List of lists elementwise greater/smaller thanElement-wise test on List elementsCombining two listsFast method for combining two listsConditional combining of nested listsHow to use select and map togetherSelect sub-lists of common length from a listCombination of lists elementwiseProducing a list of all the pairs can be made by from two lists of equal lengthCreating lists within lists by sortingComparing elements in a list of listsMultiply two lists
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List of lists elementwise greater/smaller than
Element-wise test on List elementsCombining two listsFast method for combining two listsConditional combining of nested listsHow to use select and map togetherSelect sub-lists of common length from a listCombination of lists elementwiseProducing a list of all the pairs can be made by from two lists of equal lengthCreating lists within lists by sortingComparing elements in a list of listsMultiply two lists
$begingroup$
I have two lists
a = 3,1,2,5,1,3,4,1,1
b = 4,0,3,4,2,2,5,0,2
And would like to compare each element within
Ifa>b,1,0
expecting the result
0,1,0,1,0,1,0,1,0
but it doesn't work, how can I get this type of comparison?
list-manipulation map boolean-computation
asked May 18 at 18:54
Three DiagThree Diag
346111
$endgroup$
add a comment |
$begingroup$
I have two lists
a = 3,1,2,5,1,3,4,1,1
b = 4,0,3,4,2,2,5,0,2
And would like to compare each element within
Ifa>b,1,0
expecting the result
0,1,0,1,0,1,0,1,0
but it doesn't work, how can I get this type of comparison?
list-manipulation map boolean-computation
asked May 18 at 18:54
Three DiagThree Diag
346111
$endgroup$
1
$begingroup$
Strongly related
$endgroup$
– Leonid Shifrin
May 18 at 18:57
$begingroup$
you could use1-UnitStep[b-a]?
$endgroup$
– kglr
May 18 at 19:02
$begingroup$
Of course, fixed.
$endgroup$
– Three Diag
May 18 at 19:02
$begingroup$
@kglr yep, that achieves the result, thanks
$endgroup$
– Three Diag
May 18 at 19:05
add a comment |
$begingroup$
I have two lists
a = 3,1,2,5,1,3,4,1,1
b = 4,0,3,4,2,2,5,0,2
And would like to compare each element within
Ifa>b,1,0
expecting the result
0,1,0,1,0,1,0,1,0
but it doesn't work, how can I get this type of comparison?
list-manipulation map boolean-computation
asked May 18 at 18:54
Three DiagThree Diag
346111
$endgroup$
I have two lists
a = 3,1,2,5,1,3,4,1,1
b = 4,0,3,4,2,2,5,0,2
And would like to compare each element within
Ifa>b,1,0
expecting the result
0,1,0,1,0,1,0,1,0
but it doesn't work, how can I get this type of comparison?
list-manipulation map boolean-computation
list-manipulation map boolean-computation
asked May 18 at 18:54
Three DiagThree Diag
346111
asked May 18 at 18:54
Three DiagThree Diag
346111
edited May 18 at 19:02
Three Diag
asked May 18 at 18:54
Three DiagThree Diag
346111
asked May 18 at 18:54
Three DiagThree Diag
346111
asked May 18 at 18:54
Three DiagThree Diag
346111
346111
1
$begingroup$
Strongly related
$endgroup$
– Leonid Shifrin
May 18 at 18:57
$begingroup$
you could use1-UnitStep[b-a]?
$endgroup$
– kglr
May 18 at 19:02
$begingroup$
Of course, fixed.
$endgroup$
– Three Diag
May 18 at 19:02
$begingroup$
@kglr yep, that achieves the result, thanks
$endgroup$
– Three Diag
May 18 at 19:05
add a comment |
1
$begingroup$
Strongly related
$endgroup$
– Leonid Shifrin
May 18 at 18:57
$begingroup$
you could use1-UnitStep[b-a]?
$endgroup$
– kglr
May 18 at 19:02
$begingroup$
Of course, fixed.
$endgroup$
– Three Diag
May 18 at 19:02
$begingroup$
@kglr yep, that achieves the result, thanks
$endgroup$
– Three Diag
May 18 at 19:05
1
1
$begingroup$
Strongly related
$endgroup$
– Leonid Shifrin
May 18 at 18:57
$begingroup$
Strongly related
$endgroup$
– Leonid Shifrin
May 18 at 18:57
$begingroup$
you could use
1-UnitStep[b-a]?$endgroup$
– kglr
May 18 at 19:02
$begingroup$
you could use
1-UnitStep[b-a]?$endgroup$
– kglr
May 18 at 19:02
$begingroup$
Of course, fixed.
$endgroup$
– Three Diag
May 18 at 19:02
$begingroup$
Of course, fixed.
