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Delete all lines which don't have n characters before delimiter



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
2019 Community Moderator Election Results
Why I closed the “Why is Kali so hard” questionHow can I wrap text at a certain column size?Delete all lines containing “..” and “@”How can I do a binary search of a text file for a specific character string?Count all lines between a delimiterDelete all lines of text that isn't all numbersHow to print the inputted pattern which don't have matching lines?If Extra delimiter delete last delimiterDelete last characters before delimiterHow to delete all lines that contain only duplicates characters?Delete n lines after pattern and m lines before pattern



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11















I have a very long text file (from here) which should contain 6 hexadecimal characters then a 'break' (which appears as one character and doesn't seem to show up properly in the code markdown below) followed by a few words:



00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
5080 Cisco Systems, Inc
0E+00 ASUSTek COMPUTER INC.
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
2354 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc


I've done some looking around and can't see something which would work in this situation. My question is, how can I use grep/sed/awk/perl to delete all lines of this text file which do not start with exactly 6 hexadecimal characters and then a 'break'?



P.S. For bonus points, what's the best way of sorting the file alphabetically and numerically according to the hex characters (i.e. 000000 -> FFFFFF)? Should I just use sort?










share|improve this question






























    11















    I have a very long text file (from here) which should contain 6 hexadecimal characters then a 'break' (which appears as one character and doesn't seem to show up properly in the code markdown below) followed by a few words:



    00107B Cisco Systems, Inc
    00906D Cisco Systems, Inc
    0090BF Cisco Systems, Inc
    5080 Cisco Systems, Inc
    0E+00 ASUSTek COMPUTER INC.
    000C6E ASUSTek COMPUTER INC.
    001BFC ASUSTek COMPUTER INC.
    001E8C ASUSTek COMPUTER INC.
    0015F2 ASUSTek COMPUTER INC.
    2354 ASUSTek COMPUTER INC.
    001FC6 ASUSTek COMPUTER INC.
    60182E ShenZhen Protruly Electronic Ltd co.
    F4CFE2 Cisco Systems, Inc
    501CBF Cisco Systems, Inc


    I've done some looking around and can't see something which would work in this situation. My question is, how can I use grep/sed/awk/perl to delete all lines of this text file which do not start with exactly 6 hexadecimal characters and then a 'break'?



    P.S. For bonus points, what's the best way of sorting the file alphabetically and numerically according to the hex characters (i.e. 000000 -> FFFFFF)? Should I just use sort?










    share|improve this question


























      11












      11








      11








      I have a very long text file (from here) which should contain 6 hexadecimal characters then a 'break' (which appears as one character and doesn't seem to show up properly in the code markdown below) followed by a few words:



      00107B Cisco Systems, Inc
      00906D Cisco Systems, Inc
      0090BF Cisco Systems, Inc
      5080 Cisco Systems, Inc
      0E+00 ASUSTek COMPUTER INC.
      000C6E ASUSTek COMPUTER INC.
      001BFC ASUSTek COMPUTER INC.
      001E8C ASUSTek COMPUTER INC.
      0015F2 ASUSTek COMPUTER INC.
      2354 ASUSTek COMPUTER INC.
      001FC6 ASUSTek COMPUTER INC.
      60182E ShenZhen Protruly Electronic Ltd co.
      F4CFE2 Cisco Systems, Inc
      501CBF Cisco Systems, Inc


      I've done some looking around and can't see something which would work in this situation. My question is, how can I use grep/sed/awk/perl to delete all lines of this text file which do not start with exactly 6 hexadecimal characters and then a 'break'?



      P.S. For bonus points, what's the best way of sorting the file alphabetically and numerically according to the hex characters (i.e. 000000 -> FFFFFF)? Should I just use sort?










      share|improve this question
















      I have a very long text file (from here) which should contain 6 hexadecimal characters then a 'break' (which appears as one character and doesn't seem to show up properly in the code markdown below) followed by a few words:



      00107B Cisco Systems, Inc
      00906D Cisco Systems, Inc
      0090BF Cisco Systems, Inc
      5080 Cisco Systems, Inc
      0E+00 ASUSTek COMPUTER INC.
      000C6E ASUSTek COMPUTER INC.
      001BFC ASUSTek COMPUTER INC.
      001E8C ASUSTek COMPUTER INC.
      0015F2 ASUSTek COMPUTER INC.
      2354 ASUSTek COMPUTER INC.
      001FC6 ASUSTek COMPUTER INC.
      60182E ShenZhen Protruly Electronic Ltd co.
      F4CFE2 Cisco Systems, Inc
      501CBF Cisco Systems, Inc


      I've done some looking around and can't see something which would work in this situation. My question is, how can I use grep/sed/awk/perl to delete all lines of this text file which do not start with exactly 6 hexadecimal characters and then a 'break'?



