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pic versus macro in TikZ
Draw 4 of the same figure in the same tikzpicturecopy and scale one figure (wheel)Rotate a node but not its content: the case of the ellipse decorationTikZ - bad positioning of images drawn by macroPass key option inside a macro to a TikZ drawing commandHow to define the default vertical distance between nodes?Numerical conditional within tikz keys?TikZ: Drawing an arc from an intersection to an intersectionDrawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themTikZ: clip with Pic?Nested tikz pics?
Consider this code in the TikZ - PGF manual, which uses a macro
% Main code from
% The TikZ - PGF manual
% Author: Till Tantau et al
% Version 3.1.3, released May 9, 2019
% Page 40
documentclass[tikz]standalone
begindocument
begintikzpicture
defrectanglepath-- ++(1cm,0cm) -- ++(0cm,1cm) -- ++(-1cm,0cm) -- cycle
draw (0,0) rectanglepath;
draw (1.5,0) rectanglepath;
endtikzpicture
enddocument
and this one written by me, which uses pic
documentclass[tikz]standalone
begindocument
begintikzpicture
[rectanglepath/.pic=draw (0,0)--++(1cm,0cm)--++(0cm,1cm)--++(-1cm,0cm)--cycle;]
pic at (0,0) rectanglepath;
pic at (1.5,0) rectanglepath;
endtikzpicture
enddocument
Both give us the same output
Observation
Both give the same output. I prefer the latter one, as it is more "TikZ-ish". However, we can always change a code from pic
to macro and vice versa, as above (am I wrong – is there a case in which we can't convert?), or draw the same figure using two different codes (this and this for example).
Also, I can't see any aspects in which macros are better than pic
. Even arguments: we can also have pic
with up to nine arguments with any pattern using /.style args
.
In the PGF manual, sometimes I see pic
is used, but sometimes a macro is used (it is even used in the title page!). From those examples, I can't figure out in what case I should use a macro and in what case I should use a pic
.
Question
It may be quite clear by now.
If I have to draw the same "sub-"picture many times in a TikZ picture, should I use a
pic
or a macro? And why? Is there any cases in which I must use this one and not the other?
Thanks in advance.
Edit
As for @marmot's nice codes, I have written myself some code (against it) which uses macros
documentclassarticle
usepackagetikz
begindocument
subsection*Macros can have more complicated constructions
begintikzpicture%[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
%draw[red] (-0.5,0.5) -- (0.5,-0.5);]
newcommandrectanglepath[2][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) -- (0.5,-0.5);endscope
%path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath;
rectanglepath0,0
rectanglepath[dashed]2,0
endtikzpicture
subsection*Macros can have names
begintikzpicture%[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
%draw[red] (-0.5,0.5) coordinate(-tl) -- (0.5,-0.5) coordinate(-br) ;]
newcommandrectanglepath[3][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) coordinate (#3-tl)
-- (0.5,-0.5) coordinate (#3-br);endscope
%path (0,0) pic (A) rectanglepath (2,0) pic[dashed] (B) rectanglepath;
rectanglepath0,0A
rectanglepath[dashed]2,0B
draw (A-tl) to[out=30,in=150] (B-tl) (A-br) to[out=-30,in=-150] (B-br);
endtikzpicture
subsection*Transformations are much more intuitive on macros
begintikzpicture[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);]
newcommandrectanglepath[2][]
scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1);endscope
%path (0,0) pic[rotate=45]rectanglepath (2,0) pic[dashed,rotate=-30]rectanglepath
%(4,0) pic[thick,xscale=0.5]rectanglepath;
rectanglepath[rotate=45]0,0
rectanglepath[rotate=-30,dashed]2,0
rectanglepath[thick,xscale=0.5]4,0
endtikzpicture
enddocument
tikz-pgf macros tikz-pic
add a comment |
Consider this code in the TikZ - PGF manual, which uses a macro
% Main code from
% The TikZ - PGF manual
% Author: Till Tantau et al
% Version 3.1.3, released May 9, 2019
% Page 40
documentclass[tikz]standalone
begindocument
begintikzpicture
defrectanglepath-- ++(1cm,0cm) -- ++(0cm,1cm) -- ++(-1cm,0cm) -- cycle
draw (0,0) rectanglepath;
draw (1.5,0) rectanglepath;
endtikzpicture
enddocument
and this one written by me, which uses pic
documentclass[tikz]standalone
begindocument
begintikzpicture
[rectanglepath/.pic=draw (0,0)--++(1cm,0cm)--++(0cm,1cm)--++(-1cm,0cm)--cycle;]
pic at (0,0) rectanglepath;
pic at (1.5,0) rectanglepath;
endtikzpicture
enddocument
Both give us the same output
Observation
Both give the same output. I prefer the latter one, as it is more "TikZ-ish". However, we can always change a code from pic
to macro and vice versa, as above (am I wrong – is there a case in which we can't convert?), or draw the same figure using two different codes (this and this for example).