$endgroup$
– Three Diag
May 18 at 19:02
$begingroup$
@kglr yep, that achieves the result, thanks
$endgroup$
– Three Diag
May 18 at 19:05
$begingroup$
@kglr yep, that achieves the result, thanks
$endgroup$
– Three Diag
May 18 at 19:05
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Boole@Positive[a-b]
0, 1, 0, 1, 0, 1, 0, 1, 0
1-UnitStep[b-a]
0, 1, 0, 1, 0, 1, 0, 1, 0
answered May 18 at 19:06
kglrkglr
195k10216439
$endgroup$
add a comment |
$begingroup$
kglr took the fast, vectorized operations. Here are some less optimal ones that you can have a look at for fun or for learning:
Boole@MapThread[Greater, a, b, 2]
0, 1, 0, 1, 0, 1, 0, 1, 0
Boole@Apply[Greater, Transpose[a, b, 3, 2, 1], 2]
0, 1, 0, 1, 0, 1, 0, 1, 0
answered May 18 at 19:13
C. E.C. E.
52.3k3102209
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
Boole@Positive[a-b]
0, 1, 0, 1, 0, 1, 0, 1, 0
1-UnitStep[b-a]
0, 1, 0, 1, 0, 1, 0, 1, 0
answered May 18 at 19:06
kglrkglr
195k10216439
$endgroup$
add a comment |
$begingroup$
Boole@Positive[a-b]
0, 1, 0, 1, 0, 1, 0, 1, 0
1-UnitStep[b-a]
0, 1, 0, 1, 0, 1, 0, 1, 0
answered May 18 at 19:06
kglrkglr
195k10216439
$endgroup$
add a comment |
$begingroup$
Boole@Positive[a-b]
0, 1, 0, 1, 0, 1, 0, 1, 0
1-UnitStep[b-a]
0, 1, 0, 1, 0, 1, 0, 1, 0
answered May 18 at 19:06
kglrkglr
195k10216439
$endgroup$
Boole@Positive[a-b]
0, 1, 0, 1, 0, 1, 0, 1, 0
1-UnitStep[b-a]
0, 1, 0, 1, 0, 1, 0, 1, 0
answered May 18 at 19:06
kglrkglr
195k10216439
answered May 18 at 19:06
kglrkglr
195k10216439
answered May 18 at 19:06
kglrkglr
195k10216439
answered May 18 at 19:06
kglrkglr
195k10216439
195k10216439
add a comment |
add a comment |
$begingroup$
kglr took the fast, vectorized operations. Here are some less optimal ones that you can have a look at for fun or for learning:
Boole@MapThread[Greater, a, b, 2]
0, 1, 0, 1, 0, 1, 0, 1, 0
Boole@Apply[Greater, Transpose[a, b, 3, 2, 1], 2]
0, 1, 0, 1, 0, 1, 0, 1, 0
answered May 18 at 19:13
C. E.C. E.
52.3k3102209
$endgroup$
add a comment |
$begingroup$
kglr took the fast, vectorized operations. Here are some less optimal ones that you can have a look at for fun or for learning:
Boole@MapThread[Greater, a, b, 2]
0, 1, 0, 1, 0, 1, 0, 1, 0
Boole@Apply[Greater, Transpose[a, b, 3, 2, 1], 2]
0, 1, 0, 1, 0, 1, 0, 1, 0
answered May 18 at 19:13
C. E.C. E.
52.3k3102209
$endgroup$
add a comment |
$begingroup$
kglr took the fast, vectorized operations. Here are some less optimal ones that you can have a look at for fun or for learning:
Boole@MapThread[Greater, a, b, 2]
0, 1, 0, 1, 0, 1, 0, 1, 0
Boole@Apply[Greater, Transpose[a, b, 3, 2, 1], 2]
0, 1, 0, 1, 0, 1, 0, 1, 0
answered May 18 at 19:13
C. E.C. E.
52.3k3102209
$endgroup$
kglr took the fast, vectorized operations. Here are some less optimal ones that you can have a look at for fun or for learning:
Boole@MapThread[Greater, a, b, 2]
0, 1, 0, 1, 0, 1, 0, 1, 0
Boole@Apply[Greater, Transpose[a, b, 3, 2, 1], 2]
0, 1, 0, 1, 0, 1, 0, 1, 0
answered May 18 at 19:13
C. E.C. E.
52.3k3102209
answered May 18 at 19:13
C. E.C. E.
52.3k3102209
answered May 18 at 19:13
C. E.C. E.
52.3k3102209
answered May 18 at 19:13
C. E.C. E.
52.3k3102209
52.3k3102209
add a comment |
add a comment |
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1
$begingroup$
Strongly related
$endgroup$
– Leonid Shifrin
May 18 at 18:57
$begingroup$
you could use
1-UnitStep[b-a]?$endgroup$
– kglr
May 18 at 19:02
$begingroup$
Of course, fixed.
$endgroup$
– Three Diag
May 18 at 19:02
$begingroup$
@kglr yep, that achieves the result, thanks
$endgroup$
– Three Diag
May 18 at 19:05