      P.S. For bonus points, what's the best way of sorting the file alphabetically and numerically according to the hex characters (i.e. 000000 -> FFFFFF)? Should I just use sort?







      text-processing sed grep text-formatting






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Apr 10 at 16:46









      codeforester

      405418




      405418










      asked Apr 10 at 14:46









      RoccoRocco

      785




      785




















          2 Answers
          2






          active

          oldest

          votes


















          13














          $ awk '$1 ~ /^[[:xdigit:]]6$/' file
          00107B Cisco Systems, Inc
          00906D Cisco Systems, Inc
          0090BF Cisco Systems, Inc
          000C6E ASUSTek COMPUTER INC.
          001BFC ASUSTek COMPUTER INC.
          001E8C ASUSTek COMPUTER INC.
          0015F2 ASUSTek COMPUTER INC.
          001FC6 ASUSTek COMPUTER INC.
          60182E ShenZhen Protruly Electronic Ltd co.
          F4CFE2 Cisco Systems, Inc
          501CBF Cisco Systems, Inc


          This uses awk to extract the lines that contains exactly six hexadecimal digits in the first field. The [[:xdigit:]] pattern matches a hexadecimal digit, and 6 requires six of them. Together with the anchoring to the start and end of the field with ^ and $ respectively, this will only match on the wanted lines.



          Redirect to some file to save it under a new name.



          Note that this seems to work with GNU awk (commonly found on Linux), but not with awk on e.g. OpenBSD, or mawk.




          A similar approach with sed:



          $ sed -n '/^[[:xdigit:]]6>/p' file
          00107B Cisco Systems, Inc
          00906D Cisco Systems, Inc
          0090BF Cisco Systems, Inc
          000C6E ASUSTek COMPUTER INC.
          001BFC ASUSTek COMPUTER INC.
          001E8C ASUSTek COMPUTER INC.
          0015F2 ASUSTek COMPUTER INC.
          001FC6 ASUSTek COMPUTER INC.
          60182E ShenZhen Protruly Electronic Ltd co.
          F4CFE2 Cisco Systems, Inc
          501CBF Cisco Systems, Inc


          In this expression, > is used to match the end of the hexadecimal number. This ensures that longer numbers are not matched. The > pattern matches a word boundary, i.e. the zero-width space between a word character and a non-word character.




          For sorting the resulting data, just pipe the result trough sort, or sort -f if your hexadecimal numbers uses both upper and lower case letters






          share|improve this answer




















          • 1





            Perfect, thank you very much. Exactly what I was looking for!

            – Rocco
            Apr 10 at 15:07


















          8














          And for completeness, you can do this with grep too:



          $ grep -E '^[[:xdigit:]]6b' oui.txt 
          00107B Cisco Systems, Inc
          00906D Cisco Systems, Inc
          0090BF Cisco Systems, Inc
          000C6E ASUSTek COMPUTER INC.
          001BFC ASUSTek COMPUTER INC.
          001E8C ASUSTek COMPUTER INC.
          0015F2 ASUSTek COMPUTER INC.
          001FC6 ASUSTek COMPUTER INC.
          60182E ShenZhen Protruly Electronic Ltd co.
          F4CFE2 Cisco Systems, Inc
          501CBF Cisco Systems, Inc
          $


          This extended grep expression searches for exactly 6 hex digits at the beginning of each line, followed immediately by a non-whitespace-to-whitespace boundary (b).






          share|improve this answer























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            2 Answers
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            active

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            13














            $ awk '$1 ~ /^[[:xdigit:]]6$/' file
            00107B Cisco Systems, Inc
            00906D Cisco Systems, Inc
            0090BF Cisco Systems, Inc
            000C6E ASUSTek COMPUTER INC.
            001BFC ASUSTek COMPUTER INC.
            001E8C ASUSTek COMPUTER INC.
            0015F2 ASUSTek COMPUTER INC.
            001FC6 ASUSTek COMPUTER INC.
            60182E ShenZhen Protruly Electronic Ltd co.
            F4CFE2 Cisco Systems, Inc
            501CBF Cisco Systems, Inc


            This uses awk to extract the lines that contains exactly six hexadecimal digits in the first field. The [[:xdigit:]] pattern matches a hexadecimal digit, and 6 requires six of them. Together with the anchoring to the start and end of the field with ^ and $ respectively, this will only match on the wanted lines.



