Is there any use case for the bottom type as a function parameter type?What is the difference between the semantic and syntactic views of function types?Type systems understanding problemsWhy aren't we researching more towards compile time guarantees?Why do we have to forbid non-conforming lower and upper type bounds?Question about “Type checking a multithreaded functional language with session types” by Vasconcelos et alSafe way to explicitly define new types instead of using Algebraic data types for my functional languageType-classes for type inferenceHow could one write typing rules with variables defined at call-site?What is the use case for multi-type-parameter generics?What is the use case of multi-type-parameters generic interface?
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Is there any use case for the bottom type as a function parameter type?
What is the difference between the semantic and syntactic views of function types?Type systems understanding problemsWhy aren't we researching more towards compile time guarantees?Why do we have to forbid non-conforming lower and upper type bounds?Question about “Type checking a multithreaded functional language with session types” by Vasconcelos et alSafe way to explicitly define new types instead of using Algebraic data types for my functional languageType-classes for type inferenceHow could one write typing rules with variables defined at call-site?What is the use case for multi-type-parameter generics?What is the use case of multi-type-parameters generic interface?
$begingroup$
If a function has return type of ⊥ (bottom type), that means it never returns. It can for example exit or throw, both fairly ordinary situations.
Presumably if a function had a parameter of type ⊥ it could never (safely) be called. Are there ever any reasons for defining such a function?
type-theory type-checking
$endgroup$
add a comment |
$begingroup$
If a function has return type of ⊥ (bottom type), that means it never returns. It can for example exit or throw, both fairly ordinary situations.
Presumably if a function had a parameter of type ⊥ it could never (safely) be called. Are there ever any reasons for defining such a function?
type-theory type-checking
$endgroup$
add a comment |
$begingroup$
If a function has return type of ⊥ (bottom type), that means it never returns. It can for example exit or throw, both fairly ordinary situations.
Presumably if a function had a parameter of type ⊥ it could never (safely) be called. Are there ever any reasons for defining such a function?
type-theory type-checking
$endgroup$
If a function has return type of ⊥ (bottom type), that means it never returns. It can for example exit or throw, both fairly ordinary situations.
Presumably if a function had a parameter of type ⊥ it could never (safely) be called. Are there ever any reasons for defining such a function?
type-theory type-checking
type-theory type-checking
asked May 26 at 21:08
bdslbdsl
1614
1614
add a comment |
add a comment |
5 Answers
5
active
oldest
votes
$begingroup$
One of the defining properties of the $bot$ or empty type is that there exists a function $bot to A$ for every type $A$. In fact, there exists a unique such function. It is therefore, fairly reasonable for this function to be provided as part of the standard library. Often it is called something like absurd
. (In systems with subtyping, this might be handled simply by having $bot$ be a subtype of every type. Then the implicit conversion is absurd
. Another related approach is to define $bot$ as $forall alpha.alpha$ which can simply be instantiated to any type.)
You definitely want to have such a function or an equivalent because it is what allows you to make use of functions that produce $bot$. For example, let's say I'm given a sum type $E+A$. I do a case analysis on it and in the $E$ case I'm going to throw an exception using $mathttthrow:Etobot$. In the $A$ case, I'll use $f:Ato B$. Overall, I want a value of type $B$ so I need to do something to turn a $bot$ into a $B$. That's what absurd
would let me do.
That said, there's not a whole lot of reason to define your own functions of $botto A$. By definition, they would necessarily be instances of absurd
. Still, you might do it if absurd
isn't provided by the standard library, or you wanted a type specialized version to assist type checking/inference. You can, however, easily produce functions that will end up instantiated to a type like $botto A$.
Even though there isn't much a reason to write such a function, it should generally still be allowed. One reason is that it simplifies code generation tools/macros.
$endgroup$
$begingroup$
So this means something like(x ? 3 : throw new Exception())
gets replaced for analysis purposes with something more like(x ? 3 : absurd(throw new Exception()))
?
$endgroup$
– bdsl
May 28 at 9:05
$begingroup$
If you didn't have subtyping or hadn't defined $bot$ as $forall alpha.alpha$, then the former wouldn't type check and the latter would. With subtyping, yes, something likeabsurd
would implicitly be being inserted. Of course, you could put theabsurd
inside the definition ofthrow
which is effectively what defining $bot$ as $forallalpha.alpha$ would do.
$endgroup$
– Derek Elkins
May 28 at 18:50
add a comment |
$begingroup$
To add to what has been said about the function absurd: ⊥ -> a
I have a concrete example of where this function is actually useful.
Consider the Haskell data-type Free f a
which represents a general tree structure with f
-shaped nodes and leaves containing a
s:
data Free f a = Op (f (Free f a)) | Var a
These trees can be folded with the following function:
fold :: Functor f => (a -> b) -> (f b -> b) -> Free f a -> b
fold gen alg (Var x) = gen x
fold gen alg (Op x) = alg (fmap (fold gen alg) x)
Briefly, this operation places alg
at the nodes and gen
at the leaves.
Now to the point: all recursive datastructures can be represented using a Fixed-point datatype. In Haskell this is Fix f
and it can defined as type Fix f = Free f ⊥
(i.e. Trees with f
-shaped nodes and no leaves outside of the functor f
). Traditionally this structure has a fold as well, called cata
:
cata :: Functor f => (f a -> a) -> Fix f -> a
cata alg x = fold absurd alg x
Which gives a quite neat use of absurd: since the tree cannot have any leaves (since ⊥ has no inhabitants other than undefined
), it is never possible to use the gen
for this fold and absurd
illustrates that!
