How to get the width for a math symbol to align the rows of a table?What commands are there for horizontal spacing?How to top align all rows in table by keeping fixed width?How to center align the whole table?How to Align text across multiple rowsHow to align text to the right in math mode?get math width in math unit (mu)Align math to the leftHow do I align the math symbol in each cell?How to find the width of a symbol?Vertical spacing between arrow and caption with unicode-mathUsing printeranswers environment, how to print solutions in the box without the title “Solutions”
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How to get the width for a math symbol to align the rows of a table?
What commands are there for horizontal spacing?How to top align all rows in table by keeping fixed width?How to center align the whole table?How to Align text across multiple rowsHow to align text to the right in math mode?get math width in math unit (mu)Align math to the leftHow do I align the math symbol in each cell?How to find the width of a symbol?Vertical spacing between arrow and caption with unicode-mathUsing printeranswers environment, how to print solutions in the box without the title “Solutions”
I try to align the letters b,d,t exactly vertically stacked. But the neg symbol has unkown width. What is it and how to find it out in general? Numerous spacings exist, but whats the exact one?
documentclassarticle
usepackageamsmath, booktabs
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b, d, t)$ & \
$(b, d,neg t)$ & \
$(b,neg d, t)$ & double auction \
$(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
math-mode spacing horizontal-alignment
asked May 1 at 12:48
ItsmeJulianItsmeJulian
334213
add a comment |
I try to align the letters b,d,t exactly vertically stacked. But the neg symbol has unkown width. What is it and how to find it out in general? Numerous spacings exist, but whats the exact one?
documentclassarticle
usepackageamsmath, booktabs
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b, d, t)$ & \
$(b, d,neg t)$ & \
$(b,neg d, t)$ & double auction \
$(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
math-mode spacing horizontal-alignment
asked May 1 at 12:48
ItsmeJulianItsmeJulian
334213
add a comment |
I try to align the letters b,d,t exactly vertically stacked. But the neg symbol has unkown width. What is it and how to find it out in general? Numerous spacings exist, but whats the exact one?
documentclassarticle
usepackageamsmath, booktabs
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b, d, t)$ & \
$(b, d,neg t)$ & \
$(b,neg d, t)$ & double auction \
$(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
math-mode spacing horizontal-alignment
asked May 1 at 12:48
ItsmeJulianItsmeJulian
334213
I try to align the letters b,d,t exactly vertically stacked. But the neg symbol has unkown width. What is it and how to find it out in general? Numerous spacings exist, but whats the exact one?
documentclassarticle
usepackageamsmath, booktabs
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b, d, t)$ & \
$(b, d,neg t)$ & \
$(b,neg d, t)$ & double auction \
$(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
math-mode spacing horizontal-alignment
math-mode spacing horizontal-alignment
asked May 1 at 12:48
ItsmeJulianItsmeJulian
334213
asked May 1 at 12:48
ItsmeJulianItsmeJulian
334213
edited May 7 at 12:16
ItsmeJulian
asked May 1 at 12:48
ItsmeJulianItsmeJulian
334213
asked May 1 at 12:48
ItsmeJulianItsmeJulian
334213
asked May 1 at 12:48
ItsmeJulianItsmeJulian
334213
334213
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
hphantomneg will insert a horizontal space exactly the same as neg
documentclassarticle
usepackageamsmath, booktabs
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b,hphantomneg d,hphantomneg t)$ & \
$(b,hphantomneg d,neg t)$ & \
$(b,neg d,hphantomneg t)$ & double auction \
$(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
1
this has the advantage of no def or newcommands. nice
– ItsmeJulian
May 1 at 13:14
2
@ItsmeJulian There are more commands like this. In case you need the vertical space of something there isvphantom...and for both vertical and horizontal space there isphantom....
– user187977
May 1 at 13:26
add a comment |
This makes all components the same width, specified here as 2.1ex, plus an added inter-column gap of ,,.