            Redirect to some file to save it under a new name.



            Note that this seems to work with GNU awk (commonly found on Linux), but not with awk on e.g. OpenBSD, or mawk.




            A similar approach with sed:



            $ sed -n '/^[[:xdigit:]]6>/p' file
            00107B Cisco Systems, Inc
            00906D Cisco Systems, Inc
            0090BF Cisco Systems, Inc
            000C6E ASUSTek COMPUTER INC.
            001BFC ASUSTek COMPUTER INC.
            001E8C ASUSTek COMPUTER INC.
            0015F2 ASUSTek COMPUTER INC.
            001FC6 ASUSTek COMPUTER INC.
            60182E ShenZhen Protruly Electronic Ltd co.
            F4CFE2 Cisco Systems, Inc
            501CBF Cisco Systems, Inc


            In this expression, > is used to match the end of the hexadecimal number. This ensures that longer numbers are not matched. The > pattern matches a word boundary, i.e. the zero-width space between a word character and a non-word character.




            For sorting the resulting data, just pipe the result trough sort, or sort -f if your hexadecimal numbers uses both upper and lower case letters






            share|improve this answer




















            • 1





              Perfect, thank you very much. Exactly what I was looking for!

              – Rocco
              Apr 10 at 15:07















            13














            $ awk '$1 ~ /^[[:xdigit:]]6$/' file
            00107B Cisco Systems, Inc
            00906D Cisco Systems, Inc
            0090BF Cisco Systems, Inc
            000C6E ASUSTek COMPUTER INC.
            001BFC ASUSTek COMPUTER INC.
            001E8C ASUSTek COMPUTER INC.
            0015F2 ASUSTek COMPUTER INC.
            001FC6 ASUSTek COMPUTER INC.
            60182E ShenZhen Protruly Electronic Ltd co.
            F4CFE2 Cisco Systems, Inc
            501CBF Cisco Systems, Inc


            This uses awk to extract the lines that contains exactly six hexadecimal digits in the first field. The [[:xdigit:]] pattern matches a hexadecimal digit, and 6 requires six of them. Together with the anchoring to the start and end of the field with ^ and $ respectively, this will only match on the wanted lines.



            Redirect to some file to save it under a new name.



            Note that this seems to work with GNU awk (commonly found on Linux), but not with awk on e.g. OpenBSD, or mawk.




            A similar approach with sed:



            $ sed -n '/^[[:xdigit:]]6>/p' file
            00107B Cisco Systems, Inc
            00906D Cisco Systems, Inc
            0090BF Cisco Systems, Inc
            000C6E ASUSTek COMPUTER INC.
            001BFC ASUSTek COMPUTER INC.
            001E8C ASUSTek COMPUTER INC.
            0015F2 ASUSTek COMPUTER INC.
            001FC6 ASUSTek COMPUTER INC.
            60182E ShenZhen Protruly Electronic Ltd co.
            F4CFE2 Cisco Systems, Inc
            501CBF Cisco Systems, Inc


            In this expression, > is used to match the end of the hexadecimal number. This ensures that longer numbers are not matched. The > pattern matches a word boundary, i.e. the zero-width space between a word character and a non-word character.




            For sorting the resulting data, just pipe the result trough sort, or sort -f if your hexadecimal numbers uses both upper and lower case letters






            share|improve this answer




















            • 1





              Perfect, thank you very much. Exactly what I was looking for!

