Extract rows of a table, that include less than x NULLs [duplicate]Count where any 3 columns have values (not null)What do these statements mean in the MS β exam 70-461 “skills measured” list?SQL SERVER 2008 TVF OR CHARINDEX to search column with commaHow can I do a differential query (delta plus/minus) telling me what rows are in view A that are not in view B and vice versa?Unique constraint on multiple nullable columns Sql ServerHow do I include nulls during comparisons in SQL Server?How do I include nulls during comparisons in SQLServer?I can't save Database DiagramsRecompile not working for DELETE statementPerformance gap between WHERE IN (1,2,3,4) vs IN (select * from STRING_SPLIT('1,2,3,4',','))Stored procedure or Table Function doesn't return value when parsing XML

If I cast Expeditious Retreat, can I Dash as a bonus action on the same turn?

Accidentally leaked the solution to an assignment, what to do now? (I'm the prof)

What does CI-V stand for?

Font hinting is lost in Chrome-like browsers (for some languages )

What's the point of deactivating Num Lock on login screens?

The use of multiple foreign keys on same column in SQL Server

"You are your self first supporter", a more proper way to say it

Fencing style for blades that can attack from a distance

Is this a crack on the carbon frame?

Is it important to consider tone, melody, and musical form while writing a song?

Minkowski space

Dragon forelimb placement

TGV timetables / schedules?

What is the word for reserving something for yourself before others do?

Writing rule which states that two causes for the same superpower is bad writing

How can I make my BBEG immortal short of making them a Lich or Vampire?

Modeling an IPv4 Address

How do we improve the relationship with a client software team that performs poorly and is becoming less collaborative?

I’m planning on buying a laser printer but concerned about the life cycle of toner in the machine

What are the differences between the usage of 'it' and 'they'?

To string or not to string

Prove that NP is closed under karp reduction?

What do you call a Matrix-like slowdown and camera movement effect?

Why Is Death Allowed In the Matrix?



Extract rows of a table, that include less than x NULLs [duplicate]


Count where any 3 columns have values (not null)What do these statements mean in the MS β exam 70-461 “skills measured” list?SQL SERVER 2008 TVF OR CHARINDEX to search column with commaHow can I do a differential query (delta plus/minus) telling me what rows are in view A that are not in view B and vice versa?Unique constraint on multiple nullable columns Sql ServerHow do I include nulls during comparisons in SQL Server?How do I include nulls during comparisons in SQLServer?I can't save Database DiagramsRecompile not working for DELETE statementPerformance gap between WHERE IN (1,2,3,4) vs IN (select * from STRING_SPLIT('1,2,3,4',','))Stored procedure or Table Function doesn't return value when parsing XML






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








4
















This question already has an answer here:



  • Count where any 3 columns have values (not null)

    1 answer



I am working with a SQL Server database, which includes a lot of NULLs.
To analyse my data, I want to extract all rows of the database table, that include less than x NULL marks (e.g. x=2).



My database is similar to this structure:



 c1 c2 c3 c4 c5 
-----------------------------------------------------
2 3 NULL 1 2
2 NULL NULL 1 2
2 3 NULL NULL 2
NULL 3 NULL 1 NULL
2 3 NULL 1 2


I tried the query, which doesn't return an error, but no rows are selected:



SELECT * FROM test123 
WHERE ((ISNULL(c1,1) + ISNULL(c2,1) + ISNULL(c3,1) + ISNULL(c4,1) + ISNULL(c5,1)) < 2);


I expect this query to return the 1st and the fifth row, but the result contains 0 rows.




I can't test the following code, because I don't have the rights to write on the database, but here is a (pseudo-) code for creating a table like mine:



CREATE TABLE test123(
c1 float,
c2 float,
c3 float,
c4 float,
c5 float
) GO
INSERT test123(c1,c2,c3,c4,c5)
VALUES (2,3,NULL,1,2),
(2,NULL,NULL,1,2),
(2,3,NULL,NULL,2),
(NULL,3,NULL,1,NULL),
(2,3,NULL,1,2);









share|improve this question









New contributor




sqlNewie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











marked as duplicate by Paul White sql-server
Users with the  sql-server badge can single-handedly close sql-server questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
);
);
2 days ago


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
























    4
















    This question already has an answer here:



    • Count where any 3 columns have values (not null)

      1 answer



    I am working with a SQL Server database, which includes a lot of NULLs.
    To analyse my data, I want to extract all rows of the database table, that include less than x NULL marks (e.g. x=2).