$endgroup$
add a comment |
$begingroup$
The bottom type is a subtype of every other type, which can be extremely useful in practice. For example, the type of NULL
in a theoretical type-safe version of C must be a subtype of every other pointer type, otherwise you couldn't e.g. return NULL
where a char*
was expected; similarly, the type of undefined
in theoretical type-safe JavaScript must be a subtype of every other type in the language.
As a function return type, it's also very useful to have certain functions that never return. In a strongly-typed language with exceptions, for instance, what type should exit()
or throw()
return? They never return control flow to their caller. And since the bottom type is a subtype of every other type, it's perfectly valid for a function returning Int
to instead return $bot$—that is, a function returning Int
can also choose not to return at all. (Maybe it calls exit()
, or maybe it goes into an infinite loop.) This is good to have, because whether a function ever returns or not is famously undecidable.
Finally, it's very useful for writing constraints. Suppose you want to constrain all parameters on "both sides", providing a type that must be a supertype of the parameter, and another type that must be a subtype. Since bottom is a subtype of every type, you can express "any subtype of S" as $bot prec T prec S$. Or, you can express "any type at all" as $bot prec T prec top$.
$endgroup$
3
$begingroup$
NULL
is a unit type isn't it, distinct from ⊥ which is the empty type?
$endgroup$
– bdsl
May 26 at 23:18
$begingroup$
I'm not sure quite what ≺ means in type theory.
$endgroup$
– bdsl
May 26 at 23:18
1
$begingroup$
@bdsl The curved operator here is "is a subtype of"; I'm not sure if it's standard, it's just what my professor used.
$endgroup$
– Draconis
May 26 at 23:40
1
$begingroup$
@gnasher729 True, but C also isn't particularly type-safe. I'm saying if you couldn't just cast an integer tovoid*
, you'd need a specific type for it that could be used for any pointer type.
$endgroup$
– Draconis
May 26 at 23:42
2
$begingroup$
Incidentally, the most common notation I've seen for the subtyping relation is<:
e.g. System $F_mathtt<:$.
$endgroup$
– Derek Elkins
May 27 at 1:50
|
show 6 more comments
$begingroup$
There is one use I can think of, and it's something that has been considered as an improvement to the Swift programming language.
Swift has a maybe
Monad, spelled Optional<T>
or T?
. There are many ways to interact with it.
You can use conditional unwrapping like
if let nonOptional = someOptional
print(nonOptional)
else
print("someOptional was nil")You can use
map
,flatMap
to transform the values- The force unwrap operator (
!
, of type(T?) -> T
) to forcefully unwrap the contents, otherwise triggering a crash The nil-coalescing operator (
??
, of type(T?, T) -> T
) to take its value or otherwise use a default value:let someI = Optional(100)
print(someI ?? 123) => 100 // "left operand is non-nil, unwrap it.
let noneI: Int? = nil
print(noneI ?? 123) // => 123 // left operand is nil, take right operand, acts like a "default" value
Unfortunately, there was no concise way of saying "unwrap or throw an error" or "unwrap or crash with a custom error message". Something like
let someI: Int? = Optional(123)
let nonOptionalI: Int = someI ?? fatalError("Expected a non-nil value")
doesn't compile, because fatalError
has type () -> Never
(()
is Void
, Swift' unit type, Never
is Swift's bottom type). Calling it produces Never
, which isn't compatible with the T
expected as a right operand of ??
.
In an attempt to remedy this, Swift Evolution propsoal SE-0217
- The “Unwrap or Die” operator was put forth. It was ultimately rejected, but it raised interest in making Never
be a subtype of all types.
If Never
was made to be a subtype of all types, then the previous example will be compilable:
let someI: Int? = Optional(123)
let nonOptionalI: Int = someI ?? fatalError("Expected a non-nil value")
because the call site of ??
has type (T?, Never) -> T
, which would be compatible with the (T?, T) -> T
signature of ??
.
$endgroup$
add a comment |
$begingroup$
Swift has a type "Never" which seems to be quite like the bottom type: A function declared to return Never can never return, a function with a parameter of type Never can never be called.
This is useful in connection with protocols, where there may be a restriction due to the type system of the language that a class must have a certain function, but with no requirement that this function should ever be called, and no requirement what the argument types would be.
For details you should have a look at the newer posts on the swift-evolution mailing list.
$endgroup$
7
$begingroup$
"Newer posts on the swift-evolution mailing list" is not a very clear or stable reference. Is there not a web archive of the mailing list?
$endgroup$
– Derek Elkins
May 27 at 2:10
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
One of the defining properties of the $bot$ or empty type is that there exists a function $bot to A$ for every type $A$. In fact, there exists a unique such function. It is therefore, fairly reasonable for this function to be provided as part of the standard library. Often it is called something like absurd
. (In systems with subtyping, this might be handled simply by having $bot$ be a subtype of every type. Then the implicit conversion is absurd
. Another related approach is to define $bot$ as $forall alpha.alpha$ which can simply be instantiated to any type.)
You definitely want to have such a function or an equivalent because it is what allows you to make use of functions that produce $bot$. For example, let's say I'm given a sum type $E+A$. I do a case analysis on it and in the $E$ case I'm going to throw an exception using $mathttthrow:Etobot$. In the $A$ case, I'll use $f:Ato B$. Overall, I want a value of type $B$ so I need to do something to turn a $bot$ into a $B$. That's what absurd
would let me do.
That said, there's not a whole lot of reason to define your own functions of $botto A$. By definition, they would necessarily be instances of absurd
. Still, you might do it if absurd
isn't provided by the standard library, or you wanted a type specialized version to assist type checking/inference. You can, however, easily produce functions that will end up instantiated to a type like $botto A$.