              – Rocco
              Apr 10 at 15:07













            13












            13








            13







            $ awk '$1 ~ /^[[:xdigit:]]6$/' file
            00107B Cisco Systems, Inc
            00906D Cisco Systems, Inc
            0090BF Cisco Systems, Inc
            000C6E ASUSTek COMPUTER INC.
            001BFC ASUSTek COMPUTER INC.
            001E8C ASUSTek COMPUTER INC.
            0015F2 ASUSTek COMPUTER INC.
            001FC6 ASUSTek COMPUTER INC.
            60182E ShenZhen Protruly Electronic Ltd co.
            F4CFE2 Cisco Systems, Inc
            501CBF Cisco Systems, Inc


            This uses awk to extract the lines that contains exactly six hexadecimal digits in the first field. The [[:xdigit:]] pattern matches a hexadecimal digit, and 6 requires six of them. Together with the anchoring to the start and end of the field with ^ and $ respectively, this will only match on the wanted lines.



            Redirect to some file to save it under a new name.



            Note that this seems to work with GNU awk (commonly found on Linux), but not with awk on e.g. OpenBSD, or mawk.




            A similar approach with sed:



            $ sed -n '/^[[:xdigit:]]6>/p' file
            00107B Cisco Systems, Inc
            00906D Cisco Systems, Inc
            0090BF Cisco Systems, Inc
            000C6E ASUSTek COMPUTER INC.
            001BFC ASUSTek COMPUTER INC.
            001E8C ASUSTek COMPUTER INC.
            0015F2 ASUSTek COMPUTER INC.
            001FC6 ASUSTek COMPUTER INC.
            60182E ShenZhen Protruly Electronic Ltd co.
            F4CFE2 Cisco Systems, Inc
            501CBF Cisco Systems, Inc


            In this expression, > is used to match the end of the hexadecimal number. This ensures that longer numbers are not matched. The > pattern matches a word boundary, i.e. the zero-width space between a word character and a non-word character.




            For sorting the resulting data, just pipe the result trough sort, or sort -f if your hexadecimal numbers uses both upper and lower case letters






            share|improve this answer















            $ awk '$1 ~ /^[[:xdigit:]]6$/' file
            00107B Cisco Systems, Inc
            00906D Cisco Systems, Inc
            0090BF Cisco Systems, Inc
            000C6E ASUSTek COMPUTER INC.
            001BFC ASUSTek COMPUTER INC.
            001E8C ASUSTek COMPUTER INC.
            0015F2 ASUSTek COMPUTER INC.
            001FC6 ASUSTek COMPUTER INC.
            60182E ShenZhen Protruly Electronic Ltd co.
            F4CFE2 Cisco Systems, Inc
            501CBF Cisco Systems, Inc


            This uses awk to extract the lines that contains exactly six hexadecimal digits in the first field. The [[:xdigit:]] pattern matches a hexadecimal digit, and 6 requires six of them. Together with the anchoring to the start and end of the field with ^ and $ respectively, this will only match on the wanted lines.



            Redirect to some file to save it under a new name.



            Note that this seems to work with GNU awk (commonly found on Linux), but not with awk on e.g. OpenBSD, or mawk.




            A similar approach with sed:



            $ sed -n '/^[[:xdigit:]]6>/p' file
            00107B Cisco Systems, Inc
            00906D Cisco Systems, Inc
            0090BF Cisco Systems, Inc
            000C6E ASUSTek COMPUTER INC.
            001BFC ASUSTek COMPUTER INC.
            001E8C ASUSTek COMPUTER INC.
            0015F2 ASUSTek COMPUTER INC.
            001FC6 ASUSTek COMPUTER INC.
            60182E ShenZhen Protruly Electronic Ltd co.
            F4CFE2 Cisco Systems, Inc
            501CBF Cisco Systems, Inc


            In this expression, > is used to match the end of the hexadecimal number. This ensures that longer numbers are not matched. The > pattern matches a word boundary, i.e. the zero-width space between a word character and a non-word character.




            For sorting the resulting data, just pipe the result trough sort, or sort -f if your hexadecimal numbers uses both upper and lower case letters







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Apr 10 at 15:53

























            answered Apr 10 at 14:55









            KusalanandaKusalananda

            142k18265440




            142k18265440







            • 1





              Perfect, thank you very much. Exactly what I was looking for!

              – Rocco
              Apr 10 at 15:07












            • 1





              Perfect, thank you very much. Exactly what I was looking for!

              – Rocco
              Apr 10 at 15:07







            1




            1





            Perfect, thank you very much. Exactly what I was looking for!

            – Rocco
            Apr 10 at 15:07





            Perfect, thank you very much. Exactly what I was looking for!