Also, I can't see any aspects in which macros are better than pic
. Even arguments: we can also have pic
with up to nine arguments with any pattern using /.style args
.
In the PGF manual, sometimes I see pic
is used, but sometimes a macro is used (it is even used in the title page!). From those examples, I can't figure out in what case I should use a macro and in what case I should use a pic
.
Question
It may be quite clear by now.
If I have to draw the same "sub-"picture many times in a TikZ picture, should I use a
pic
or a macro? And why? Is there any cases in which I must use this one and not the other?
Thanks in advance.
Edit
As for @marmot's nice codes, I have written myself some code (against it) which uses macros
documentclassarticle
usepackagetikz
begindocument
subsection*Macros can have more complicated constructions
begintikzpicture%[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
%draw[red] (-0.5,0.5) -- (0.5,-0.5);]
newcommandrectanglepath[2][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) -- (0.5,-0.5);endscope
%path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath;
rectanglepath0,0
rectanglepath[dashed]2,0
endtikzpicture
subsection*Macros can have names
begintikzpicture%[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
%draw[red] (-0.5,0.5) coordinate(-tl) -- (0.5,-0.5) coordinate(-br) ;]
newcommandrectanglepath[3][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) coordinate (#3-tl)
-- (0.5,-0.5) coordinate (#3-br);endscope
%path (0,0) pic (A) rectanglepath (2,0) pic[dashed] (B) rectanglepath;
rectanglepath0,0A
rectanglepath[dashed]2,0B
draw (A-tl) to[out=30,in=150] (B-tl) (A-br) to[out=-30,in=-150] (B-br);
endtikzpicture
subsection*Transformations are much more intuitive on macros
begintikzpicture[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);]
newcommandrectanglepath[2][]
scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1);endscope
%path (0,0) pic[rotate=45]rectanglepath (2,0) pic[dashed,rotate=-30]rectanglepath
%(4,0) pic[thick,xscale=0.5]rectanglepath;
rectanglepath[rotate=45]0,0
rectanglepath[rotate=-30,dashed]2,0
rectanglepath[thick,xscale=0.5]4,0
endtikzpicture
enddocument
tikz-pgf macros tikz-pic
My experience is that pics are faster. For example, the threads on a screw.
– John Kormylo
May 25 at 13:45
@JohnKormylo If yes, probably it is faster on very long documents. On reports I usually write, they are equal in time taken
– The old JouleV
May 25 at 15:16
add a comment |
Consider this code in the TikZ - PGF manual, which uses a macro
% Main code from
% The TikZ - PGF manual
% Author: Till Tantau et al
% Version 3.1.3, released May 9, 2019
% Page 40
documentclass[tikz]standalone
begindocument
begintikzpicture
defrectanglepath-- ++(1cm,0cm) -- ++(0cm,1cm) -- ++(-1cm,0cm) -- cycle
draw (0,0) rectanglepath;
draw (1.5,0) rectanglepath;
endtikzpicture
enddocument
and this one written by me, which uses pic
documentclass[tikz]standalone
begindocument
begintikzpicture
[rectanglepath/.pic=draw (0,0)--++(1cm,0cm)--++(0cm,1cm)--++(-1cm,0cm)--cycle;]
pic at (0,0) rectanglepath;
pic at (1.5,0) rectanglepath;
endtikzpicture
enddocument
Both give us the same output
Observation
Both give the same output. I prefer the latter one, as it is more "TikZ-ish". However, we can always change a code from pic
to macro and vice versa, as above (am I wrong – is there a case in which we can't convert?), or draw the same figure using two different codes (this and this for example).
Also, I can't see any aspects in which macros are better than pic
. Even arguments: we can also have pic
with up to nine arguments with any pattern using /.style args
.