    My database is similar to this structure:



     c1 c2 c3 c4 c5 
    -----------------------------------------------------
    2 3 NULL 1 2
    2 NULL NULL 1 2
    2 3 NULL NULL 2
    NULL 3 NULL 1 NULL
    2 3 NULL 1 2


    I tried the query, which doesn't return an error, but no rows are selected:



    SELECT * FROM test123 
    WHERE ((ISNULL(c1,1) + ISNULL(c2,1) + ISNULL(c3,1) + ISNULL(c4,1) + ISNULL(c5,1)) < 2);


    I expect this query to return the 1st and the fifth row, but the result contains 0 rows.




    I can't test the following code, because I don't have the rights to write on the database, but here is a (pseudo-) code for creating a table like mine:



    CREATE TABLE test123(
    c1 float,
    c2 float,
    c3 float,
    c4 float,
    c5 float
    ) GO
    INSERT test123(c1,c2,c3,c4,c5)
    VALUES (2,3,NULL,1,2),
    (2,NULL,NULL,1,2),
    (2,3,NULL,NULL,2),
    (NULL,3,NULL,1,NULL),
    (2,3,NULL,1,2);









    share|improve this question









    New contributor




    sqlNewie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.











    marked as duplicate by Paul White sql-server
    Users with the  sql-server badge can single-handedly close sql-server questions as duplicates and reopen them as needed.

    StackExchange.ready(function()
    if (StackExchange.options.isMobile) return;

    $('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
    var $hover = $(this).addClass('hover-bound'),
    $msg = $hover.siblings('.dupe-hammer-message');

    $hover.hover(
    function()
    $hover.showInfoMessage('',
    messageElement: $msg.clone().show(),
    transient: false,
    position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
    dismissable: false,
    relativeToBody: true
    );
    ,
    function()
    StackExchange.helpers.removeMessages();

    );
    );
    );
    2 days ago


    This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.




















      4












      4








      4


      0







      This question already has an answer here:



      • Count where any 3 columns have values (not null)

        1 answer



      I am working with a SQL Server database, which includes a lot of NULLs.
      To analyse my data, I want to extract all rows of the database table, that include less than x NULL marks (e.g. x=2).



      My database is similar to this structure:



       c1 c2 c3 c4 c5 
      -----------------------------------------------------
      2 3 NULL 1 2
      2 NULL NULL 1 2
      2 3 NULL NULL 2
      NULL 3 NULL 1 NULL
      2 3 NULL 1 2


      I tried the query, which doesn't return an error, but no rows are selected:



      SELECT * FROM test123 
      WHERE ((ISNULL(c1,1) + ISNULL(c2,1) + ISNULL(c3,1) + ISNULL(c4,1) + ISNULL(c5,1)) < 2);


      I expect this query to return the 1st and the fifth row, but the result contains 0 rows.




      I can't test the following code, because I don't have the rights to write on the database, but here is a (pseudo-) code for creating a table like mine:



      CREATE TABLE test123(
      c1 float,
      c2 float,
      c3 float,
      c4 float,
      c5 float
      ) GO
      INSERT test123(c1,c2,c3,c4,c5)
      VALUES (2,3,NULL,1,2),
      (2,NULL,NULL,1,2),
      (2,3,NULL,NULL,2),
      (NULL,3,NULL,1,NULL),
      (2,3,NULL,1,2);









      share|improve this question









      New contributor




      sqlNewie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.













      This question already has an answer here:



      • Count where any 3 columns have values (not null)

        1 answer



      I am working with a SQL Server database, which includes a lot of NULLs.
      To analyse my data, I want to extract all rows of the database table, that include less than x NULL marks (e.g. x=2).



