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What is a fully qualified name?
Is there a context where the expression `a.b::c` makes sense?What is the difference between #include <filename> and #include “filename”?What are the differences between a pointer variable and a reference variable in C++?What does the explicit keyword mean?What is the “-->” operator in C++?What is the copy-and-swap idiom?What is The Rule of Three?What are the basic rules and idioms for operator overloading?C++11 introduced a standardized memory model. What does it mean? And how is it going to affect C++ programming?Image Processing: Algorithm Improvement for 'Coca-Cola Can' RecognitionWhat are the new features in C++17?
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As far as I can tell, the term fully qualified isn't mentioned in the standard (e.g.), but I can recall "hearing" it many times online.
What do people mean when they say a name is fully qualified?
Does this count?
A::f()
or only this?
::A::f()
And, if it is standard, which wording have I not found?
c++ language-lawyer c++17
edited May 23 at 12:04
dfri
37k463105
asked May 23 at 10:35
Lightness Races in OrbitLightness Races in Orbit
302k56490844
add a comment |
As far as I can tell, the term fully qualified isn't mentioned in the standard (e.g.), but I can recall "hearing" it many times online.
What do people mean when they say a name is fully qualified?
Does this count?
A::f()
or only this?
::A::f()
And, if it is standard, which wording have I not found?
c++ language-lawyer c++17
edited May 23 at 12:04
dfri
37k463105
asked May 23 at 10:35
Lightness Races in OrbitLightness Races in Orbit
302k56490844
7
With the injected class name one can really qualify stuff.::A::A::A::A::f(). Not sure if it's "fully" though.
– StoryTeller
May 23 at 10:42
9
@StoryTeller We should petition to add that term to the standard! really-really-really-qualified-id etc
– Lightness Races in Orbit
May 23 at 11:24
What does the language-lawyer tag mean?
– Evorlor
May 23 at 21:38
5
@Evorlor Hover your mouse over it (and/or click)
– Lightness Races in Orbit
May 23 at 23:07
add a comment |
As far as I can tell, the term fully qualified isn't mentioned in the standard (e.g.), but I can recall "hearing" it many times online.
What do people mean when they say a name is fully qualified?
Does this count?
A::f()
or only this?
::A::f()
And, if it is standard, which wording have I not found?
c++ language-lawyer c++17
edited May 23 at 12:04
dfri
37k463105
asked May 23 at 10:35
Lightness Races in OrbitLightness Races in Orbit
302k56490844
As far as I can tell, the term fully qualified isn't mentioned in the standard (e.g.), but I can recall "hearing" it many times online.
What do people mean when they say a name is fully qualified?
Does this count?
A::f()
or only this?
::A::f()
And, if it is standard, which wording have I not found?
c++ language-lawyer c++17
c++ language-lawyer c++17
edited May 23 at 12:04
dfri
37k463105
asked May 23 at 10:35
Lightness Races in OrbitLightness Races in Orbit
302k56490844
edited May 23 at 12:04
dfri
37k463105
asked May 23 at 10:35
Lightness Races in OrbitLightness Races in Orbit
302k56490844
edited May 23 at 12:04
dfri
37k463105
edited May 23 at 12:04
dfri
37k463105
edited May 23 at 12:04
dfri
37k463105
37k463105
asked May 23 at 10:35
Lightness Races in OrbitLightness Races in Orbit
302k56490844
asked May 23 at 10:35
Lightness Races in OrbitLightness Races in Orbit
302k56490844
asked May 23 at 10:35
Lightness Races in OrbitLightness Races in Orbit
302k56490844
302k56490844
7
With the injected class name one can really qualify stuff.::A::A::A::A::f(). Not sure if it's "fully" though.
– StoryTeller
May 23 at 10:42
9
@StoryTeller We should petition to add that term to the standard! really-really-really-qualified-id etc
– Lightness Races in Orbit
May 23 at 11:24
What does the language-lawyer tag mean?
– Evorlor
May 23 at 21:38
5
@Evorlor Hover your mouse over it (and/or click)
– Lightness Races in Orbit
May 23 at 23:07
add a comment |
7
With the injected class name one can really qualify stuff.::A::A::A::A::f(). Not sure if it's "fully" though.
– StoryTeller
May 23 at 10:42
9
@StoryTeller We should petition to add that term to the standard! really-really-really-qualified-id etc
– Lightness Races in Orbit
May 23 at 11:24
What does the language-lawyer tag mean?