In the PGF manual, sometimes I see pic
is used, but sometimes a macro is used (it is even used in the title page!). From those examples, I can't figure out in what case I should use a macro and in what case I should use a pic
.
Question
It may be quite clear by now.
If I have to draw the same "sub-"picture many times in a TikZ picture, should I use a
pic
or a macro? And why? Is there any cases in which I must use this one and not the other?
Thanks in advance.
Edit
As for @marmot's nice codes, I have written myself some code (against it) which uses macros
documentclassarticle
usepackagetikz
begindocument
subsection*Macros can have more complicated constructions
begintikzpicture%[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
%draw[red] (-0.5,0.5) -- (0.5,-0.5);]
newcommandrectanglepath[2][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) -- (0.5,-0.5);endscope
%path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath;
rectanglepath0,0
rectanglepath[dashed]2,0
endtikzpicture
subsection*Macros can have names
begintikzpicture%[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
%draw[red] (-0.5,0.5) coordinate(-tl) -- (0.5,-0.5) coordinate(-br) ;]
newcommandrectanglepath[3][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) coordinate (#3-tl)
-- (0.5,-0.5) coordinate (#3-br);endscope
%path (0,0) pic (A) rectanglepath (2,0) pic[dashed] (B) rectanglepath;
rectanglepath0,0A
rectanglepath[dashed]2,0B
draw (A-tl) to[out=30,in=150] (B-tl) (A-br) to[out=-30,in=-150] (B-br);
endtikzpicture
subsection*Transformations are much more intuitive on macros
begintikzpicture[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);]
newcommandrectanglepath[2][]
scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1);endscope
%path (0,0) pic[rotate=45]rectanglepath (2,0) pic[dashed,rotate=-30]rectanglepath
%(4,0) pic[thick,xscale=0.5]rectanglepath;
rectanglepath[rotate=45]0,0
rectanglepath[rotate=-30,dashed]2,0
rectanglepath[thick,xscale=0.5]4,0
endtikzpicture
enddocument
tikz-pgf macros tikz-pic
Consider this code in the TikZ - PGF manual, which uses a macro
% Main code from
% The TikZ - PGF manual
% Author: Till Tantau et al
% Version 3.1.3, released May 9, 2019
% Page 40
documentclass[tikz]standalone
begindocument
begintikzpicture
defrectanglepath-- ++(1cm,0cm) -- ++(0cm,1cm) -- ++(-1cm,0cm) -- cycle
draw (0,0) rectanglepath;
draw (1.5,0) rectanglepath;
endtikzpicture
enddocument
and this one written by me, which uses pic
documentclass[tikz]standalone
begindocument
begintikzpicture
[rectanglepath/.pic=draw (0,0)--++(1cm,0cm)--++(0cm,1cm)--++(-1cm,0cm)--cycle;]
pic at (0,0) rectanglepath;
pic at (1.5,0) rectanglepath;
endtikzpicture
enddocument
Both give us the same output
Observation
Both give the same output. I prefer the latter one, as it is more "TikZ-ish". However, we can always change a code from pic
to macro and vice versa, as above (am I wrong – is there a case in which we can't convert?), or draw the same figure using two different codes (this and this for example).
Also, I can't see any aspects in which macros are better than pic
. Even arguments: we can also have pic
with up to nine arguments with any pattern using /.style args
.
In the PGF manual, sometimes I see pic
is used, but sometimes a macro is used (it is even used in the title page!). From those examples, I can't figure out in what case I should use a macro and in what case I should use a pic
.
Question
It may be quite clear by now.
If I have to draw the same "sub-"picture many times in a TikZ picture, should I use a
pic
or a macro? And why? Is there any cases in which I must use this one and not the other?
Thanks in advance.