Even though there isn't much a reason to write such a function, it should generally still be allowed. One reason is that it simplifies code generation tools/macros.
$endgroup$
$begingroup$
So this means something like(x ? 3 : throw new Exception())
gets replaced for analysis purposes with something more like(x ? 3 : absurd(throw new Exception()))
?
$endgroup$
– bdsl
May 28 at 9:05
$begingroup$
If you didn't have subtyping or hadn't defined $bot$ as $forall alpha.alpha$, then the former wouldn't type check and the latter would. With subtyping, yes, something likeabsurd
would implicitly be being inserted. Of course, you could put theabsurd
inside the definition ofthrow
which is effectively what defining $bot$ as $forallalpha.alpha$ would do.
$endgroup$
– Derek Elkins
May 28 at 18:50
add a comment |
$begingroup$
One of the defining properties of the $bot$ or empty type is that there exists a function $bot to A$ for every type $A$. In fact, there exists a unique such function. It is therefore, fairly reasonable for this function to be provided as part of the standard library. Often it is called something like absurd
. (In systems with subtyping, this might be handled simply by having $bot$ be a subtype of every type. Then the implicit conversion is absurd
. Another related approach is to define $bot$ as $forall alpha.alpha$ which can simply be instantiated to any type.)
You definitely want to have such a function or an equivalent because it is what allows you to make use of functions that produce $bot$. For example, let's say I'm given a sum type $E+A$. I do a case analysis on it and in the $E$ case I'm going to throw an exception using $mathttthrow:Etobot$. In the $A$ case, I'll use $f:Ato B$. Overall, I want a value of type $B$ so I need to do something to turn a $bot$ into a $B$. That's what absurd
would let me do.
That said, there's not a whole lot of reason to define your own functions of $botto A$. By definition, they would necessarily be instances of absurd
. Still, you might do it if absurd
isn't provided by the standard library, or you wanted a type specialized version to assist type checking/inference. You can, however, easily produce functions that will end up instantiated to a type like $botto A$.
Even though there isn't much a reason to write such a function, it should generally still be allowed. One reason is that it simplifies code generation tools/macros.
$endgroup$
$begingroup$
So this means something like(x ? 3 : throw new Exception())
gets replaced for analysis purposes with something more like(x ? 3 : absurd(throw new Exception()))
?
$endgroup$
– bdsl
May 28 at 9:05
$begingroup$
If you didn't have subtyping or hadn't defined $bot$ as $forall alpha.alpha$, then the former wouldn't type check and the latter would. With subtyping, yes, something likeabsurd
would implicitly be being inserted. Of course, you could put theabsurd
inside the definition ofthrow
which is effectively what defining $bot$ as $forallalpha.alpha$ would do.
$endgroup$
– Derek Elkins
May 28 at 18:50
add a comment |
$begingroup$
One of the defining properties of the $bot$ or empty type is that there exists a function $bot to A$ for every type $A$. In fact, there exists a unique such function. It is therefore, fairly reasonable for this function to be provided as part of the standard library. Often it is called something like absurd
. (In systems with subtyping, this might be handled simply by having $bot$ be a subtype of every type. Then the implicit conversion is absurd
. Another related approach is to define $bot$ as $forall alpha.alpha$ which can simply be instantiated to any type.)
You definitely want to have such a function or an equivalent because it is what allows you to make use of functions that produce $bot$. For example, let's say I'm given a sum type $E+A$. I do a case analysis on it and in the $E$ case I'm going to throw an exception using $mathttthrow:Etobot$. In the $A$ case, I'll use $f:Ato B$. Overall, I want a value of type $B$ so I need to do something to turn a $bot$ into a $B$. That's what absurd
would let me do.
That said, there's not a whole lot of reason to define your own functions of $botto A$. By definition, they would necessarily be instances of absurd
. Still, you might do it if absurd
isn't provided by the standard library, or you wanted a type specialized version to assist type checking/inference. You can, however, easily produce functions that will end up instantiated to a type like $botto A$.
Even though there isn't much a reason to write such a function, it should generally still be allowed. One reason is that it simplifies code generation tools/macros.
$endgroup$
One of the defining properties of the $bot$ or empty type is that there exists a function $bot to A$ for every type $A$. In fact, there exists a unique such function. It is therefore, fairly reasonable for this function to be provided as part of the standard library. Often it is called something like absurd
. (In systems with subtyping, this might be handled simply by having $bot$ be a subtype of every type. Then the implicit conversion is absurd
. Another related approach is to define $bot$ as $forall alpha.alpha$ which can simply be instantiated to any type.)
You definitely want to have such a function or an equivalent because it is what allows you to make use of functions that produce $bot$. For example, let's say I'm given a sum type $E+A$. I do a case analysis on it and in the $E$ case I'm going to throw an exception using $mathttthrow:Etobot$. In the $A$ case, I'll use $f:Ato B$. Overall, I want a value of type $B$ so I need to do something to turn a $bot$ into a $B$. That's what absurd
would let me do.
That said, there's not a whole lot of reason to define your own functions of $botto A$. By definition, they would necessarily be instances of absurd
. Still, you might do it if absurd
isn't provided by the standard library, or you wanted a type specialized version to assist type checking/inference. You can, however, easily produce functions that will end up instantiated to a type like $botto A$.