– Evorlor
May 23 at 21:38
5
@Evorlor Hover your mouse over it (and/or click)
– Lightness Races in Orbit
May 23 at 23:07
7
7
With the injected class name one can really qualify stuff.
::A::A::A::A::f(). Not sure if it's "fully" though.– StoryTeller
May 23 at 10:42
With the injected class name one can really qualify stuff.
::A::A::A::A::f(). Not sure if it's "fully" though.– StoryTeller
May 23 at 10:42
9
9
@StoryTeller We should petition to add that term to the standard! really-really-really-qualified-id etc
– Lightness Races in Orbit
May 23 at 11:24
@StoryTeller We should petition to add that term to the standard! really-really-really-qualified-id etc
– Lightness Races in Orbit
May 23 at 11:24
What does the language-lawyer tag mean?
– Evorlor
May 23 at 21:38
What does the language-lawyer tag mean?
– Evorlor
May 23 at 21:38
5
5
@Evorlor Hover your mouse over it (and/or click)
– Lightness Races in Orbit
May 23 at 23:07
@Evorlor Hover your mouse over it (and/or click)
– Lightness Races in Orbit
May 23 at 23:07
add a comment |
2 Answers
2
active
oldest
votes
An identifier that uses the scope resolution operator is a qualified name as per [expr.prim.id.qual]. Otherwise it is unqualified.
The standard doesn't define the meaning of fully qualified, but it does mention it in [library]/[requirements]/[organization]/[contents] which says (quote from standard draft)
Whenever a name x defined in the standard library is mentioned, the name x is assumed to be fully qualified as ::std::x, unless explicitly described otherwise.
For example, if the Effects: element for library function F is described as calling library function G, the function ::std::G is meant.
Wikipedia defines Fully qualified name:
In computer programming, a fully qualified name is an unambiguous name that specifies which object, function, or variable a call refers to without regard to the context of the call
Only a name qualified starting from the global namespace is unambiguous without context. This is the common usage.
answered May 23 at 10:43
eerorikaeerorika
94.4k671139
add a comment |
Indeed, it is not a standard term. It has no definition in the standard.
However, the phrase "fully qualified" appears exactly once, in [contents] (15.5.1.1 "Library contents" in the as-of-writing most current draft N4800) paragraph 3:
Whenever a name
xdefined in the standard library is mentioned, the namexis assumed to be fully qualified as::std::x, unless explicitly described otherwise.
So in this definition, only names starting with :: are fully qualified.
answered May 23 at 10:44
Sebastian RedlSebastian Redl
52k579123
add a comment |
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2 Answers
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2 Answers
2
active
oldest
votes
active
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active
oldest
votes
An identifier that uses the scope resolution operator is a qualified name as per [expr.prim.id.qual]. Otherwise it is unqualified.
The standard doesn't define the meaning of fully qualified, but it does mention it in [library]/[requirements]/[organization]/[contents] which says (quote from standard draft)
Whenever a name x defined in the standard library is mentioned, the name x is assumed to be fully qualified as ::std::x, unless explicitly described otherwise.
For example, if the Effects: element for library function F is described as calling library function G, the function ::std::G is meant.
Wikipedia defines Fully qualified name:
In computer programming, a fully qualified name is an unambiguous name that specifies which object, function, or variable a call refers to without regard to the context of the call
Only a name qualified starting from the global namespace is unambiguous without context. This is the common usage.
answered May 23 at 10:43
eerorikaeerorika
94.4k671139
add a comment |
An identifier that uses the scope resolution operator is a qualified name as per [expr.prim.id.qual]. Otherwise it is unqualified.
The standard doesn't define the meaning of fully qualified, but it does mention it in [library]/[requirements]/[organization]/[contents] which says (quote from standard draft)
Whenever a name x defined in the standard library is mentioned, the name x is assumed to be fully qualified as ::std::x, unless explicitly described otherwise.
For example, if the Effects: element for library function F is described as calling library function G, the function ::std::G is meant.
Wikipedia defines Fully qualified name:
In computer programming, a fully qualified name is an unambiguous name that specifies which object, function, or variable a call refers to without regard to the context of the call
Only a name qualified starting from the global namespace is unambiguous without context. This is the common usage.
answered May 23 at 10:43
eerorikaeerorika
94.4k671139
add a comment |
An identifier that uses the scope resolution operator is a qualified name as per [expr.prim.id.qual]. Otherwise it is unqualified.