Edit
As for @marmot's nice codes, I have written myself some code (against it) which uses macros
documentclassarticle
usepackagetikz
begindocument
subsection*Macros can have more complicated constructions
begintikzpicture%[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
%draw[red] (-0.5,0.5) -- (0.5,-0.5);]
newcommandrectanglepath[2][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) -- (0.5,-0.5);endscope
%path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath;
rectanglepath0,0
rectanglepath[dashed]2,0
endtikzpicture
subsection*Macros can have names
begintikzpicture%[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
%draw[red] (-0.5,0.5) coordinate(-tl) -- (0.5,-0.5) coordinate(-br) ;]
newcommandrectanglepath[3][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) coordinate (#3-tl)
-- (0.5,-0.5) coordinate (#3-br);endscope
%path (0,0) pic (A) rectanglepath (2,0) pic[dashed] (B) rectanglepath;
rectanglepath0,0A
rectanglepath[dashed]2,0B
draw (A-tl) to[out=30,in=150] (B-tl) (A-br) to[out=-30,in=-150] (B-br);
endtikzpicture
subsection*Transformations are much more intuitive on macros
begintikzpicture[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);]
newcommandrectanglepath[2][]
scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1);endscope
%path (0,0) pic[rotate=45]rectanglepath (2,0) pic[dashed,rotate=-30]rectanglepath
%(4,0) pic[thick,xscale=0.5]rectanglepath;
rectanglepath[rotate=45]0,0
rectanglepath[rotate=-30,dashed]2,0
rectanglepath[thick,xscale=0.5]4,0
endtikzpicture
enddocument
tikz-pgf macros tikz-pic
tikz-pgf macros tikz-pic
edited May 25 at 16:11
The old JouleV
asked May 25 at 11:38
The old JouleVThe old JouleV
19.5k43176
19.5k43176
My experience is that pics are faster. For example, the threads on a screw.
– John Kormylo
May 25 at 13:45
@JohnKormylo If yes, probably it is faster on very long documents. On reports I usually write, they are equal in time taken
– The old JouleV
May 25 at 15:16
add a comment |
My experience is that pics are faster. For example, the threads on a screw.
– John Kormylo
May 25 at 13:45
@JohnKormylo If yes, probably it is faster on very long documents. On reports I usually write, they are equal in time taken
– The old JouleV
May 25 at 15:16
My experience is that pics are faster. For example, the threads on a screw.
– John Kormylo
May 25 at 13:45
My experience is that pics are faster. For example, the threads on a screw.
– John Kormylo
May 25 at 13:45
@JohnKormylo If yes, probably it is faster on very long documents. On reports I usually write, they are equal in time taken
– The old JouleV
May 25 at 15:16
@JohnKormylo If yes, probably it is faster on very long documents. On reports I usually write, they are equal in time taken
– The old JouleV
May 25 at 15:16
add a comment |
1 Answer
1
active
oldest
votes
Here are threefour examples of things that are much harder to achieve in the macro approach. The first three examples have been translated to macros in the revised question.
documentclassarticle
usepackagetikz
begindocument
subsection*Pics can have more complicated constructions
tikzsetrectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) coordinate(-tl) -- (0.5,-0.5) coordinate(-br) ;
begintikzpicture
path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath;
endtikzpicture
subsection*Pics can have names
begintikzpicture
path (0,0) pic (A) rectanglepath (2,0) pic[dashed] (B) rectanglepath;
draw (A-tl) to[out=30,in=150] (B-tl) (A-br) to[out=-30,in=-150] (B-br);
endtikzpicture
subsection*Transformations are much more intuitive on pics
begintikzpicture
path (0,0) pic[rotate=45]rectanglepath (2,0) pic[dashed,rotate=-30]rectanglepath
(4,0) pic[thick,xscale=0.5]rectanglepath;
endtikzpicture
subsection*You can insert pics in paths
begintikzpicture[xboard/.style=insert path=
(0,0) grid (#1,#1)
foreach X in 1,...,#1
(X-0.5,X-0.5) picrectanglepath (X-0.5,#1-X+0.5) pic[rotate=90]rectanglepath]
draw[xboard=1,xshift=2cm,xboard=3,xshift=4cm,xboard=5];
endtikzpicture
enddocument
My personal take: pic
s win, at least in the above-described scenarios. IMHO the translated macros in the revised question substantiate this.
Notice that "behind the scenes" pics are macros at some level. So you will always be able to reproduce the outcome of a pic with a macro. However, the effort will be more substantial. And yes, if you are in the mood to do some unnecessary extra work, you can use macros instead of pics. So, yes, the choice can depend on the mood of the day.
Let me also stress that there are scenarios in which pics perform worse. An example of this type may be a life wheel.
BTW, there is also the insert path
option that is sometimes preferable over pic
s IMO.
1
+1: Perfect answer!
– Dr. Manuel Kuehner
May 25 at 13:42
2
@JouleV Well, at some level apic
is a macro. My point is simply that things are harder to achieve with macros, and your macros substantiate this. I never claimed that you cannot achieve things done with a pic also with a macro, it is just harder and also less elegant IMHO.