Even though there isn't much a reason to write such a function, it should generally still be allowed. One reason is that it simplifies code generation tools/macros.
answered May 27 at 2:10
Derek ElkinsDerek Elkins
10.4k12435
10.4k12435
$begingroup$
So this means something like(x ? 3 : throw new Exception())
gets replaced for analysis purposes with something more like(x ? 3 : absurd(throw new Exception()))
?
$endgroup$
– bdsl
May 28 at 9:05
$begingroup$
If you didn't have subtyping or hadn't defined $bot$ as $forall alpha.alpha$, then the former wouldn't type check and the latter would. With subtyping, yes, something likeabsurd
would implicitly be being inserted. Of course, you could put theabsurd
inside the definition ofthrow
which is effectively what defining $bot$ as $forallalpha.alpha$ would do.
$endgroup$
– Derek Elkins
May 28 at 18:50
add a comment |
$begingroup$
So this means something like(x ? 3 : throw new Exception())
gets replaced for analysis purposes with something more like(x ? 3 : absurd(throw new Exception()))
?
$endgroup$
– bdsl
May 28 at 9:05
$begingroup$
If you didn't have subtyping or hadn't defined $bot$ as $forall alpha.alpha$, then the former wouldn't type check and the latter would. With subtyping, yes, something likeabsurd
would implicitly be being inserted. Of course, you could put theabsurd
inside the definition ofthrow
which is effectively what defining $bot$ as $forallalpha.alpha$ would do.
$endgroup$
– Derek Elkins
May 28 at 18:50
$begingroup$
So this means something like
(x ? 3 : throw new Exception())
gets replaced for analysis purposes with something more like (x ? 3 : absurd(throw new Exception()))
?$endgroup$
– bdsl
May 28 at 9:05
$begingroup$
So this means something like
(x ? 3 : throw new Exception())
gets replaced for analysis purposes with something more like (x ? 3 : absurd(throw new Exception()))
?$endgroup$
– bdsl
May 28 at 9:05
$begingroup$
If you didn't have subtyping or hadn't defined $bot$ as $forall alpha.alpha$, then the former wouldn't type check and the latter would. With subtyping, yes, something like
absurd
would implicitly be being inserted. Of course, you could put the absurd
inside the definition of throw
which is effectively what defining $bot$ as $forallalpha.alpha$ would do.$endgroup$
– Derek Elkins
May 28 at 18:50
$begingroup$
If you didn't have subtyping or hadn't defined $bot$ as $forall alpha.alpha$, then the former wouldn't type check and the latter would. With subtyping, yes, something like
absurd
would implicitly be being inserted. Of course, you could put the absurd
inside the definition of throw
which is effectively what defining $bot$ as $forallalpha.alpha$ would do.$endgroup$
– Derek Elkins
May 28 at 18:50
add a comment |
$begingroup$
To add to what has been said about the function absurd: ⊥ -> a
I have a concrete example of where this function is actually useful.
Consider the Haskell data-type Free f a
which represents a general tree structure with f
-shaped nodes and leaves containing a
s:
data Free f a = Op (f (Free f a)) | Var a
These trees can be folded with the following function:
fold :: Functor f => (a -> b) -> (f b -> b) -> Free f a -> b
fold gen alg (Var x) = gen x
fold gen alg (Op x) = alg (fmap (fold gen alg) x)
Briefly, this operation places alg
at the nodes and gen
at the leaves.
Now to the point: all recursive datastructures can be represented using a Fixed-point datatype. In Haskell this is Fix f
and it can defined as type Fix f = Free f ⊥
(i.e. Trees with f
-shaped nodes and no leaves outside of the functor f
). Traditionally this structure has a fold as well, called cata
:
cata :: Functor f => (f a -> a) -> Fix f -> a
cata alg x = fold absurd alg x
Which gives a quite neat use of absurd: since the tree cannot have any leaves (since ⊥ has no inhabitants other than undefined
), it is never possible to use the gen
for this fold and absurd
illustrates that!
$endgroup$
add a comment |
$begingroup$
To add to what has been said about the function absurd: ⊥ -> a
I have a concrete example of where this function is actually useful.
Consider the Haskell data-type Free f a
which represents a general tree structure with f
-shaped nodes and leaves containing a
s:
data Free f a = Op (f (Free f a)) | Var a
These trees can be folded with the following function:
fold :: Functor f => (a -> b) -> (f b -> b) -> Free f a -> b
fold gen alg (Var x) = gen x
fold gen alg (Op x) = alg (fmap (fold gen alg) x)
Briefly, this operation places alg
at the nodes and gen
at the leaves.
Now to the point: all recursive datastructures can be represented using a Fixed-point datatype. In Haskell this is Fix f
and it can defined as type Fix f = Free f ⊥
(i.e. Trees with f
-shaped nodes and no leaves outside of the functor f
). Traditionally this structure has a fold as well, called cata
:
cata :: Functor f => (f a -> a) -> Fix f -> a
cata alg x = fold absurd alg x
Which gives a quite neat use of absurd: since the tree cannot have any leaves (since ⊥ has no inhabitants other than undefined
), it is never possible to use the gen
for this fold and absurd
illustrates that!
$endgroup$
add a comment |
$begingroup$
To add to what has been said about the function absurd: ⊥ -> a
I have a concrete example of where this function is actually useful.
Consider the Haskell data-type Free f a
which represents a general tree structure with f
-shaped nodes and leaves containing a
s:
data Free f a = Op (f (Free f a)) | Var a
These trees can be folded with the following function:
fold :: Functor f => (a -> b) -> (f b -> b) -> Free f a -> b
fold gen alg (Var x) = gen x
fold gen alg (Op x) = alg (fmap (fold gen alg) x)
Briefly, this operation places alg
at the nodes and gen
at the leaves.