This allows some flexibility if the array content changes and allows for the presence of neg in the first column.
documentclassarticle
usepackageamsmath, booktabs
newcommandcw2.1ex
defz(#1,#2,#3)%
(makebox[cw][r]$#1$,,,makebox[cw][r]$#2$,,,makebox[cw][r]$#3$)
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$z(b,d,t)$ & \
$z(b,d,neg t)$ & \
$z(b,neg d,t)$ & double auction \
$z(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
But if you wanted the output tailored to this particular set of arrays, then
documentclassarticle
usepackageamsmath, booktabs
setbox0=hbox$b$
edefcwAthewd0
setbox0=hbox$neg d$
edefcwBthewd0
setbox0=hbox$neg t$
edefcwCthewd0
defz(#1,#2,#3)%
(makebox[cwA][r]$#1$,,,makebox[cwB][r]$#2$,,,makebox[cwC][r]$#3$)
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$z(b,d,t)$ & \
$z(b,d,neg t)$ & \
$z(b,neg d,t)$ & double auction \
$z(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
answered May 1 at 12:53
Steven B. SegletesSteven B. Segletes
165k9209425
add a comment |
Another way uses the eqparbox package, which defines a system of tags for the standard box commands: all boxes sharing the same tag have as width of the natural width of the widest box in the series.
documentclassarticle
usepackageamsmath, booktabs
usepackageeqparbox
newcommandeqmathbox[2][T]eqmakebox[#1][r]$#2$
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b, eqmathbox[D]d,eqmathbox t)$ & \
$(b,eqmathbox[D]d, eqmathboxt)$ & \
$(b,eqmathbox[D]neg d, eqmathboxt)$ & double auction \
$(b,eqmathbox[D]neg d,eqmathboxneg t)$ & \ bottomrule
endtabular
enddocument
edited 2 days ago
CarLaTeX
36.4k556156
answered May 1 at 13:20
BernardBernard
179k779211
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
hphantomneg will insert a horizontal space exactly the same as neg
documentclassarticle
usepackageamsmath, booktabs
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b,hphantomneg d,hphantomneg t)$ & \
$(b,hphantomneg d,neg t)$ & \
$(b,neg d,hphantomneg t)$ & double auction \
$(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
1
this has the advantage of no def or newcommands. nice
– ItsmeJulian
May 1 at 13:14
2
@ItsmeJulian There are more commands like this. In case you need the vertical space of something there isvphantom...and for both vertical and horizontal space there isphantom....
– user187977
May 1 at 13:26
add a comment |
hphantomneg will insert a horizontal space exactly the same as neg
documentclassarticle
usepackageamsmath, booktabs
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b,hphantomneg d,hphantomneg t)$ & \
$(b,hphantomneg d,neg t)$ & \
$(b,neg d,hphantomneg t)$ & double auction \
$(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
1
this has the advantage of no def or newcommands. nice
– ItsmeJulian
May 1 at 13:14
2
@ItsmeJulian There are more commands like this. In case you need the vertical space of something there isvphantom...and for both vertical and horizontal space there isphantom....
– user187977
May 1 at 13:26
add a comment |
hphantomneg will insert a horizontal space exactly the same as neg
documentclassarticle
usepackageamsmath, booktabs
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b,hphantomneg d,hphantomneg t)$ & \
$(b,hphantomneg d,neg t)$ & \
$(b,neg d,hphantomneg t)$ & double auction \
$(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
hphantomneg will insert a horizontal space exactly the same as neg
documentclassarticle
usepackageamsmath, booktabs
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b,hphantomneg d,hphantomneg t)$ & \
$(b,hphantomneg d,neg t)$ & \
$(b,neg d,hphantomneg t)$ & double auction \
$(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
edited May 1 at 13:15
answered May 1 at 13:12
user187977
1
this has the advantage of no def or newcommands. nice
– ItsmeJulian
May 1 at 13:14
2
@ItsmeJulian There are more commands like this. In case you need the vertical space of something there isvphantom...and for both vertical and horizontal space there isphantom....
– user187977
May 1 at 13:26
add a comment |
1
this has the advantage of no def or newcommands. nice
– ItsmeJulian
May 1 at 13:14
2
@ItsmeJulian There are more commands like this. In case you need the vertical space of something there isvphantom...and for both vertical and horizontal space there isphantom....
– user187977
May 1 at 13:26
1
1
this has the advantage of no def or newcommands. nice
– ItsmeJulian
May 1 at 13:14
this has the advantage of no def or newcommands. nice
– ItsmeJulian
May 1 at 13:14
2
2
@ItsmeJulian There are more commands like this. In case you need the vertical space of something there is
vphantom... and for both vertical and horizontal space there is phantom....– user187977
May 1 at 13:26
@ItsmeJulian There are more commands like this. In case you need the vertical space of something there is
vphantom... and for both vertical and horizontal space there is phantom....– user187977
May 1 at 13:26
add a comment |
This makes all components the same width, specified here as 2.1ex, plus an added inter-column gap of ,,.