– marmot
May 25 at 15:42
2
@JouleV You also misinterpreted "The first thingy hasnewcommandrectanglepath[2][]...
, the nextnewcommandrectanglepath[3][]...
, they are not the same. ". The point is that you have to write different macros for different situations, and if you want to have the combined functionality, things become even more complicated. BTW,foreach X in 1,2,3 begintikzpicture[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);] path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath; endtikzpicture
works ...
– marmot
May 25 at 15:55
1
butforeach X in 1,2,3 begintikzpicture newcommandrectanglepath[2][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);endscope rectanglepath0,0 rectanglepath[dashed]2,0 endtikzpicture
doesn't. (Yes, I know how to fix it but it is, again, more complicated.)
– marmot
May 25 at 15:55
1
@JouleV I tried to answer the question If I have to draw the same "sub-"picture many times in a TikZ picture, should I use a pic or a macro? And why?. My answer is that in most situationspic
s are less complicated, which is why they are arguably preferable.
– marmot
May 25 at 16:48
|
show 18 more comments
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
oldest
votes
Here are threefour examples of things that are much harder to achieve in the macro approach. The first three examples have been translated to macros in the revised question.
documentclassarticle
usepackagetikz
begindocument
subsection*Pics can have more complicated constructions
tikzsetrectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) coordinate(-tl) -- (0.5,-0.5) coordinate(-br) ;
begintikzpicture
path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath;
endtikzpicture
subsection*Pics can have names
begintikzpicture
path (0,0) pic (A) rectanglepath (2,0) pic[dashed] (B) rectanglepath;
draw (A-tl) to[out=30,in=150] (B-tl) (A-br) to[out=-30,in=-150] (B-br);
endtikzpicture
subsection*Transformations are much more intuitive on pics
begintikzpicture
path (0,0) pic[rotate=45]rectanglepath (2,0) pic[dashed,rotate=-30]rectanglepath
(4,0) pic[thick,xscale=0.5]rectanglepath;
endtikzpicture
subsection*You can insert pics in paths
begintikzpicture[xboard/.style=insert path=
(0,0) grid (#1,#1)
foreach X in 1,...,#1
(X-0.5,X-0.5) picrectanglepath (X-0.5,#1-X+0.5) pic[rotate=90]rectanglepath]
draw[xboard=1,xshift=2cm,xboard=3,xshift=4cm,xboard=5];
endtikzpicture
enddocument
My personal take: pic
s win, at least in the above-described scenarios. IMHO the translated macros in the revised question substantiate this.
Notice that "behind the scenes" pics are macros at some level. So you will always be able to reproduce the outcome of a pic with a macro. However, the effort will be more substantial. And yes, if you are in the mood to do some unnecessary extra work, you can use macros instead of pics. So, yes, the choice can depend on the mood of the day.
Let me also stress that there are scenarios in which pics perform worse. An example of this type may be a life wheel.
BTW, there is also the insert path
option that is sometimes preferable over pic
s IMO.
1
+1: Perfect answer!
– Dr. Manuel Kuehner
May 25 at 13:42
2
@JouleV Well, at some level apic
is a macro. My point is simply that things are harder to achieve with macros, and your macros substantiate this. I never claimed that you cannot achieve things done with a pic also with a macro, it is just harder and also less elegant IMHO.
– marmot
May 25 at 15:42
2
@JouleV You also misinterpreted "The first thingy hasnewcommandrectanglepath[2][]...
, the nextnewcommandrectanglepath[3][]...
, they are not the same. ". The point is that you have to write different macros for different situations, and if you want to have the combined functionality, things become even more complicated. BTW,foreach X in 1,2,3 begintikzpicture[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);] path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath; endtikzpicture
works ...
– marmot
May 25 at 15:55
1
butforeach X in 1,2,3 begintikzpicture newcommandrectanglepath[2][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);endscope rectanglepath0,0 rectanglepath[dashed]2,0 endtikzpicture
doesn't. (Yes, I know how to fix it but it is, again, more complicated.)
– marmot
May 25 at 15:55
1
@JouleV I tried to answer the question If I have to draw the same "sub-"picture many times in a TikZ picture, should I use a pic or a macro? And why?. My answer is that in most situationspic
s are less complicated, which is why they are arguably preferable.