Now to the point: all recursive datastructures can be represented using a Fixed-point datatype. In Haskell this is Fix f
and it can defined as type Fix f = Free f ⊥
(i.e. Trees with f
-shaped nodes and no leaves outside of the functor f
). Traditionally this structure has a fold as well, called cata
:
cata :: Functor f => (f a -> a) -> Fix f -> a
cata alg x = fold absurd alg x
Which gives a quite neat use of absurd: since the tree cannot have any leaves (since ⊥ has no inhabitants other than undefined
), it is never possible to use the gen
for this fold and absurd
illustrates that!
$endgroup$
To add to what has been said about the function absurd: ⊥ -> a
I have a concrete example of where this function is actually useful.
Consider the Haskell data-type Free f a
which represents a general tree structure with f
-shaped nodes and leaves containing a
s:
data Free f a = Op (f (Free f a)) | Var a
These trees can be folded with the following function:
fold :: Functor f => (a -> b) -> (f b -> b) -> Free f a -> b
fold gen alg (Var x) = gen x
fold gen alg (Op x) = alg (fmap (fold gen alg) x)
Briefly, this operation places alg
at the nodes and gen
at the leaves.
Now to the point: all recursive datastructures can be represented using a Fixed-point datatype. In Haskell this is Fix f
and it can defined as type Fix f = Free f ⊥
(i.e. Trees with f
-shaped nodes and no leaves outside of the functor f
). Traditionally this structure has a fold as well, called cata
:
cata :: Functor f => (f a -> a) -> Fix f -> a
cata alg x = fold absurd alg x
Which gives a quite neat use of absurd: since the tree cannot have any leaves (since ⊥ has no inhabitants other than undefined
), it is never possible to use the gen
for this fold and absurd
illustrates that!
answered May 27 at 16:28
J_mie6J_mie6
21017
21017
add a comment |
add a comment |
$begingroup$
The bottom type is a subtype of every other type, which can be extremely useful in practice. For example, the type of NULL
in a theoretical type-safe version of C must be a subtype of every other pointer type, otherwise you couldn't e.g. return NULL
where a char*
was expected; similarly, the type of undefined
in theoretical type-safe JavaScript must be a subtype of every other type in the language.
As a function return type, it's also very useful to have certain functions that never return. In a strongly-typed language with exceptions, for instance, what type should exit()
or throw()
return? They never return control flow to their caller. And since the bottom type is a subtype of every other type, it's perfectly valid for a function returning Int
to instead return $bot$—that is, a function returning Int
can also choose not to return at all. (Maybe it calls exit()
, or maybe it goes into an infinite loop.) This is good to have, because whether a function ever returns or not is famously undecidable.
Finally, it's very useful for writing constraints. Suppose you want to constrain all parameters on "both sides", providing a type that must be a supertype of the parameter, and another type that must be a subtype. Since bottom is a subtype of every type, you can express "any subtype of S" as $bot prec T prec S$. Or, you can express "any type at all" as $bot prec T prec top$.
$endgroup$
3
$begingroup$
NULL
is a unit type isn't it, distinct from ⊥ which is the empty type?
$endgroup$
– bdsl
May 26 at 23:18
$begingroup$
I'm not sure quite what ≺ means in type theory.
$endgroup$
– bdsl
May 26 at 23:18
1
$begingroup$
@bdsl The curved operator here is "is a subtype of"; I'm not sure if it's standard, it's just what my professor used.
$endgroup$
– Draconis
May 26 at 23:40
1
$begingroup$
@gnasher729 True, but C also isn't particularly type-safe. I'm saying if you couldn't just cast an integer tovoid*
, you'd need a specific type for it that could be used for any pointer type.
$endgroup$
– Draconis
May 26 at 23:42
2
$begingroup$
Incidentally, the most common notation I've seen for the subtyping relation is<:
e.g. System $F_mathtt<:$.
$endgroup$
– Derek Elkins
May 27 at 1:50
|
show 6 more comments
$begingroup$
The bottom type is a subtype of every other type, which can be extremely useful in practice. For example, the type of NULL
in a theoretical type-safe version of C must be a subtype of every other pointer type, otherwise you couldn't e.g. return NULL
where a char*
was expected; similarly, the type of undefined
in theoretical type-safe JavaScript must be a subtype of every other type in the language.
As a function return type, it's also very useful to have certain functions that never return. In a strongly-typed language with exceptions, for instance, what type should exit()
or throw()
return? They never return control flow to their caller. And since the bottom type is a subtype of every other type, it's perfectly valid for a function returning Int
to instead return $bot$—that is, a function returning Int
can also choose not to return at all. (Maybe it calls exit()
, or maybe it goes into an infinite loop.) This is good to have, because whether a function ever returns or not is famously undecidable.
Finally, it's very useful for writing constraints. Suppose you want to constrain all parameters on "both sides", providing a type that must be a supertype of the parameter, and another type that must be a subtype. Since bottom is a subtype of every type, you can express "any subtype of S" as $bot prec T prec S$. Or, you can express "any type at all" as $bot prec T prec top$.
$endgroup$
3
$begingroup$
NULL
is a unit type isn't it, distinct from ⊥ which is the empty type?
$endgroup$
– bdsl
May 26 at 23:18
$begingroup$
I'm not sure quite what ≺ means in type theory.
$endgroup$
– bdsl
May 26 at 23:18
1
$begingroup$
@bdsl The curved operator here is "is a subtype of"; I'm not sure if it's standard, it's just what my professor used.