The standard doesn't define the meaning of fully qualified, but it does mention it in [library]/[requirements]/[organization]/[contents] which says (quote from standard draft)
Whenever a name x defined in the standard library is mentioned, the name x is assumed to be fully qualified as ::std::x, unless explicitly described otherwise.
For example, if the Effects: element for library function F is described as calling library function G, the function ::std::G is meant.
Wikipedia defines Fully qualified name:
In computer programming, a fully qualified name is an unambiguous name that specifies which object, function, or variable a call refers to without regard to the context of the call
Only a name qualified starting from the global namespace is unambiguous without context. This is the common usage.
answered May 23 at 10:43
eerorikaeerorika
94.4k671139
An identifier that uses the scope resolution operator is a qualified name as per [expr.prim.id.qual]. Otherwise it is unqualified.
The standard doesn't define the meaning of fully qualified, but it does mention it in [library]/[requirements]/[organization]/[contents] which says (quote from standard draft)
Whenever a name x defined in the standard library is mentioned, the name x is assumed to be fully qualified as ::std::x, unless explicitly described otherwise.
For example, if the Effects: element for library function F is described as calling library function G, the function ::std::G is meant.
Wikipedia defines Fully qualified name:
In computer programming, a fully qualified name is an unambiguous name that specifies which object, function, or variable a call refers to without regard to the context of the call
Only a name qualified starting from the global namespace is unambiguous without context. This is the common usage.
answered May 23 at 10:43
eerorikaeerorika
94.4k671139
edited May 28 at 18:07
answered May 23 at 10:43
eerorikaeerorika
94.4k671139
answered May 23 at 10:43
eerorikaeerorika
94.4k671139
answered May 23 at 10:43
eerorikaeerorika
94.4k671139
94.4k671139
add a comment |
add a comment |
Indeed, it is not a standard term. It has no definition in the standard.
However, the phrase "fully qualified" appears exactly once, in [contents] (15.5.1.1 "Library contents" in the as-of-writing most current draft N4800) paragraph 3:
Whenever a name
xdefined in the standard library is mentioned, the namexis assumed to be fully qualified as::std::x, unless explicitly described otherwise.
So in this definition, only names starting with :: are fully qualified.
answered May 23 at 10:44
Sebastian RedlSebastian Redl
52k579123
add a comment |
Indeed, it is not a standard term. It has no definition in the standard.
However, the phrase "fully qualified" appears exactly once, in [contents] (15.5.1.1 "Library contents" in the as-of-writing most current draft N4800) paragraph 3:
Whenever a name
xdefined in the standard library is mentioned, the namexis assumed to be fully qualified as::std::x, unless explicitly described otherwise.
So in this definition, only names starting with :: are fully qualified.
answered May 23 at 10:44
Sebastian RedlSebastian Redl
52k579123
add a comment |
Indeed, it is not a standard term. It has no definition in the standard.
However, the phrase "fully qualified" appears exactly once, in [contents] (15.5.1.1 "Library contents" in the as-of-writing most current draft N4800) paragraph 3:
Whenever a name
xdefined in the standard library is mentioned, the namexis assumed to be fully qualified as::std::x, unless explicitly described otherwise.
So in this definition, only names starting with :: are fully qualified.
answered May 23 at 10:44
Sebastian RedlSebastian Redl
52k579123
Indeed, it is not a standard term. It has no definition in the standard.
However, the phrase "fully qualified" appears exactly once, in [contents] (15.5.1.1 "Library contents" in the as-of-writing most current draft N4800) paragraph 3:
Whenever a name
xdefined in the standard library is mentioned, the namexis assumed to be fully qualified as::std::x, unless explicitly described otherwise.
So in this definition, only names starting with :: are fully qualified.
answered May 23 at 10:44
Sebastian RedlSebastian Redl
52k579123
answered May 23 at 10:44
Sebastian RedlSebastian Redl
52k579123
answered May 23 at 10:44
Sebastian RedlSebastian Redl
52k579123
answered May 23 at 10:44
Sebastian RedlSebastian Redl
52k579123
52k579123
add a comment |
add a comment |
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7
With the injected class name one can really qualify stuff.
::A::A::A::A::f(). Not sure if it's "fully" though.– StoryTeller
May 23 at 10:42
9
@StoryTeller We should petition to add that term to the standard! really-really-really-qualified-id etc
– Lightness Races in Orbit
May 23 at 11:24
What does the language-lawyer tag mean?
– Evorlor
May 23 at 21:38
5
@Evorlor Hover your mouse over it (and/or click)
– Lightness Races in Orbit
May 23 at 23:07