– marmot
May 25 at 16:48
|
show 18 more comments
Here are threefour examples of things that are much harder to achieve in the macro approach. The first three examples have been translated to macros in the revised question.
documentclassarticle
usepackagetikz
begindocument
subsection*Pics can have more complicated constructions
tikzsetrectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) coordinate(-tl) -- (0.5,-0.5) coordinate(-br) ;
begintikzpicture
path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath;
endtikzpicture
subsection*Pics can have names
begintikzpicture
path (0,0) pic (A) rectanglepath (2,0) pic[dashed] (B) rectanglepath;
draw (A-tl) to[out=30,in=150] (B-tl) (A-br) to[out=-30,in=-150] (B-br);
endtikzpicture
subsection*Transformations are much more intuitive on pics
begintikzpicture
path (0,0) pic[rotate=45]rectanglepath (2,0) pic[dashed,rotate=-30]rectanglepath
(4,0) pic[thick,xscale=0.5]rectanglepath;
endtikzpicture
subsection*You can insert pics in paths
begintikzpicture[xboard/.style=insert path=
(0,0) grid (#1,#1)
foreach X in 1,...,#1
(X-0.5,X-0.5) picrectanglepath (X-0.5,#1-X+0.5) pic[rotate=90]rectanglepath]
draw[xboard=1,xshift=2cm,xboard=3,xshift=4cm,xboard=5];
endtikzpicture
enddocument
My personal take: pic
s win, at least in the above-described scenarios. IMHO the translated macros in the revised question substantiate this.
Notice that "behind the scenes" pics are macros at some level. So you will always be able to reproduce the outcome of a pic with a macro. However, the effort will be more substantial. And yes, if you are in the mood to do some unnecessary extra work, you can use macros instead of pics. So, yes, the choice can depend on the mood of the day.
Let me also stress that there are scenarios in which pics perform worse. An example of this type may be a life wheel.
BTW, there is also the insert path
option that is sometimes preferable over pic
s IMO.
1
+1: Perfect answer!
– Dr. Manuel Kuehner
May 25 at 13:42
2
@JouleV Well, at some level apic
is a macro. My point is simply that things are harder to achieve with macros, and your macros substantiate this. I never claimed that you cannot achieve things done with a pic also with a macro, it is just harder and also less elegant IMHO.
– marmot
May 25 at 15:42
2
@JouleV You also misinterpreted "The first thingy hasnewcommandrectanglepath[2][]...
, the nextnewcommandrectanglepath[3][]...
, they are not the same. ". The point is that you have to write different macros for different situations, and if you want to have the combined functionality, things become even more complicated. BTW,foreach X in 1,2,3 begintikzpicture[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);] path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath; endtikzpicture
works ...
– marmot
May 25 at 15:55
1
butforeach X in 1,2,3 begintikzpicture newcommandrectanglepath[2][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);endscope rectanglepath0,0 rectanglepath[dashed]2,0 endtikzpicture
doesn't. (Yes, I know how to fix it but it is, again, more complicated.)
– marmot
May 25 at 15:55
1
@JouleV I tried to answer the question If I have to draw the same "sub-"picture many times in a TikZ picture, should I use a pic or a macro? And why?. My answer is that in most situationspic
s are less complicated, which is why they are arguably preferable.
– marmot
May 25 at 16:48
|
show 18 more comments
Here are threefour examples of things that are much harder to achieve in the macro approach. The first three examples have been translated to macros in the revised question.
documentclassarticle
usepackagetikz
begindocument
subsection*Pics can have more complicated constructions
tikzsetrectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) coordinate(-tl) -- (0.5,-0.5) coordinate(-br) ;
begintikzpicture
path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath;
endtikzpicture
subsection*Pics can have names
begintikzpicture
path (0,0) pic (A) rectanglepath (2,0) pic[dashed] (B) rectanglepath;
draw (A-tl) to[out=30,in=150] (B-tl) (A-br) to[out=-30,in=-150] (B-br);
endtikzpicture
subsection*Transformations are much more intuitive on pics
begintikzpicture
path (0,0) pic[rotate=45]rectanglepath (2,0) pic[dashed,rotate=-30]rectanglepath
(4,0) pic[thick,xscale=0.5]rectanglepath;
endtikzpicture
subsection*You can insert pics in paths
begintikzpicture[xboard/.style=insert path=
(0,0) grid (#1,#1)
foreach X in 1,...,#1
(X-0.5,X-0.5) picrectanglepath (X-0.5,#1-X+0.5) pic[rotate=90]rectanglepath]
draw[xboard=1,xshift=2cm,xboard=3,xshift=4cm,xboard=5];
endtikzpicture
enddocument
My personal take: pic
s win, at least in the above-described scenarios. IMHO the translated macros in the revised question substantiate this.