            – Rocco
            Apr 10 at 15:07













            8














            And for completeness, you can do this with grep too:



            $ grep -E '^[[:xdigit:]]6b' oui.txt 
            00107B Cisco Systems, Inc
            00906D Cisco Systems, Inc
            0090BF Cisco Systems, Inc
            000C6E ASUSTek COMPUTER INC.
            001BFC ASUSTek COMPUTER INC.
            001E8C ASUSTek COMPUTER INC.
            0015F2 ASUSTek COMPUTER INC.
            001FC6 ASUSTek COMPUTER INC.
            60182E ShenZhen Protruly Electronic Ltd co.
            F4CFE2 Cisco Systems, Inc
            501CBF Cisco Systems, Inc
            $


            This extended grep expression searches for exactly 6 hex digits at the beginning of each line, followed immediately by a non-whitespace-to-whitespace boundary (b).






            share|improve this answer



























              8














              And for completeness, you can do this with grep too:



              $ grep -E '^[[:xdigit:]]6b' oui.txt 
              00107B Cisco Systems, Inc
              00906D Cisco Systems, Inc
              0090BF Cisco Systems, Inc
              000C6E ASUSTek COMPUTER INC.
              001BFC ASUSTek COMPUTER INC.
              001E8C ASUSTek COMPUTER INC.
              0015F2 ASUSTek COMPUTER INC.
              001FC6 ASUSTek COMPUTER INC.
              60182E ShenZhen Protruly Electronic Ltd co.
              F4CFE2 Cisco Systems, Inc
              501CBF Cisco Systems, Inc
              $


              This extended grep expression searches for exactly 6 hex digits at the beginning of each line, followed immediately by a non-whitespace-to-whitespace boundary (b).






              share|improve this answer

























                8












                8








                8







                And for completeness, you can do this with grep too:



                $ grep -E '^[[:xdigit:]]6b' oui.txt 
                00107B Cisco Systems, Inc
                00906D Cisco Systems, Inc
                0090BF Cisco Systems, Inc
                000C6E ASUSTek COMPUTER INC.
                001BFC ASUSTek COMPUTER INC.
                001E8C ASUSTek COMPUTER INC.
                0015F2 ASUSTek COMPUTER INC.
                001FC6 ASUSTek COMPUTER INC.
                60182E ShenZhen Protruly Electronic Ltd co.
                F4CFE2 Cisco Systems, Inc
                501CBF Cisco Systems, Inc
                $


                This extended grep expression searches for exactly 6 hex digits at the beginning of each line, followed immediately by a non-whitespace-to-whitespace boundary (b).






                share|improve this answer













                And for completeness, you can do this with grep too:



                $ grep -E '^[[:xdigit:]]6b' oui.txt 
                00107B Cisco Systems, Inc
                00906D Cisco Systems, Inc
                0090BF Cisco Systems, Inc
                000C6E ASUSTek COMPUTER INC.
                001BFC ASUSTek COMPUTER INC.
                001E8C ASUSTek COMPUTER INC.
                0015F2 ASUSTek COMPUTER INC.
                001FC6 ASUSTek COMPUTER INC.
                60182E ShenZhen Protruly Electronic Ltd co.
                F4CFE2 Cisco Systems, Inc
                501CBF Cisco Systems, Inc
                $


                This extended grep expression searches for exactly 6 hex digits at the beginning of each line, followed immediately by a non-whitespace-to-whitespace boundary (b).







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Apr 10 at 20:03









                Digital TraumaDigital Trauma

                6,13211730




                6,13211730



























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                    What should I write in an apology letter, since I have decided not to join a company after accepting an offer letterShould I keep looking after accepting a job offer?What should I do when I've been verbally told I would get an offer letter, but still haven't gotten one after 4 weeks?Do I accept an offer from a company that I am not likely to join?New job hasn't confirmed starting date and I want to give current employer as much notice as possibleHow should I address my manager in my resignation letter?HR delayed background verification, now jobless as resignedNo email communication after accepting a formal written offer. How should I phrase the call?What should I do if after receiving a verbal offer letter I am informed that my written job offer is put on hold due to some internal issues?Should I inform the current employer that I am about to resign within 1-2 weeks since I have signed the offer letter and waiting for visa?What company will do, if I send their offer letter to another company