      My database is similar to this structure:



       c1 c2 c3 c4 c5 
      -----------------------------------------------------
      2 3 NULL 1 2
      2 NULL NULL 1 2
      2 3 NULL NULL 2
      NULL 3 NULL 1 NULL
      2 3 NULL 1 2


      I tried the query, which doesn't return an error, but no rows are selected:



      SELECT * FROM test123 
      WHERE ((ISNULL(c1,1) + ISNULL(c2,1) + ISNULL(c3,1) + ISNULL(c4,1) + ISNULL(c5,1)) < 2);


      I expect this query to return the 1st and the fifth row, but the result contains 0 rows.




      I can't test the following code, because I don't have the rights to write on the database, but here is a (pseudo-) code for creating a table like mine:



      CREATE TABLE test123(
      c1 float,
      c2 float,
      c3 float,
      c4 float,
      c5 float
      ) GO
      INSERT test123(c1,c2,c3,c4,c5)
      VALUES (2,3,NULL,1,2),
      (2,NULL,NULL,1,2),
      (2,3,NULL,NULL,2),
      (NULL,3,NULL,1,NULL),
      (2,3,NULL,1,2);




      This question already has an answer here:



      • Count where any 3 columns have values (not null)

        1 answer







      sql-server query isnull






      share|improve this question









      New contributor




      sqlNewie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      sqlNewie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited Apr 3 at 19:23









      MDCCL

      6,85331745




      6,85331745






      New contributor




      sqlNewie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked Apr 3 at 16:57









      sqlNewiesqlNewie

      283




      283




      New contributor




      sqlNewie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      sqlNewie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      sqlNewie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




      marked as duplicate by Paul White sql-server
      Users with the  sql-server badge can single-handedly close sql-server questions as duplicates and reopen them as needed.

      StackExchange.ready(function()
      if (StackExchange.options.isMobile) return;

      $('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
      var $hover = $(this).addClass('hover-bound'),
      $msg = $hover.siblings('.dupe-hammer-message');

      $hover.hover(
      function()
      $hover.showInfoMessage('',
      messageElement: $msg.clone().show(),
      transient: false,
      position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
      dismissable: false,
      relativeToBody: true
      );
      ,
      function()
      StackExchange.helpers.removeMessages();

      );
      );
      );
      2 days ago


      This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.









      marked as duplicate by Paul White sql-server
      Users with the  sql-server badge can single-handedly close sql-server questions as duplicates and reopen them as needed.

      StackExchange.ready(function()
      if (StackExchange.options.isMobile) return;

      $('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
      var $hover = $(this).addClass('hover-bound'),
      $msg = $hover.siblings('.dupe-hammer-message');

      $hover.hover(
      function()
      $hover.showInfoMessage('',
      messageElement: $msg.clone().show(),
      transient: false,
      position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
      dismissable: false,
      relativeToBody: true
      );
      ,
      function()
      StackExchange.helpers.removeMessages();

      );
      );
      );
      2 days ago


      This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






















          2 Answers
          2






          active

          oldest

          votes


















          7














          You should use a case statement like this:



          SELECT * 
          FROM test123
          WHERE (
          (CASE WHEN C1 IS NULL THEN 1 ELSE 0 END +
          CASE WHEN C2 IS NULL THEN 1 ELSE 0 END +
          CASE WHEN C3 IS NULL THEN 1 ELSE 0 END +
          CASE WHEN C4 IS NULL THEN 1 ELSE 0 END +
          CASE WHEN C5 IS NULL THEN 1 ELSE 0 END)
          < 2);


          The ISNULL approach is returning your actual values when the value isn't NULL, which pushes all of the rows over the 2 mark.






          share|improve this answer






























            8














            Permissions to create a table in the current database shouldn't preclude you from creating one you can work with. You can just create a #temp table:



            CREATE TABLE #test123(
            c1 float,
            c2 float,
            c3 float,
            c4 float,
            c5 float
            );