Notice that "behind the scenes" pics are macros at some level. So you will always be able to reproduce the outcome of a pic with a macro. However, the effort will be more substantial. And yes, if you are in the mood to do some unnecessary extra work, you can use macros instead of pics. So, yes, the choice can depend on the mood of the day.
Let me also stress that there are scenarios in which pics perform worse. An example of this type may be a life wheel.
BTW, there is also the insert path
option that is sometimes preferable over pic
s IMO.
Here are threefour examples of things that are much harder to achieve in the macro approach. The first three examples have been translated to macros in the revised question.
documentclassarticle
usepackagetikz
begindocument
subsection*Pics can have more complicated constructions
tikzsetrectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1);
draw[red] (-0.5,0.5) coordinate(-tl) -- (0.5,-0.5) coordinate(-br) ;
begintikzpicture
path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath;
endtikzpicture
subsection*Pics can have names
begintikzpicture
path (0,0) pic (A) rectanglepath (2,0) pic[dashed] (B) rectanglepath;
draw (A-tl) to[out=30,in=150] (B-tl) (A-br) to[out=-30,in=-150] (B-br);
endtikzpicture
subsection*Transformations are much more intuitive on pics
begintikzpicture
path (0,0) pic[rotate=45]rectanglepath (2,0) pic[dashed,rotate=-30]rectanglepath
(4,0) pic[thick,xscale=0.5]rectanglepath;
endtikzpicture
subsection*You can insert pics in paths
begintikzpicture[xboard/.style=insert path=
(0,0) grid (#1,#1)
foreach X in 1,...,#1
(X-0.5,X-0.5) picrectanglepath (X-0.5,#1-X+0.5) pic[rotate=90]rectanglepath]
draw[xboard=1,xshift=2cm,xboard=3,xshift=4cm,xboard=5];
endtikzpicture
enddocument
My personal take: pic
s win, at least in the above-described scenarios. IMHO the translated macros in the revised question substantiate this.
Notice that "behind the scenes" pics are macros at some level. So you will always be able to reproduce the outcome of a pic with a macro. However, the effort will be more substantial. And yes, if you are in the mood to do some unnecessary extra work, you can use macros instead of pics. So, yes, the choice can depend on the mood of the day.
Let me also stress that there are scenarios in which pics perform worse. An example of this type may be a life wheel.
BTW, there is also the insert path
option that is sometimes preferable over pic
s IMO.
edited May 28 at 20:16
answered May 25 at 13:37
marmotmarmot
134k6174322
134k6174322
1
+1: Perfect answer!
– Dr. Manuel Kuehner
May 25 at 13:42
2
@JouleV Well, at some level apic
is a macro. My point is simply that things are harder to achieve with macros, and your macros substantiate this. I never claimed that you cannot achieve things done with a pic also with a macro, it is just harder and also less elegant IMHO.
– marmot
May 25 at 15:42
2
@JouleV You also misinterpreted "The first thingy hasnewcommandrectanglepath[2][]...
, the nextnewcommandrectanglepath[3][]...
, they are not the same. ". The point is that you have to write different macros for different situations, and if you want to have the combined functionality, things become even more complicated. BTW,foreach X in 1,2,3 begintikzpicture[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);] path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath; endtikzpicture
works ...
– marmot
May 25 at 15:55
1
butforeach X in 1,2,3 begintikzpicture newcommandrectanglepath[2][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);endscope rectanglepath0,0 rectanglepath[dashed]2,0 endtikzpicture
doesn't. (Yes, I know how to fix it but it is, again, more complicated.)
– marmot
May 25 at 15:55
1
@JouleV I tried to answer the question If I have to draw the same "sub-"picture many times in a TikZ picture, should I use a pic or a macro? And why?. My answer is that in most situationspic
s are less complicated, which is why they are arguably preferable.
– marmot
May 25 at 16:48
|
show 18 more comments
1
+1: Perfect answer!
