSizeis not necessary.
$endgroup$
– DLichti
Jun 6 at 9:26
$begingroup$
@DLichti, thank you; great point. Will update with an edit.
$endgroup$
– kglr
Jun 6 at 9:32
$begingroup$
The styles rotation can be simplified by dropping
Reverse@... and using Last[meshstyles = RotateLeft[meshstyles]], # &. Setting the PointSize is not necessary.$endgroup$
– DLichti
Jun 6 at 9:26
$begingroup$
The styles rotation can be simplified by dropping
Reverse@... and using Last[meshstyles = RotateLeft[meshstyles]], # &. Setting the PointSize is not necessary.$endgroup$
– DLichti
Jun 6 at 9:26
$begingroup$
@DLichti, thank you; great point. Will update with an edit.
$endgroup$
– kglr
Jun 6 at 9:32
$begingroup$
@DLichti, thank you; great point. Will update with an edit.
$endgroup$
– kglr
Jun 6 at 9:32
add a comment |
$begingroup$
The problem is that in order for MeshStyle to cycle through the list, you have to have more than one mesh, and this is determined by the number of MeshFunctions you have. By default, this is set to
MeshFunctions -> #1&
for ListLinePlot. If you add
MeshFunctions -> #1 &, #2 &
to your plot, Yellow will be used for the horizontal mesh, and Green for the vertical mesh, e.g.
SeedRandom[15];
ListLinePlot[Table[1/n + RandomReal[-1, 1]/n, n, 1, 20],
Table[1/n, n, 1, 20], Mesh -> 5, 7,
MeshFunctions -> #1 &, #2 &, PlotStyle -> Red, Blue,
MeshStyle -> Yellow, Green]
answered Jun 4 at 13:56
rcollyerrcollyer
28.8k674167
$endgroup$
add a comment |
$begingroup$
The problem is that in order for MeshStyle to cycle through the list, you have to have more than one mesh, and this is determined by the number of MeshFunctions you have. By default, this is set to
MeshFunctions -> #1&
for ListLinePlot. If you add
MeshFunctions -> #1 &, #2 &
to your plot, Yellow will be used for the horizontal mesh, and Green for the vertical mesh, e.g.
SeedRandom[15];
ListLinePlot[Table[1/n + RandomReal[-1, 1]/n, n, 1, 20],
Table[1/n, n, 1, 20], Mesh -> 5, 7,
MeshFunctions -> #1 &, #2 &, PlotStyle -> Red, Blue,
MeshStyle -> Yellow, Green]
answered Jun 4 at 13:56
rcollyerrcollyer
28.8k674167
$endgroup$
add a comment |
$begingroup$
The problem is that in order for MeshStyle to cycle through the list, you have to have more than one mesh, and this is determined by the number of MeshFunctions you have. By default, this is set to
MeshFunctions -> #1&
for ListLinePlot. If you add
MeshFunctions -> #1 &, #2 &
to your plot, Yellow will be used for the horizontal mesh, and Green for the vertical mesh, e.g.
SeedRandom[15];
ListLinePlot[Table[1/n + RandomReal[-1, 1]/n, n, 1, 20],
Table[1/n, n, 1, 20], Mesh -> 5, 7,
MeshFunctions -> #1 &, #2 &, PlotStyle -> Red, Blue,
MeshStyle -> Yellow, Green]
answered Jun 4 at 13:56
rcollyerrcollyer
28.8k674167
$endgroup$
The problem is that in order for MeshStyle to cycle through the list, you have to have more than one mesh, and this is determined by the number of MeshFunctions you have. By default, this is set to
MeshFunctions -> #1&
for ListLinePlot. If you add
MeshFunctions -> #1 &, #2 &
to your plot, Yellow will be used for the horizontal mesh, and Green for the vertical mesh, e.g.
SeedRandom[15];
ListLinePlot[Table[1/n + RandomReal[-1, 1]/n, n, 1, 20],
Table[1/n, n, 1, 20], Mesh -> 5, 7,
MeshFunctions -> #1 &, #2 &, PlotStyle -> Red, Blue,
MeshStyle -> Yellow, Green]
answered Jun 4 at 13:56
rcollyerrcollyer
28.8k674167
answered Jun 4 at 13:56
rcollyerrcollyer
28.8k674167
answered Jun 4 at 13:56
rcollyerrcollyer
28.8k674167
answered Jun 4 at 13:56
rcollyerrcollyer
28.8k674167
28.8k674167
add a comment |
add a comment |
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