This allows some flexibility if the array content changes and allows for the presence of neg in the first column.
documentclassarticle
usepackageamsmath, booktabs
newcommandcw2.1ex
defz(#1,#2,#3)%
(makebox[cw][r]$#1$,,,makebox[cw][r]$#2$,,,makebox[cw][r]$#3$)
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$z(b,d,t)$ & \
$z(b,d,neg t)$ & \
$z(b,neg d,t)$ & double auction \
$z(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
But if you wanted the output tailored to this particular set of arrays, then
documentclassarticle
usepackageamsmath, booktabs
setbox0=hbox$b$
edefcwAthewd0
setbox0=hbox$neg d$
edefcwBthewd0
setbox0=hbox$neg t$
edefcwCthewd0
defz(#1,#2,#3)%
(makebox[cwA][r]$#1$,,,makebox[cwB][r]$#2$,,,makebox[cwC][r]$#3$)
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$z(b,d,t)$ & \
$z(b,d,neg t)$ & \
$z(b,neg d,t)$ & double auction \
$z(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
answered May 1 at 12:53
Steven B. SegletesSteven B. Segletes
165k9209425
add a comment |
This makes all components the same width, specified here as 2.1ex, plus an added inter-column gap of ,,.
This allows some flexibility if the array content changes and allows for the presence of neg in the first column.
documentclassarticle
usepackageamsmath, booktabs
newcommandcw2.1ex
defz(#1,#2,#3)%
(makebox[cw][r]$#1$,,,makebox[cw][r]$#2$,,,makebox[cw][r]$#3$)
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$z(b,d,t)$ & \
$z(b,d,neg t)$ & \
$z(b,neg d,t)$ & double auction \
$z(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
But if you wanted the output tailored to this particular set of arrays, then
documentclassarticle
usepackageamsmath, booktabs
setbox0=hbox$b$
edefcwAthewd0
setbox0=hbox$neg d$
edefcwBthewd0
setbox0=hbox$neg t$
edefcwCthewd0
defz(#1,#2,#3)%
(makebox[cwA][r]$#1$,,,makebox[cwB][r]$#2$,,,makebox[cwC][r]$#3$)
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$z(b,d,t)$ & \
$z(b,d,neg t)$ & \
$z(b,neg d,t)$ & double auction \
$z(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
answered May 1 at 12:53
Steven B. SegletesSteven B. Segletes
165k9209425
add a comment |
This makes all components the same width, specified here as 2.1ex, plus an added inter-column gap of ,,.
This allows some flexibility if the array content changes and allows for the presence of neg in the first column.
documentclassarticle
usepackageamsmath, booktabs
newcommandcw2.1ex
defz(#1,#2,#3)%
(makebox[cw][r]$#1$,,,makebox[cw][r]$#2$,,,makebox[cw][r]$#3$)
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$z(b,d,t)$ & \
$z(b,d,neg t)$ & \
$z(b,neg d,t)$ & double auction \
$z(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
But if you wanted the output tailored to this particular set of arrays, then
documentclassarticle
usepackageamsmath, booktabs
setbox0=hbox$b$
edefcwAthewd0
setbox0=hbox$neg d$
edefcwBthewd0
setbox0=hbox$neg t$
edefcwCthewd0
defz(#1,#2,#3)%
(makebox[cwA][r]$#1$,,,makebox[cwB][r]$#2$,,,makebox[cwC][r]$#3$)
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$z(b,d,t)$ & \
$z(b,d,neg t)$ & \
$z(b,neg d,t)$ & double auction \
$z(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
answered May 1 at 12:53
Steven B. SegletesSteven B. Segletes
165k9209425
This makes all components the same width, specified here as 2.1ex, plus an added inter-column gap of ,,.
This allows some flexibility if the array content changes and allows for the presence of neg in the first column.