– Dr. Manuel Kuehner
May 25 at 13:42
2
@JouleV Well, at some level apic
is a macro. My point is simply that things are harder to achieve with macros, and your macros substantiate this. I never claimed that you cannot achieve things done with a pic also with a macro, it is just harder and also less elegant IMHO.
– marmot
May 25 at 15:42
2
@JouleV You also misinterpreted "The first thingy hasnewcommandrectanglepath[2][]...
, the nextnewcommandrectanglepath[3][]...
, they are not the same. ". The point is that you have to write different macros for different situations, and if you want to have the combined functionality, things become even more complicated. BTW,foreach X in 1,2,3 begintikzpicture[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);] path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath; endtikzpicture
works ...
– marmot
May 25 at 15:55
1
butforeach X in 1,2,3 begintikzpicture newcommandrectanglepath[2][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);endscope rectanglepath0,0 rectanglepath[dashed]2,0 endtikzpicture
doesn't. (Yes, I know how to fix it but it is, again, more complicated.)
– marmot
May 25 at 15:55
1
@JouleV I tried to answer the question If I have to draw the same "sub-"picture many times in a TikZ picture, should I use a pic or a macro? And why?. My answer is that in most situationspic
s are less complicated, which is why they are arguably preferable.
– marmot
May 25 at 16:48
1
1
+1: Perfect answer!
– Dr. Manuel Kuehner
May 25 at 13:42
+1: Perfect answer!
– Dr. Manuel Kuehner
May 25 at 13:42
2
2
@JouleV Well, at some level a
pic
is a macro. My point is simply that things are harder to achieve with macros, and your macros substantiate this. I never claimed that you cannot achieve things done with a pic also with a macro, it is just harder and also less elegant IMHO.– marmot
May 25 at 15:42
@JouleV Well, at some level a
pic
is a macro. My point is simply that things are harder to achieve with macros, and your macros substantiate this. I never claimed that you cannot achieve things done with a pic also with a macro, it is just harder and also less elegant IMHO.– marmot
May 25 at 15:42
2
2
@JouleV You also misinterpreted "The first thingy has
newcommandrectanglepath[2][]...
, the next newcommandrectanglepath[3][]...
, they are not the same. ". The point is that you have to write different macros for different situations, and if you want to have the combined functionality, things become even more complicated. BTW, foreach X in 1,2,3 begintikzpicture[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);] path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath; endtikzpicture
works ...– marmot
May 25 at 15:55
@JouleV You also misinterpreted "The first thingy has
newcommandrectanglepath[2][]...
, the next newcommandrectanglepath[3][]...
, they are not the same. ". The point is that you have to write different macros for different situations, and if you want to have the combined functionality, things become even more complicated. BTW, foreach X in 1,2,3 begintikzpicture[rectanglepath/.pic=draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);] path (0,0) picrectanglepath (2,0) pic[dashed]rectanglepath; endtikzpicture
works ...– marmot
May 25 at 15:55
1
1
but
foreach X in 1,2,3 begintikzpicture newcommandrectanglepath[2][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);endscope rectanglepath0,0 rectanglepath[dashed]2,0 endtikzpicture
doesn't. (Yes, I know how to fix it but it is, again, more complicated.)– marmot
May 25 at 15:55
but
foreach X in 1,2,3 begintikzpicture newcommandrectanglepath[2][]scope[shift=(#2),#1]draw (-0.5,-0.5) rectangle ++(1,1); draw[red] (-0.5,0.5) -- (0.5,-0.5);endscope rectanglepath0,0 rectanglepath[dashed]2,0 endtikzpicture
doesn't. (Yes, I know how to fix it but it is, again, more complicated.)– marmot
May 25 at 15:55
1
1
@JouleV I tried to answer the question If I have to draw the same "sub-"picture many times in a TikZ picture, should I use a pic or a macro? And why?. My answer is that in most situations
pic
s are less complicated, which is why they are arguably preferable.– marmot
May 25 at 16:48
@JouleV I tried to answer the question If I have to draw the same "sub-"picture many times in a TikZ picture, should I use a pic or a macro? And why?. My answer is that in most situations
pic
s are less complicated, which is why they are arguably preferable.– marmot
May 25 at 16:48
|
show 18 more comments
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My experience is that pics are faster. For example, the threads on a screw.
– John Kormylo
May 25 at 13:45
@JohnKormylo If yes, probably it is faster on very long documents. On reports I usually write, they are equal in time taken
– The old JouleV
May 25 at 15:16