$endgroup$
– Draconis
May 26 at 23:40
1
$begingroup$
@gnasher729 True, but C also isn't particularly type-safe. I'm saying if you couldn't just cast an integer tovoid*
, you'd need a specific type for it that could be used for any pointer type.
$endgroup$
– Draconis
May 26 at 23:42
2
$begingroup$
Incidentally, the most common notation I've seen for the subtyping relation is<:
e.g. System $F_mathtt<:$.
$endgroup$
– Derek Elkins
May 27 at 1:50
|
show 6 more comments
$begingroup$
The bottom type is a subtype of every other type, which can be extremely useful in practice. For example, the type of NULL
in a theoretical type-safe version of C must be a subtype of every other pointer type, otherwise you couldn't e.g. return NULL
where a char*
was expected; similarly, the type of undefined
in theoretical type-safe JavaScript must be a subtype of every other type in the language.
As a function return type, it's also very useful to have certain functions that never return. In a strongly-typed language with exceptions, for instance, what type should exit()
or throw()
return? They never return control flow to their caller. And since the bottom type is a subtype of every other type, it's perfectly valid for a function returning Int
to instead return $bot$—that is, a function returning Int
can also choose not to return at all. (Maybe it calls exit()
, or maybe it goes into an infinite loop.) This is good to have, because whether a function ever returns or not is famously undecidable.
Finally, it's very useful for writing constraints. Suppose you want to constrain all parameters on "both sides", providing a type that must be a supertype of the parameter, and another type that must be a subtype. Since bottom is a subtype of every type, you can express "any subtype of S" as $bot prec T prec S$. Or, you can express "any type at all" as $bot prec T prec top$.
$endgroup$
The bottom type is a subtype of every other type, which can be extremely useful in practice. For example, the type of NULL
in a theoretical type-safe version of C must be a subtype of every other pointer type, otherwise you couldn't e.g. return NULL
where a char*
was expected; similarly, the type of undefined
in theoretical type-safe JavaScript must be a subtype of every other type in the language.
As a function return type, it's also very useful to have certain functions that never return. In a strongly-typed language with exceptions, for instance, what type should exit()
or throw()
return? They never return control flow to their caller. And since the bottom type is a subtype of every other type, it's perfectly valid for a function returning Int
to instead return $bot$—that is, a function returning Int
can also choose not to return at all. (Maybe it calls exit()
, or maybe it goes into an infinite loop.) This is good to have, because whether a function ever returns or not is famously undecidable.
Finally, it's very useful for writing constraints. Suppose you want to constrain all parameters on "both sides", providing a type that must be a supertype of the parameter, and another type that must be a subtype. Since bottom is a subtype of every type, you can express "any subtype of S" as $bot prec T prec S$. Or, you can express "any type at all" as $bot prec T prec top$.
edited May 26 at 23:43
answered May 26 at 23:08
DraconisDraconis
6,0371921
6,0371921
3
$begingroup$
NULL
is a unit type isn't it, distinct from ⊥ which is the empty type?
$endgroup$
– bdsl
May 26 at 23:18
$begingroup$
I'm not sure quite what ≺ means in type theory.
$endgroup$
– bdsl
May 26 at 23:18
1
$begingroup$
@bdsl The curved operator here is "is a subtype of"; I'm not sure if it's standard, it's just what my professor used.
$endgroup$
– Draconis
May 26 at 23:40
1
$begingroup$
@gnasher729 True, but C also isn't particularly type-safe. I'm saying if you couldn't just cast an integer tovoid*
, you'd need a specific type for it that could be used for any pointer type.
$endgroup$
– Draconis
May 26 at 23:42
2
$begingroup$
Incidentally, the most common notation I've seen for the subtyping relation is<:
e.g. System $F_mathtt<:$.
$endgroup$
– Derek Elkins
May 27 at 1:50
|
show 6 more comments
3
$begingroup$
NULL
is a unit type isn't it, distinct from ⊥ which is the empty type?
$endgroup$
– bdsl
May 26 at 23:18
$begingroup$
I'm not sure quite what ≺ means in type theory.
$endgroup$
– bdsl
May 26 at 23:18
1
$begingroup$
@bdsl The curved operator here is "is a subtype of"; I'm not sure if it's standard, it's just what my professor used.
$endgroup$
– Draconis
May 26 at 23:40
1
$begingroup$
@gnasher729 True, but C also isn't particularly type-safe. I'm saying if you couldn't just cast an integer tovoid*
, you'd need a specific type for it that could be used for any pointer type.
$endgroup$
– Draconis
May 26 at 23:42
2
$begingroup$
Incidentally, the most common notation I've seen for the subtyping relation is<:
e.g. System $F_mathtt<:$.
$endgroup$
– Derek Elkins
May 27 at 1:50
3
3
$begingroup$
NULL
is a unit type isn't it, distinct from ⊥ which is the empty type?$endgroup$
– bdsl
May 26 at 23:18
$begingroup$
NULL
is a unit type isn't it, distinct from ⊥ which is the empty type?$endgroup$
– bdsl
May 26 at 23:18
$begingroup$
I'm not sure quite what ≺ means in type theory.
$endgroup$
– bdsl
May 26 at 23:18
$begingroup$
I'm not sure quite what ≺ means in type theory.
$endgroup$
– bdsl
May 26 at 23:18
1
1
$begingroup$
@bdsl The curved operator here is "is a subtype of"; I'm not sure if it's standard, it's just what my professor used.
$endgroup$
– Draconis
May 26 at 23:40
$begingroup$
@bdsl The curved operator here is "is a subtype of"; I'm not sure if it's standard, it's just what my professor used.