documentclassarticle
usepackageamsmath, booktabs
newcommandcw2.1ex
defz(#1,#2,#3)%
(makebox[cw][r]$#1$,,,makebox[cw][r]$#2$,,,makebox[cw][r]$#3$)
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$z(b,d,t)$ & \
$z(b,d,neg t)$ & \
$z(b,neg d,t)$ & double auction \
$z(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
But if you wanted the output tailored to this particular set of arrays, then
documentclassarticle
usepackageamsmath, booktabs
setbox0=hbox$b$
edefcwAthewd0
setbox0=hbox$neg d$
edefcwBthewd0
setbox0=hbox$neg t$
edefcwCthewd0
defz(#1,#2,#3)%
(makebox[cwA][r]$#1$,,,makebox[cwB][r]$#2$,,,makebox[cwC][r]$#3$)
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$z(b,d,t)$ & \
$z(b,d,neg t)$ & \
$z(b,neg d,t)$ & double auction \
$z(b,neg d,neg t)$ & \ bottomrule
endtabular
enddocument
answered May 1 at 12:53
Steven B. SegletesSteven B. Segletes
165k9209425
edited May 1 at 13:03
answered May 1 at 12:53
Steven B. SegletesSteven B. Segletes
165k9209425
answered May 1 at 12:53
Steven B. SegletesSteven B. Segletes
165k9209425
answered May 1 at 12:53
Steven B. SegletesSteven B. Segletes
165k9209425
165k9209425
add a comment |
add a comment |
Another way uses the eqparbox package, which defines a system of tags for the standard box commands: all boxes sharing the same tag have as width of the natural width of the widest box in the series.
documentclassarticle
usepackageamsmath, booktabs
usepackageeqparbox
newcommandeqmathbox[2][T]eqmakebox[#1][r]$#2$
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b, eqmathbox[D]d,eqmathbox t)$ & \
$(b,eqmathbox[D]d, eqmathboxt)$ & \
$(b,eqmathbox[D]neg d, eqmathboxt)$ & double auction \
$(b,eqmathbox[D]neg d,eqmathboxneg t)$ & \ bottomrule
endtabular
enddocument
edited 2 days ago
CarLaTeX
36.4k556156
answered May 1 at 13:20
BernardBernard
179k779211
add a comment |
Another way uses the eqparbox package, which defines a system of tags for the standard box commands: all boxes sharing the same tag have as width of the natural width of the widest box in the series.
documentclassarticle
usepackageamsmath, booktabs
usepackageeqparbox
newcommandeqmathbox[2][T]eqmakebox[#1][r]$#2$
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b, eqmathbox[D]d,eqmathbox t)$ & \
$(b,eqmathbox[D]d, eqmathboxt)$ & \
$(b,eqmathbox[D]neg d, eqmathboxt)$ & double auction \
$(b,eqmathbox[D]neg d,eqmathboxneg t)$ & \ bottomrule
endtabular
enddocument
edited 2 days ago
CarLaTeX
36.4k556156
answered May 1 at 13:20
BernardBernard
179k779211
add a comment |
Another way uses the eqparbox package, which defines a system of tags for the standard box commands: all boxes sharing the same tag have as width of the natural width of the widest box in the series.
documentclassarticle
usepackageamsmath, booktabs
usepackageeqparbox
newcommandeqmathbox[2][T]eqmakebox[#1][r]$#2$
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b, eqmathbox[D]d,eqmathbox t)$ & \
$(b,eqmathbox[D]d, eqmathboxt)$ & \
$(b,eqmathbox[D]neg d, eqmathboxt)$ & double auction \
$(b,eqmathbox[D]neg d,eqmathboxneg t)$ & \ bottomrule
endtabular
enddocument
edited 2 days ago
CarLaTeX
36.4k556156
answered May 1 at 13:20
BernardBernard
179k779211
Another way uses the eqparbox package, which defines a system of tags for the standard box commands: all boxes sharing the same tag have as width of the natural width of the widest box in the series.
documentclassarticle
usepackageamsmath, booktabs
usepackageeqparbox
newcommandeqmathbox[2][T]eqmakebox[#1][r]$#2$
begindocument
begintabular@ll@
toprule
combination & example \ midrule
$(b, eqmathbox[D]d,eqmathbox t)$ & \
$(b,eqmathbox[D]d, eqmathboxt)$ & \
$(b,eqmathbox[D]neg d, eqmathboxt)$ & double auction \
$(b,eqmathbox[D]neg d,eqmathboxneg t)$ & \ bottomrule
endtabular
enddocument
edited 2 days ago
CarLaTeX
36.4k556156
answered May 1 at 13:20
BernardBernard
179k779211
edited 2 days ago
CarLaTeX
36.4k556156
edited 2 days ago
CarLaTeX
36.4k556156
edited 2 days ago
CarLaTeX
36.4k556156
36.4k556156
answered May 1 at 13:20
BernardBernard
179k779211
answered May 1 at 13:20
BernardBernard
179k779211
answered May 1 at 13:20
BernardBernard
179k779211
179k779211
add a comment |
add a comment |
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