            INSERT #test123(c1,c2,c3,c4,c5);
            VALUES (2,3,NULL,1,2),
            (2,NULL,NULL,1,2),
            (2,3,NULL,NULL,2),
            (NULL,3,NULL,1,NULL),
            (2,3,NULL,1,2);


            To see why ISNULL isn't effective here, run this query:



            SELECT ISNULL(c1,1), ISNULL(c2,1), ISNULL(c3,1), ISNULL(c4,1), ISNULL(c5,1)
            FROM #test123;


            You've given every column in every row a value. So now you're evaluating the SUM of inflated values, and erroneously evaluating a property of the actual value (what happens when one of the values is negative?), instead of evaluating the COUNT of values that either are NULL or are NOT NULL.



            It's more code but a simple way to address this is:



            SELECT * FROM #test123
            WHERE CASE WHEN c1 IS NULL THEN 1 ELSE 0 END
            + CASE WHEN c2 IS NULL THEN 1 ELSE 0 END
            + CASE WHEN c3 IS NULL THEN 1 ELSE 0 END
            + CASE WHEN c4 IS NULL THEN 1 ELSE 0 END
            + CASE WHEN c5 IS NULL THEN 1 ELSE 0 END < 2;





            share|improve this answer





























              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              7














              You should use a case statement like this:



              SELECT * 
              FROM test123
              WHERE (
              (CASE WHEN C1 IS NULL THEN 1 ELSE 0 END +
              CASE WHEN C2 IS NULL THEN 1 ELSE 0 END +
              CASE WHEN C3 IS NULL THEN 1 ELSE 0 END +
              CASE WHEN C4 IS NULL THEN 1 ELSE 0 END +
              CASE WHEN C5 IS NULL THEN 1 ELSE 0 END)
              < 2);


              The ISNULL approach is returning your actual values when the value isn't NULL, which pushes all of the rows over the 2 mark.






              share|improve this answer



























                7














                You should use a case statement like this:



                SELECT * 
                FROM test123
                WHERE (
                (CASE WHEN C1 IS NULL THEN 1 ELSE 0 END +
                CASE WHEN C2 IS NULL THEN 1 ELSE 0 END +
                CASE WHEN C3 IS NULL THEN 1 ELSE 0 END +
                CASE WHEN C4 IS NULL THEN 1 ELSE 0 END +
                CASE WHEN C5 IS NULL THEN 1 ELSE 0 END)
                < 2);


                The ISNULL approach is returning your actual values when the value isn't NULL, which pushes all of the rows over the 2 mark.






                share|improve this answer

























                  7












                  7








                  7







                  You should use a case statement like this:



                  SELECT * 
                  FROM test123
                  WHERE (
                  (CASE WHEN C1 IS NULL THEN 1 ELSE 0 END +
                  CASE WHEN C2 IS NULL THEN 1 ELSE 0 END +
                  CASE WHEN C3 IS NULL THEN 1 ELSE 0 END +
                  CASE WHEN C4 IS NULL THEN 1 ELSE 0 END +
                  CASE WHEN C5 IS NULL THEN 1 ELSE 0 END)
                  < 2);


                  The ISNULL approach is returning your actual values when the value isn't NULL, which pushes all of the rows over the 2 mark.






                  share|improve this answer













                  You should use a case statement like this:



                  SELECT * 
                  FROM test123
                  WHERE (
                  (CASE WHEN C1 IS NULL THEN 1 ELSE 0 END +
                  CASE WHEN C2 IS NULL THEN 1 ELSE 0 END +
                  CASE WHEN C3 IS NULL THEN 1 ELSE 0 END +
                  CASE WHEN C4 IS NULL THEN 1 ELSE 0 END +
                  CASE WHEN C5 IS NULL THEN 1 ELSE 0 END)
                  < 2);


                  The ISNULL approach is returning your actual values when the value isn't NULL, which pushes all of the rows over the 2 mark.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Apr 3 at 17:07