$endgroup$
– Draconis
May 26 at 23:40
1
1
$begingroup$
@gnasher729 True, but C also isn't particularly type-safe. I'm saying if you couldn't just cast an integer to
void*
, you'd need a specific type for it that could be used for any pointer type.$endgroup$
– Draconis
May 26 at 23:42
$begingroup$
@gnasher729 True, but C also isn't particularly type-safe. I'm saying if you couldn't just cast an integer to
void*
, you'd need a specific type for it that could be used for any pointer type.$endgroup$
– Draconis
May 26 at 23:42
2
2
$begingroup$
Incidentally, the most common notation I've seen for the subtyping relation is
<:
e.g. System $F_mathtt<:$.$endgroup$
– Derek Elkins
May 27 at 1:50
$begingroup$
Incidentally, the most common notation I've seen for the subtyping relation is
<:
e.g. System $F_mathtt<:$.$endgroup$
– Derek Elkins
May 27 at 1:50
|
show 6 more comments
$begingroup$
There is one use I can think of, and it's something that has been considered as an improvement to the Swift programming language.
Swift has a maybe
Monad, spelled Optional<T>
or T?
. There are many ways to interact with it.
You can use conditional unwrapping like
if let nonOptional = someOptional
print(nonOptional)
else
print("someOptional was nil")You can use
map
,flatMap
to transform the values- The force unwrap operator (
!
, of type(T?) -> T
) to forcefully unwrap the contents, otherwise triggering a crash The nil-coalescing operator (
??
, of type(T?, T) -> T
) to take its value or otherwise use a default value:let someI = Optional(100)
print(someI ?? 123) => 100 // "left operand is non-nil, unwrap it.
let noneI: Int? = nil
print(noneI ?? 123) // => 123 // left operand is nil, take right operand, acts like a "default" value
Unfortunately, there was no concise way of saying "unwrap or throw an error" or "unwrap or crash with a custom error message". Something like
let someI: Int? = Optional(123)
let nonOptionalI: Int = someI ?? fatalError("Expected a non-nil value")
doesn't compile, because fatalError
has type () -> Never
(()
is Void
, Swift' unit type, Never
is Swift's bottom type). Calling it produces Never
, which isn't compatible with the T
expected as a right operand of ??
.
In an attempt to remedy this, Swift Evolution propsoal SE-0217
- The “Unwrap or Die” operator was put forth. It was ultimately rejected, but it raised interest in making Never
be a subtype of all types.
If Never
was made to be a subtype of all types, then the previous example will be compilable:
let someI: Int? = Optional(123)
let nonOptionalI: Int = someI ?? fatalError("Expected a non-nil value")
because the call site of ??
has type (T?, Never) -> T
, which would be compatible with the (T?, T) -> T
signature of ??
.
$endgroup$
add a comment |
$begingroup$
There is one use I can think of, and it's something that has been considered as an improvement to the Swift programming language.
Swift has a maybe
Monad, spelled Optional<T>
or T?
. There are many ways to interact with it.
You can use conditional unwrapping like
if let nonOptional = someOptional
print(nonOptional)
else
print("someOptional was nil")You can use
map
,flatMap
to transform the values- The force unwrap operator (
!
, of type(T?) -> T
) to forcefully unwrap the contents, otherwise triggering a crash The nil-coalescing operator (
??
, of type(T?, T) -> T
) to take its value or otherwise use a default value:let someI = Optional(100)
print(someI ?? 123) => 100 // "left operand is non-nil, unwrap it.
let noneI: Int? = nil
print(noneI ?? 123) // => 123 // left operand is nil, take right operand, acts like a "default" value
Unfortunately, there was no concise way of saying "unwrap or throw an error" or "unwrap or crash with a custom error message". Something like
let someI: Int? = Optional(123)
let nonOptionalI: Int = someI ?? fatalError("Expected a non-nil value")
doesn't compile, because fatalError
has type () -> Never
(()
is Void
, Swift' unit type, Never
is Swift's bottom type). Calling it produces Never
, which isn't compatible with the T
expected as a right operand of ??
.
In an attempt to remedy this, Swift Evolution propsoal SE-0217
- The “Unwrap or Die” operator was put forth. It was ultimately rejected, but it raised interest in making Never
be a subtype of all types.
If Never
was made to be a subtype of all types, then the previous example will be compilable:
let someI: Int? = Optional(123)
let nonOptionalI: Int = someI ?? fatalError("Expected a non-nil value")
because the call site of ??
has type (T?, Never) -> T
, which would be compatible with the (T?, T) -> T
signature of ??
.
$endgroup$
add a comment |
$begingroup$
There is one use I can think of, and it's something that has been considered as an improvement to the Swift programming language.
Swift has a maybe
Monad, spelled Optional<T>
or T?
. There are many ways to interact with it.
You can use conditional unwrapping like
if let nonOptional = someOptional
print(nonOptional)
else
print("someOptional was nil")You can use
map
,flatMap
to transform the values- The force unwrap operator (
!
, of type(T?) -> T
) to forcefully unwrap the contents, otherwise triggering a crash The nil-coalescing operator (
??
, of type(T?, T) -> T
) to take its value or otherwise use a default value:let someI = Optional(100)
print(someI ?? 123) => 100 // "left operand is non-nil, unwrap it.
let noneI: Int? = nil
print(noneI ?? 123) // => 123 // left operand is nil, take right operand, acts like a "default" value
Unfortunately, there was no concise way of saying "unwrap or throw an error" or "unwrap or crash with a custom error message". Something like
let someI: Int? = Optional(123)
let nonOptionalI: Int = someI ?? fatalError("Expected a non-nil value")
doesn't compile, because fatalError
has type () -> Never
(()
is Void
, Swift' unit type, Never
is Swift's bottom type). Calling it produces Never
, which isn't compatible with the T
expected as a right operand of ??