                  Josh DarnellJosh Darnell

                  7,84022243




                  7,84022243























                      8














                      Permissions to create a table in the current database shouldn't preclude you from creating one you can work with. You can just create a #temp table:



                      CREATE TABLE #test123(
                      c1 float,
                      c2 float,
                      c3 float,
                      c4 float,
                      c5 float
                      );

                      INSERT #test123(c1,c2,c3,c4,c5);
                      VALUES (2,3,NULL,1,2),
                      (2,NULL,NULL,1,2),
                      (2,3,NULL,NULL,2),
                      (NULL,3,NULL,1,NULL),
                      (2,3,NULL,1,2);


                      To see why ISNULL isn't effective here, run this query:



                      SELECT ISNULL(c1,1), ISNULL(c2,1), ISNULL(c3,1), ISNULL(c4,1), ISNULL(c5,1)
                      FROM #test123;


                      You've given every column in every row a value. So now you're evaluating the SUM of inflated values, and erroneously evaluating a property of the actual value (what happens when one of the values is negative?), instead of evaluating the COUNT of values that either are NULL or are NOT NULL.



                      It's more code but a simple way to address this is:



                      SELECT * FROM #test123
                      WHERE CASE WHEN c1 IS NULL THEN 1 ELSE 0 END
                      + CASE WHEN c2 IS NULL THEN 1 ELSE 0 END
                      + CASE WHEN c3 IS NULL THEN 1 ELSE 0 END
                      + CASE WHEN c4 IS NULL THEN 1 ELSE 0 END
                      + CASE WHEN c5 IS NULL THEN 1 ELSE 0 END < 2;





                      share|improve this answer



























                        8














                        Permissions to create a table in the current database shouldn't preclude you from creating one you can work with. You can just create a #temp table:



                        CREATE TABLE #test123(
                        c1 float,
                        c2 float,
                        c3 float,
                        c4 float,
                        c5 float
                        );

                        INSERT #test123(c1,c2,c3,c4,c5);
                        VALUES (2,3,NULL,1,2),
                        (2,NULL,NULL,1,2),
                        (2,3,NULL,NULL,2),
                        (NULL,3,NULL,1,NULL),
                        (2,3,NULL,1,2);


                        To see why ISNULL isn't effective here, run this query:



                        SELECT ISNULL(c1,1), ISNULL(c2,1), ISNULL(c3,1), ISNULL(c4,1), ISNULL(c5,1)
                        FROM #test123;


                        You've given every column in every row a value. So now you're evaluating the SUM of inflated values, and erroneously evaluating a property of the actual value (what happens when one of the values is negative?), instead of evaluating the COUNT of values that either are NULL or are NOT NULL.



                        It's more code but a simple way to address this is:



                        SELECT * FROM #test123
                        WHERE CASE WHEN c1 IS NULL THEN 1 ELSE 0 END
                        + CASE WHEN c2 IS NULL THEN 1 ELSE 0 END
                        + CASE WHEN c3 IS NULL THEN 1 ELSE 0 END
                        + CASE WHEN c4 IS NULL THEN 1 ELSE 0 END
                        + CASE WHEN c5 IS NULL THEN 1 ELSE 0 END < 2;





                        share|improve this answer

























                          8












                          8








                          8







                          Permissions to create a table in the current database shouldn't preclude you from creating one you can work with. You can just create a #temp table:



                          CREATE TABLE #test123(
                          c1 float,
                          c2 float,
                          c3 float,
                          c4 float,
                          c5 float
                          );

                          INSERT #test123(c1,c2,c3,c4,c5);
                          VALUES (2,3,NULL,1,2),
                          (2,NULL,NULL,1,2),
                          (2,3,NULL,NULL,2),
                          (NULL,3,NULL,1,NULL),
                          (2,3,NULL,1,2);


                          To see why ISNULL isn't effective here, run this query:



                          SELECT ISNULL(c1,1), ISNULL(c2,1), ISNULL(c3,1), ISNULL(c4,1), ISNULL(c5,1)
                          FROM #test123;


                          You've given every column in every row a value. So now you're evaluating the SUM of inflated values, and erroneously evaluating a property of the actual value (what happens when one of the values is negative?), instead of evaluating the COUNT of values that either are NULL or are NOT NULL.