.
In an attempt to remedy this, Swift Evolution propsoal SE-0217
- The “Unwrap or Die” operator was put forth. It was ultimately rejected, but it raised interest in making Never
be a subtype of all types.
If Never
was made to be a subtype of all types, then the previous example will be compilable:
let someI: Int? = Optional(123)
let nonOptionalI: Int = someI ?? fatalError("Expected a non-nil value")
because the call site of ??
has type (T?, Never) -> T
, which would be compatible with the (T?, T) -> T
signature of ??
.
$endgroup$
There is one use I can think of, and it's something that has been considered as an improvement to the Swift programming language.
Swift has a maybe
Monad, spelled Optional<T>
or T?
. There are many ways to interact with it.
You can use conditional unwrapping like
if let nonOptional = someOptional
print(nonOptional)
else
print("someOptional was nil")You can use
map
,flatMap
to transform the values- The force unwrap operator (
!
, of type(T?) -> T
) to forcefully unwrap the contents, otherwise triggering a crash The nil-coalescing operator (
??
, of type(T?, T) -> T
) to take its value or otherwise use a default value:let someI = Optional(100)
print(someI ?? 123) => 100 // "left operand is non-nil, unwrap it.
let noneI: Int? = nil
print(noneI ?? 123) // => 123 // left operand is nil, take right operand, acts like a "default" value
Unfortunately, there was no concise way of saying "unwrap or throw an error" or "unwrap or crash with a custom error message". Something like
let someI: Int? = Optional(123)
let nonOptionalI: Int = someI ?? fatalError("Expected a non-nil value")
doesn't compile, because fatalError
has type () -> Never
(()
is Void
, Swift' unit type, Never
is Swift's bottom type). Calling it produces Never
, which isn't compatible with the T
expected as a right operand of ??
.
In an attempt to remedy this, Swift Evolution propsoal SE-0217
- The “Unwrap or Die” operator was put forth. It was ultimately rejected, but it raised interest in making Never
be a subtype of all types.
If Never
was made to be a subtype of all types, then the previous example will be compilable:
let someI: Int? = Optional(123)
let nonOptionalI: Int = someI ?? fatalError("Expected a non-nil value")
because the call site of ??
has type (T?, Never) -> T
, which would be compatible with the (T?, T) -> T
signature of ??
.
answered May 27 at 15:57
AlexanderAlexander
38217
38217
add a comment |
add a comment |
$begingroup$
Swift has a type "Never" which seems to be quite like the bottom type: A function declared to return Never can never return, a function with a parameter of type Never can never be called.
This is useful in connection with protocols, where there may be a restriction due to the type system of the language that a class must have a certain function, but with no requirement that this function should ever be called, and no requirement what the argument types would be.
For details you should have a look at the newer posts on the swift-evolution mailing list.
$endgroup$
7
$begingroup$
"Newer posts on the swift-evolution mailing list" is not a very clear or stable reference. Is there not a web archive of the mailing list?
$endgroup$
– Derek Elkins
May 27 at 2:10
add a comment |
$begingroup$
Swift has a type "Never" which seems to be quite like the bottom type: A function declared to return Never can never return, a function with a parameter of type Never can never be called.
This is useful in connection with protocols, where there may be a restriction due to the type system of the language that a class must have a certain function, but with no requirement that this function should ever be called, and no requirement what the argument types would be.
For details you should have a look at the newer posts on the swift-evolution mailing list.
$endgroup$
7
$begingroup$
"Newer posts on the swift-evolution mailing list" is not a very clear or stable reference. Is there not a web archive of the mailing list?
$endgroup$
– Derek Elkins
May 27 at 2:10
add a comment |
$begingroup$
Swift has a type "Never" which seems to be quite like the bottom type: A function declared to return Never can never return, a function with a parameter of type Never can never be called.
This is useful in connection with protocols, where there may be a restriction due to the type system of the language that a class must have a certain function, but with no requirement that this function should ever be called, and no requirement what the argument types would be.
For details you should have a look at the newer posts on the swift-evolution mailing list.
$endgroup$
Swift has a type "Never" which seems to be quite like the bottom type: A function declared to return Never can never return, a function with a parameter of type Never can never be called.
This is useful in connection with protocols, where there may be a restriction due to the type system of the language that a class must have a certain function, but with no requirement that this function should ever be called, and no requirement what the argument types would be.
For details you should have a look at the newer posts on the swift-evolution mailing list.
answered May 26 at 23:21
gnasher729gnasher729
13.3k1824
13.3k1824
7
$begingroup$
"Newer posts on the swift-evolution mailing list" is not a very clear or stable reference. Is there not a web archive of the mailing list?
$endgroup$
– Derek Elkins
May 27 at 2:10
add a comment |
7
$begingroup$
"Newer posts on the swift-evolution mailing list" is not a very clear or stable reference. Is there not a web archive of the mailing list?
$endgroup$
– Derek Elkins
May 27 at 2:10
7
7
$begingroup$
"Newer posts on the swift-evolution mailing list" is not a very clear or stable reference. Is there not a web archive of the mailing list?
$endgroup$
– Derek Elkins
May 27 at 2:10
$begingroup$
"Newer posts on the swift-evolution mailing list" is not a very clear or stable reference. Is there not a web archive of the mailing list?
$endgroup$
– Derek Elkins
May 27 at 2:10
add a comment |
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