                          It's more code but a simple way to address this is:



                          SELECT * FROM #test123
                          WHERE CASE WHEN c1 IS NULL THEN 1 ELSE 0 END
                          + CASE WHEN c2 IS NULL THEN 1 ELSE 0 END
                          + CASE WHEN c3 IS NULL THEN 1 ELSE 0 END
                          + CASE WHEN c4 IS NULL THEN 1 ELSE 0 END
                          + CASE WHEN c5 IS NULL THEN 1 ELSE 0 END < 2;





                          share|improve this answer













                          Permissions to create a table in the current database shouldn't preclude you from creating one you can work with. You can just create a #temp table:



                          CREATE TABLE #test123(
                          c1 float,
                          c2 float,
                          c3 float,
                          c4 float,
                          c5 float
                          );

                          INSERT #test123(c1,c2,c3,c4,c5);
                          VALUES (2,3,NULL,1,2),
                          (2,NULL,NULL,1,2),
                          (2,3,NULL,NULL,2),
                          (NULL,3,NULL,1,NULL),
                          (2,3,NULL,1,2);


                          To see why ISNULL isn't effective here, run this query:



                          SELECT ISNULL(c1,1), ISNULL(c2,1), ISNULL(c3,1), ISNULL(c4,1), ISNULL(c5,1)
                          FROM #test123;


                          You've given every column in every row a value. So now you're evaluating the SUM of inflated values, and erroneously evaluating a property of the actual value (what happens when one of the values is negative?), instead of evaluating the COUNT of values that either are NULL or are NOT NULL.



                          It's more code but a simple way to address this is:



                          SELECT * FROM #test123
                          WHERE CASE WHEN c1 IS NULL THEN 1 ELSE 0 END
                          + CASE WHEN c2 IS NULL THEN 1 ELSE 0 END
                          + CASE WHEN c3 IS NULL THEN 1 ELSE 0 END
                          + CASE WHEN c4 IS NULL THEN 1 ELSE 0 END
                          + CASE WHEN c5 IS NULL THEN 1 ELSE 0 END < 2;






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Apr 3 at 17:09









                          Aaron BertrandAaron Bertrand

                          154k18298493




                          154k18298493













                              Popular posts from this blog

                              Wikipedia:Vital articles Мазмуну Biography - Өмүр баян Philosophy and psychology - Философия жана психология Religion - Дин Social sciences - Коомдук илимдер Language and literature - Тил жана адабият Science - Илим Technology - Технология Arts and recreation - Искусство жана эс алуу History and geography - Тарых жана география Навигация менюсу

                              Bruxelas-Capital Índice Historia | Composición | Situación lingüística | Clima | Cidades irmandadas | Notas | Véxase tamén | Menú de navegacióneO uso das linguas en Bruxelas e a situación do neerlandés"Rexión de Bruxelas Capital"o orixinalSitio da rexiónPáxina de Bruselas no sitio da Oficina de Promoción Turística de Valonia e BruxelasMapa Interactivo da Rexión de Bruxelas-CapitaleeWorldCat332144929079854441105155190212ID28008674080552-90000 0001 0666 3698n94104302ID540940339365017018237

                              What should I write in an apology letter, since I have decided not to join a company after accepting an offer letterShould I keep looking after accepting a job offer?What should I do when I've been verbally told I would get an offer letter, but still haven't gotten one after 4 weeks?Do I accept an offer from a company that I am not likely to join?New job hasn't confirmed starting date and I want to give current employer as much notice as possibleHow should I address my manager in my resignation letter?HR delayed background verification, now jobless as resignedNo email communication after accepting a formal written offer. How should I phrase the call?What should I do if after receiving a verbal offer letter I am informed that my written job offer is put on hold due to some internal issues?Should I inform the current employer that I am about to resign within 1-2 weeks since I have signed the offer letter and waiting for visa?What company will do, if I send their offer letter to another company